Which formula demonstrates a double replacement reaction?
1. A + B --> AB
2. AB + CD --> AC + BD
3. AB --> A + B
4. A + BC --> AC + B

Answer: The mass

Explanation: ability to rust, flammability, and ability to combust are chemical properties.

Answer:

commensalism

Explanation:

It's not parasitism as the shark is not harmed in the relationship

Answer:

B. One element changes into another.

Explanation:

We can see from the equation that uranium is changed to thorium and helium. Transmutation is the process by which one element is changed to another through radioactive decay, nuclear bombardment, or other similar processes.

Answer:b

Explanation:

Answer:

You would find starch in a plant leaf.

Explanation:

This is due to the fact that when there is excess energy, it will be stored in plant tissue as starch.

Answer: B. nebula

Explanation:

Answer:

B. nebula

Explanation:

Birth takes place inside hydrogen-based dust clouds called nebulae.

-TheUnknownScientist

Answer:

I would choose pear fruits are a good source of carbohydrates hopefully its right sorry if its not

Answer: Fruit

Fruits have a lot of carbohydrates in them :) Hope this helped!

Answer:

500mL.

Explanation:

i think A but if I'm wrong sorry

then if increasing then becoming spread out so letter A

The Mesopotamians discovered copper (Cu) in 9000 BC.

Answer:

experiments

Explanation:

I am not sure but heres my take

Answer:

It was only after the invention of electron microscope that the idea developed

Answer:

ions

Explanation:

Answer:

Acids: react with metals, taste sour

Both: can cause burns, conduct electricity

Basis: react with nonmetals, taste bitter

Explanation:

This is the right answer

Answer:

Acids: react with metals, taste sour

Both: can cause burns, conduct electricity

Basis: react with nonmetals, taste bitter

it's right, I did it.

Answer:

dfdfaxc b

Explanation:

Answer:

5 g/cm^3

Explanation:√3V=1.91293cm

Answer:

An element's mass number (A) is the sum of the number of protons and the number of neutrons. The small contribution of mass from electrons is disregarded in calculating the mass number.

Answer:

Burning of the candle is both physical and chemical change. Burning of the candle melts the wax and hence physical state of wax has changed from solid to liquid.  

Again the wax combines with the atmospheric oxygen and changes to carbon dioxide, heat and light.  

Thus both the changes are accompanied by the burning of the candle.

Explanation:

hope this helps!

~mina

Answer: Both are compounds

Explanation:

[tex]\text{N}_{2}[/tex] is an element, not a compound.

Answer:

d

Explanation:

Answer:

Yes, the combustion of hydrogen is spontaneous from the given conditions.

Explanation:

Let look at the reaction:

[tex]2H_2_{(g)} + O_2_{(g)} \to 2H_2O_{(g)}[/tex]

[tex]K_p = \dfrac{[P(H_2O)]^2}{[P(H_2)^2\times P(O_2)]} ----- (1)[/tex]

The total pressure of the tank = 1 atm

[tex]\mathtt{Pressure \ of \ the \ gas = moles \ fraction \of \ gas \times total \ pressure}[/tex]

Thus, pressure of [tex]O_2[/tex] gas = [tex]\dfrac{9.38 \times 10^{-3} }{(9.38 \times 10^{-3} + 2.46 \times 10^{-8} + 1.79 \times 10^{-4}} \times 1 atm[/tex]

[tex]P(O_2) = 0.9813 atm[/tex]

Pressure of [tex]H_2O[/tex] gas =[tex]\dfrac{1.78 \times 10^{-4}}{9.38 \times 10^{-3} + 2.46 \times 1)^{-8} + 1.78 \times 10^{-4}} \times 1 \ atm[/tex]

Pressure of H_2 gas = [tex]2.573 \times 10^{-6} \ atm[/tex]

From equation (1);

[tex]K_p = \dfrac{(0.0187)^2}{(2.573 \times 10^{-6})^2 \times (0.913) } \\ \\ K_p = 5.383 \times 10^7[/tex]

So, applying the equation:

[tex]\Delta G^0 = -RT In K_p \\ \\ = -8.314 \times (300)K \times IN(5.383 \times 10^7) \\ \\ = -45880.109 J \\ \\ = -45.800 \ kJ\\ \\[/tex]

Thus;

[tex]\Delta G^0 < 0[/tex]

Thus, Yes the combustion of hydrogen is spontaneous from the above conditions. From thermodynamics, we realize that assuming ∆G is negative, the reaction is spontaneous. Again we understand that ∆G=∆H-T∆S. However, for combustion, water will definitely be formed.

Finally, we can conclude that;

∆H is negative;

∆S is positive; &

∆G is also negative.

Thus, from above, we conclude combustion of hydrogen is spontaneous.

The combustion of hydrogen gas with the oxygen gas for the formation of the water vapor is a spontaneous reaction.

To know about the condition that the given reaction is spontaneous or not we will use the below equation and must get the negative value:

ΔG° = -RTlnKp, where

R = universal gas constant

T = temperature

Kp = partial pressure constant

Firstly we have to calculate the value of Kp.

Given chemical reaction is:

2H₂(g) + O₂(g) → 2H₂O(g)

Value of Kp for the given reaction is:

Kp = [p(H₂O)]² / [p(H₂)]².[p(O₂)]

Partial pressure will be calculated as:

p = mole fraction × total pressure

Given that total pressure of gas = 1atm

p(H₂O) = (1.79×10⁻⁴ / 1.79×10⁻⁴+2.46×10⁻⁸+9.38×10⁻³) × 1 = 0.0187

p(H₂) = (2.46×10⁻⁸ / 1.79×10⁻⁴+2.46×10⁻⁸+9.38×10⁻³) × 1 = 2.573 × 10⁻⁶

p(O₂) = (9.38×10⁻³ / 1.79×10⁻⁴+2.46×10⁻⁸+9.38×10⁻³) × 1 = 0.913

Putting all these values on the equation of Kp, we get

Kp = (0.0187)² / (2.573 × 10⁻⁶)²(0.913) = 5.383 × 10⁷

Now putting values in the first equation we get,

ΔG° = -(8.314)(300)ln(5.383 × 10⁷)

ΔG° = -45,800 kJ

Hence, given reaction is spontaneous.

To know more about spontaneous reaction, visit the below link:

https://brainly.com/question/24376583

Answer:

7 mol.dm^3

Explanation:

formula for calculating concentration: C = n/v

Start by changing 5000ml solution to dm^3 because volume is in dm^3

1 ml = 1cm^3

then from a cm^3 to dm^3 you divide by 1000

5000ml = 5000cm^3

5000÷1000= 5dm^3

c = n/v

= 35/5

= 7mol.dm^3

Answer:

Thank youuuuu bestie, you really pulling through

Answer:

yessss

Explanation:

Answer:

1) 5.0 mL, 4.0 mL, 3.0 mL and 2.0 mL respectively.

2) 3.0 mL

Explanation:

Hello there!

1) In this case, by considering that the equation we use for dilutions contain the initial and final concentrations and volumes:

[tex]C_1V_1=C_2V_2[/tex]

For the first four solutions, we compute the volume of the stock one (V1) as shown below:

[tex]V_1=\frac{C_2V_2}{C_1}[/tex]

Thus, we obtain:

[tex]V_1^1=\frac{3.5x10^{-5}M*10.00mL}{7.0x10^{-5}M} =5.0mL\\\\V_1^2=\frac{2.8x10^{-5}M*10.00mL}{7.0x10^{-5}M} =4.0mL\\\\V_1^3=\frac{2.1x10^{-5}M*10.00mL}{7.0x10^{-5}M} =3.0mL\\\\V_1^4=\frac{1.4x10^{-5}M*10.00mL}{7.0x10^{-5}M} =2.0mL[/tex]

2) In this case, for a final concentration of 2.1x10-5 M and a volume of 10.00 mL, the volume of the stock solution would be:

[tex]V_1=\frac{2.1x10^{-5}M*10.00mL}{7.0x10^{-5}M} =3.0mL[/tex]

Best regards!

Answer:

Miscible

Explanation:

Mixed completely

Answer:

a

Explanation:

i am wrong haha

Answer:

are u out of time ?

Explanation: