Answer: The motion of a ball falling down through the atmosphere, or a model rocket being launched up into the atmosphere are both examples of Newton's first law. The motion of a kite when the wind changes can also be described by the first law.
Explanation:
Determine the acceleration that an unbalanced force of 28 N gives to a 6.8 kg mass.
Answer:
4.12 m/s^2
Explanation:
unbalanced force means the presence of resultant force (net force)
[tex]net \: force \: = mass \times accleration[/tex]
f = 28N
m = 6.8kg
a = ?
? = 28/6.8
= 4.1176...
approximately = 4.12 m/s^2
I will give you branilest!
A race car exerts 18,344 N while the car travels at an acceleration of 92.54 m/s2. What is the mass of the car? (Use the formula m=F/a)
Answer:
The answer is 198.23 kg
Explanation:
To find the mass of an object given it's mass and acceleration we use the formula
where
m is the mass
F is the force
a is the acceleration
From the question
a = 92.54 m/s²
F = 18,344 N
We have
We have the final answer as
198.23 kg
Answer:
198.22
Explanation:
using m=f/a you divide the force by the acceleration to get the mass (18344 / 92.54) = 198.22
Which of the following would be useful to show the growth rate of plants at varying temperatures?
bar graph
circle graph
line graph
frequency table
Answer:
line graph
Explanation:
Ik im late but i hope this helps lol
a tractor with 2000 kg of mass pulls a plow equal to 80.0 kg, exerting a 200 N force on it. The tractor and plow set moves horizontally to the right with an acceleration of 0.500 m / s2. The resistance force that the soil exerts on the plow has a modulus, in Newton, equal to?
Answer:
The resistance force that the soil exerts on the plough is 160 Newtons.
Explanation:
Fr = m.a
Fr = 80. 0,5
Fr = 40 N
Ft - F = Fr
200 - F = 40
F = 200 - 40
F = 160 Newtons
Occupants of cars hit from behind, even at low speed, often suffer serious neck injury from whiplash. During a low‑spee rear‑end collision, a person's head suddenly pivots about the base of the neck through a 50∘ angle, a motion that lasts 220 ms.The distance from the base of the neck to the center of the head is typically about 20 cm, and the head normally comprises about 6.0% of body weight.Model the motion of the head as having a uniform speed over the course of its pivot. Compute answers to two significant figures.1. What is the acceleration ????centacent of the head during the collision?2. What force ????F does the neck exert on the head of a 65 kg65 kg person in the collision? Neglect the force of gravity on the head, and report the answer in units of both newtons and pounds.3. Would headrests mounted to the backs of the car seats help protect against whiplash? Why or why not?a. Yes. A headrest applies an upward force on the head, along the direction of the neck, that cancels the downward force applied by the neck.b. Yes. A headrest ensures that both the head and the body experience the same forward force at roughly the same time.c. No. A headrest applies a mostly horizontal force to the head, so does not affect the mostly vertical force applied by the neck during whiplash.d. No. A headrest reduces the angle traversed by the head, not the speed of the head relative to the body, thus it does not affect the force that the neck applies to the head.
Answer:
a) a= 19 m/s2, b ) F = F = 38 N
c) the correct one is B
Explanation:
1) To solve this exercise, let's use the concept of torque, let's start by looking for the mass of the mass of the head, which is 65 of 65 kg
m= 0.06 65 = 3.9 kg
torque is defined
τ = F x R
the bold indicate vectors
τ = F R sin θ
the force is the weight of the head and the distance R = 0.20 m
τ = mg R sin θ
τ = 3.9 9.8 0.2 sin 50
τ = 5.86 N m
Newton's second law expression for rotational motion is
τ = I α
In general, the head is approximated by a sphere, so the moment of foolishness with respect to the base of the neck (turning point) using the parallel axis theorem is
I = I_sphere + m d²
Neck height data is not indicated, so we will assume that it is zero (d = 0)
I = 2/5 m R²
angular and linear acceleration are related
a = α R
α = a / R
let's replace
τ = 2/5 mR² (a / R)
a = 5/2 τ / mR
let's calculate
a = 5/2 5.86 / (3.9 0.2)
a = 18.8 m / s²
a= 19 m/s²
2) as the neck and the head are related, the forces are action and reaction, therefore the neck force is
F = m g
F = 3.9 9.8 = 38.2 N
F = 38 N
3) He asks us about the efficiency of the headrest, after reviewing the different alternatives, the correct one is B
Yes. A headrest ensures that both the head and the body experience the same forward force at approximately the same time.
PLEASE HELP
What do safety symbols look like? What do they mean? Provide at least three examples.
Answer: Safety symbols have a triangle shape, usually the colors are red, orange, and yellow. On the symbol of an element there can be a line going across diagonal They can have symbols that have a person slipping to let you know if someones mopping you may slip. Others may have one that has fire that lets you know fire may happen. And last but not least others can have deers on them to let you deers are on the street/road. Hope this helps.
Explanation:
what is the acceleration of a cat who starts from rest and moves 11.5 m in 2.8 s?
Answer:
The acceleration is 4
Explanation:
use the formula v= change in position/change in time for vecter quantity's which will be in word problems that say acceleration or velocity.
define density with a suitable formula
Answer:
ratio between m/v
or d= m/v
m= mass
v= volume
Can you help me please! Love you
Answer:
I think its B. wait...U love ME?????
In a car's suspension system, each wheel is connected to a vertical spring; these springs absorb shocks when the car travels on bumpy roads. In one car, each spring has a spring constant of 4.6 × 10⁴ N/m.
If this 1300 kg car is driven at 23 m/s through the bottom of a circular dip in the road that has a radius of 600 m, by how much do these springs compress compared to when the car is driven on a flat road?
Answer:
6.23 mm
Explanation:
The vertical acceleration at the bottom of the dip (in addition to that required to counter gravity) is ...
a = v²/r = (23 m/s)²/(600 m) = 529/600 m/s²
Then the force on the car (in addition to that required to counter gravity) is ...
F = Ma = (1300 kg)(529/600 m/s²) = 1146 1/6 N
The additional force supplied by each of the 4 springs is 1/4 of this, so the additional spring compression is ...
((1146 1/6 N)/4)/(4.6×10^4 N/m) ≈ 0.00623 m = 6.23 mm
The springs are compressed an additional 6.23 mm to provide the required vertical acceleration.
_____
We have to assume that the path followed by the car's center of mass has a radius of 600 m. We're also assuming that the rotational motion of the car about its center of mass does not require any differential force between front and back springs, as it will be at a constant rate for a constant speed through the dip. And, we assume that the mass of the car is evenly among the four springs (often not the case).
Answer:
Explanation:
Given this 1300 kg car is driven at 23 m/s through a circular dip in the road of radius of 600m,
its centrifugal acceleration = speed^2 / radius
= 23^2 / 600
= 0.8817 m/s^2
The centrifugal force in turn = mass * acceleration
= 1300 * 0.8817
= 1146.17 N
This force is absorbed by suspension springs of the four wheels.
Given spring constant of 4.6 x 10^4 N/m and 4 springs total,
the extra compression = Force / number of springs / spring constant
= 1146.17 / 4 / 4.6 x 10^4
= 0.006229 m
= 6.23 mm
Note that this is the extra compression on springs during drive-through of the dip compared to when the car is driven on a flat road. There is a constant compression on springs due to weight of the car which is the same whether the car is driving through a dip or on a flat road.
2 physical properties for manganese
three charges are located at 100m intervals along a horizontal line: a charge of -3.0C on the left, 2.0C in the middle, and 1.0C on the right. What is the resultant force on the 1.0C charge due to the other two
We know, force is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
Here, k in a constant.
[tex]Net \ Force = F_1+F_2\\\\Net \ Force = k(\dfrac{Qq_1}{r_1^2}+\dfrac{Qq_2}{r_2^2})\\\\Net \ Force = k( \dfrac{-3}{50}+\dfrac{2}{50})\\\\Net \ Force = 9\times 10^9\times \dfrac{-1}{50}\ N\\\\Net\ Force = -1.8\times 10^8\ N[/tex]
Hence, this is the required solution.
How far from the home did Karen and her mother travel during the first hour of the trip?
Answer:
none cuz she was too bus yelling at the cashier at the gas station
Which statement is true of the electric field at a distance from the source charge?
A it is independent of the source charge
B It is directly proportional to the source charge
C it is inversely proportional to the source charge
D it is directly proportional to the distance
Answer:
It is directly proportional to the source charge.
Explanation:
I found it pretty sure it's right hit me up on my insta
desiignerjoe173
A 58.72 kg person holding a steel ball stands motionless on a frozen lake.
The person then throws the ball, which propels the person at 1.05 m/s to the
right and the ball 3.75 m/s to the left. If the initial momentum of the system is
zero, what is the mass of the steel ball?
Answer: 16.44 kg
Explanation:
How can you predict the number of swings an 80 cm pendulum will make in 15 seconds?
shannon dropped his ICP textbook. how fast was it going after 3 seconds? how far did it fall? please guys help mee quickly pleaseeee
¡Hola!
For this problem, first, lets recabe information:
v = 0 m/s
t = 3 s
g = 9,82 m/s²
v' = ?
d = ?
First, for calculate the final velocity:
v' = v + g * t
v' = 0 m/s + 9,82 m/s² * 3 s
v' = 29,46 m/s [tex]\leftarrow \boxed{\text{Velocity} }[/tex]
Now, for calculate how far did it fall:
d = v * t + g * t^2 / 2
Like v = 0 m/s, we can simplificate equation:
d = g * t^2 / 2
d = 9,82 m/s² * (3 s)^2 / 2
d = 9,82 m/s² * 9 s² / 2
d = 88,38 m / 2
d = 44.19 m [tex]\leftarrow \boxed{\text{Distance} }[/tex]
¡Buena suerte!
List some of the most common injuries that can occur from sports. Please hurry!
A car is traveling with a velocity of 20 M/S and has a weight (mass) of 1000 kg. The car has kinetic energy calculate it
Answer:
200000 joules or 200 kilojoules
Explanation:
Kinetic energy = 1/2m(v^v)
Kinetic energy = 1/2*1000* 20^20
Kinetic energy = 500*400
Kinetic energy = 200000 joules or 200 kilojoules
Which of the following statements is true?
Type 2 diabetes is usually caused by genetics.
Regular exercise is one way to prevent Type 2 diabetes.
Congenital heart disease is caused by an unhealthy lifestyle.
The most common warning sign for cancer is chest pain
Answer:
yes that is true the answer is regular exercise
Explanation:
I did a question like this before and also type 1 diabetes is an injection
The true statement is that regular exercise is one way to prevent Type 2 diabetes. Thus, the correct option is B.
What is the significance of exercise?The significance of exercise is determined by the fact that it significantly enhances your brain health, regulates weight, reduces the threat of disease, strengthens bones and muscles, and improves your ability to do everyday activities.
According to the context of this question, type 2 diabetes is not usually caused by genetics as it is also caused by uncontrollable intake of sugar. Congenital heart disease is caused by the disruption of the normal development of the heart. The most common warning sign for cancer is swelling or lumps, fatigue, weight loss, etc.
Therefore, the true statement is that regular exercise is one way to prevent Type 2 diabetes. Thus, the correct option is B.
To learn more about Type 2 diabetes, refer to the link:
https://brainly.com/question/864309
#SPJ2
The airport has a new plane that can go from 0 miles per hour to 100 miles per hour in 10 seconds. What is being described about the new plane?
a. acceleration
b. speed
c. velocity
d. magnitude
Answer:
acceleration
Explanation: how fast something can get to a certain speed
how does 'g' at a point vary with the distance from the centre of earth?
Answer:
No gravity
Explanation:
because their is not gravity on earth and also close to the sun but not as close as mecury
If an object has zero acceleration, does it have to have zero velocity?
Answer:
Yes, the velocity would also be zero.
Explanation:
Acceleration is the change in velocity over time, therefore, there has to be a change in velocity for something to accelerate. which means without acceleration, the object has no velocity.
You are traveling through the forest and encounter an ancient well. You want to know how deep the well is. If you drop a coin and hear it hit the bottom of the well in 3 seconds, how deep is the well?
I will give you branilest!
A 1500 kg car accelerates at a rate of 3.0 m/s2. How much force is the car's engine producing?
Explain.
Hellow!
First, lets recabe information:
m (mass) = 1500 kg
a (aceleration) = 3 m/s²
F (Force) = ?
For calculate Force, if we have mass and aceleration, we can applicate the second law of Newton:
"Force is proportional to the product of the mass plus aceleration."
In a equation, this is like:
F = m * a
Let's replace according we information, and let's resolve:
F = 1500 kg * 3 m/s²
F = 4500 N
Result:
The force applicated is of 4500 Newtons.
Gud Luck!
Which could describe the properties of sedimentary rock?
PLASE HELP
DUE TODAY
Answer:
☝ Some of the properties of sedimentary rocks
A projectile is fired into the air at an angle of 50° above ground level and hits a target downrange. Neglecting air drag, it will also hit the target if fired at the same speed at an angle of
Answer:
18 m/s
Explanation:
Range of a projectile on level ground is:
R = v₀² sin(2θ) / g
14.3 m = v₀² sin(2×13°) / 9.8 m/s²
v₀ = 17.9 m/s
Rounded to two significant figures, the launch speed was 18 m/s.
If the bullet is launched at an angle of 50 degrees above ground level, the target will be struck. The angle remains the same. The launch angle obtained is 50 degrees.
Given:
The initial shot was fired at an angle of 50 degrees above ground.
The projectile's starting velocity (v) and magnitude of velocity will remain constant if it is shot at the same pace.
Let the angle of the projectile is x,
The horizontal component of velocity can be calculated as follows:
[tex]v(x) = v * cos(x)[/tex]
We can write:
since the horizontal part of velocity remains constant:
[tex]v(x1) = v(x2)[/tex]
[tex]cos(50) = cos(x)[/tex]
[tex]50 = x[/tex]
Therefore, if the projectile is launched at the same speed at a 50° angle above ground level, it will strike the target.
To know more about the projectile:
https://brainly.com/question/13388411
#SPJ4
The correct response is given when the angle is asked a question.
A train is traveling at a speed of 50km/hr. How.many hours will it take the train to travel 800 km?
Answer:
It would take 16 hours
Explanation:
800 divided by 50 = 16
Brainly pls
Answer: [tex]t[/tex] = 16
Explanation:
Hey there! I will give the following reason, if you have any questions feel free to ask me in the comments below.
Because a train is traveling at a speed of 50 km/hr and a train needs to travel 800 km, you would need to divide the distance by the speed to find the hours.
Formula: [tex]t[/tex] = [tex]\frac{distance}{speed}[/tex]
The distance would be 800, and the speed would be 50.
[tex]t = \frac{800}{50}[/tex]
Simplify.
[tex]t = 16[/tex]
~I hope this helps you! :)~
Velocity is the
i. distance travelled per unit time
il. time taken per unit distance
a.
9.
ii. time taken per unit displacement
iv. displacement per unit time
Okay, hun. Velocity is a vector quantity that measures displacement over a period of time. Velocity = Speed/Time (v=s/t). Hope this helped you. I took physics over 4 years ago. I'm more of a biology/chemistry person. (I major in those)
A shell is fired from a mortar over level terrain. The firing speed is 59 m/s and the mortar is aimed 70° above the horizontal. Find the range of the shell.
Answer:
228.23m
Explanation:
Vy=59sin70=55.44m/s
x=V0t+1/2at^2
0=55.44t-4.9t^2
t=11.31s
Vx=59cos70=20.18m/s
Range=20.18*11.31=228.23m