Answer: (x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)2•(x-3)2
Step-by-step explanation: Step by Step Solution
More Icon
STEP
1
:
Equation at the end of step 1
((((((((((((((x-4)•(x-1)•(x+2))•(x+3))•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
2
:
Equation at the end of step 2
(((((((((((((x-4)•(x-1)•(x+2)•(x+3))•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
3
:
Equation at the end of step 3
((((((((((((x-4)•(x-1)•(x+2)•(x+3)•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
4
:
Multiplying Exponential Expressions:
4.1 Multiply (x-4) by (x-4)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x-4) and the exponents are :
1 , as (x-4) is the same number as (x-4)1
and 1 , as (x-4) is the same number as (x-4)1
The product is therefore, (x-4)(1+1) = (x-4)2
Equation at the end of step
4
:
(((((((((((x-4)2•(x-1)•(x+2)•(x+3)•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
5
:
5.1 Rewrite (1-x) as (-1) • (x-1)
Multiplying Exponential Expressions:
5.2 Multiply (x-1) by (x-1)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x-1) and the exponents are :
1 , as (x-1) is the same number as (x-1)1
and 1 , as (x-1) is the same number as (x-1)1
The product is therefore, (x-1)(1+1) = (x-1)2
STEP
7
:
Pulling out like terms
7.1 Pull out like factors :
-x - 2 = -1 • (x + 2)
Multiplying Exponential Expressions:
7.2 Multiply (x + 2) by (x + 2)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x+2) and the exponents are :
1 , as (x+2) is the same number as (x+2)1
and 1 , as (x+2) is the same number as (x+2)1
The product is therefore, (x+2)(1+1) = (x+2)2
STEP
9
:
Pulling out like terms
9.1 Pull out like factors :
-x - 3 = -1 • (x + 3)
Multiplying Exponential Expressions:
9.2 Multiply (x + 3) by (x + 3)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x+3) and the exponents are :
1 , as (x+3) is the same number as (x+3)1
and 1 , as (x+3) is the same number as (x+3)1
The product is therefore, (x+3)(1+1) = (x+3)
((((((((x-4)2•(x-1)2•(x+2)2•-1•(x+3)2•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
10
:
Equation at the end of step 10
(((((((x-4)2•(x-1)2•(x+2)2•(x+3)2•(-x-4)•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
11
:
STEP
12
:
Pulling out like terms
12.1 Pull out like factors :
-x - 4 = -1 • (x + 4)
Equation at the end of step
12
:
((((((x-4)2•(x-1)2•(x+2)2•(x+3)2•(-x-4)•(x+1)•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)
STEP
13
:
STEP
14
:
Pulling out like terms
14.1 Pull out like factors :
-x - 4 = -1 • (x + 4)
Equation at the end of step
14
STEP
15
STEP
16
:
Pulling out like terms
16.1 Pull out like factors :
-x - 4 = -1 •
Equation at the end of step
16
:
STEP
17
:
STEP
18
:
Pulling out like terms
18.1 Pull out like factors :
-x - 4 = -1 • (x + 4)
Multiplying Exponential Expressions:
18.2 Multiply (x + 4) by (x + 4)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x+4) and the exponents are :
1 , as (x+4) is the same number as (x+4)1
and 1 , as (x+4) is the same number as (x+4)1
The product is therefore, (x+4)(1+1) = (x+4)2
Equation at the end of step
18
:
(((x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(-x-1)•(2-x)•(3-x)•(x+1))•(2-x))•(x-3)
STEP
19
:
STEP
20
:
Pulling out like terms
20.1 Pull out like factors :
-x - 1 = -1 • (x + 1)
Multiplying Exponential Expressions:
20.2 Multiply (x + 1) by (x + 1)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x+1) and the exponents are :
1 , as (x+1) is the same number as (x+1)1
and 1 , as (x+1) is the same number as (x+1)1
The product is therefore, (x+1)(1+1) = (x+1)2
Equation at the end of step
20
:
((x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)•(3-x)•(2-x))•(x-3)
STEP
21
:
21.1 Rewrite (2-x) as (-1) • (x-2)
Multiplying Exponential Expressions:
21.2 Multiply (x-2) by (x-2)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x-2) and the exponents are :
1 , as (x-2) is the same number as (x-2)1
and 1 , as (x-2) is the same number as (x-2)1
The product is therefore, (x-2)(1+1) = (x-2)2
22.1 Multiply (x-3) by (x-3)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (x-3) and the exponents are :
1 , as (x-3) is the same number as (x-3)1
and 1 , as (x-3) is the same number as (x-3)1
The product is therefore, (x-3)(1+1) = (x-3)2
Final result :
(x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)2•(x-3)2
According to Greg, perfect cherry pies have a ratio of
240 cherries to
3pies.
How many cherries does Greg need to make
9 perfect cherry pies?
What is the value of x in the equation 8 + x = 3? (4 points) −5 5 11 24
Answer:
-5 is the correct answer
Answer:
-5
Step-by-step explanation:
a) write √3 × √6 in the form b√2 where b is an integer
Answer: 3√2
√3 . √6 = √(3.6) = √(9.2) = √(3².2) = 3√2
Step-by-step explanation:
Answer:
b = 3
Step-by-step explanation:
[tex] \sqrt{6} [/tex]can be written as [tex] \sqrt{3} \times \sqrt{2} [/tex]
So, lets arrange it.
[tex] \sqrt{3} \times \sqrt{6} = \sqrt{3} \times \sqrt{3} \times \sqrt{2} = 3 \sqrt{2} [/tex]
Hence b = 3.
The radii of two right circular cylinders are in the ratio 3 : 4 and their heights are in the ratio 1 : 2. Calculate the ratio of their curved surface areas
Answer:
18.852:50.272
Step-by-step explanation:
Step one:
given
The radii of two right circular cylinders are in the ratio 3 : 4
r1= 3
r2= 4
Their heights are in the ratio 1 : 2
h1= 1
h2= 2
Step two:
The expression for the curve surface area is
CSA= 2πrh
CAS1= 2πr1h1
CAS1= 2*3.142*3*1
CAS1= 18.852
CAS2= 2πr2h2
CAS2= 2*3.142*4*2
CAS1= 50.272
The ratio of their curved surface areas
=18.852:50.272
Find the VALUE of or EVALUATE 7a - 9 when a = 10. (HINT: 7a means 7 times a which is 7 times 10)
Answer:
61
Step-by-step explanation:
7a-9 = 7(10)-9 = 70-9 = 61
Determine which of the following terms are not considered to be like terms with the expression -6s2t. Select all situations that apply.
( s2)( t)
10 ∙ s2 ∙ t
4( s ∙ t)
-6( s2 + t)
s2t
s2 ∙ t2
Please help I dont have much time
Answer:
[tex](s^{2})(t) , 10^{2}t, s^{2}t[/tex] are the correct answers
Step-by-step explanation:
The others don't work because they don't have the same power for each variable.
Answer:
It is s^2(t), 10 *s^2 * t, and (1/4) (s^2)(t)
Round each number to the tenths place.
0.95
0.63
0.555
WILL GIVE BRAINELIEST ( dont know how to spell it lol)
Temperature can be measured in degrees Celsius (°C). A temperature of 0°C is the freezing point of water. Which statements are true?
Select all correct answers.
A temperature of 10°C is colder than –12°C.
A temperature of 10°C is colder than –12°C.
When the temperature is 70° above freezing, the temperature is 70°C.
When the temperature is 70° above freezing, the temperature is 70°C.
A temperature of –16°C is colder than –12°C.
A temperature of –16°C is colder than –12°C.
A temperature of –8°C is colder than –12°C.
A temperature of –8°C is colder than –12°C.
A half degree above the freezing point is a negative number.
A half degree above the freezing point is a negative number.
When the temperature is 7° below freezing, the temperature is –7°C.
Answer:
When the temperature is 70° above freezing, the temperature is 70°C.
A temperature of –16°C is colder than –12°C.
When the temperature is 7° below freezing, the temperature is –7°C.
A temperature of 10°C is colder than –12°C.
When the temperature is 70° above freezing, the temperature is 70°C.
A temperature of –8°C is colder than –12°C.
When the temperature is 7° below freezing, the temperature is –7°C.
Michael earns $9 per hour. He works 28 hours each week. How much does he earn in 6 weeks?
Answer:
$1, 512
This is how:
1) Michael works 28 hours in one week. So how many hours does he work in 6 weeks?
So you need to calculate : 28 × 6 = 168
SO THIS IS THE TOTAL NUMBER OF HOURS FOR 6 WEEKS.
2) because Michael gets paid $9 PER HOUR :
You will need to multiply the amount of money he receives with the total number of hours he works.
168 × 9 = $ 1, 512
He earns $1,512 in 6 weeks
Please help due in 10 minutes
this was pretty simple it's kind of like the other one I in the past
Answer:
72 sec im srry if its wrong i cant see it good
Step-by-step explanation:
I bought a used,beat up car for $2000.i rebuilt it.
I sold the car for 75% more the what I bought it for. What was my profit
Please help me I need this answer by the end of the day.
Answer:
The answer is 3500
Step-by-step explanation:
All you have to do is get 175% of 2000. This is 3,500.
Rewrite the following expression using one or more properties of logarithms and evaluate? Plz help :)
Answer:
[tex]log( \frac{1}{ {10}^{ - 5} } ) = log( {10}^{5} ) = 5 log(10) = 5[/tex]
5 is the right answer.Can somebody help me
Answer:
AB ≈ 3.14 ft
Step-by-step explanation:
The arc AB is calculated as
AB = circumference of circle × fraction of circle
= πd × [tex]\frac{45}{360}[/tex] ( where d is the diameter )
= 8π × [tex]\frac{1}{8}[/tex]
= π
≈ 3.14 ft ( to 2 dec. places )
Solve for x.
15
20
Х
12
X=
Enter the number that belongs in the green box.
= [?]
Enter
Answer:
The value of x = 9
Step-by-step explanation:
Angle Bisector Theorem
An angle bisector of a triangle would cut the opposite side into two segments that are proportional to the other two sides of the triangle.
Thus,
[tex]\frac{x}{15}=\:\frac{12}{20}[/tex]
Cross Multiply the expression
[tex]\:20\times x=12\times 15[/tex]
Divide both sides by 20
[tex]\frac{20x }{20}=\frac{180}{20}[/tex]
[tex]x=9[/tex]
Therefore, the value of x = 9
In a box of chocolates, 1/5 of the chocolates contain nuts.
The rest of the chocolates do not contain nuts.
Write down the ratio of the number of chocolates that contain nuts to number of chocolates that do not contain nuts.
Give your answer in the form of 1:n
Answer:
1:4
Step-by-step explanation:
Ratios and Fractions
It's given 1/5 of the chocolates in a box contain nuts. The rest do not contain nuts. The portion that does not contain nuts is:
[tex]1 - \frac{1}{5}=\frac{4}{5}[/tex]
We need to calculate the ratio of the number of chocolates that contain nuts to the number of chocolates that do not contain nuts.
This can be done by dividing 1/5 by 4/5:
[tex]\displaystyle \frac{\frac{1}{5}}{\frac{4}{5}}[/tex]
Operating:
[tex]\displaystyle \frac{1}{5}\cdot\frac{5}{4}=\frac{1}{4}[/tex]
Expressing it as a ratio: 1:4
What is the slope of the line in the graph?
Slope = ______
Answer:
1/1 or 1
Step-by-step explanation:
Answer:
1 or 1/1
Step-by-step explanation:
Humans living in highly populated areas are more inclined to _______. a. violence b. socially isolate c. appetite loss d. all of the above
Answer:
Humans living in highly populated areas are more inclined to violence.
Answer:
A. Violence
Step-by-step explanation:
got it right, hope this helps!
Please help !!
[90 points if correct]
Answer:
2201.8348 ; 3 ; x / (1 + 0.01)
Step-by-step explanation:
1)
Final amount (A) = 2400 ; rate (r) = 6% = 0.06, time, t = 1.5 years
Sum = principal = p
Using the relation :
A = p(1 + rt)
2400 = p(1 + 0.06(1.5))
2400 = p(1 + 0.09)
2400 = p(1.09)
p = 2400 / 1.09
p = 2201.8348
2.)
12000 amount to 15600 at 10% simple interest
A = p(1 + rt)
15600 = 12000(1 + 0.1t)
15600 = 12000 + 1200t
15600 - 12000 = 1200t
3600 = 1200t
t = 3600 / 1200
t = 3 years
3.)
A = p(1 + rt)
x = p(1 + x/100 * 1/x)
x = p(1 + x /100x)
x = p(1 + 1 / 100)
x = p(1 + 0.01)
x = p(1.01)
x / 1.01 = p
x / (1 + 0.01)
Answer:
2201.8348 ; 3 ; x / (1 + 0.01)
Step-by-step explanation:
Hope this helps! (:
what is the improper fraction of 1 1/8
PLZ HELP this is the question
Answer:
I think is D
I'm not that sure but hope it helps
Solve for x in the equation x2 + 20x+100= 36.
Answer:
-16, -4
Step-by-step explanation:
x² +20x +100 -36 = 0
x² +20x +64 = 0
x² -Sx +P =0, where S= sum of roots, P=product of roots
so what 2 numbers have
S= -20 and P = 64 , ...that ul be -4, -16
or you can use factoring:
( x+16) ( x+4) = 0
x+16 = 0 , x= -16
x+4 =0, x = -4
or you can do quadratic equation, or graph ...
Answer: The Answer is:
Fraction form: x= -32/11
Decimal form: x= -2.90909....
Step-by-step explanation:
1. Add similar elements: 2x+20x=22x
22x+100=36
2. Subtract 100 from both sides:
22x+100-100=36-100
3. Simplify:
22x=-64
4. Divide both sides by 22:
22x÷22=-64÷22
5. Your Answer:
x= -32/11
What does bc equal ?
Answer:
180
Step-by-step explanation:
What is y equal to ?
Answer:
y= 42
Step-by-step explanation:
angles in a triangle add up to 180
48+90=138
180-138= 42
(if you need the value of x)
180-48=132
132/2=66
x=66
(value of z)
90+66=156
180-156=24
z=24
Evaluate −6 − (−2). (1 point)
A.−4
B.−8
C.4
D.12
Answer:
A. -4
Step-by-step explanation:
−6 − (−2) = -6 + 2
= -4
Hope this helped :)
b. Betelgeuse
d. Sirius
2. Which star has a surface temperature most similar to the surface temperature of Alpha Centauri?
a Polaris
c. Procyon B
b. Betelgeuse
d. Sirius
Help me plz
Answer:
I think A..............
The temperature of the radiating layers of a star at which its continuous spectrum is produced is known as surface temperature of star.
Polaris star has a surface temperature most similar to the surface temperature of Alpha Centauri.Betelgeuse and Proxima Centauri have the same surface temperature .Sun has highest luminosity.Blue Giants type of star has a high temperature and a high luminosity.Learn more:
https://brainly.com/question/17717852
HELP I WILL NARK BRAINLIEST
Answer:
number 2 (-8 -2)
Step-by-step explanation:
What is the local minimum value of the function? (Round answer to the
nearest hundredth)
g(x) = x4 – 5x² + 4
Answer here
Help pls I’m in trouble I need this
Answer:
We conclude that:
g(-3) = 3.5Step-by-step explanation:
Some background Concepts:
From the graph, it is clear that at x = -10, the graph intersects the x-axis.
So, the x-intercept of the graph is (-10, 0).
It means g(-10) = 0
From the graph, it is clear that at y = 5, the graph intersects the y-axis.
So, the y-intercept of the graph is (0, 5).
It means g(0) = 5
Determining g(-3):
From the graph, it is clear that at x = -3, the value of the function output = 3.5.
In other words,
at x = -3, g(-3) = 3.5
Therefore, we conclude that:
g(-3) = 3.5A florist can order roses in bunches of 12 and lilies in bunches of 8. Last month she ordered the same number of roses and lilies. If she ordered no more than 100 of each kind of flower, how many bunches of each could she have ordered? Find all the possible combinations.
Answer:
2 bunches of roses and 3 bunches of lilies.
4 bunches of roses and 6 bunches of lilies.
Step-by-step explanation:
Given that:
Roses come in a bunch of 12 flowers and
Lilies come in a bunch of 8 flowers
Number of roses ordered is equal to the number of lilies ordered.
Total number of flowers ordered are lesser than 100.
To find:
The possible number of combinations such that equal number of flowers are bought.
Solution:
Here, we need to find the Least Common Multiple.
[tex]12 = \underline{2 \times 2} \times 3[/tex]
[tex]8 = \underline{2 \times 2} \times 2[/tex]
LCM = [tex]2\times 2 \times 3 \times 2 = 24[/tex]
Therefore, we need to find the number of bunches such that number of flowers of each type bought are equal to LCM or multiples of LCM.
i.e.
24, 48, 72, 96 ....
Here, two types of flowers are there.
Therefore, 24 of each type, total 48 flowers i.e. 2 bunches of roses and 3 bunches of lilies.
48 of each type, total 96 flowers i.e. 4 bunches of roses and 6 bunches of lilies.
Total possible combinations:
2 bunches of roses and 3 bunches of lilies.
4 bunches of roses and 6 bunches of lilies.