Answer:
The law zero of thermodynamics.
Explanation:
The law zero of thermodynamics, which tells us that heat flows from a body at a higher temperature to another body with lower temperature, when the heat transfer is zero, it is said that the two bodies are in thermal equilibrium, their temperatures are equal
When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. Suppose another bomb is tested, and 1.5 grams of matter are converted into energy. How many joules of energy are released by the explosion?
Answer:
The value is [tex]E = 1.35 *10^{14} \ J[/tex]
Explanation:
From the question we are told that
The mass of matter converted to energy on first test is [tex]m = 1 \ g = 0.001 \ kg[/tex]
The mass of matter converted to energy on second test [tex]m_1 = 1.5 \ g = 1.5 *10^{-3} \ kg[/tex]
Generally the amount of energy that was released by the explosion is mathematically represented as
[tex]E = m * c^2[/tex]
=> [tex]E = 1.5 *10^{-3} * [ 3.0 *10^{8}]^2[/tex]
=> [tex]E = 1.35 *10^{14} \ J[/tex]
When landing from a jump, a basketball player of mass 82 kg has a velocity of 1.2 m/s right before they hit the ground. The player then lands on the floor with their feet and is quickly brought to a stop. If the the floor deforms by 0.025 m while the player lands on it, what was the average force under the player's feet during the landing
Answer:
2361.6N
Explanation:
Mass of player = 82kg
Velocity = 1.2m/s
Kinetic energy of player:
= 1/2mv²
= 1/2*82*1.2²
= 41x1.44
= 59.04J
Final kinetic energy = 0
Change in kinetic energy
|∆k| = |0-59.04|
= 59.04
Workdone by the feet = fd
d = 0.025
Fd = 59.04
F = 59.04/0.025
= 2361.6N
This is his average force.
Find the quantity of heat needed
to melt 100g of ice at -10 °C
into water at 10 °C. (39900 J)
(Note: Specific heat of ice is
2100 Jkg 'K', specific heat
of water is 4200 Jkg K',
Latent heat of fusion of ice is
336000 Jkg ').
Answer:
Approximately [tex]3.99\times 10^{4}\; \rm J[/tex] (assuming that the melting point of ice is [tex]0\; \rm ^\circ C[/tex].)
Explanation:
Convert the unit of mass to kilograms, so as to match the unit of the specific heat capacity of ice and of water.
[tex]\begin{aligned}m&= 100\; \rm g \times \frac{1\; \rm kg}{1000\; \rm g} \\ &= 0.100\; \rm kg\end{aligned}[/tex]
The energy required comes in three parts:
Energy required to raise the temperature of that [tex]0.100\; \rm kg[/tex] of ice from [tex](-10\; \rm ^\circ C)[/tex] to [tex]0\; \rm ^\circ C[/tex] (the melting point of ice.)Energy required to turn [tex]0.100\; \rm kg[/tex] of ice into water while temperature stayed constant.Energy required to raise the temperature of that newly-formed [tex]0.100\; \rm kg[/tex] of water from [tex]0\; \rm ^\circ C[/tex] to [tex]10\;\ rm ^\circ C[/tex].The following equation gives the amount of energy [tex]Q[/tex] required to raise the temperature of a sample of mass [tex]m[/tex] and specific heat capacity [tex]c[/tex] by [tex]\Delta T[/tex]:
[tex]Q = c \cdot m \cdot \Delta T[/tex],
where
[tex]c[/tex] is the specific heat capacity of the material,[tex]m[/tex] is the mass of the sample, and[tex]\Delta T[/tex] is the change in the temperature of this sample.For the first part of energy input, [tex]c(\text{ice}) = 2100\; \rm J \cdot kg \cdot K^{-1}[/tex] whereas [tex]m = 0.100\; \rm kg[/tex]. Calculate the change in the temperature:
[tex]\begin{aligned}\Delta T &= T(\text{final}) - T(\text{initial}) \\ &= (0\; \rm ^\circ C) - (-10\; \rm ^\circ C) \\ &= 10\; \rm K\end{aligned}[/tex].
Calculate the energy required to achieve that temperature change:
[tex]\begin{aligned}Q_1 &= c(\text{ice}) \cdot m(\text{ice}) \cdot \Delta T\\ &= 2100\; \rm J \cdot kg \cdot K^{-1} \\ &\quad\quad \times 0.100\; \rm kg \times 10\; \rm K\\ &= 2.10\times 10^{3}\; \rm J\end{aligned}[/tex].
Similarly, for the third part of energy input, [tex]c(\text{water}) = 4200\; \rm J \cdot kg \cdot K^{-1}[/tex] whereas [tex]m = 0.100\; \rm kg[/tex]. Calculate the change in the temperature:
[tex]\begin{aligned}\Delta T &= T(\text{final}) - T(\text{initial}) \\ &= (10\; \rm ^\circ C) - (0\; \rm ^\circ C) \\ &= 10\; \rm K\end{aligned}[/tex].
Calculate the energy required to achieve that temperature change:
[tex]\begin{aligned}Q_3&= c(\text{water}) \cdot m(\text{water}) \cdot \Delta T\\ &= 4200\; \rm J \cdot kg \cdot K^{-1} \\ &\quad\quad \times 0.100\; \rm kg \times 10\; \rm K\\ &= 4.20\times 10^{3}\; \rm J\end{aligned}[/tex].
The second part of energy input requires a different equation. The energy [tex]Q[/tex] required to melt a sample of mass [tex]m[/tex] and latent heat of fusion [tex]L_\text{f}[/tex] is:
[tex]Q = m \cdot L_\text{f}[/tex].
Apply this equation to find the size of the second part of energy input:
[tex]\begin{aligned}Q_2&= m \cdot L_\text{f}\\&= 0.100\; \rm kg \times 3.36\times 10^{5}\; \rm J\cdot kg^{-1} \\ &= 3.36\times 10^{4}\; \rm J\end{aligned}[/tex].
Find the sum of these three parts of energy:
[tex]\begin{aligned}Q &= Q_1 + Q_2 + Q_3 = 3.99\times 10^{4}\; \rm J\end{aligned}[/tex].
Find the resultant of the following displacement:
A = 20 Km 30° south of east;
B = 50 Km due west;
C = 40 Km north east;
D = 30 Km 60° south of west.
Answer:
Explanation:
Basically you just have to find the left vectors. To do so divide A, C and D into horizontal and vertical vector. A: 10km to south and 10root3 to east. Just sine and cosine of 30 at 20km. D: 15 km to west and 15root3 to south. Again sine and cosine of 60 at 30 km. C: 45 degrees so 20root2 to north and east. Add all these up with B. Then you have 7.696 km due south and 19.395 km due west. Resultant displacement magnitude = root(7.696^2+19.395^2)=20.866 south of west with angle=arctan(7.696/19.395)=21.644 degrees
A woman exerts a horizontal force of 3 pounds on a box as she pushes it up a ramp that is 10 feet long and inclined at an angle of 30 degrees above the horizontal. Find the work done on the box.
Answer: 67 how much candy does nick have
Explanation:
Mark walked 2 miles east than 1 mile north how would you determine his total displacement
They could determine it by counting their total amount of miles mark went by the directions he went to walk those miles.
An ambulance is traveling east at 62.4 m/s. Behind it a car travels along the same direction at 34.5 m/s. The ambulance driver hears his siren with a wavelength of 0.47 m. What wavelength would a stationary observer behind the ambulance measure for the sound? The velocity of sound in air is 343 m/s.
Answer:
The answer is "0.5555 m"
Explanation:
Where the reference leaves the list and the viewer is at rest:
[tex]\lambda'=\frac{v-v_s}{v} \times \lambda\\\\[/tex]
[tex]=\frac{343 \frac{m}{s} - (-62.4 \frac{m}{s})}{343 \frac{m}{s}} \times 0.47 \ m\\\\ =\frac{343 \frac{m}{s} + 62.4 \frac{m}{s}}{343 \frac{m}{s}} \times 0.47 \ m\\\\ =\frac{405.4 \frac{m}{s}}{343 \frac{m}{s}} \times 0.47 \ m\\\\ =\frac{405.4 \frac{m}{s}}{343 \frac{m}{s}} \times 0.47 \ m[/tex]
[tex]=0.5555 \ m[/tex]
To celebrate a victory, a pitcher throws her glove straight upward with an initial speed of 5.3 m/s. How long does it take for the glove to reach its maximum height
Hello!!
For the maximum height the final velocity is zero, because can't up more.
Then, use the formula:
V = Vi + gt
Replacing, we have:
0 m/s = 5,3 m/s + (-9,8 m/s² * t)
0 m/s - 5,3 m/s = -9,8 m/s² * t
(-5,3 m/s) / -9,8 m/s² = t
t = 0,54 s
The time it will take to reach the maximum height is 0,54 seconds.
Why do you need air resistance in a parachute ?what happens without it?
And
How does air resistance affect acceleration and terminal velocity
write the characteristic of aluminum
Answer:
see below
Explanation:
alluminium is,
1.lustrous
2.highly malleable
3.reactive metal
4.some times acts as non metal
5.good conductor
6.obtained from bauxite
7.Atomic number 13 so electrons and protons are 13
8.neurons are 14
9.ductile
10.melting point is very high approximately 660 degree celsius.
Answer:
It has low density, is non-toxic, has a high thermal conductivity, has excellent corrosion resistance and can be easily cast, machined and formed.
Explanation:
pls tell the answer
Just flip one of the batteries to connect one's positive terminal to others negative terminal.
Car 1 drives 20 mph to the south, and car 2 drives 30 mph to the north. From
the frame of reference of car 1, what is the velocity of car 2?
Answer:
10 mph faster than car 1 is going
Explanation:
What determines the type of air mass that forms in an area?
Question 11 options:
The amount of oxygen present
The amount of air present
The direction of air flow
The location where it forms
Answer: no because you have left the number
Explanation:
A food processor draws 8.47 A of current when connected to a potential difference of 110 V.
How much electrical energy is consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day?
Answer:
27.95[kW*min]
Explanation:
We must remember that the power can be determined by the product of the current by the voltage.
[tex]P=V*I[/tex]
where:
P = power [W]
V = voltage [volt]
I = amperage [Amp]
Now replacing:
[tex]P=110*8.47\\P=931.7[W][/tex]
Now the energy consumed can be obtained mediate the multiplication of the power by the amount of time in operation, we must obtain an amount in Kw per hour [kW-min]
[tex]Energy = 931.7[kW]*30[days]*10[\frac{min}{1day} ]=279510[W*min]or 27.95[kW*min][/tex]
Drag each item to indicate whether it is a characteristic of dark matter or baryonic matter. (2 points)
Dark Matter
Baryonic Matter
:: has been observed directly
:: interacts with baryonic matter
:: interacts with electromagnetic radiation
has not been observed directly
:: does not interact with electromagnetic radiation
++ does not interact with baryonic matter
Answer:
Dark matter:
- Doesn't interact with baryonic matter.
- It has not been observed directly
- dark matter does not absorb, reflect or even emit light, thereby making it to be extremely hard to spot. Therefore, it does not interact with electromagnetic radiation.
Explanation:
Dark matter:
- Doesn't interact with baryonic matter.
- It has not been observed directly
- dark matter does not absorb, reflect or even emit light, thereby making it to be extremely hard to spot. Therefore, it does not interact with electromagnetic radiation.
Baryonic matter:
- Has been observed directly because it includes nearly all the matter that we see in the world daily.
- It interacts with baryonic matter
- interacts with electromagnetic radiation
Dark Matter:
It has not been observed directly.It does not interact with baryonic matter.It does not interact with electromagnetic radiation.Baryonic Matter:
It has been observed directly.It interacts with baryonic matter.It interacts with electromagnetic radiation.Dark matter can be defined as often invisible substances that are difficult to spot because they don't absorb, emit or reflect light.
Hence, dark matter do not affect human view because they do not interact or interfere with electromagnetic radiation (force).
Although, humans can see right through the (weakly interacting) dark matter but it has not been observed directly.
Baryonic matter can be defined as a dark matter that is made up of baryons such as neutrons, and protons. Also, they are ordinary matter (both fermions and hadrons), as distinct from exotic forms.
In conclusion. baryonic matter has been observed directly and it can interact with electromagnetic radiation.
Read more: https://brainly.com/question/15677526
A 50.0-kg child stands at the rim of a merry-go-round of radius 2.00 m, rotating in such a way that it makes one revolution in 2.09 s. What minimum coefficient of static friction between her feet and the floor of the merry-go-round is required to keep her in the circular path
Answer:
2.01
Explanation:
First, we need to find the centripetal acceleration.
We're given that the merry go round rotates 1 revolution in 2.09 seconds. Converting to rpm, we know that it rotates 30 revolution per minute
Now this speed gotten in rpm will be converted to m/s, to ease the calculation
30 rpm = πdN/60 m/s
30 rpm = (3.142 * 4 * 30)/60
30 rpm = 377.04/60
30 rpm = 6.284 m/s
a(c) = v²/r
a(c) = 6.284²/2
a(c) = 39.49 / 2
a(c) = 19.74 m/s²
F = ma
F = 50 * 19.74
F = 987 N
Also, Normal Force, F(n) =
F(n) = mg
F(n) = 50 * 9.81
F(n) = 490.5
We then use this to find the coefficient of static friction, μ
μ = F/F(n)
μ = 987 / 490.5
μ = 2.01
A toy car weighing 3.2 N gets pushed a distance of 10 m in 1.3 s. What is the momentum of the car?
Answer:
2.51 kg * m/s
Explanation:
In order to find momentum, use the equation below:
momentum = mass * velocity.
Since neither mass nor velocity was given, you must solve for both variables.
In order to solve for mass, use the force equation for its weight / gravitational force.
Fg (gravitational force) = 3.2 N = ma = 9.8m
mass = 3.2 N / 9.8 m/s^2 = 0.326531 kg
In order to solve for velocity, use the equation:
velocity = displacement / time
velocity = 10m / 1.3 s = 7.69231 m/s
Momentum = mass * velocity = 0.326531 kg * 7.69231 m/s = 2.51177 kg * m/s = 2.51 kg * m/s
A tissue is a group of similar cells that perform a specific function in an organism true or false
Answer:
true
Explanation:
HELP NOW PLS !!
If you exert 950 N*s of impulse on a 12 kg frictionless cart over the course of 5 seconds, how far will it travel during those seconds?
Answer:
The value is [tex]s =197.88 \ m[/tex]
Explanation:
From the question we are told that
The impulse is [tex]I = 950 \ N\cdot s[/tex]
The mass is [tex]m = 12 \ kg[/tex]
The time t = 5 s
Generally impulse is mathematically represented as
[tex]I = F * t[/tex]
=> [tex]F = \frac{I}{t}[/tex]
=> [tex]F = \frac{950 }{ 5 }[/tex]
=> [tex]F = 190 \ N[/tex]
Generally force is mathematically represented as
[tex]F = m * a[/tex]
=> [tex]a = \frac{F }{ m }[/tex]
=> [tex]a = \frac{190 }{ 12 }[/tex]
=> [tex]a = 15.83 \ m/s^2[/tex]
Generally from kinematic equation , the distance covered is
[tex]s = ut + \frac{1}{2} * at^2[/tex]
Here u is the initial velocity of the cart and the value is [tex]u = m/s[/tex]
=> [tex]s = 0 * 5 + \frac{1}{2} * 15.83 * 5^2[/tex]
=> [tex]s =197.88 \ m[/tex]
An earth satellite travels in a circular orbit at 20,000 mph if the radius of the orbit is 4,300 mi what angular velocity is generated?
Answer:
0.00129rad/s
Explanation:
The angular velocity is expressed as;
v = wr
w is the angular velocity
r is the radius
Given
v = 20,000 mph
r = 4300mi
Get w;
w = v/r
w = 20000* 0.44704/4300*1609.34
w = 8940.8/6,920,162
w = 0.00129rad/s
Hence the angular velocity generated is 0.00129rad/s
Help me please I’ll give brainliest
Answer:
zoom in
Explanation:
A car accidently roll of a cliff. As it leaves the cliff it has horzontal velocity of 13 m/s it hits the ground 60m from the shoreline. Calculate the hight of the cliff
Answer: The height of the cliff is 104.59 m
Explanation:
The horizontal speed of the car when it leaves the cliff is 13 m/s, and it hits the ground 60m from the shoreline.
Here we can use the relationship:
Time*Speed = Distance.
To find the time that the car is in the air, we know that:
speed = 13m/s
distance = 60m
time = T
13m/s*T = 60m
T = (60m)/13m/s = 4.62 s
This means that the car is falling for 4.62 seconds.
Now let's analyze the vertical problem.
As the car leaves the cliff, it only has horizontal velocity, this means that the vertical initial velocity will be zero
The only force acting in the vertical axis is the gravitational force, this means that the acceleration will be equal to the gravitational acceleration, which is:
g = 9.8m/s^2
then:
a = -9.8m/s^2
Where the negative sign is because the acceleration is pulling the car downwards.
To get the vertical velocity, we could integrate over time to get:
v(t) = (-9.8m/s^2)*t + v0
Where v0 is the constant of integration and the initial vertical velocity, that we already know that is equal to zero, then the vertical velocity as a function of time can be written as:
v(t) = (-9.8m/s^2)*t
To get the vertical position equation, we need to integrate again over the time:
P(t) = (1/2)*(-9.8m/s^2)*t^2 + H
Where H is the constant of integration and the initial vertical position, then H will be the height of the cliff.
We know that the car needs 4.62 seconds to hit the ground, this means that:
P(4.6s) = 0m
Then:
P(t) = (1/2)*(-9.8m/s^2)*(4.62s)^2 + H = 0
(-4.9m/s^2)*(4.62s)^2 + H = 0
H = (4.9m/s^2)*(4.62s)^2 = 104.59 m
This means that the cliff is 104.59 meters high
how do i find out the maximum speed and things? also, if you can give the answer and tell me why that would be amazing!!
Answer:
See the answers and the explanation below.
Explanation:
To solve these questions we must understand that speed is the relationship between the displacement and the time that the displacement lasts.
1. 300 [km], in 5 [hr]
d = displacement [km]
[tex]v = d/t[/tex]
where:
v = velocity [km/h]
t = time [hr]
[tex]v = 300/5\\v = 60 [km/h][/tex]
In one hour : [tex]d = 60*1\\d = 60 [km][/tex]
b. Car B 100 [km] in 2 [hr]
[tex]v =100/2\\v = 50 [km/h]\\[/tex]
C. The car A has the greatest average speed.
Two workers are sliding 500 kg crate across the floor. One worker pushes forward on the crate with a force of 440 N while the other pulls in the same direction with a force of 340 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor
Answer:
0.159
Explanation:
Given that
F1 = 440 N
F2 = 340 N
m = 500 kg
acceleration, a = 0 m/s²
Remember that F = m.a
If F - f(f) = 0, then F = f(f)
N = mg
f(f) = μN, substituting for N, we have
f(f) = μmg
The total force, F = F1 + F2
F = 440 + 340
F = 780 N
Recall that we'd already proven that
F = f(f), so F = 780 N = f(f)
And again, f(f) = μmg, if we substitute for all the values, we have
780 = μ * 500 * 9.81
780 = μ * 4905
μ = 780 / 4905
μ = 0.159
Therefore, the coefficient of static friction of the crate on the floor is 0.159
A boy on a bicycle approaches a brick wall as he sounds his horn at a frequency 400 Hz. The sound he hears reflected back from the wall is at a frequency 408 Hz. At what speed is the boy riding his bicycle toward the wall
Answer:
6.8 m/s
Explanation:
To solve this, we would use the Doppler's Effect. Doppler's effect is represented by the formula
f = [(g + vr)/(g + vs)].fo, where
f = observed frequency, 408 Hz
g = speed of sound in air, 340 m/s
vr = velocity of the receiver
vs = velocity of the source, 0 m/s
fo = source frequency, 400 Hz
Now, applying the values to the equation, we have
408 = [(340 + vr)/(340 + 0) * 400
408/400 = (340 + vr)/340
1.02 * 340 = 340 + vr
346.8 = 340 + vr
vr = 346.8 - 340
vr = 6.8 m/s
Therefore the speed at which the boy is riding his bicycle towards the wall is 6.8 m/s
A model airplane with mass 1.0 kg is held by a wire so that it flies in a horizontal circle with radius 20.0 m. The airplane engine provides a net thrust of 1.0 N perpendicular to the wire. (a) Find the torque the net thrust produces about the center of the circle. (b) Find the angular acceleration of the airplane when it is in this horizontal flight.
Answer:
330
Explanation:
(a) The torque the net thrust produces about the center of the circle is of 20 N-m.
(b) The angular acceleration of the airplane when it is in this horizontal flight is 0.1 rad/s².
Given data:
The mass of model airplane is, m = 1.0 kg.
The radius of horizontal circle is, r = 20.0 m.
The magnitude of net thrust by engine is, F = 1.0 N.
(a)
The effort made to turn any object is known as the torque. The mathematical expression for the torque is given as,
T = F × r
Solving as,
T = 1.0 × 20.0
T = 20 N-m
Thus, we can conclude that the torque the net thrust produces about the center of the circle is of 20 N-m.
(b)
The expression for the angular acceleration of airplane during the horizontal flight is given as,
[tex]T = I \times \alpha[/tex]
Here, I is the moment of inertia of airplane and its value is,
[tex]I = \dfrac{1}{2}mr^{2}\\\\\\I = \dfrac{1}{2} \times 1.0 \times 20^{2}\\\\\\I =200 \;\rm kg.m^{2}[/tex]
So, the angular acceleration is,
20 = 200 × α
α = 20/200
α = 0.1 rad/s²
Thus, we can conclude that the angular acceleration of the airplane when it is in this horizontal flight is 0.1 rad/s².
Learn more about the torque here:
https://brainly.com/question/19247046
Question 1 of 25
Two asteroids with masses 3.71 x 10 kg and 1.88 x 104 kg are separated by
a distance of 1,300 m. What is the gravitational force between the asteroids?
Newton's law of gravitation is F gravity
Gm, 2 The gravitational
constant Gis 6.67 x 10-11 Nm²/kg?
A. 275 x 10"N
B. 4.13 x 10°N
C. 2.04 x 10°N
O D. 3.58 x 10-N
SUBMIT
Answer:
(A)
Explanation:
Answer:
275 x 10"N
Explanation:
A sound wave enters a new medium where sound travels faster. How does this affect the frequency and wavelength of the sound?
А. The frequency increases and the wavelength decreases.
B. The frequency decreases and the wavelength increases.
C. The frequency stays the same and the wavelength increases.
D.The frequency stays the same and the wavelength decreases.
E. Neither the frequency nor the wavelength is affected.
Answer:
The frequency stays the same and the wavelength decreases.
Explanation:
When sound wave enters a new medium where sound travels faster, its frequency will remain same because it depends only on the source.
The relation between wavelength and speed is inverse, it means when the speed of sound increases, its wavelength will decrease.
So, the frequency stays the same and the wavelength decreases. Hence, the correct option is (d).
The gravity on Earth is 9.8m/s2, the mass of a bowling ball is about 5kg. What is the weight of the bowling ball on the Earth?
Answer:
yo can someone answer i need this
Explanation:
what belongs in the center section
Answer:
The second one I think
Explanation:
B