Which of the binomials below is a factor of this trinomial? x^2 - 7x - 18A. x+2B. x-2C. x-3D. x+3

Which Of The Binomials Below Is A Factor Of This Trinomial? X^2 - 7x - 18A. X+2B. X-2C. X-3D. X+3

Answers

Answer 1

Given:

The function is:

[tex]x^2-7x-18[/tex]

Find-:

The binomials below are a factor of this trinomial

Explanation-:

Function is:

[tex]=x^2-7x-18[/tex]

Factor is:

[tex]\begin{gathered} =x^2-7x-18 \\ \\ =x^2-9x+2x-18 \\ \\ \end{gathered}[/tex]

The factor of quadratic equation,

[tex]\begin{gathered} =x^2-9x+2x-18 \\ \\ =x(x-9)+2(x-9) \\ \\ =(x-9)(x+2) \end{gathered}[/tex]

The factore of this trinomial is x + 2.


Related Questions

Algebra:What is the value of this expression when t = -12?-3|t − 8| + 1.5A. 61.5B. 13.5C. -10.5D. -58. 5

Answers

1) Given that t =-12 let's plug into that expression the value for t

2) Now let's plug into that and solve it.

-3|t-8| +1.5 Applying the absolute value property

-3|t -8| +1.5 Plug into that t=-12

-3|-12 -8| +1.5

-3|-20| +1.5

-3*20 +1.5

-60 +1.5

-58.5

A 6-sided die is rolled. What is the probability of rolling a number that is even and a 3?A. 1B. 1/2C. 0D. 1/3

Answers

Answer

OptionC is correct.

Explanation

The probability of an event is calculated as the number of elements inthat event divided by the total number of elements inthesample space.

For this question, we are asked to find the probability of obtaining a number that is even and a 3 on a 6-sided die.

Number of digits that are even and a 3 on a 6-sided die = 0

Total number of digits on a 6-sided die = 6

Probability of obtaining a number that is even and a 3 on a 6-sided die = (0/6) = 0

Hope this Helps!!!

the Supreme Choice pizza at Pizza Paradise containing three different meats and three different vegetables. The customer can select any one of the five types of crust. If there are 6 meats and 9 vegetables to choose from, how many different Supreme choices Pizza can be made?

Answers

The Supreme Choice pizza at Pizza Paradise contains:

-) 3 different types of meat

-) 3 different vegetables

There are:

-) 5 types of crust (the customer can select one of them)

-) 6 types of meat

-) 9 vegetables

How many different Supreme choices Pizza can be made? ​

We can use the combinatory operator.

The customer can choose 3 different types of meat out of 6. The number of possible selections is:

For the crust, the customer can choose 1 of 5 possible types. Then, the number of different ways he can choose the crust is simply 5.

For the vegetables, there are 9 in total, and the customer can choose 3 different types. Again, using the combinatory operator, we have:

So we have 20 possible ways of choosing 3 types of meat, 5 possible ways of choosing 1 type of crust, and 84 different ways to choose 3 different vegetables.

For the total number of different Supreme choices Pizza a customer can make, we take the product:

20*5*84 = 8400

That is, there are 8400 different Supreme choices pizza.

Mr. Morales drove 360 to a conference. He had transmission problems on the return trip and it took him 3 hours longer at an average speed of 30 mph less than the trip going. What was his average speed on the return trip?

Answers

Remember that

The speed is equal to divide the distance by the time

speed=d/t

Let

t ----> time spend to go to the conference in hours

s ----> speed trip going

Conference trip

s=360/t ------> equation 1

Return trip

speed=360/(t+3)

speed=s-30

s-30=360/(t+3) ------> equation 2

substitute equation 1 in equation 2

(360/t)-30=360/(t+3)

Multiply both sides by t(t+3) to remove fractions

360(t+3)-30t(t+3)=360t

360t+1,080-30t^2-90t=360t

simplify

30t^2+90t-1,080=0

Solve the quadratic equation

The solutions for t are

t=-7.7 h -----> is not a solution, because is a negative number

t=4.69 hours

Find out the average speed on the return trip

speed=360/(t+3)

speed=360/(4.69+3)

speed=46.81 mph

Is this statement true or not? cos (cos^-1 (2)) = 2 Explain why or why not.

Answers

True

1) Let's evaluate that, using one identity for that:

[tex]\begin{gathered} \cos (\cos ^{-1}(2))= \\ \cos (\cos ^{-1}(\theta))=\theta \\ \cos (\cos ^{-1}(2))=2 \end{gathered}[/tex]

2) Since the cosine of the arc cosine (theta) is equal to theta, we can state that this trigonometric equation is true.

3) Hence, that's true.

Are the two lines parallel, perpendicular, or neither? Parallel Perpendicular O Neither

Answers

Answer:

Explanation:

• Parallel lines ,are lines that ,do not intersect ,no matter how long the line is drawn.

,

• Perpendicular lines, are lines that ,form an angle of 90 degrees, with one another.

From the given options, the following options apply:

• Graph 1: Parallel

,

• Graph 2: Neither

,

• Graph 3: Perpendicular

,

• Graph 4: Neither

Find the approximate volume of the cylinder below in cubic centimeters. Round your answer to the nearest hundredth. 14 cm 20 cm

Answers

Answer: Volume of a cylinder = 3, 077.20 cubic centimeter

Given data

Diameter of the cylinder = 14cm

Height of the cylinder = 20cm

Radius = diameter / 2

radius = 14/2

radius = 7 cm

[tex]\begin{gathered} \text{Volume of the cylinder = }\pi\cdot r^2\cdot\text{ h} \\ \pi\text{ = 3.14, r = 7cm, and h = 20cm} \\ \text{V = 3.14 }\cdot7^2\cdot\text{ 20} \\ \text{V = 3.14 x 49 x 20} \\ \text{V = 3.14 x 980} \\ \text{V = 3, 077.20 cm}^3 \end{gathered}[/tex]

Find three consecutive integers whose sum is negative twelve. Set up an equation and solve

Answers

x + (x+1)+ (x+2) = -12

3x+3 =-12

Solve for x

3x =-12-3

3x=-15

Divide both sides by 3:

3x/3 = -15/3

x = -5

First integer is -5

Second is integer -5+1 =-4

Third integer -5+2 = -3

Graph the piecewise function f(x) = 3/2x+1 , -4 <= x<= 0 x-5 , 1 <= x<= 3 The image is attached for reference.

Answers

The piecewise function f(x) is composed bt two lines: 3/2x + 1 and x - 5. To graph a line, we need to connect two points that lie on the line. In the case of the first line, we can use its endpoints x = -4 and x = 0.

Substituting x = -4 into the equation of the first line, we get:

[tex]\begin{gathered} y=\frac{3}{2}(-4)+1 \\ y=-6+1 \\ y=-5 \end{gathered}[/tex]

Then, the point (-4, -5) lies on the first line.

Substituting x = 0 into the equation of the first line, we get:

[tex]\begin{gathered} y=\frac{3}{2}(0)+1 \\ y=1 \end{gathered}[/tex]

Then, the point (0,1) lies on the first line.

In the case of the second line, the endpoints x = 1 and x = 3.

Substituting x = 1 into the equation of the second line, we get:

[tex]\begin{gathered} y=1-5 \\ y=-4 \end{gathered}[/tex]

Then, the point (1,-4) lies on the second line.

Substituting x = 3 into the equation of the second line, we get:

[tex]\begin{gathered} y=3-5 \\ y=-2 \end{gathered}[/tex]

Then, the point (3,-2) lies on the second line.

Connecting these points with two different lines as stated before, we get the graph of f(x) as follows:

Can someone please explain it to me I don't get it

Answers

We have the general rule for a rotation of 90° counterclockwise:

[tex]r_{90}(x,y)=(y,-x)[/tex]

and the general rule for a y=-x reflection is:

[tex]r_{y=-x}(x,y)=(-y,-x)[/tex]

In this case, we have the points R=(2,-2), S=(5,-1) and T=(3,-5).

Then, we first have to use the 90° rotation on all points:

[tex]\begin{gathered} r_{90}(R)=r_{90}(2,-2)=(-2,-2)=R^{\prime} \\ r_{90}(S)=r_{90}(5,-1)=(-1,-5)=S^{\prime} \\ r_{90}(T)=r_{90}(3,-5)=(-5,-3)=T^{\prime} \end{gathered}[/tex]

Now we use the y=-x reflection on our new points:

[tex]\begin{gathered} r_{y=-x}(R^{\prime})=r_{y=-x}(-2,-2)=(2,2)=R^{\doubleprime} \\ r_{y=-x}(S^{\prime})=r_{y=-x}(-1,-5)=(5,1)=S^{\doubleprime} \\ r_{y=-x}(T^{\prime})=r_{y=-x}(-5,-3)=(3,5)=T^{\doubleprime} \end{gathered}[/tex]

therefore, the final points after the transformations are:

R''=(2,2)

S''=(5,1)

T''=(3,5)

Find the range of allowable values based on the given information. Round to the nearest tenth.15; can vary by 2%Enter the correct answers in the boxes.Hide HintMultiply the percentage by the number to find the amount of error allowed.• Add and subtract the amount of error from the original number to find the range.to

Answers

15 can vary by 2%, this means that the range of values you can observe are 2% below 15 and 2% above 15.

First, you have to determine how much does the percentage represents with regards to the value of reference. To do so, you have to calculate the 2% of 15:

-Multiply 2 by 15 and divide the result by 100

[tex]\frac{2\cdot15}{100}=\frac{30}{100}=3[/tex]

The 2% of 15 is 3, which means that the range of values you are looking for is 3 units below 15 and 3 units above.

The minimum value of the range: subtract 3 to 15

[tex]15-3=12[/tex]

The maximum value of the range: add 3 to 15

[tex]15+3=18[/tex]

The range of allowable values is [12;18]

Physicists tell us that altitude h in feet of a projectile t seconds after firing is h=-16t^2+v0t+h0, where v0 is the initial velocity in feet per second and h0 is the altitude in feet from which it is fired. If a rocket is launched from a hilltop 2400 feet above the desert with an initial upward velocity of 400 feet per second, then when will it land on the desert ?

Answers

The formula that the physicists told was

[tex]h(t)=-16t^2+v_0t+h_0[/tex]

We know that

v₀ = 400 ft/s

h₀ = 2400 ft

Then let's put it into the formula

[tex]\begin{gathered} h(t)=-16t^2+400t+2400 \\ \\ \end{gathered}[/tex]

We want to know then it will land on the desert, in other words, when the height is equal to zero, then

[tex]-16t^2+400t+2400=0[/tex]

Then we must solve that quadratic equation, to solve it let's first divide all by 16

[tex]\begin{gathered} -16t^2+400t+2400=0 \\ \\ -t^2+25t+150=0 \end{gathered}[/tex]

Because it's an easier equation to solve and the solution is the same. Now we can apply the quadratic formula

[tex]t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

Plug the values

[tex]\begin{gathered} t=\frac{-25\pm\sqrt{25^2-4\cdot(-1)\cdot150}}{2\cdot(-1)} \\ \\ t=\frac{-25\pm\sqrt{625+4\cdot150}}{-2} \\ \\ t=\frac{25\pm\sqrt{625+600}}{2} \\ \\ t=\frac{25\pm\sqrt{1225}}{2} \\ \\ t=\frac{25\pm35}{2} \\ \\ t=\frac{25+35}{2}=\frac{60}{2}=30\text{ seconds} \end{gathered}[/tex]

We can ignore the other solution because it's negative and negative time is not a valid solution. Therefore, 30 seconds after its launch, the rocket will land in the desert

What is the volume of a marble sphere is about 7,238.23 cubic millimeters. What is the radius? (Round your answer to the nearest millimeter.)

Answers

The volume of a sphere can be calculated using this formula:

[tex]V=\frac{4}{3}\pi r^3[/tex]

Where "r" is the radius of the sphere and "V" is the volume of the sphere.

If you solve for "r", you get this new formula:

[tex]r=\sqrt[3]{\frac{3V}{4\pi}}[/tex]

In this case you know that:

[tex]V\approx7,238.23\operatorname{mm}^3[/tex]

Therefore, you can substitute this value into the second formula and then evaluate, in order to find the radius of this sphere:

[tex]\begin{gathered} r=\sqrt[3]{\frac{(3)(7,238.23\operatorname{mm}^3)}{4\pi}} \\ \\ r\approx12\operatorname{mm} \\ \end{gathered}[/tex]

The answer is:

[tex]r\approx12\operatorname{mm}[/tex]

-50=3(15)+b solve for b

Answers

Given that -50=3(15)+b

expand

-50=45+b

collect like terms

-50 - 45 = 45 - 45 + b

-95 = b

b = -95

Which of the following would be the variance of this population data set: 3, 9,8, 9, 4, 5, 7, 11, 9, 7, 5, 4, 3, 1

Answers

GIVEN:

We are given the set of data as indicated below;

[tex]3,9,8,9,4,5,7,11,9,7,5,4,3,1[/tex]

Required;

To find the variance of the data set.

Step-by-step solution;

We begin by calculating the mean of the data set as follows;

[tex]\begin{gathered} Mean=\frac{3+9+8+9+4+5+7+11+9+7+5+4+3+1}{14} \\ \\ Mean=\frac{85}{14}=6.07142857143 \end{gathered}[/tex]

We now round the mean to two decimal places and we have;

[tex]Mean\approx6.07[/tex]

Next we subtract the mean from EACH value in the data set. the individual results are the "deviation from the mean."

After that we square each deviation from the mean, and then add them all up.

This is effectively explained by the formula for the variance which is;

[tex]\begin{gathered} variance=s^2 \\ \\ s^2=\frac{\Sigma(x-\bar{x})^2}{n-1} \end{gathered}[/tex]

We now have;

[tex]\begin{gathered} (3-6.07)^2+(9-6.07)^2+(8-6.07)^2+...+(3-6.07)+(1-6.07)^2 \\ \\ =9.4249+8.5849+3.7249+8.5849+4.2849+1.1449+0.8649+24.3049 \\ \\ +8.5849+0.8649+1.1449+4.2849+9.4249+25.7049 \\ \\ =110.9286 \end{gathered}[/tex]

Now we can refine the formula as shown below;

[tex]\begin{gathered} s^2=\frac{\Sigma(x-\bar{x})^2}{n-1} \\ \\ Where,\text{ }n=14 \\ \\ s^2=\frac{110.9286}{14-1} \\ \\ s^2=\frac{110.9286}{13} \\ \\ s^2=8.53296923077 \end{gathered}[/tex]

We can round this to 2 decimal places and the variance therefore is;

ANSWER:

[tex]variance\approx8.53[/tex]

given ️KPM =~ ️AYC complete each of the following statements

Answers

a)

[tex]\bar{KM}\cong\bar{AC}[/tex]

b)

[tex]\bar{CY}\cong\bar{MP}[/tex]

c)

[tex]\bar{PK}\cong\bar{AY}[/tex]

d)

[tex]\angle Y\cong\angle P[/tex]

e)

[tex]\angle K\cong\angle A[/tex]

f)

[tex]\angle ACY\cong\angle KMP[/tex]

g)

[tex]\Delta\text{MPK}\cong\Delta CYA[/tex]

h)

[tex]\Delta\text{YAC}=\Delta\text{PKM}[/tex]

I need help with this expected value out come assignment

Answers

To fill the values, we are given a list of the percentage of customers that spend a specific amount of money.

The x1, x2, x3, and x4 are the money spent, and the P(x1), P(x2),... are the proportion of customers that spend that amount, in decimal

Then, we can complete:

[tex]\begin{gathered} X_1=8 \\ . \\ P(X_1)=0.20 \\ . \\ X_1\cdot P(X_1)=8\cdot0.20=1.6 \\ \end{gathered}[/tex][tex]\begin{gathered} X_2=10 \\ . \\ P\left(X_2\right)=0.35 \\ . \\ X_3\cdot P(X_3)=10\cdot0.35=3.5 \end{gathered}[/tex][tex]\begin{gathered} X_3=12 \\ . \\ P(X_3)=0.40 \\ . \\ X_3\cdot P(X_3)=12\cdot0.40=4.8 \end{gathered}[/tex]

[tex]\begin{gathered} X_4=15 \\ . \\ P(X_4)=0.05 \\ . \\ X_4\cdot P(X_4)=15\cdot0.05=0.75 \end{gathered}[/tex]

((5x-16) cubed -4)cubed = 216,000X = _________

Answers

Given the equation:

[tex]((5x-16)^3-4)^3=216000[/tex]

Applying the exponent laws:

[tex]\begin{gathered} \sqrt[3]{((5x-16)^3-4)^3}=\sqrt[3]{216000} \\ (5x-16)^3-4=60 \end{gathered}[/tex]

Simplify:

[tex]\begin{gathered} (5x-16)^3-4+4=60+4 \\ (5x-16)^3=64 \end{gathered}[/tex]

Applying the exponent laws:

[tex]\begin{gathered} \sqrt[3]{(5x-16)^3}=\sqrt[3]{64} \\ Simplify \\ 5x-16=4 \\ 5x-16+16=4+16 \\ 5x=20 \\ \frac{5x}{5}=\frac{20}{5} \\ x=4 \end{gathered}[/tex]

Answer: x = 4

I need help with several questions, I don't really understand pre algbrea at all.

Answers

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

Using the data in the table to find the rate of change in the length of the baby girl:

Choosing any two consecutive points, we have that the:

[tex]\text{Average Rate of change =}\frac{Differen\text{ce in the two consecutive lengths }}{\text{Difference in the consecutive months}}[/tex][tex]Average\text{ Rate of change = }\frac{21.5\text{ -20}}{6-4}[/tex][tex]\begin{gathered} \text{Average Rate of change =}\frac{1.5}{2} \\ =\text{ 0.75 inch per month} \end{gathered}[/tex]

CONCLUSION:

The final answer = 0. 75 inch per month

write the point slope form of the equation of the line passing through the points ( -5, 6) and (0 , 1)

Answers

Let us find the slope first

[tex]\begin{gathered} m=\text{slope = }\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{1-6}{0+5} \\ m=-\frac{5}{5}=-1 \end{gathered}[/tex]

The equation can be found as follows using the points (0 ,1)

[tex]\begin{gathered} m=\frac{y-y_1}{x-x_1_{}_{}} \\ m=\frac{y-1}{x-0} \\ -1=\frac{y-1}{x} \\ -x=y-1 \\ y=-x+1 \end{gathered}[/tex]

please find amplitude period and phase shifty=sin(2x-pi/2)

Answers

For the sinusoidal function:

[tex]y=A\sin (Bx+C)+D[/tex]

we have that:

A represents the amplitude

2pi/B represents the Period

C is the phase shift

D is the vertical shift.

In this case, we have the following equation:

[tex]y=\sin (2x-\frac{\pi}{2})[/tex]

then, the amplitude is A = 1.

For the period, we have the following:

[tex]\begin{gathered} B=2 \\ \Rightarrow\frac{2\pi}{B}=\frac{2\pi}{2}=\pi=\text{Period} \\ \end{gathered}[/tex]

thus, the period is pi.

Finally, notice that C = -pi/2, thus, the phase shift is -pi/2

Is the LCD ( X + 2 ) and 3( X + 6) ?

Answers

To add 2 algebraic fractions we must make their denominators the same

Then we must have the LCM of both denominators

Since the denominators area (x + 2) and (3x + 6), then

We can take 3 as a common factor from the 2nd denominator

[tex]\begin{gathered} 3x+6=3(\frac{3x}{3}+\frac{6}{3}) \\ 3x+6=3(x+2) \end{gathered}[/tex]

Then the LCM of the 2 denominators is 3(x + 2)

Now we can change the first denominator to 3(x + 2) by multiplying up and down by 3

solving quadratic function by completing the squares

Answers

Consider the given equation,

[tex]-32=2(x^2+10)[/tex]

Apply the method of completing square as follows,

[tex]\begin{gathered} -32=2(x^2+2(x)(5)) \\ -32+50=2(x^2+2(x)(5))+2(25) \\ 18=2(x^2+2(x)(5)+25) \\ 18=2(x^2+2(x)(5)+(5)^2) \\ 18=2(x+5)^2 \\ \frac{18}{2}=(x+5)^2 \\ (x+5)^2=9 \\ x+5=\sqrt[]{9} \\ x+5=\pm3 \\ x+5=3\text{ }or\text{ }x+5=-3 \\ x=3-5\text{ }or\text{ }x=-3-5 \\ x=-2\text{ }or\text{ }x=-8 \end{gathered}[/tex]

Thus, the solutions of the quadratic equation are -2 and -8.

#3ItYour piggy bank is filled with coins!contains 27 quarters, 18 dimes, 11 nickels,and 124 pennies. You turn you bank upside-down and a coin falls out. What is theprobability the coin is worth less than 25¢?

Answers

Given data:

27 quarters (25¢)

18 dimes (10¢)

11 nickels (5¢)

124 pennies (1¢)

Total coins: 180

Coins that are less than 25¢: 27+18+11=56

Probability that the coin that falls out worths less than 25¢:

[tex]P(<25)=\frac{coins\text{ }<25}{total\text{ }coins}=\frac{56}{180}=\frac{14}{45}\approx0.311[/tex]Then, the probability that the coin that falls out worths less than 25¢ is 14/45 or approximately 0.311

COSEddQuestions9.75725 pes1Karina wants to solve the following quadratic equation by factoring154.r? – 25.1 +6=0She started the problem as shown below. Help her finish factoring, show all your steps, and solve for x,Show Your WorkCorrect answer

Answers

To factor the given equation, rewrite the middle terms as binomials.

[tex]4x^2-24x-x+6=0[/tex]

Group the terms and then factor out the common monomial from each group.

[tex]4x(x-6)-(x-6)=0[/tex]

Factor the common binomial factor.

[tex](4x-1)(x-6)=0[/tex]

Since the factored form of the expression at the left is

[tex](4x-1)(x-6)=0[/tex]

we may obtain the values inside the squares by multiplying the factors. We may use the FOIL method to obtain each term.

Thus, we get the following.

Product of the first terms:

[tex](4x)(x)=4x^2[/tex]

Product of the Outer Terms:

[tex](4x)(-6)=-24x[/tex]

Product of the Inner Terms:

[tex](-1)(x)=-x[/tex]

Product of the Last Terms:

[tex](-1)(-6)=6[/tex]

Thus, the terms inside the first figures should be -x and -24x, respectively.

Sari had 3/4 of a bag of pretzels. Her younger brother ate some, leaving her with 1/8 of a bag.What fraction of the bag did Sari's brother eat?M. 4/12P. 2/4R. 5/8S. 7/8

Answers

To solve this problem you have to subtract the remaining pretzels from the initial number of bags of pretzels.

Computing the subtraction, you get:

[tex]\frac{3}{4}-\frac{1}{8}=\frac{6}{8}-\frac{1}{8}.[/tex]

Simplifying the above result, you get:

[tex]\frac{5}{8}.[/tex]Answer: [tex]\frac{5}{8}.[/tex]

The perimeter of a square field is 292 yards. How long is each side

Answers

We know that the four side of a square are congruent, this means that

every side have the same length. Then, the perimeter (P) is given by

[tex]\begin{gathered} P=L+L+L+L=4L \\ or\text{ equivalenlty,} \\ P=4L \end{gathered}[/tex]

From the given information, we know that P= 292 yards. So we have

[tex]4L=292\text{ yd}[/tex]

Then, by dividing both sides by 4, we get

[tex]\begin{gathered} L=\frac{292}{4} \\ L=73 \end{gathered}[/tex]

Therefore, each side measures 73 yards

Answer:

73 yards

Step-by-step explanation:

292 divided by 4= 73

Please mark brainliest have a nice day

You are planning to rent a car for a road trip. Company A charges a base price of $56 plus a charge of 0.25 per mile. A competing car company, Company B, charges a base price of $45 plus a charge of $0.58 per mile,(a) Write a formula for the total cost Ca, of renting a car from Company A as a function of the number of miles, m: driven.(b) Write a formula for the total cost Cb , of renting a car from Company B as a function of the number of miles, m. driven.(c) At what mileage will the cost of renting a car be the same from both companies? Round decimal to two places.

Answers

Part a)

Since m is the number of miles driven and company A charges a base price of $56 plus a charge of $0.25 per mile, we can write the following equation:

[tex]Ca=56+0.25m[/tex]Part b)

Again, since m is the number of miles driven and company B charges a base price of $45 plus a charge of $0.58 per mile, we can write the following equation:

[tex]Cb=45+0.58m[/tex]Part c)

The cost of renting a car from both companies will be the same when:

[tex]Ca=Cb[/tex]

Then, we solve the following equation for m:

[tex]\begin{gathered} 56+0.25m=45+0.58m \\ \text{ Subtract 56 from both sides of the equation} \\ 56+0.25m-56=45+0.58m-56 \\ 0.25m=0.58m-10 \\ \text{ Subtract 0.58 m from both sides of the equation} \\ 0.25m-0.58m=0.58m-10-0.58m \\ -0.33m=-10 \\ \text{ Divide by 0.33 from both sides of the equation} \\ \frac{-0.33m}{-0.33}=\frac{-10}{-0.33} \\ m\approx33.33\Rightarrow\text{ The symbol }\approx\text{ is read "approximately"} \end{gathered}[/tex]

Therefore, the cost of renting a car from both companies will be the same at 33.33 miles.

Suppose a shoe factory produces both low- grade and high-grade shoes. the factory produces atleast twice as many low-grade as high-grade shoes. the maximum possible production is 500 pairs of shoes. A dealer calls for delivery of atleast 100 high-grade pairs of shoes per day. suppose the operation makes a profit of 2.00 dollars per a pair of shoes on high-grade shoes and 1.00 dollar per pairs of shoes on low-grade shoes. How many pairs of shoes of each type should be produced for maximum profit ?Let X denote the number of high-grade shoes. Let Y denote the number of low-grade shoes. Please be fast and Give all steps my teacher needs it after an hour so please give answers in 3o minutes.

Answers

I will write an equation for each statement

the factory produces atleast twice as many low-grade as high-grade shoes.

[tex]y\ge2x[/tex]

maximum possible production is 500 pairs of shoes.

[tex]\begin{gathered} x+y=500 \\ y=500-x \end{gathered}[/tex]

where x is the number of high-grade shoes and y the number of Low-grade shoes

and replace on the first equation

[tex]\begin{gathered} 500-x\ge2x \\ 500\ge2x+x \\ 500\ge3x \\ x\le\frac{500}{3}\approx166.66 \end{gathered}[/tex]

the value of x must be less than or equal to 166.6 but we must use whole numbers so it will be 166

now replace on

[tex]x+y=500[/tex]

to find y

[tex]\begin{gathered} 166+y=500 \\ y=500-166 \\ y=334 \end{gathered}[/tex]

suppose the operation makes a profit of 2.00 dollars per a pair of shoes on high-grade shoes and 1.00 dollar per pairs of shoes on low-grade shoes.

[tex]2x+y=P[/tex]

where P is the profit

and replce x and y to find the value of the profit

[tex]\begin{gathered} P=2(166)+334 \\ P=332+334 \\ p=666 \end{gathered}[/tex]

The maximun profit must be $666

GameStop sells used games the games are usually $60 but are on sale for 15% off what is the percent decrease between the original and sale price for the game

Answers

Percentage decrease in price

Original price = $60

Find 15% of 60

Then

10% of 60 is $6

5% of 60 is $6/2 = $3

In consecuence 15% of $60 is 6+3 = $9

Then precent decrease in price is $9

And New price is 60-9 = $51

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