The destructive interference formula for diffraction grating problems is [tex]d sin \theta = (n+\frac{1}{2})\lambda[/tex].
What is the definition of destructive interference?Destructive interference happens when the maxima of two waves are 180° out of phase a positive displacement of one wave is canceled exactly by a negative displacement of the other wave.
The formula for brighter patches resulting from constructive interference and darker patches resulting from destructive interference in a diffraction grating is:
[tex]\rm d sin \theta = n \lambda[/tex]
The grating spacing is denoted by d, the angle of light is denoted by a the fringe order is denoted by n, and the wavelength is denoted by [tex]\rm \lambda[/tex].
The destructive interference formula is now based on the fact that destructive interference occurs between the fringes.
Hence the destructive interference formula for diffraction grating problems is [tex]d sin \theta = (n+\frac{1}{2})\lambda[/tex].
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Answer:
A. dsin =
Explanation:
What is the new period if the pendulum is taken to a planet that has 4 times the mass and 4 times the radius of earth
The new period of the pendulum when it is taken to the new planet is double of its period on Earth.
Period of a pendulumThe period of a pendulum is given by the following formula;
[tex]T = 2\pi \sqrt{\frac{l}{g} }[/tex]
where;
g is acceleration due to gravity of the pendulumL is length of the pendulumAcceleration due to gravity of the new planetThe acceleration due to gravity of the new planet is calculated as follows;
[tex]g_E = \frac{GM_E}{R_E^2} = 9.81 \ m/s^2 \\\\g(new \ planet) = \frac{G(4M_E)}{(4R_E)^2} = \frac{4GM_E}{16R_E^2} = \frac{GM_E}{4R_E^2} = \frac{9.81}{4} = 2.45 \ m/s^2[/tex]
New period of the pendulum[tex]T = 2\pi \sqrt{\frac{l}{g} } \\\\T =\frac{2\pi \sqrt{l} }{\sqrt{g} } \\\\T_1\sqrt{g_1} = T_2\sqrt{g_2} \\\\T_E\sqrt{g_E} = T\sqrt{g} \\\\T = \frac{T_E\sqrt{g_E}}{\sqrt{g} } \\\\T = \frac{T_E \times \sqrt{9.81} }{\sqrt{2.45} } \\\\T = 2T_E[/tex]
Thus, the new period of the pendulum when it is taken to the new planet is double of its period on Earth.
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A 80kg astronaut is training in human centrifuge to prepare for a launch. The astronaut uses the centrifuge to practice having a 3.16g force (3.16 times his own weight) on his back. The radius is 12m.
Attached is a picture of the question.
The answers on the model of the human centrifuge ready for the launch to each question of the statement are listed below:
a) A force of 2479.210 newtons is acting on the astronaut's back.
b) A net centripetal force of 2479.210 newtons is acting on the astronaut.
c) The centripetal acceleration of the astronaut is 30.990 meters per square second.
d) The astronaut has a linear speed of approximately 19.284 meters per second.
e) The angular speed of the astronaut is 1.607 radians per second (15.346 revolutions per minute).
How to apply Newton's laws to analyze a process in a human centrifuge trainingThe human centrifuge experiments a centripetal acceleration when it reaches a peak angular speed. In this question we must apply Newton's laws of motion and concepts of centripete and centrifugal forces to answer the questions. Now we proceed to answer the questions:
How much force is acting on the astronaut's back?By the third Newton's law the astronaut experiments a rection force (F), in newtons, which has the same magnitude to centrifugal force but opposed to that force. The magnitude of the force acting on the back of the astronaut is equal to:
[tex]F = 3.16\cdot (80\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 2479.210\,N[/tex]
A force of 2479.210 newtons is acting on the astronaut's back. [tex]\blacksquare[/tex]
What is the net centripetal force on the astronaut?By the second and third Newton's laws we know that the net centripetal force on the astronaut is equal to the magnitude of the force found in the previous question. Thus, a net centripetal force of 2479.210 newtons is acting on the astronaut. [tex]\blacksquare[/tex]
What is the astronaut's centripetal acceleration?The centripetal acceleration of the astronaut (a), in meters per square second, is found by dividing the result of the previous question by the mass of the astronaut (m), in kilograms:
[tex]a = \frac{F}{m}[/tex] (1)
If we know that F = 2479.210 newtons and m = 80 kilograms, then the centripetal acceleration of the astronaut is:
[tex]a = \frac{2479.210\,N}{80\,kg}[/tex]
[tex]a = 30.990\,\frac{m}{s^{2}}[/tex]
The centripetal acceleration of the astronaut is 30.990 meters per square second. [tex]\blacksquare[/tex]
What is the astronaut's linear speed?By definition of uniform circular motion, we have the following formula for the linear velocity of the astronaut (v):
[tex]v = \sqrt{a\cdot r}[/tex] (1)
Where r is the radius of the human centrifuge, in meters.
If we know that [tex]a = 30.990\,\frac{m}{s^{2}}[/tex] and [tex]r = 12\,m[/tex], then linear velocity of the astronaut is:
[tex]v = \sqrt{\left(30.990\,\frac{m}{s^{2}} \right)\cdot (12\,m)}[/tex]
v ≈ 19.284 m/s
The astronaut has a linear speed of approximately 19.284 meters per second. [tex]\blacksquare[/tex]
What is the astronaut's angular speed?The angular speed of the astronaut (ω), in radians per second, is found by the following kinematic relationship:
[tex]\omega = \frac{v}{R}[/tex] (1)
If we know that v ≈ 19.284 m/s and R = 12 m, then the angular speed is:
[tex]\omega = \frac{19.284\,\frac{m}{s} }{12\,m}[/tex]
ω = 1.607 rad/s (15.346 rev/m)
The angular speed of the astronaut is 1.607 radians per second (15.346 revolutions per minute). [tex]\blacksquare[/tex]
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(please answer) It is better to jump on a smooth, flat surface than on thick carpeting.
Question 5 options:
True
False
I believe the answer to your question would be True
When an object standing on the floor is tipped, the height of its center of gravity (cg) may or may not change. Classify each case as stable, unstable, or neutral
The three types of equilibrium in an object are; stable, unstable, or neutral equilibrium.
What is equilibrium?The term equilibrium refers to a situation in which all the forces acting on an object are balanced such that the object does not move. The question is incomplete as the images are missing.
There are three types of equilibrium:
Stable equilibrium: In a stable equilibrium, the object returns to rest in its original place when displlaced.Unstable equilibrium: In this type of equilibrium, the body moves further away from its original position when displaced.Neutral equilibrium: In this type of equilibrium, the object comes to rest in a new position when displaced.Learn more equilibrium of forces: https://brainly.com/question/12262457
When an object standing on the floor is tipped, the height of its center of gravity (cg) for each case as stable, unstable, or neutral may increase, decreased and remain same respectively.
What is the equilibrium state of a standing object?Equilibrium is the location of the body, in which the body be static or in motion and does not change it with respect to time.
The equilibrium of an object can be classified in the 3 following types.
Stable Equilibrium- Stable equilibrium is the condition, in which the object gains its position back after displacing it.Unstable Equilibrium-Unstable equilibrium is the condition, in which the object does not gain its position back after displacing it.Neutral Equilibrium-Natural equilibrium is the condition, in which the object displace from its position and there is no force acting on it.When an object standing on the floor is tipped, the height of its center of gravity (cg) may or may not change.
The stability of object demands in the center of gravity. Lower the value of CG, results in more stable object. For each case,
Stable-Center of gravity is increased when tipped.Unstable-Center of gravity is decreased when tipped.Natural-Center of gravity is remained at same level when tipped.Thus, when an object standing on the floor is tipped, the height of its center of gravity (cg) for each case as stable, unstable, or neutral may increase, decreased and remain same respectively.
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When using a different calorimeter, and mixing 50 ml of hot water at 65 degrees c with 60 ml of water in the calorimete
The specific heat capacity of the calorimeter used in mixing the water is determined as 21.87 J/g⁰C.
Conseervation of energyThe heat capacity of the calirometer is determined by applying the principle of conservation of energy.
Heat lost by the hot water = Heat gained by the calirometer
[tex]Q _w = Q_c\\\\M_w C_w\Delta \theta _w = M_c C_c\Delta \theta _c[/tex]
where;
M is massmass = density x volume = ρV
Density of water = 1 g/ml
Mass of hot water = 1 x (50) = 50 g
Mass of water in calorimeter = 1 x (60) = 60 g
Equilibrium temperature[tex]\Delta T_c = 5.5\\\\T - 25 = 5.5\\\\T = 30.5 \ ^0C[/tex]
Specific heat capacity of the calirometer[tex]50 \times 4.184 \times (65 - 30.5) = 60 \times C_c \times (30.5 - 25)\\\\7217.4 = 330C_c\\\\C_c = \frac{7217.4}{330} \\\\C_c = 21.87 \ J/g^0C[/tex]
Thus, the specific heat capacity of the calorimeter used in mixing the water is determined as 21.87 J/g⁰C.
The complete question is below
When using a different calorimeter, and mixing 50 ml of hot water at
65 degrees C with 60 ml of water in the calorimeter at 25 degrees C, the temperature of the calorimeter increased by 5.5 degrees C.
a. Calculate the heat capacity of this calorimeter?
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How much energy does a pair of hair straighteners transfer every second
Answer:
It depends...
Explanation:
If you know how much watts the pair of hair straighteners use, you can use that as the energy every second. A normal flat iron for hair would be 300 watts, so we could say that it uses 300 jolts or watts of energy per second.
Which of the following was correctly predicted by Einstein's theory of gravity?
(A) the origin of mass
(B) law of refraction
(C) the measure of G
(D) light deflected around large objects because of their gravity
Answer:
(D) light deflected around large objects because of their gravity
I hope this helps you
:)
How does a white dwarf compare to our sun as it exists now?.
Answer:
answer down below
Explanation:
it has similar mass but the white dwarf is much denser
Hello people ~
Sound cannot travel through
(a) air
(b) water
(c) air
(d) vacuum
Answer:
Vaccum
Explanation:
Sound travels through the particles of different matter In vaccum there is no air so no matter and so no particles .So sound can't travel through vaccum.You can test it .
Take a speaker and keep it inside a bottle ,close it .You won't hear any soundUse F = 1/T as your basis:
7. What is the period of 60.0Hz electrical power?
The answer is 16.7 ms but please show your work.
[tex]\\ \rm\rightarrowtail \nu=\dfrac{1}{T}[/tex]
[tex]\\ \rm\rightarrowtail T=\dfrac{1}{\nu}[/tex]
[tex]\\ \rm\rightarrowtail T=\dfrac{1}{60}[/tex]
[tex]\\ \rm\rightarrowtail T=1.67\times 10^{-4}s[/tex]
[tex]\\ \rm\rightarrowtail T=16.7\times 10^{-3}s[/tex]
[tex]\\ \rm\rightarrowtail T=16.7ms[/tex]
Collette is twisting a screwdriver. The scredriver has a handle with a radius of 18 mm. If she is exerting a force of 14 N, how much torque is she causing? PLEASE HELPPP!!!!
A. 25 Nm
B. 0.25 Nm
C. 1.3 Nm
D 0.75 Nm
Torque:-
[tex]\\ \rm\Rrightarrow \tau =14(0.018)[/tex]
[tex]\\ \rm\Rrightarrow \tau=0.25Nm[/tex]
option B
Please help asap its for anatomy
explain the basic mechanical process through which micturition occurs, including an explanation of why someone might not be able to "hold it in" any longer if they wait too long to urinate and why it might be harder for older people to hold their urine for a long time
The smooth muscle in the wall of the bladder when stretched triggers the micturition reflex (urination).
What is a Bladder?This is defined as a lined layers of muscle tissue that stretch to hold urine in organisms.
In older people the elasticity of the bladder is reduced which is why it makes it harder for them to hold urine for a long time.
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The game starts with the serve on the left side of the court.
O
True
O
False
Answer:
Explanation:
well it depends what game are you talking about
Suppose that a simple pendulum consists of a small 60.0 g bob at the end of a cord of negligible mass. If the angle 0 between the cord and the vertical is given by g - (0.0800 rad) cos[(4.43 rad/s) t 0], what are (u) the pendulum's length and (b) its maximum kinetic energy
Based on the mass of the bob and the angle between the cord and the vertical, the pendulum length is 0.50m.
The maximum kinetic energy can be found to be 9.42 x 10⁻⁴J.
What is the pendulum length?This can be found as:
= g-force / w²
Solving gives:
= 9.8 / 4.43²
= 0.4998 m
= 0.50 m
What is the maximum kinetic energy?This can be found as:
= 0.5 × m × w² × A²
Maximum kinetic energy is:
= 0.5 × 60 × 10⁻³ × (4.43 × 0.4998 x 0.08 rad)²
= 9.42 x 10⁻⁴J
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Why doesn't mercury have an atmosphere?
Answer:
The main reasons are two. Mercury's atmosphere is hard to hold onto because it is small and does not have much gravity. As Mercury is close to the Sun, any atmosphere is blasted away by material being blown off the Sun.
Hope this helps friend!
Can you hear the vibrations a tuning fork puts off when hit?
no
Explanation:
no not an vibration signal
What does the text mean when it says “naming an elements is like creating history
Answer: When you name an element, it's usually because the element is newly discovered. So by naming an element you are creating something that will last throughout history.
Explanation:
A man pushes a 8 kg object. A distance of 5. 0 m upward along a frictionless slope that makes an angle of 30° with the horizontal. His force is parallel to the slope. If the speed of the object decreases at a rate of 1. 5 m/s, then the work done by the man is:
Answer:
is 200 J
Explanation:
hope this is the right answer
easy one here pls help thanks so much
A round tube weighs 30 lbs. If the tube is stood on end it pushes down on the floor with a pressure of
2 lbs/in?. How many square inches is the end of the tube?
Answer:
15in2
Explanation:
The diagram shows part of a radio antenna.The plastic tube protects the radio antenna from bad weather.Dust particles carried by the wind rub against the plastic tube.After some time, the dust particles cause the tube to become positively charged.State the property of plastic that allows it to become electrostatically charged.
Have a good day!! :>
What do tripped circuit breakers and blown fuses indicate.
Answer:
When a circuit breaker regularly trips or a fuse repeatedly blows, it is a sign that you are making excessive demands on the circuit and need to move some appliances and devices to other circuits. Or, it may indicate that your house has too few circuits and is in need of a service upgrade.
What is current of 12 ohm? help me pleasee
Answer:
2.5A
Explanation:
We know the relation :
V = IR
V = voltage (potential difference)I = currentR = resistanceBy using the formula,
I = V/RI = 30/12I = 10/4I = 2.5AAnswer :-
Current of Device = 2.5 Ampere .Explanation :-
As per the provided information in the given question, we have been given that the Potential Difference is 30 Volt . The Resistance is given as 12 Ohm . And, we have been asked to calculate the Current of the Device.
For calculating the Current , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed { \sf{ \: Current \: = \: \dfrac{Potential \: Difference}{Resistance} \: }} [/tex]
Therefore , by Substituting the given values in the above Formula :-
[tex] \dag \: \: \: \sf { Current \: = \: \dfrac{Potential \: Difference}{Resistance} } [/tex]
[tex] \longmapsto \: \: \: \sf { Current \: = \: \dfrac{30}{12} } [/tex]
[tex] \longmapsto \: \: \: \textbf {\textsf {Current \: = \: 2.5 }} [/tex]
Hence :-
Current = 2.5 Ampere .[tex]\underline {\rule {180pt} {4pt}} [/tex]
how can you say metre cube is a derived unit
Answer:
The newton (lowercase n!) is a derived unit because its definition consists of multiplication of three defined base units and nothing else. Its meaning is thus derived, not independently defined.
A car initially travels at 10 m/s when passing the "acceleration line". The car then accelerates Q. at 8m/s2 until reaching a final velocity of 40 m/s. What is the car's displacement during the acceleration?
answer choices
3.75 m
93.75 m
100 m
1590 m
[tex]\text{Given that,}\\\\\text{Initial velocity,}~ u = 10 ~ms^{-1}\\\\\text{Final velocity,}~ v = 40 ~ ms^{-1}\\\\\text{Acceleration,}~ a = 8 ~ ms^{-2}\\ \\\text{Time ,}~ t =?\\\\\text{Displacement, }~ s = ?\\\\\text{We know that,}\\\\a= \dfrac{v-u}{t}\\ \\\implies t = \dfrac{v-u}{a} = \dfrac{40-10}{8} = \dfrac{30}{8} = 3.75 ~sec \\\\s=\left(\dfrac{u+v}2\right)t=\left(\dfrac{10+40}2 \right)3.75 = \left(\dfrac{50}{2}\right)3.75 = 25 \times 3.75 = 93.75~m[/tex]
[tex]\text{Hence, the displacement of the car is 93.75 m}[/tex]
A garbage can of mass 12 kg standing on horizontal ground is pushed by a horizontal force of 40N. If the coefficient of static friction is 0. 32 and the coefficient of dynamic or
kinetic friction is 0. 24 between the can and ground, the acceleration of the garbage can is
____ m/s2
The acceleration of the garbage can is 2.55 m/s².
What is acceleration?Acceleration is the rate of change of velocity with respect to time.
To calculate the acceleration of the can, we use the formula below
Formula:
ma = F-mg(η-μ)............ Equation 1Where:
F = Horizontal forcem = mass of the cang = acceleration due to gravitya = acceleration of the canμ = Coefficient of static frictionη = Coefficient of kinetic frictionMake a the subject of the equation
a = [F-mg(η-μ)]/m.................. Equation 2From the question,
Given:
F = 40 Nm = 12 kgg = 9.8 m/s²μ = 0.32η = 0.24Substitute these values into equation 2
a = [40-12×9.8(0.32-0.24)]/12a = (40-9.408)/12a = 30.592/12a = 2.55 m/s²Hence, the acceleration of the garbage can is 2.55 m/s².
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What is the 3rd largest planet in the solar system?
Answer:
Uranus
Explanation:
Your welcome
A planet is a celestial body. The third-largest planet in the solar system is Uranus.
What is a planet?A celestial body is differentiated from the fixed stars by its apparent mobility (including the moon and sun), especially in relation to its claimed impact on people and events.
A planet is a celestial body. The third-largest planet in the solar system is Uranus.
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A car initially travels west with a kinetic energy of 10 J. Then it travels east at three times its original speed. What is its kinetic energy when it is traveling east
KE₁ = 1/2mv²
10 J = 1/2mv²
KE₂ = 1/2m(3v)²
KE₂ = 1/2mv².9
KE₂ = 10 . 9 = 90 J
Why did astronomers suspect an eighth planet beyond uranus? how did they determine where to look for it? construct the correct explanation.
drag the terms on the left to the appropriate blanks on the right to complete the sentences.
brightness - mass - orbit - position - kepler's third law - value - law of gravity
observation of uranus showed small but significant discrepancy between its predicted ______ and its actual ________ , which could mean that another object perturbed its motion.
in the mid-1800s, astronomers used the ________ to predict where a planet would have to be.
Astronomers suspected an eighth planet beyond Uranus because of the irregularities in the motion of Uranus suggested that gravity from another planet was affecting it.
Who is an astronaut?It should be noted that an astronaut simply means an individual who is trained to travel in spacecrafts.
In this case, astronomers suspected an eighth planet beyond Uranus because of the irregularities in the motion of Uranus suggested that gravity from another planet was affecting it.
In mid-1800s, astronomers used the orbits of most asteroids to predict where a planet would have to be.
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angular velocity of a rotating wheel increases 2 rev/s every minute. The angular acceleration of this wheel is:
The angular acceleration of the rotating wheel at the given rate of change of angular velocity is 0.21 rad/s².
Angular acceleration of the wheel
The angular acceleration of an object is the rate of change of anguar velocity of the object with time.
[tex]\alpha = \frac{\Delta \omega }{\Delta t}[/tex]
where;
Δω is the change in the angular velocityΔt is the change in timeChange in angular velocity of the wheel is calculated as follows;
[tex]\Delta \omega = 2 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = 4\pi \ rad/s = 12.57 \ rad/s[/tex]
Change in time, Δt = 1 min = 60 s
The angular acceleration of the rotating wheel is calculated as follows;
α = (12.57) / (60)
α = 0.21 rad/s²
Thus, the angular acceleration of the rotating wheel at the given rate of change of angular velocity is 0.21 rad/s².
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The vertebral region is _________ to the scapular region.
Answer:
The answer is medial!
Explanation:
The vertebral region is medial to the scapula.
Hope This Helps!
-Justin:)