Which inequality is represented by the given graph?10-10A. y ≤-32-5B. y ≤ 3x +5C. y ≥-3x - 5OD. y ≤ 3x-5
Answers
Given:
A graph is given
Required:
To calculate which option is correct
Explanation:
Let the function is y=ax+b
because y=ax+b passes through
[tex]\begin{gathered} (\frac{5}{3},0)\text{ and \lparen0,-5\rparen \lparen given\rparen} \\ \\ so\text{ b=-5 let it be equation I} \\ \\ \frac{5}{3}a-5=0\text{ let it be equation II} \\ \\ so\text{ a=3, b=-5} \\ \\ therefore\text{ y=3x-5} \\ \\ because\text{ the shaded area is below the line so} \\ \\ y\leq3x-5\text{ is represnted by given graph} \end{gathered}[/tex]Required answer:
Option D
Related Questions
in. » What is the area of this triangle? in2 h = 12 in. b = 3 in. Пhtm
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Find the GCF of each pair of monomials 54hg and 18g
Answers
GCF is the greatest common factor of two terms
54 and 18 have common factors, let us find the factors of each one and find the common factors
18 = 1 x 18, 2 x 9, 3, x 6, then
Its factors are 1, 2, 3, 6, 9, 18
54 = 1 x 54, 2 x 27, 3 x 18, 6 x 9
Its factors are 1, 2, 3, 6, 9, 18, 27, 54
The common factors of both are
1, 2, 3, 6, 9, 18
The greatest one is 18
Both terms have variable g, then
GCF of them is 18g
The GCF of 54hg and 18g is 18g
Is 15.1 greater than 1480.8?
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ANSWER
1480.8 is greater than 15.1
EXPLANATION
We want to find which number is greater between 15.1 and 1480.8
We see that the highest place value in the number 15.1 is Tens, i.e.:
T U Tnth
1 5 . 1
While in 1480.8, the highest place value is Thousands, i.e.:
T H T U Tnth
1 4 8 0 . 8
Since Thousands is greater than Tens, we see that 1480.8 is greater than 15.1
find the value of x such that 365 based seven + 43 based x = 217 based 10.
Answers
We need to find the base x in the following equation:
[tex]365_7+43_x=217_{10}[/tex]First, lets convert 365 from base 7 to base 10. This is given by
[tex]365_7=3\times7^2+6\times7^1+5\times7^0[/tex]where the upperindex denotes the position of eah number. This gives
[tex]\begin{gathered} 365_7=3\times49+6\times7+5\times1 \\ 365_7=147+42+5 \\ 365_7=194_{10} \end{gathered}[/tex]that is, 365 based 7 is equal to 194 bases 10.
Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:
[tex]43_x=4\times x^1+3\times x^0[/tex]where again, the superindex 0 and 1 denote the position 0 and 1 in the number 43. This gives
[tex]43_x=(4x+3)_{10}[/tex]Now, we have all number in base 10. Then, our first equation can be written in base 10 as
[tex]194_{10}+(4x+3)_{10}=217_{10}[/tex]For simplicity, we can omit the 10 and get
[tex]194+4x+3=217[/tex]so, we can solve this equation for x. By combining similar terms. we have
[tex]197+4x=217[/tex]and by moving 197 to the right hand side, we obtain
[tex]\begin{gathered} 4x=217-197 \\ 4x=20 \end{gathered}[/tex]Finally, we get
[tex]\begin{gathered} x=\frac{20}{4} \\ x=5 \end{gathered}[/tex]Therefore, the solution is x=5
Determine if I II m based on the information given on the diagram. If yes, state the converse that roves the lines are arallel.
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Looking at the diagram, there is a transversal cutting across lines m ans n. The angles formed are congruent because they are 90 degrees. We can see that the angles are in similar positions and in the same side of the transversal. This means that they are corresponding angles.
Recall the corresponding angles postulate which states that if corresponding angles are congruent when two lines are crossed by a transversal, then the two lines crossed by the transversal are parallel
Thus,
line l is parallel to line m
The correponding angles converse prove that they are parallel
1. What inequality represents the sentence?(1 point)C0UThe product of a number and 12 is no more than 15.12n< 15O12n > 1512n > 1512n<15hjb
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First, the product of a number and 12 can be wu
[tex] {25x}^{2} - 4x + 16[/tex]is NOT a perfect square trinomial. Which criteria are not met?
Answers
Answer:
b is not the product of 2 times the product of the roots because:
Explanation:
The initial expression is:
25x² - 4x + 16
It is a trinomial because it has three terms: 25x², - 4x, and 16.
Additionally, the 1st and 3rd term are perfect squares because:
[tex]\begin{gathered} \sqrt[]{25x^2}=5x^{} \\ \sqrt[]{16}=4 \end{gathered}[/tex]Finally, the only correct statement is that b is not the product of 2 times the product of the roots because:
[tex]\begin{gathered} -4x\ne2(5x)(4) \\ -4x\ne40x \end{gathered}[/tex]Therefore, the answer is: b is not the product of 2 times the product of the roots because:
Find the quotient.n^12 / n^4 =There is a picture if you need it.
Answers
ANSWER:
[tex]n^8[/tex]STEP-BY-STEP EXPLANATION:
We have the following expression
[tex]n^{12}\div n^4[/tex]In this case, the exponents are subtracted since it is a division, therefore we would have:
[tex]\begin{gathered} n^{12}\div n^4=n^{12-4} \\ n^{12}\div n^4=n^8 \end{gathered}[/tex]Quadratic: y = - x2 - 4x - 1 Step 1: Identify the coefficients a = ? b = ? C = ? a = 1. b = 4, and c = 1 a = -1. b = -4, and c = 1 a = 1. b = -4. and C = -1 a = - 1. b = -4. and C = -1
Answers
The general quadratic equation is:
y = ax² + bx + c
where a, b, and c are the coefficients
In the case of
y = -x² - 4x - 1
the coefficients are:
a = -1
b = -4
c = -1
Geometry question 2: give the length of VU.Circumcenter and Incenter.
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The picture tells us that sides OV and VU have the same length. With this information we can construct an equation for x:
[tex]7x+2=3x+10[/tex]Let's substract 3x and 2 from both sides of this equation:
[tex]\begin{gathered} 7x+2-3x-2=3x+10-3x-2 \\ 4x=8 \end{gathered}[/tex]Then we can divide both sides by 4:
[tex]\begin{gathered} \frac{4x}{4}=\frac{8}{4} \\ x=2 \end{gathered}[/tex]Then the length of VU is given by:
[tex]3x+10=3*2+10=16[/tex]AnswerThen the answer is 16.
Simplify 8* (9 + 2 ) - 6 / 2
Answers
solution
[tex]\begin{gathered} 8\times(9+2)-6/2 \\ 8\times(11)-3 \\ 88-3 \\ 85 \end{gathered}[/tex]answer: 85
9. Six months later, there were no tricycles in the shop. There were onlybicycles and tandem bikes. There are a total of 68 seats and 120 wheels inthe shop. Let: B be the bicycles and N be the tandem bikes. How do youtranslate this into mathematical equations? *
Answers
Each bicycle has 2 wheels and 1 seat, and each tandem bike has 2 wheels and 2 seats. So, we can write this mathmatically by writing one equation for the amount of seats and one for the amount of wheels.
If each bicycle has 2 wheels and each tandem bike also have 2 wheels, then the total number of wheels, 120, will be:
[tex]\begin{gathered} 2B+2N=120 \\ 2(B+N)=120 \\ B+N=60 \end{gathered}[/tex]Smilarlly, if each bicycle has 1 seat and each tandem bike has 2 seats, then the total number of seats, 68, will be:
[tex]\begin{gathered} 1B+2N=68 \\ B+2N=68 \end{gathered}[/tex]So, in the end, we have a system of two equations:
[tex]\begin{gathered} B+N=60 \\ B+2N=68 \end{gathered}[/tex]point O is the center of the regular nonagon shown below. find the angle of rotation about O that maps F to IA....° rotation about O maps F to I
Answers
the angle between each side or vertex of an nonagon is 40 °
we have the sum of 3 angles
FOG=40
FOH=40
HOI=40
so the rotaton about O maps F to I is
[tex]40+40+40=120[/tex]120°
A trap for insects is in the shape of a triangular prism. The area of the base is 4.5 in and the height of the prism is 3 in. What is the volume of this trap? The volume of the trap is in?
Answers
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
triangular prism (trap)
base area = 4.5 in²
height = 3in
volume = ?
Step 02:
volume = base area * h
= 4.5 in² * 3 in
= 13.5 in³
The answer is:
The volume of the trap is 13.5 in³
Suppose that the functions s and I are defined for all real numbers x as follows.s(x) = x³t(x) = 5x²Write the expressions for (t•s) (x) and (t-s) (x) and evaluate (t+s) (-1).(t*•s)(x) = 0
Answers
Given that,
The functions s and t are defined for all real numbers x as follows,
[tex]\begin{gathered} s\left(x\right)=x^3 \\ t\left(x\right)=5x^2 \end{gathered}[/tex]To find the expressions for (t•s) (x) and (t-s) (x)
To evaluate (t+s) (-1).
Explanation:
we have that,
[tex]\left(t•s\right)x=t(x)•s(x)[/tex]Substitute the values we get,
[tex]\left(t•s\right)x=(5x^2)(x^3)[/tex][tex]\left(t•s\right)x=5x^5[/tex]To find (t-s) (x)
we get,
[tex]\left(t-s\right)x=t(x)-s(x)[/tex][tex]\left(t-s\right)x=5x^2-x^3[/tex]To evaluate (t+s) (-1)
[tex]\left(t+s\right)(x)=t(x)+s(x)[/tex]we get,
[tex]\left(t+s\right)(x)=5x^2+x^3[/tex]Put x=-1, we get
[tex]\left(t+s\right)(-1)=5(-1)^2+(-1)^3[/tex][tex](t+s)(-1)=5-1[/tex][tex](t+s)(-1)=4[/tex]Answers are:
[tex]\left(t•s\right)x=5x^5[/tex][tex]\left(t-s\right)x=5x^2-x^3[/tex][tex](t+s)(-1)=4[/tex]Can u please help me solve? I am reviewing for a final, ty
Answers
Solution
Part A : The students verify the two identity very well and it was properly
solved
[tex]\begin{gathered} sin^2x+cos^2x=1 \\ sin^2x=1-cos^2x \\ cos^2x=1-sin^2x \end{gathered}[/tex]reason why the substitution work for both students
Also the inverse of identity like
[tex]\begin{gathered} \frac{1}{sinx}=cosecx=cscx \\ \frac{1}{tanx}=cotx \\ where \\ tanx=\frac{sinx}{cosx} \\ cotx=\frac{cosx}{sinx} \end{gathered}[/tex]Therefore the two identity that where used by students A's is
[tex]\begin{gathered} cos^2x=1-sin^2x \\ \frac{1}{sinx}=cscx \end{gathered}[/tex]The first one appear in Step 3, while the second one appear in Step 5
A suit being sold for $268 has a 33% discount.Find the original cost of the suit.
Answers
Let x represent the original cost of the suit.
To calculate the discount, they calculated the 33% of the original price and then subtracted the result from the original price.
To calculate the 33% of any given value you have to do as follows:
33/100=0.33
0.33x → represents the 33% of the original price.
The price with discount was obtained by subtracting the 33% discount from the original price, symbolically:
x-0.33x=268
Clear the value of x:
[tex]\begin{gathered} 0.67x=268 \\ x=\frac{268}{0.67} \\ x=400 \end{gathered}[/tex]The original price of the suit is $400
A. Adrian says that 4(-9) =36. Why is Adrian incorrect? B. What is one change you can make to Adrian's equation to make it correct?
Answers
Answer:
A. Adrian is incorrect because the product of a positive number and a negative number should be negative.
B. Change 4 to -4 so as to have two negative numbers being multiplied together, this will give us a positive result as seen below;
[tex]-4(-9)=36[/tex]Explanation:
A) When a positive number is multiplied by a negative and vice versa, the product will be negative.
We're told that Adrian multiplied a positive number by a negative number and had a positive result 4(-9) = 36. This is incorrect because the product of a positive number and a negative number should be negative.
B) The product of two negative numbers will be positive. So we can change 4 to -4 so as to have two negative numbers being multiplied together, this will give us a positive result as seen below;
[tex]-4(-9)=36[/tex]An architect's sketch of plans for the front of a garage in the shape of pentagon is shown below. What is the approximate perimeter of thefront of the garage?-8-6 -4 -2A. about 36 ftB. about 21 ftC. about 10 ftD. about 77 ft
Answers
Using the given pentagon, let's find the perimeter.
From the graph, we can deduce the vertices of the pentagon below:
(0, 9.5), (5.5, 7), (5.5, 0), (-5.5, 0), (-5.5, 7)
Let's find the perimeter.
To find the perimeter, let's first find the length of each side using the distance formula:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2+y_1)^2}[/tex]Now, let's label the figure:
Thus, we have the following:
• Length of AB:
Where:
(x1, y1) ==> (0, 9.5)
(x2, y2) ==> (5.5, 7)
We have:
[tex]\begin{gathered} AB=\sqrt{(5.5-0)^2+(7-9.5)^2} \\ \\ AB=\sqrt{(5.5)^2+(-2.5)^2} \\ \\ AB=\sqrt{30.25+6.25}=\sqrt{36.50} \\ \\ AB=6.04\text{ ft} \end{gathered}[/tex]The length of AB = 6 ft
Also the length of AE will be 6 ft.
• Length of BC:
Where:
(x1, y1) ==> (5.5, 7)
(x2, y2) ==> (5.5, 0)
Thus, we have:
[tex]\begin{gathered} BC=\sqrt{(5.5-5.5)^2+(0-7)^2} \\ \\ BC=\sqrt{0+(-7)^2} \\ \\ BC=7\text{ ft} \end{gathered}[/tex]The length of BC = 7 ft
The length of DE will also be 7 ft.
• Length of CD:
Where:
(x1, y1) ==> (5.5, 0)
(x2, y2) ==> (-5.5, 0)
Thus, we have:
[tex]\begin{gathered} CD=\sqrt{(5.5-(-5.5))^2+(0-0)^2} \\ \\ CD=\sqrt{(5.5+5.5)^2} \\ \\ CD=\sqrt{11^2} \\ \\ CD=11\text{ ft} \end{gathered}[/tex]Therefore, we have the following side lengths.
• AB = 6 ft
,• BC = 7 ft
,• CD = 11 ft
,• DE = 7 ft
,• AE = 6 ft
To find the perimeter, let's sum up the side lengths:
Perimeter = AB + BC + CD + DE + AE
Perimeter = 6 + 7 + 11 + 7 + 6
Perimeter = 37 ft
Therefore, the perimeter of the front garage is about 36 ft.
• ANSWER:
A. about 36 ft.
Help me please and thank you.Answer choices: “Yes, they would be back to their original salary”.“No, they would not be back to their original salary”.
Answers
Given that:
- The person's salary was reduced by 3%.
- The next year the person is given a 3% raise.
- The salary that was reduced was $40,000.
A percentage can be converted to a decimal number by dividing it by 100. Then:
[tex]3\text{\%}=\frac{3}{100}=0.03[/tex]If $40,000 was decreased by 3%, the new salary would be:
[tex]\text{ \$}40,000-(0.03)(\text{\$}40,000)=\text{\$}38,800[/tex]You know that the next year that new salary is increased by 3%. Then, you can determine that the new salary for this year is:
[tex]\text{ \$}38,800+(0.03)(\text{\$}38,800)=\text{\$}39,964[/tex]Notice that:
[tex]\text{\$}40,000\ne\text{\$}39,964[/tex]Hence, the answers are:
- If one's salary is $40,000 and decreased by 3% the salary would be:
[tex]\text{\$}38,800[/tex]- If they were then given a 3% increase the following year they would have:
[tex]\text{\$}39,964[/tex]- Second option.
Given the inequalities y < 2x + 2 and y> x-7 graphed on the same coordinategrid, which of the following coordinates gives a true statement?A. (-2,2)B. (4,0)C. (0,4)D. None of the above
Answers
we have a system of inequalities
y<2x+2
y>x-7
The solution of the given system is the shaded area below the dashed line y=2x+2 and above the dashed line y=x-7.
If an ordered pair is a solution of the system, then the ordered pair must lie on the shaded region of the solution
using a graphing tool
we have the points
(-2,2)
(4,0)
(0,4)
A solution is the point (4,0)
The answer is the option CLast year, Lucy had $30,000 to invest. She invested some of it in an account that paid 8% simple interest per year, and she invested the rest in an account that paid 6% simple interest per year. After one year, she received a total of $1880 in interest. How much did she invest in each account?
Answers
Solution:
Given:
[tex]Pr\text{ incipal= \$30000}[/tex]Let x be the principal for the 8% simple interest per year
Let y be the principal for the 6% simple interest per year
Hence,
[tex]x+y=30000\ldots\ldots\ldots\ldots\ldots\ldots(1)[/tex]The formula for calculating simple interest is;
[tex]\begin{gathered} I=\frac{P\times T\times R}{100} \\ T=1\text{year} \\ I=\frac{PR}{100} \end{gathered}[/tex][tex]\begin{gathered} I_x=\frac{x\times8}{100} \\ I_x=0.08x \\ \\ I_y=\frac{y\times6}{100} \\ I_y=0.06y \\ \\ I=I_x+I_y=1880 \\ 0.08x+0.06y=1880\ldots\ldots\ldots\ldots\ldots(2) \end{gathered}[/tex]Solving the two equations simultaneously;
[tex]\begin{gathered} x+y=30000\ldots\ldots\ldots\ldots\ldots\ldots(1)\times0.08 \\ 0.08x+0.08y=2400\ldots\ldots\ldots\ldots\ldots\ldots.\text{.}(1) \\ 0.08x+0.06y=1880\ldots\ldots\ldots\ldots\ldots\ldots..(2) \\ \text{Subtracting equation (2) from (1);} \\ \text{equaton (1)-equation (2);} \\ 0.02y=520 \\ \text{Dividing both sides by 0.02 to get y,} \\ y=\frac{520}{0.02} \\ y=26000 \\ \\ \text{Substituting y into equation (1) to get x,} \\ x+y=30000 \\ x+26000=30000 \\ x=30000-26000 \\ x=4000 \end{gathered}[/tex]Therefore,
Lucy invested $4,000 principal for 8% simple interest.
Lucy invested $26,000 principal for 6% simple interest.
witch number is the additive inverse of -101\4
Answers
Answer:
Explanation:
The additive inverse of a number x is the number which when added sums to zero
Write an equation of the line passing through (-2,7) and having slope -5 . Give the answer in slope-intercept form.The equation of the line in slope-intercept form is enter your response here.
Answers
The line passes through (-2, 7) and m = - 5.
Slope-intercept form: y = mx + b; then:
7 = (-5)(-2) + b
7 = 10 + b
b = -3
y = -5x - 3
Suppose the figure shows f(t), the interest rate on an investment t years after the initial deposit. The straight line is tangent to the graph of y=f(t) when t=8. How fast was the internet rate riding at that time?
Answers
Concept:
The slope of the tangent to the curve at any point gives the instantaneous rate of change of the function.
From the given graph, it is observed that the line is tangent to the curve at point (8,9).
So the slope of this line will give the rate of change of the function i.e. interest rate at that instant.
The slope (m) of the line joining (0,0) and (8,9) is given by,
[tex]\begin{gathered} m=\frac{9-0}{8-0} \\ m=\frac{9}{8} \\ m=1.125 \end{gathered}[/tex]Since the slope comes out to be positive, it means that the function is increasing with respect to time.
Thus, the interest rate is increasing at the rate 1.125, at the given time instant.
I don't know how to begin or try this problem
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length =24, width =15
1) The best way to tackle this question is by sketching this out:
2) We can think of it as a rectangle whose area is 360yd². Since the farmer has 54 yds we can write out this:
We can set two equations: one evolving the sum of three sides and the other one the area:
[tex]\begin{gathered} 2b+h=54 \\ bh=360 \\ ----- \\ 2b=54-h\Rightarrow b=27-\frac{h}{2} \\ bh=360 \\ (27-\frac{h}{2})h=360 \\ \\ 27h-\frac{h^2}{2}=360 \\ -\frac{h^2}{2}+27h-360=0 \\ \frac{h^2}{2}-27h+360=0 \\ h=\frac{27\pm\sqrt[]{(27)^2-4(\frac{1}{2})(360)}}{2(\frac{1}{2})} \\ h=24 \\ --- \\ 2b+24=54 \\ 2b=54-24 \\ 2b=30 \\ b=15 \end{gathered}[/tex]someone help me with this question..this is a practice question
Answers
Answer:
68
Explanation:
We start with the mode:
[tex]\text{Mode}=l+\frac{(f_1-f_0)\times h}{(2f_1-f_0-f_2)}[/tex]Where the terms are defined as follows:
[tex]\begin{gathered} l=\text{lower limit of the modal class} \\ f_1=\text{frequency of the modal class} \\ f_0=\text{frequency of the class before the modal class} \\ f_2=\text{frequency of the class after the modal class} \\ h=\text{size of the class interval} \end{gathered}[/tex]From the table, the modal class is 65-69.
Therefore:
[tex]\begin{gathered} l=\text{6}5 \\ f_1=\text{1}9 \\ f_0=\text{1}0 \\ f_2=\text{1}3 \\ h=\text{5} \end{gathered}[/tex]We substitute into the formula:
[tex]\begin{gathered} \text{Mode}=65+\frac{(19-10)\times5}{(2\times19-10-13)} \\ =65+\frac{9\times5}{15} \\ =65+\frac{45}{15} \\ =65+3 \\ =68 \end{gathered}[/tex]The mode of the given data is 68.
Which of the following has its area and perimeter numerically equal?
An equilateral triangle of side 1 cm
A square of side 1 cm
A regular pentagon of side 1 cm.
Answers
The option that has its area and perimeter numerically equal is none of the above.
What is the area?When an equilateral triangle of side 1 cm, the perimeter will be: = 1 + 1 + 1 = 3cm
The area will be ✓3/4 × 1² = 0.433cm²
For a square of side 1 cm, the perimeter is 4cm and the area is 1cm².
A regular pentagon of side 1 cm. The area is 1.72 cm and the perimeter is 5cm.
Therefore, the options given aren't the same.
Learn more about area on:
brainly.com/question/25292087
#SPJ1
Which vegetable grown inthe south corner east of the wood street community garden?
Answers
Given:
The picture shows the vegetables grown in the wood street community garden.
To find:
The vegetable which is on the south-east corner of street wood community gar
using the pythagorean theoerem, find the length of the missing side if necessary round your answer to the nearest tenth. side A=30 ft side C=40ft Answer: side C=
Answers
answer:
side C = 50 ft