Which of the following angle relationships in △ABC are correct? Select all that apply. There is a triangle ABC in which the length of side AB is 3.1, the length of side BC is 3, and the length of side AC is 2.9.
A. m∠A < m∠C B. m∠B = m∠C C. m∠A < m∠B D. m∠B < m∠A < m∠C

Answer: See explanation

Step-by-step explanation:

Your question isn't complete but I guess that you want to find the population of the cats in Year 1. This will be represented by x. Therefore,

x + (25% × x) = 60

x + (0.25 × x) = 60

x + 0.25x = 60

1.25x = 60

x = 60/1.25

x = 48

The population of cats in year 1 is 48

In order to get an unbiased sample of interest in soccer, the school survey should be conducted D. every fifth student entering the cafeteria.

Sampling methods are methods used to select a sample using specific methods. This includes various types of probability sampling and non probability sampling methods.

Given that,

Brookwood High School is considering adding co-ed soccer to the sports program for the fall season.

We need to get an unbiased sample of interest.

If the survey is conducted only among the members of the soccer team, the result will be biases because only the interest of someone in the team is known.

Similarly, in the case of students in freshman homerooms and girls in PE class.

If we select every fifth student entering the cafeteria, there is a chance for all the levels of students to be included which eliminates the possible bias.

Hence the option is D.

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Answer:

y = 1/2x + 3

Step-by-step explanation:

Rise/Run and since y = 3 when x = 0, then the b part in y = mx + b is 3.

Answer:

[tex]\sqrt{61}[/tex]

Step-by-step explanation:

x = 6 units horizontally

y = 5 units vertically

Use the pythagorean theorem[tex]\sqrt{x^{2} + y^{2} } = L[/tex]

Plug x and y into the equation, and you will get [tex]\sqrt{61}[/tex] as the length.

Answer:

7.8 units (which is to the nearest tenth)

Step-by-step explanation:

We apply the Pythagorean Theorem here; the length of the line is the length of the hypotenuse of a triangle whose horizontal leg length is 6 and whose vertical leg length is 5 units.  This Theorem is expressed symbolically as

a^2 + b^2 = c^2.  In this particular case, a = 6, b = 5 and c is to be determined.  Performing the calculations, we get

6^2 + 5^2 = c^2, or:

36 + 25 = 61 = c^2

Taking the positive square root of both sides, we get c = √61 ) exactly,

which rounds off to 7.8 units (to the nearest tenth).

The length of the line is 7.8 units.

Answer:

The "middle triangle"

50+85+n=180

n+135=180

n=45

The "left side triangle"

x+68+45=180

x=67

The "right-side triangle"

50+74+z=180

124+z=180

z=56

y=180-56

y=124

Let me know if this helps!

Answer:

x^2 - 5x - 6  =  (x - 2)(x - 3).

Step-by-step explanation:

f(x) = x^2 - 5x - 6

We need 2 numbers whose product is - 6 and whose sum is -5. They are   -3 and -2:

The factors are x- 2  and x - 3.

Answer:

x-6  

Step-by-step explanation:

Answer:

A bird drops a stick to the ground from a height of 80 feet. The equation 0=−16x2+64x+80 gives the number of seconds that have passed when it hits the ground. After about how many seconds did the stick hit the ground?

Step-by-step explanation:

h = -16t^2 + 80   Stick hits the ground when h = 0:

0 = -16t^2 + 80    

16t^2 = 80

t^2 = 80/16 = 5

t = POSITIVE root 5 (due to the real world nature of the problem)

t approximately 2.236 seconds.

========================================

Graph is a downward opening parabola with h-intercept of 80, t-intercept(s) of sqrt(5), - sqrt(5)

Symmetric about h-axis, though I would only graph on the right side of the h-axis since  

that is where t >= 0.

Answer:

increase

Step-by-step explanation:

Increase definition: become or make greater in size, amount, intensity, or degree.

Decrease definition: make or become smaller or fewer in size, amount, intensity, or degree.

Answer:

Step-by-step explanation:

The prime factorization of 200 is as follows: 200 = 2 × 2 × 2 × 5 × 5.

The prime factorization of 200 will be equal to 2 × 2 × 2 ×  5 × 5 or 2³ × 5².

It is given that a number is 200.

We have to find out the prime factorization of 200.

What do you mean by prime factorization ?

Prime factorization is a way to find the prime factors of a number, such that the original number is evenly divisible by the prime numbers.

As per the question ;

The given number is 200.

We have to find the prime factors of 200.

This meant to find out the prime numbers we should multiply together to make the original number which is 200.

So ;

200

= 2 × 100

= 2 × 2 × 50

= 2 × 2 × 5 × 10

= 2 × 2 × 2 ×  5 × 5

or

= 2³ × 5²

Thus , the prime factorization of 200 will be equal to 2 × 2 × 2 ×  5 × 5 or 2³ × 5².

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Answer:

[tex]x->-2^{-}, p(x)->-\infty[/tex] and as [tex]x->-2^{+}, p(x)->-\infty[/tex]

Step-by-step explanation:

Given

[tex]p(x) = \frac{x^2-2x-3}{x+2}[/tex] -- Missing from the question

Required

The behavior of the function around its vertical asymptote at [tex]x = -2[/tex]

[tex]p(x) = \frac{x^2-2x-3}{x+2}[/tex]

Expand the numerator

[tex]p(x) = \frac{x^2 + x -3x - 3}{x+2}[/tex]

Factorize

[tex]p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}[/tex]

Factor out x + 1

[tex]p(x) = \frac{(x -3)(x + 1)}{x+2}[/tex]

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

[tex]x -> -2^{-}[/tex] Say x = -3

[tex]p(x) = \frac{(x -3)(x + 1)}{x+2}[/tex]

[tex]p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12[/tex]

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

[tex]x->-2^{-}, p(x)->-\infty[/tex]

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: [tex]x>-2[/tex]

Say x = -2.1

[tex]p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1[/tex]

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

[tex]x->-2^{+}, p(x)->-\infty[/tex]

So, the behavior is:

[tex]x->-2^{-}, p(x)->-\infty[/tex] and as [tex]x->-2^{+}, p(x)->-\infty[/tex]

Answer:

that's The truth

Step-by-step explanation:

that's more like a trade

Answer:

14in approx

Step-by-step explanation:

Given data

number of rotations= 10

Distance travelled=  879.2 inches

Hence if in 10 rotations the distance covered is  879.2 inches

               in 1 rotation the distance covered will be x inches

cross multiply

10x= 879.2

x=  879.2/10

x=  87.92 inches

This means that the circumference of the  tire is 87.92 in

From

C= 2πr

Let us solve for r

87.92=2*3.142*r

87.92=6.284r

r= 87.92/6.284

r= 13.9

Hence the radius is 14in approx

Answer:

The answer is b

Step-by-step explanation:

The formula for the surface area of rectangular prisms is

A=2(wl+hl+hw)

Now input the length width and hight into the right spots

=2*(2*6.6+3.3*6.6+3.3*2)

And you will end up with the answer

=83.16

Step-by-step explanation:

jeuejejejejejnenenenennens

Answer:h=16+2+vt +s

Step-by-step explanation:

Answer:

correct

Step-by-step explanation:

maybe

The area of the rectangle is 3[tex]\sqrt{56}[/tex]

Given,

A rectangle has a length of √7 and a width of 3√8.

We need to find the area of the rectangle.

The area is given by:

Area = Length x width

Find the length and width of a rectangle.

Length = [tex]\sqrt{7}[/tex]

Width = 3[tex]\sqrt{8}[/tex]

Find the area of the rectangle.

Area =  Length x width

       = [tex]\sqrt{7}[/tex] x 3[tex]\sqrt{8}[/tex]

When there are two different square roots we multiply them together under one root.

[tex]\sqrt{a\times b} ~~=~~\sqrt{a}\times\sqrt{b}[/tex]

Now,

       = 3[tex]\sqrt{7\times8}[/tex]

       = 3[tex]\sqrt{56}[/tex]

Thus the area of the rectangle is 3[tex]\sqrt{56}[/tex]

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Step-by-step explanation:

nth term = 1 - 5n

6th term = 1 - 5(6)

= 1 - 30

= - 29

Answer:

3:1

Step-by-step explanation:

Answer:

The simplest form of 279 is 31.

Step-by-step explanation:

Hope this helps

Answer:

the awnser is 10 and 1/x+ 1/y is = 5/12

Answer:

1 ) 140

2) 60

Step-by-step explanation:

1. It touches the y intercept at 140 and 0 in the x axis so 140

NOTE : THE NUMBER THE TOUCHES THE Y INTERCCEPT IS ALWAYS THE ANSWER/ IT GOES DOWN 3 ACROSS 3 SO IT AND U WILL SEE IF IT TOUCHES THE Y INTERCEPT IT WILL BE 140

2. it goes from 140 to 200 just subtract them to get how much she gets

Please mark as brainliest

Have a great day, be safe and healthy

Thank u  

XD

Answer:

2.74 Seconds

Step-by-step explanation:

-16t²+120=0

-16t²=-120

t²=7.5

t=2.74

Answer:

The answer is below

Step-by-step explanation:

Two triangles are congruent if they have the same shape and their corresponding sides are equal to each other.

1) AB = DC, BE = CE     (given)

2) ∠AEB≅∠DEC  (vertical angles are congruent)

3) ΔABE ≅ ΔACE (side angle side congruence theorem)

If the two sides and an included angle of one triangle is equal to two sides and one included angle of another triangle, then the two triangles are congruent by SAS congruence theorem.

Answer:

The first derivative of [tex]y = \sqrt{\frac{1-x}{1+x} }[/tex] is [tex]y' = -\frac{1}{(1-x)\cdot (1+x)^{3/2}}[/tex].

Step-by-step explanation:

Let [tex]y = \sqrt{\frac{1-x}{1+x} }[/tex]. we can determine its first derivative by Rule for the Square Root Function, Rule for Power Function, Rule of Chain and Rule for the Addition of Functions, Rule for the Subtraction of Functions, Rule for the Division of Functions:

[tex]y' = \frac{1}{2\cdot \sqrt{\frac{1-x}{1+x} }}\cdot \frac{(-1)\cdot (1+x)-(1)\cdot (1-x)}{(1+x)^{2}}[/tex]

[tex]y' = \frac{1}{2}\cdot \sqrt{\frac{1+x}{1-x} }\cdot \left[\frac{-1-x-1+x}{(1+x)^{2}} \right][/tex]

[tex]y' = \frac{1}{2}\cdot \sqrt{\frac{1+x}{1-x} } \cdot \left[-\frac{2}{(1+x)^{2}} \right][/tex]

[tex]y' = -\frac{1}{(1-x)\cdot (1+x)^{3/2}}[/tex]

The first derivative of [tex]y = \sqrt{\frac{1-x}{1+x} }[/tex] is [tex]y' = -\frac{1}{(1-x)\cdot (1+x)^{3/2}}[/tex].