Which field is required when importing vendors

Answer: 134. 89 $

Step-by-step explanation: Dina wishes to 1000$ deposit  into an investment account and then withdraw the total in the account in five years. She has the choice of two different accounts. Blue Star account: interest is earned at an annual interest rate of 6.13%  compounded weekly (52 weeks in a year). Red Star account: interest is earned at an annual interest rate of 5.95%  compounded continuously. Which investment account - Blue Star or Red Star - will result in the greatest total at the end of five years? What is the total after five years for this account? How much more is it than the total for the other account?

Answer:

3/4 ratio

Step-by-step explanation:

This is the answer

Answer:

Part 1: -10, -5, 0, 8 Part 2: -3/2, -15%, 0.80, 143%, 2 1/4

Step-by-step explanation:

Part 1: The lower the number, the lower the temperature
Part 2: Convert the fractions into decimals

2 1/4 = 2.25
-15% = -0.15
143% = 1.43
-3/2 = -1.5
0.80 = 0.80
The order from least to greatest is -3/2, -15%, 0.80, 143%, 2 1/4
Hope this helps :)

Step 1 :

Find the mean of the data :

(2+4+6+8) / 4 = 20/4 = 5

Step 2 :

Find the distance between each data and mean.

Distance between 2 and 5 is 3

Distance between 4 and 5 is 1

Distance between 6 and 5 is 1

Distance between 8 and 5 is 3

Step 3 :

Add all the distances :

3+1+1+3 = 8

Step 4 :

Divide it by the number of data :

8 / 4 = 2

2 is the average absolute deviation.

"The beautiful thing about learning is that no one can take it away from YOU"

B.B.King

well, hmmm to check for polar symmetry, hmmm say we simply replace the value for either "r" or "θ" or both in the original equation, if the equation rendered is the same as the original, there you have it, symmetry, so let's do that.

[tex]\underline{\textit{testing for symmetry to the }\frac{\pi }{2}~line\qquad \qquad r=-r~~,~~\theta =-\theta } \\\\\\ r=-7+2cos(3\theta )\implies (-r)=-7+2cos[3(-\theta )]\implies -r=-7+2cos(-3\theta ) \\\\\\ \stackrel{symmetry~identity}{-r=-7+2\stackrel{\downarrow }{cos(3\theta )}}\implies r=7-2cos(3\theta )\impliedby \textit{woopsie, no dice} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\underline{\textit{testing for symmetry to the polar axis}\qquad \qquad \theta =-\theta} \\\\\\ r=-7+2cos(3\theta )\implies r=-7+2cos[3(-\theta )]\implies r=-7+2cos(-3\theta ) \\\\\\ \stackrel{symmetry~identity}{r=-7+2\stackrel{\downarrow }{cos(3\theta )}}\impliedby \textit{low and behold\qquad \Large \checkmark}[/tex]

now, we could run a test for "the pole" or namely the origin by simply changin r = -r, however we already know where the symmetry is, so no need.

Check the picture below.

a function is odd if f(-x) = - f(x)

f(x) = x³ + 2x

and

f(-x) = (-x)³ + 2 * (-x) = - x³ - 2x = - (x³+2x) = - f(x)

Answer:

Step-by-step explanation:

tlk here

Answer:

5x+1=7

Step-by-step explanation:

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's check I the given pairs of triangles are congruent or not ~

[tex]\qquad \sf  \dashrightarrow \:ABC \cong FED[/tex]

These triangles are congruent by SSS congruency, as it's three sides are equal.

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \:LMN \not \cong PQO[/tex]

・ ．━━━━━━━†━━━━━━━━━．・

These triangles are not congruent because they don't fulfill any congruency criteria.

[tex]\qquad \sf  \dashrightarrow \: XVW \cong YZA [/tex]

These triangles are congruent by AAS congruency criteria, since two angles and one of the side is common.

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \: GHI \not \cong IJG [/tex]

These triangles are not congruent because they don't fulfill any criteria.

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \: PQR\cong QPO[/tex]

These triangles are congruent by SSS congruency, as it's two sides are equal and one side is common.

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \: JIK \cong HIG [/tex]

These triangles are congruent by SAS congruency, since two sides and Angle between them are equal.

・ ．━━━━━━━†━━━━━━━━━．・

These given triangles are congruent by SSS congruency, because they have two equal sides and one common side in there.

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \: BCD \cong FED [/tex]

These triangles are congruent by ASA congruency, because they have one pair equal angles, one pair of vertical opposite angles (they are equal) and a side between them equal.

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \: LKM \cong LNM [/tex]

These given triangles are congruent by SSS congruency, because they have two equal sides and one common side in there.

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

Check the picture below, so the lines look more or less like so, so the shape that we'll be getting will be the shape of a bowl with a hole in it, thus we'll use the washer method.

the way I use to get the larger Radius is simply using the "area under the curve" method, namely f(x) - g(x), where g(x) in this case is the axis of rotation.

so to get "R" and "r" we can get it by

[tex]\stackrel{y = 1}{(1)}~~ - ~~\stackrel{\stackrel{\textit{axis of rotation}}{y = -3}}{(-3)}\implies 1+3\implies \stackrel{R}{4} \\\\\\ \stackrel{y = \ln(x)}{\ln(x)}~~ - ~~\stackrel{\stackrel{\textit{axis of rotation}}{y = -3}}{(-3)}\implies \stackrel{r}{ln(x)+3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{R^2}{(4)^2}~~ - ~~\stackrel{r^2}{[\ln(x)+3]^2}\implies 16~~ - ~~[\ln^2(x)+6\ln(x)+9] \\\\\\ \ln^2(x)+6\ln(x)+7~\hfill \boxed{\displaystyle\int~[\ln^2(x)+6\ln(x)+7]dx}[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♫[/tex]

Let's see ~

Remember : value of 1 meter = 100 centimeters

[tex]\qquad \sf  \dashrightarrow \:1 \: m = 100 \: cm[/tex]

[tex]\qquad \sf  \dashrightarrow \:1 \: cm = \frac{1}{100} \: m[/tex]

[tex]\qquad \sf  \dashrightarrow \:1 \: cm = 0.01 \: m[/tex]

・ ．━━━━━━━†━━━━━━━━━．・

As we know

So

turn down to fraction

[tex]\\ \rm\rightarrowtail \dfrac{1}{100}[/tex]

Turn to decimal

[tex]\\ \rm\rightarrowtail 0.01m[/tex]

Answer:

B

Step-by-step explanation:

A) 1 + 1 + 1 + 1 = 4

4 / 4 = 1

B) 4 + 4 = 8

8 / 2 = 4

Answer: B

Step-by-step explanation:

Using proportions, it is found that the error was treating the 100% value as a percent(100) instead of a decimal 1, hence the correct value is of 96.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, we have that 100% = 1 of the number is w, while 6 is equals to 6.25% = 0.0625. Hence the rule of three is given by:

1 - w

0.0625 - 6

Applying cross multiplication:

0.0625w = 6.

w = 6/0.0625

w = 96.

The error was treating the 100% value as a percent(100) instead of a decimal 1, hence the correct value is of 96.

More can be learned about proportions at https://brainly.com/question/24372153

Answer:

See below ↓

Step-by-step explanation:

Let's find the x and y values.

Step 1 : Equate the y expressions.

Step 2 : Convert fractions in the equation to whole numbers.

Step 3 : Bring x terms to one side and constant terms to the other.

Step 4 : Solve for y by plugging the value of x into one of the given equations.

Step-by-step explanation:

y = -x/2 - 1

the y-intercept is right there : -1.

it is the y-value when x = 0

the point of y-intercept is therefore (0, -1).

the x-intercept is the other way around. it is the x- value when y = 0.

0 = -x/2 - 1

1 = -x/2

-2 = x

the point of x-intercept is therefore (-2, 0)

Answer:

an = 9(⅔)^(n-1)

Step-by-step explanation:

The formula for explicit is: An = a1(r)^(n-1)

Answer:

  (b)  0.3 microns or larger

Step-by-step explanation:

A particle of size 0.3 microns is judged to be the most penetrating particle size. So, a rating for the filtering of those particles will be a worst-case rating. For particles of any other size, the filter will perform better than for 0.3 micron particles. HEPA filters are rated based on their performance with particles ...

  0.3 microns or larger

Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 1

Rewrite and add each vector:

[tex]p=\langle40cos70^\circ,40sin70^\circ\rangle\\q=\langle50cos270^\circ,50sin270^\circ\rangle\\r=\langle60cos235^\circ,60sin235^\circ\rangle\\p+q+r=\langle40cos70^\circ+50cos270^\circ+60cos235^\circ,40sin70^\circ+50sin270^\circ+60sin235^\circ\rangle\\p+q+r\approx\langle-20.73,-61.56\rangle[/tex]

Find the magnitude of the resulting vector:

[tex]||p+q+r||=\sqrt{x^2+y^2}\\||p+q+r||=\sqrt{(-20.73)^2+(-61.56)^2}\\||p+q+r||\approx64.96[/tex]

Therefore, the best answer is D) 64.959

Problem 2

Think of the vectors like this:

[tex]t=\langle7cos240^\circ,7sin240^\circ\rangle\\u=\langle10cos30^\circ,10sin30^\circ\rangle\\v=\langle15cos310^\circ,15sin310^\circ\rangle[/tex]

By adding the vectors, we have:

[tex]t+u+v=\langle7cos240^\circ+10cos30^\circ+15cos310^\circ,7sin240^\circ+10sin30^\circ+15sin310^\circ\rangle\\t+u+v\approx\langle14.8,-12.55\rangle[/tex]

Since the direction of a vector is [tex]\theta=tan^{-1}(\frac{y}{x})[/tex], we have:

[tex]\theta=tan^{-1}(\frac{y}{x})\\\theta=tan^{-1}(\frac{-12.55}{14.8})\\\theta\approx-40.3^\circ[/tex]

Don't forget to take into account that the resulting vector is in Quadrant IV since the horizontal component is positive and the vertical component is negative, so we will add 360° to our angle to get the result:

[tex]\theta=360^\circ+(-40.3)^\circ\\\theta=319.7^\circ[/tex]

Therefore, the best answer is D) 320°

Problem 3

Again, rewrite the vectors and add them:

[tex]u=\langle30cos70^\circ,30sin70^\circ\rangle\\v=\langle40cos220^\circ,40sin220^\circ\rangle\\u+v=\langle30cos70^\circ+40cos220^\circ,30sin70^\circ+40sin220^\circ\rangle\\u+v\approx\langle-20.38,2.48\rangle[/tex]

Using the direction formula:

[tex]\theta=tan^{-1}(\frac{y}{x})\\\theta=tan^{-1}(\frac{2.48}{-20.38})\\\theta\approx-6.94^\circ[/tex]

As the vector is located in Quadrant II, we need to add 180° to our angle:

[tex]\theta=180^\circ+(-6.94)^\circ\\\theta=173.06^\circ[/tex]

Therefore, the best answer is D) 173°

Problem 4

Using scalar multiplication:

[tex]-3u=-3\langle35,-12\rangle=\langle-105,36\rangle[/tex]

Find the magnitude of the resulting vector:

[tex]||-3u||=\sqrt{x^2+y^2}\\||-3u||=\sqrt{(-105)^2+(36)^2}\\||-3u||=111[/tex]

Find the direction of the resulting vector:

[tex]\theta=tan^{-1}(\frac{y}{x})\\\theta=tan^{-1}(\frac{36}{-105})\\\theta\approx-18.92^\circ[/tex]

As the vector is located in Quadrant II, we need to add 180° to our angle:

[tex]\theta=180^\circ+(-18.92)^\circ\\\theta=161.08^\circ[/tex]

Therefore, the best answer is C) 111; 161°

Problem 5

Using scalar multiplication:

[tex]5v=5\langle25cos40^\circ,25sin40^\circ\rangle=\langle125cos40^\circ,125sin40^\circ\rangle[/tex]

Since the direction of the angle doesn't change in scalar multiplication, it only affects the magnitude, so the magnitude of the resulting vector would be [tex]||5v||=125[/tex], making the correct answer C) 125; 200°

We will see that for Stuart the maximum height is 30ft, and for Francisco it is 46.0625 ft

In the case of Stuart it is simple, as we have a graph, we just need to see the largest y-value on the graph. We can see that it is y = 30, then for Stuart, the largest distance from the ground is 30ft.

In the case of Francisco, we need to find the maximum of:

g(x)= -16x^2 + 50x +7

Notice that this is a quadratic of negative leading coefficient, so the maximum is at the vertex.

x = -50/(2*-16) = 25/16

Evaluating the function in 25/16 we get:

g(25/16) = -16*(25/16)^2 + 50*(25/16) +7 = 46.0625 ft

If you want to learn more about quadratic functions, you can read:

https://brainly.com/question/1214333

Answer:

The graph is stretched horizontally by a factor of 4 and shifted up 1 unit

Step-by-step explanation:

The effect of transforming the function is (b) The graph is stretched horizontally by a factor of 4 and shifted up 1 unit

The functions are given as:

f(x) = 3sin(x)+1

g(x) = 3sin(x/4)+2

Start by stretching the function f(x) horizontally by a scale factor of 4.

So, we have:

f'(x) = 3sin(x/4) + 1

Next, shift the function f'(x) upward by 1 unit.

So, we have:

f'(x) = 3sin(x/4) + 1 + 1

Evaluate the sum

f'(x) = 3sin(x/4) + 2

Rewrite as:

g(x) = 3sin(x/4) + 2

Hence, the effect of transforming the function is (b) The graph is stretched horizontally by a factor of 4 and shifted up 1 unit

Read more about function transformation at:

https://brainly.com/question/17586310

Answer:

The Inch To Feet Calculator is available online here for free at BYJU'S. One inch is equal to 0.083333 feet. One foot is equal to 12 inches.

Step-by-step explanation:

Answer:

-9 3/4a+10 2/5

Step-by-step explanation:

-12 * 5/6a = -10a

-12 * -7/8 =  10 1/2

1/14 * 3 1/2a = 1/4 a

1/14 * -1 2/5 = -1/10

Put it together: -10a + 10 1/2 + 1/4a - 1/10

-10a+1/4a = -9 3/4a

10 1/2-1/10= 10 2/5

-9 3/4a + 10 2/5

Answer:

▲ Base and height. This is the basic volume equation of a triangular prism: Volume = 0.5 * Base * Height * Length. ...

◣ Right triangle. Probably the most popular type of prism! ...

▲ 3 sides. Volume = 0.25 * √( (a+b+c) * (-a+b+c) * (a-b+c) * (a+b-c) ) * Length.

Step-by-step explanation:

Answer:

Pi times radius to the power of two times the height  

Step-by-step explanation

i gave you the formula now solve

Answer:

y=2x-1

Step-by-step explanation:

Step-by-step explanation:

(−3/4b^2)(−6a^2b^5)

= 9 a²b³

function :  y = (-x) - 6

Find x-intercept :

Find y-intercept :

mark these two points on both the axis and draw a straight linear graph.

passes coordinates : (0, -6), (-6, 0)

[tex]\\ \rm\rightarrowtail y=-x-6[/tex]

Take some point s

Graph it

[tex]\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=10\\ h=18 \end{cases}\implies V=\cfrac{\pi (10)^2(18)}{3}\implies \stackrel{using~\pi =3.14}{V=1884}[/tex]

Answer:

5/5 out of the 7/5 make ONE whole while 2/5 is left over.

The ONE whole is added to nine to make 10 and the remaining 2/5 is also added to the 10 hence 9 7/5 = 10 2/5

Step-by-step explanation:

5/5 out of the 7/5 make ONE whole while 2/5 is left over.

The ONE whole is added to nine to make 10 and the remaining 2/5 is also added to the 10 hence 9 7/5 = 10 2/5

Answer:

Step-by-step explanation:

Answer:

given ,

two points A ( -1 , 2 ) and B ( 0 , -14 )

______________________________________

[tex]\fbox\pink{Solution -}[/tex]

let the midpoint be P ( x , y )

using midpoint formula ,

[tex]P(x,y) = ( \frac{ x_{1} + x_{2} }{2} , \frac{ y_{1} + y_{2} }{2} ) \\ \\ P(x,y) = ( \frac{ - 1 + 0}{2} , \frac{2 + ( - 14)}{2} ) \\ \\ (x,y) = ( \frac{ - 1}{2} , \frac{ - 12}{2} ) \\ \\ x = \frac{ - 1}{2} \\ \\ y = \frac{ - 12}{2} => - 6[/tex]

thus ,

the coordinates of the midpoint are

[tex]\red{P( \frac{ - 1}{2} , - 6)} \\ \\ or \\ \\ \red{P( -0.5 , - 6 )} [/tex]

hope helpful :D

Answer:

Step-by-step explanation:

A(-1,2)  x₁ = -1  &  y₁ = 2

B(0 ,-14)   x₂ = 0  & y₂ = -14

[tex]\text{ \sf Midpoint = $\left(\dfrac{x_{1}+x_{2}}{2} ,\dfrac{y_{1}+y_{2}}{2}\right)$ }[/tex]

              [tex]= \left (\dfrac{-1+0}{2} ,\dfrac{2+[-14]}{2} \right) \\\\\\=\left(\dfrac{-1}{2}, \dfrac{-12}{2}\right)\\\\\\=\left( -0.5 , -6 \right)[/tex]