Which equation could be used to solve problems involving the relationships between the angles?
A) 90+(8a+9)=(11+2a)
B) 90-(8a+9)=(11+2a)
C) (11+2a)-90=(8a+9)
D) (8a+9)-(11+2a)=90

Answer:

9 hours with no stops

Step-by-step explanation:

540 mile drive  

60 MPH

distance divided by rate is 540 divided by 60 = 9

Answer:

c = 2.6 = [tex]\frac{13}{5}[/tex] = 2 [tex]\frac{3}{5}[/tex]

Step-by-step explanation:

d = 0.26 = [tex]\frac{13}{50}[/tex]

Hope this helps

Answer:

$6

Step-by-step explanation:

Answer:

Hello

Step-by-step explanation:

I can't see the picture, can you please explain the problem in the comment bar below this so can edit my answer to help?

Answer: $181.48 O_O

Step-by-step explanation: i know that stuff

Answer:

$530.48

Step-by-step explanation:

i can answer now yay

Answer:

i dont see a x-

Step-by-step explanation:

Answer: A cross section is the shape we get when cutting straight through an object.

Step-by-step explanation:

Answer:

1,728 yd²

Step-by-step explanation:

Area = b × h

36 yd will be the replacement for b

48 yd will be the replacement for h

Now we multiply 36 by 48

36 × 48 = 1,728 yd²

Answer:

1728

Step-by-step explanation:

Answer:

[tex]f(x) = 3^x[/tex] --- Function A

[tex]f(x) = x^2 - 5[/tex] --- Function B

[tex]f(x) = 18x -6[/tex] --- Function C

Step-by-step explanation:

Solving (a): Equation of Function A

An exponential equation is represented as:

[tex]y = ab^x[/tex]

From the graph of function A,

[tex]x = 0\ when\ y = 1[/tex]

[tex]x = 1\ when\ y = 3[/tex]

For: [tex]x = 0\ when\ y = 1[/tex]

[tex]y = ab^x[/tex] becomes

[tex]1 = ab^0[/tex]

[tex]1 = a[/tex]

[tex]a =1[/tex]

For: [tex]x = 1\ when\ y = 3[/tex]

[tex]y = ab^x[/tex] becomes

[tex]3 = a*b^1[/tex]

[tex]3 = a*b[/tex]

Substitute 1 for a

[tex]3 = 1*b[/tex]

[tex]3 = b[/tex]

[tex]b = 3[/tex]

[tex]y = ab^x[/tex] becomes

[tex]y = 1*3^x[/tex]

[tex]y = 3^x[/tex]

Replace y with f(x)

[tex]f(x) = 3^x[/tex]

Solving (b): Equation of Function B

A quadratic equation is represented as:

[tex]y = ax^2 + bx + c[/tex]

From the table of function B,

[tex]x = 3\ when\ y =4[/tex]

[tex]x = 5\ when\ y =20[/tex]

[tex]x = 6\ when\ y =31[/tex]

For: [tex]x = 3\ when\ y =4[/tex]

[tex]y = ax^2 + bx + c[/tex] becomes

[tex]4 = a*3^2 + b*3 + c[/tex]

[tex]4 = a*9 + 3b + c[/tex]

[tex]4 = 9a + 3b + c[/tex]

For [tex]x = 5\ when\ y =20[/tex]

[tex]y = ax^2 + bx + c[/tex] becomes

[tex]20 = a*5^2 + b*5 + c[/tex]

[tex]20 = a*25 + b*5 + c[/tex]

[tex]20 = 25a + 5b + c[/tex]

For [tex]x = 6\ when\ y =31[/tex]

[tex]y = ax^2 + bx + c[/tex] becomes

[tex]31 = a*6^2 + b*6 + c[/tex]

[tex]31 = a*36 + b*6 + c[/tex]

[tex]31 = 36a + 6b + c[/tex]

So, we solve for a, b and c in:

[tex]4 = 9a + 3b + c[/tex]

[tex]20 = 25a + 5b + c[/tex]

[tex]31 = 36a + 6b + c[/tex]

Make c the subject in [tex]4 = 9a + 3b + c[/tex]

[tex]c = 4 - 9a - 3b[/tex]

Substitute [tex]c = 4 - 9a - 3b[/tex] in [tex]20 = 25a + 5b + c[/tex] and [tex]31 = 36a + 6b + c[/tex]

[tex]20 = 25a + 5b + c[/tex] becomes

[tex]20 = 25a + 5b + 4-9a-3b[/tex]

Collect Like Terms

[tex]-4+20 = 25a -9a+ 5b -3b[/tex]

[tex]16 = 16a+ 2b[/tex]

Divide through by 2

[tex]8 = 8a + b[/tex]

[tex]c = 4 - 9a - 3b[/tex]

[tex]31 = 36a + 6b + c[/tex] becomes

[tex]31 = 36a + 6b + 4 - 9a - 3b[/tex]

Collect Like Terms

[tex]-4+31 = 36a - 9a+ 6b - 3b[/tex]

[tex]27 = 27a+ 3b[/tex]

Divide through by 3

[tex]9 = 9a + b[/tex]

Solve for a and b in: [tex]8 = 8a + b[/tex] and [tex]9 = 9a + b[/tex]

Subtract both equations:

[tex]8 - 9 = 8a - 9a + b - b[/tex]

[tex]8 - 9 = 8a - 9a[/tex]

[tex]-1 = -a[/tex]

Divide both sides by -1

[tex]1 = a[/tex]

[tex]a = 1[/tex]

Substitute 1 for a in [tex]9 = 9a + b[/tex]

[tex]9 = 9*1 + b[/tex]

[tex]9 = 9 +b[/tex]

Subtract 9 from both sides

[tex]9-9=9-9+b[/tex]

[tex]0=b[/tex]

[tex]b = 0[/tex]

Substitute [tex]b = 0[/tex] and [tex]a = 1[/tex] in [tex]c = 4 - 9a - 3b[/tex]

[tex]c = 4 - 9*1-3*0[/tex]

[tex]c = 4 - 9-0[/tex]

[tex]c = -5[/tex]

So, the equation is:

[tex]y = ax^2 + bx + c[/tex]

[tex]y=1*x^2 +0*x-5[/tex]

[tex]y=x^2 -5[/tex]

Replace y with f(x)

[tex]f(x) = x^2 - 5[/tex]

Solving (c): Equation of Function C

This is calculated using:

[tex]f(x) =a + (x -1)d[/tex]

Where

[tex]a = 12[/tex] -- the first term

d = the difference between successive terms

[tex]d = 30 -12 = 48-30 = 66 -48[/tex]

[tex]d =18[/tex]

So, we have:

[tex]f(x) =a + (x -1)d[/tex]

[tex]f(x) = 12 + (x - 1)*18[/tex]

Open bracket

[tex]f(x) = 12 + 18x - 18[/tex]

Collect Like Terms

[tex]f(x) = 18x - 18+12[/tex]

[tex]f(x) = 18x -6[/tex]

Step-by-step explanation:

Answer: -40

Step-by-step explanation:

Answer:

35 squared plus x squared equals 78 Squared

which makes your answer

69.7

Step-by-step explanation:

Answer:

35 square + x square 78 square

= 69.7

Step-by-step explanation:

Answer:

2x+15=33

Step-by-step explanation:

Let n be the number of days he has been doing sit ups, not counting the first day. Since he does 2 more sit-ups for each day, then the number of additional sit-ups is 2n.

Since he started doing  15 sit-ups on the first day, the total number of sit-ups

after x days would be 2n+15.

Since he did a total of 33 sit ups today, then 2n+15=33

Answer:

-x

Step-by-step explanation:

Answer:

Rip i saw you said times up :/

Step-by-step explanation:

Answer:

1 - 155 +27n

2- 2x+15=33

Step-by-step explanation:

hope this helps

Answer:

(1-2) LS = 288cm² TS = 378cm²

(3-4) LS = 1419.2 TS = 1673.5

(5) LS = 543 TS = 606

Step-by-step explanation:

(1-2)

7 1/2 = 7.5

7.5 x 15 = 112.5

9 x 12  ➗ 2 = 54

54 x 2 = 108

9 x 7.5 = 67 .5

(3-4)

3.14 x 81 = 254.3

(5)

9 x 15 = 135 x 2 = 270

15 x 7 = 105 x 2 = 210

9 x 7 = 63

(add)

Answer:

D

Step-by-step explanation:

there are data values from 17-26

so D

Answer:

400 + 8m

Step-by-step explanation:

Starts with $400 in her account. Every day (we'll use the variable m for the number of days), she deposits $8.

400 + 8m

If you were to be asked how much money she has in her bank account after 10 days, you plug in 10 for m. Same for any other number of days.

Answer:

15 times-

Step-by-step explanation:

Answer:

the answer is 78,000

Step-by-step explanation:

your welcome

Just do this in your head,780/10=78 then add on the three zeros from 780000 that you didnt use. 78>>> 78000

Answer=78000

Based on the model, we find the dimensions of the cube. The length of the model building is 2/3 centimeter. The width of the model building is 1/3 centimeter. The height of the model building is 1/2 centimeter. The volume of the model building is 1/9 cubic centimeter.

A cube is 3- dimensional shape with 6 equal sides, 6 faces, and 6 vertices in geometry. Each face of a cube is a square. In 3 – dimension, the cube’s sides are; the length, width, and height. Sides of a cube are all equal i.e. Length = Width = Height = a.

The length = breadth = height (of one cube) = 1/6 cm

The length of the model consist of 4 cubes.

Length of model building = 4 * 1/6 cm = 2/3 cm

The width of the model consist of 2 cubes.

Width of model building = 2 * 1/6 cm = 1/3 cm

The height of the model consist of 3 cubes.

Height of model building = 3 * 1/6 cm = 1/2 cm

Volume of the model (cuboid) =

= Length * breadth * height

= [tex]\frac{2}{3} * \frac{1}{3}*\frac{1}{2} = \frac{1}{9}[/tex]

Learn more about dimensions of a cube here

https://brainly.com/question/6507675

#SPJ2

Answer:

23/6

Step-by-step explanation:

3/56

Answer:

X=6

Step-by-step explanation:

Answer: x=6

Step-by-step explanation: Solve for x by simplifying both sides of the equation, then isolate your variable.

I hope this helps.