Which expression is equivalent to this polynomial?

6x2 + 10x − 56

A.
4(x − 4) − 2(3x2 + 3x − 20)
B.
(3x2 + 5x − 28) + (3x2 − 5x − 28)
C.
4(x − 4) + 2(3x2 + 3x − 20)
D.
(3x2 + 5x − 28) − (3x2 + 5x − 28)

Answer:

Volume of cylinder = 12,560 feet³

Step-by-step explanation:

Given:

Height of cylinder = 40 ft

Radius of cylinder = 10 ft

Find:

Can its volume be 10 ft ?

Computation:

Volume of cylinder = πr²h

Volume of cylinder = (22/7)(10)²(40)

Volume of cylinder = (3.14)(10)²(40)

Volume of cylinder = (3.14)(100)(40)

Volume of cylinder = 12,560 feet³

Volume of this cylinder never be 10 feet

Answer:

35 mph

Step-by-step explanation:

As you might have learned in your physics class, the average speed of a car in mph is 50. You should write this down on some paper.

After writing it down, we need to look at what the problem is asking us, so we don't get confused. " How fast was he going on the way to the bookstore?"

This means that we need to calculate his mph speed on the way to the bookstore by subtracting something.

50 mph=Average

Alternate Route= -15

After you have written THAT down in your notes, you need to ask yourself,

"What is 50-15?"

Calculating 50-15 will make the "15 mph slower" show up and calculating that with the average will get you your answer.

50-15 is 35

Answer:

Midpoint (-2,4)

distance nearest tenth = 8.9

The approximate distance = 9

Step-by-step explanation:

Formulas

PQ midpoint = (x2 + x1)/2, (y2 + y1)/2

distance d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

Givens

x2 = -4

x1 = 0

y2 = 1

y1 = 7

Solution

M(PQ) = (-4+0)/2, (1 + 7)/2

M(PQ) = -2, 4

The midpoint is -2,4

The distance = sqrt( (4 - 0)^2 + (1 + 7)^2 )

The distance = sqrt(16 + 64)

The distance = sqrt(80)

The distance = 4√5           exactly

The distance = 8.94    

The distance = 8.9            To the nearest tenth

Question 2

The distance is rounded to the nearest whole number which is 9.

Answer:

A

Step-by-step explanation:

I am to determine the future value of Thomas' deposit with annual compounding

The formula for calculating future value:

FV = P (1 + r)^n

FV = Future value  

P = Present value  

R = interest rate  

N = number of years  

840 x (1.075)^5 = 1205.93

I am to determine the future value of Sherill's deposit in 5 years using simple interest

The amount that would be in the account = amount deposited + interest earned on deposit

interest earned on deposit can be determined by determining the simple interest

Simple interest = amount deposited x time x interest rate

1250 x 0.069 x 5 = 431.25

Amount that would be in her account after 5 years = 1250 +  431.25 =  1681.25

Sheril's money is higher by - 1681.25 -  1205.93 = 475.32

Answer:

[tex]X=85.123m[/tex]

[tex]Y=184.88m[/tex]

Step-by-step explanation:

From the question we are told that:

Campfire Bearing from Colonel[tex]x=N 71 \textdegree E[/tex]

Distance b/w Colonel and Sarge [tex]Z=235feet[/tex]

Campfire Bearing from Sarge [tex]y=N 45 \textdegree E[/tex]  

Generally the angles x' and y' are solved

[tex]x'=90 \textdegree-71 \textdegree[/tex]

[tex]x'=19 \textdegree[/tex]

[tex]y'=90 \textdegree-45 \textdegree[/tex]

[tex]y'=45 \textdegree[/tex]

Generally the angle z' is  solved

Sum of angles of a triangle is 180

Therefore

[tex]z'=180 \textdegree-(19+45) \textdegree[/tex]

[tex]z'=116 \textdegree[/tex]

Generally the sine rule equation for for all distances is mathematically given by

[tex]\frac{Z}{sinz'}=\frac{X}{sinx'}=\frac{Y}{siny}[/tex]

Generally the the distance b/w the Colonel and the campfire X is mathematically given as

[tex]\frac{235}{sin116}=\frac{X}{sinx'}[/tex]

[tex]\frac{235}{sin116}=\frac{X}{sin19}[/tex]

[tex]X=85.123m[/tex]

Generally the the distance b/w Sarge and the campfire X is mathematically given as

[tex]\frac{235}{sin116}=\frac{Y}{siny}[/tex]

[tex]\frac{235}{sin116}=\frac{Y}{sin45}[/tex]

[tex]Y=184.88m[/tex]

Answer:

x = -20/11

Step-by-step explanation:

and how -(11 x)/4 - 5 = 0

1/4 (7 x - 12) = 1/2 (9 x + 4)

hope this helps

Answer:

X = 11/20

Step-by-step explanation:

7/4x-3=2+9/2x

We move all terms to the left:

7/4x-3-(2+9/2x)=0

Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R

Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R

We add all the numbers together, and all the variables

7/4x-(9/2x+2)-3=0

We get rid of parentheses

7/4x-9/2x-2-3=0

We calculate fractions

14x/8x^2+(-36x)/8x^2-2-3=0

We add all the numbers together, and all the variables

14x/8x^2+(-36x)/8x^2-5=0

We multiply all the terms by the denominator

14x+(-36x)-5*8x^2=0

Wy multiply elements

-40x^2+14x+(-36x)=0

We get rid of parentheses

-40x^2+14x-36x=0

We add all the numbers together, and all the variables

-40x^2-22x=0

a = -40; b = -22; c = 0;

Δ = b2-4ac

Δ = -222-4·(-40)·0

Δ = 484

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

Δ−−√=484−−−√=22

x1=−b−Δ√2a=−(−22)−222∗−40=0−80=0

x2=−b+Δ√2a=−(−22)+222∗−40=44−80=−11/20

Answer:

[tex]x^2+y^2=9[/tex]

Step-by-step explanation:

Equation of a circle (when centred at the origin):

[tex]x^2+y^2=r^2[/tex] where r is the radius of the circle

Plug in the point (0,3) to solve for the radius squared

[tex]0^2+3^2=r^2\\9=r^2[/tex]

Plug r² back into the original equation

[tex]x^2+y^2=9[/tex]

I hope this helps!

Answer:

1/3

Step-by-step explanation:

Answer: 9.

Step-by-step explanation:

6 large rooms which will add up to 18

9 small rooms which will also add up to 18 totaling the 36 guests.

The no. of small and large rooms in the hotel are 9 and 6 respectively.

A linear equation is an algebraic equation of degree one. In general, the variable or the variables(in the case of a linear equation in two variables) the variables are x and y.

Given, Emily is blocking off several rooms in a hotel for guests coming to her wedding.

Let us assume that small rooms be x and large rooms to be y.

Emily booked a total of 15 rooms which is x + y = 15...(i).

which can accommodate 36 guests altogether which is 2x + 3y = 36...(ii)

Now if we multiply eqn(i) by 2 it'll be 2x + 2y = 30...(iii)

Now subtracting eqn(iii) from eqn(ii) we get y = 6.

substituting the value of y in eqn(iii) we get x = 9.

So, the number of small rooms is 9 and no. of large rooms is 6.

learn more about linear equations here :

https://brainly.com/question/13738061

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Answer: I don’t understand What is the value of 3 to the power of 2 + 4(2 + 4) × 6 ÷ 8 + 4 but I can solve 2 + 4(2 + 4) × 6 ÷ 8 + 4 for you. Look at the picture

Step-by-step explanation: Hope this help :D

Answer:

$20.30  plus tax

Step-by-step explanation:

You multiply 28 x .30 and that is your discount.

Answer:

$20.30

Step-by-step explanation:

Answer:

B. 44°

Step-by-step explanation:

Central angle = 3x + 10°

Inscribed angle = 2x - 17°

Now

Central angle = 2 * inscribed angle

( Central angle is double of the inscribed angle standing on same arc)

3x + 10° = 2 ( 2x - 17°)

3x + 10° = 4x - 34°

4x - 3x = 34 ° + 10°

x = 44°

Hope it will help :)❤

Answer:

C. 70%

Step-by-step explanation:

35 / 50 = 70/100 = 70%

So she will be 70% accurate in the next shot.

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

C

Step-by-step explanation:

because d + Q = 19 is just counting the coins, not the monetary value

and .25q + .10d signs values per coin type.

Answer:

Solution given:

7x-29=2x+16[length from the circumference of circle is equal to same point]

7x-2x=16+29

5x=45

x=45/5=9

now.

XY=2×9+16=18+16=34 is your answer

The measure of tangent XY is 34.

If two tangents are drawn to a circle from an external point, then they are equal in length.

This property is often used in geometry problems to find the length of a tangent segment or to solve for an unknown variable.

We have,

The two tangents in a circle are equal.

So,

2x + 16 = 7x - 29

Solve for x.

2x + 16 = 7x - 29

7x - 2x = 16 + 29

5x = 45

x = 9

Now,

XY

= 2x + 16

= 2 x 9 + 16

= 18 + 16

= 34

Thus,

The measure of XY is 34.

Learn more about tangent on a circle here:

https://brainly.com/question/23265136

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Answer:

5 / 8

Step-by-step explanation:

Total possible outcomes = (1, 2, 3, 4, 5, 6, 7, 8)

Odd outcomes = (1, 3, 5, 7)

Outcomes > 7 = 8

Required outcomes = (1, 3, 5, 7, 8)

Number of required outcomes = 5

P(pointer stops on odd or number > 7) = required outcome / Total possible outcomes

P(pointer stops on odd or number > 7) :

= 5 / 8

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

[tex]PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ[/tex]

Likewise:

[tex]\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ[/tex]

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

[tex]m\angle PAC=m\angle PAB+m\angle BAC[/tex]

Likewise:

[tex]m\angle QAB=m\angle QAC+m\angle BAC[/tex]

Since ∠QAC ≅ ∠PAB:

[tex]m\angle PAC=m\angle QAC+m\angle BAC[/tex]

And by substitution:

[tex]m\angle PAC=m\angle QAB[/tex]

Thus:

[tex]\angle PAC\cong \angle QAB[/tex]

Then by SAS Congruence:

[tex]\Delta PAC\cong \Delta BAQ[/tex]

And by CPCTC:

[tex]PC\cong BQ[/tex]

Answer:

Step-by-step explanation:

To prove PC = BQ, we need to prove triangle APC and ABQ are congruent.

AP = AB as they are part of equilateral triangle APB

AC = AQ as they are part of equilateral triangle AQC

Angle PAC = Angle PAB + Angle BAC = 60 + Angle BAC

Angle BAQ = Angle QAC + Angle BAC = 60 + Angle BAC = Angle PAC

By SAS, triangle APC and ABQ are congruent and therefore

PC = BQ

Answer:

540

Step-by-step explanation:

area of trapezium is b×h

Answer:

540 Sq m

Step-by-step explanation:

Area of parallelogram EFGH

= base * height

= 30 * 18

= 540 Sq m

Answer:

Area:12.5663706            Circumference: 12.5663706

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer: 1

Step-by-step explanation:

Answer:

1. 11x + 11.  2. 3x - 4.

Step-by-step explanation:

sorry if im wrong

Question:

A particle moves along the x-axis so that its position at time t>0 is given by [tex]x(t)=\frac{t^2 -9}{3t^2 +8}[/tex]

Show that the velocity of the particle at time t is given by [tex]v(t) = \frac{70t}{(3t^2 + 8)^2}[/tex]

Answer:

[tex]v(t) = \frac{70t}{(3t^2 + 8)^2}[/tex]

Step-by-step explanation:

Given

[tex]x(t)=\frac{t^2 -9}{3t^2 +8}[/tex]

Required

Show that:

[tex]v(t) = \frac{70t}{(3t^2 +8)^2}[/tex]

To calculate v(t), we use:

[tex]v(t) = x'(t)[/tex]

So, we have:

[tex]x(t)=\frac{t^2 -9}{3t^2 +8}[/tex]

Apply quotient rule

[tex]x'(t) = \frac{vu' - uv'}{v^2}[/tex]

Where

[tex]u =t^2 - 9[/tex]

[tex]v=3t^2 + 8[/tex]

So:

[tex]u =t^2 - 9[/tex]

[tex]u' = 2t[/tex]

[tex]v=3t^2 + 8[/tex]

[tex]v' = 6t[/tex]

So, we have:

[tex]x'(t) = \frac{vu' - uv'}{v^2}[/tex]

[tex]x'(t) = \frac{(3t^2 + 8) * 2t - (t^2 - 9) * 6t}{(3t^2 + 8)^2}[/tex]

Expand the numerator

[tex]x'(t) = \frac{6t^3 + 16t - 6t^3 + 54t}{(3t^2 + 8)^2}[/tex]

Collect like terms

[tex]x'(t) = \frac{6t^3 - 6t^3+ 16t + 54t}{(3t^2 + 8)^2}[/tex]

[tex]x'(t) = \frac{70t}{(3t^2 + 8)^2}[/tex]

Recall that:

[tex]v(t) = x'(t)[/tex]

[tex]v(t) = \frac{70t}{(3t^2 + 8)^2}[/tex]

Proved

Answer:

-3 = D

Step-by-step explanation:

A really smart freind of mine says this is the answer.