Which of the following are not polynomials?​

Answer:

The correct statements are:

1: mEFD = mEGD

3: mED = mFD

5: mFD = 120°

Step-by-step explanation:

Let's analyse each statement:

1: mEFD = mEGD

Let's find the value of the angle ECD, using the sum of the internal angles of a quadrilateral:

[tex]60 + 90 + 90 + mECD = 360[/tex]

[tex]mECD = 120\°[/tex]

The angle ECD is a central angle, related to the arc ED, so the arc ED also has 120°.

The angle EFD inscribes the arc ED, so we have:

[tex]mEFD = mED/2[/tex]

[tex]mEFD = 120/2 = 60\°[/tex]

So the angles mEFD and mEGD are equal. The statement is TRUE.

2. mEGD = mECD

This statement is FALSE, because mEGD = 60° and mECD = 120°

3. mED = mFD

If mED is 120° and mEF = mFD, we have:

[tex]mED + mEF + mFD = 360[/tex]

[tex]2*mFD = 360 - 120[/tex]

[tex]mFD = 120\°[/tex]

So the statement is TRUE, both arcs have 120°.

4. mEF = 60°

This statement is FALSE, because we calculated before that mEF = mFD = 120°

5. mFD = 120°

This statemente is TRUE, because we calculated before that mFD = 120°.

So the correct statements are 1, 3 and 5

The true statements are: [tex]\angle EFD =\angle EGD[/tex], [tex]\overset{\huge\frown}{FD} = \overset{\huge\frown}{ED}[/tex] and [tex]\overset{\huge\frown}{FD} =120[/tex]

Start by calculating the measure of angle ECD.

We have:

[tex]\angle ECD = 2 * \angle EGD[/tex]

So, we have:

[tex]\angle ECD = 2 * 60[/tex]

[tex]\angle ECD = 120[/tex]

The above means that:

[tex]\overset{\huge\frown}{ED} = 120[/tex]

So, the measure of angle EFD is:

[tex]\angle EFD = 0.5 * \overset{\huge\frown}{ED}[/tex]

[tex]\angle EFD = 0.5 * 120[/tex]

[tex]\angle EFD = 60[/tex]

From the question, we have:

[tex]\angle EGD = 60[/tex]

So, it is true that:

[tex]\angle EFD =\angle EGD[/tex]

To calculate the measure of arc FD, we have:

[tex]\overset{\huge\frown}{FD} + \overset{\huge\frown}{DE} + \overset{\huge\frown}{EF} =360[/tex]

Lengths EF and DE are congruent.

So, we have:

[tex]2\overset{\huge\frown}{FD} + \overset{\huge\frown}{DE} =360[/tex]

[tex]\overset{\huge\frown}{DE} = \overset{\huge\frown}{ED} = 120[/tex]

So, we have:

[tex]2\overset{\huge\frown}{FD} + 120 =360[/tex]

Divide through by 2

[tex]\overset{\huge\frown}{FD} + 60 =180[/tex]

Subtract 60 from both sides

[tex]\overset{\huge\frown}{FD} =120[/tex]

This means that:

[tex]\overset{\huge\frown}{FD} = \overset{\huge\frown}{ED}[/tex] and [tex]\overset{\huge\frown}{FD} =120[/tex] are true

Hence, the true statements are: [tex]\angle EFD =\angle EGD[/tex], [tex]\overset{\huge\frown}{FD} = \overset{\huge\frown}{ED}[/tex] and [tex]\overset{\huge\frown}{FD} =120[/tex]

Read more about cyclic theorems at:

https://brainly.com/question/26168678

Answer:

1/8

Step-by-step explanation:

There are 3 + 3 + 6 = 12 marbles in the bag and 12 * 12 = 144 ways to choose two marbles when replacing. There are 3 * 6 = 18 ways to choose a red marble and then a blue marble so the probability is 18 / 144 = 1 / 8.

Answer:

As x increases, the rate of change of f(x) exceeds the rate of change of g(x).

Step-by-step explanation:

Hope this helps :)

Answer:

Pythagorean Theorem: a² + b² = c² should be used.

Step-by-step explanation:

51² + b² = 60²

b² = 60² - 51²

b = 3√111

b = 31.607

Pythagorean Theorem is used to find any missing side of a right triangle if 2 other sides are present.

Answer:

Pythagoras theorem

EXPLANATION

HYPOTHENUS SQUARE =OPPOSITE SQUARE + ADJACENT SQUARE

i.e 60^2= 51^2+x^2

i.e 3600=2601+x^2

collecting like terms we have

3600-2601=x^2

999=x^2

√999=x

x=31.6

Answer:

A

Step-by-step explanation:

The zeroes of the function are the x values when f(x) = 0 so we can write:

0 = x² + x - 30

0 = (x + 6)(x - 5) (To factor this we need to find 2 numbers that have a sum of 1 and a product of -30; these numbers are 6 and -5)

x + 6 = 0 or x - 5 = 0 (Use Zero Product Property)

x = -6, 5

Hey there! :)

Answer:

A. x = -6 and x = 5.

Step-by-step explanation:

Given:

f(x) = x² + x - 30

Factor the equation by finding two numbers that sum up to 1 and multiply into -30. We get:

-5, 6

Use these to express this quadratic function in factored form:

f(x) = (x - 5) (x + 6)

Set each factor equal to 0 to solve for the zeros of the equation:

0 = x - 5

x = 5

-------------

0 = x + 6

x = -6

Therefore, the correct answer is A. x = -6 and x = 5.

Answer:

radius

Step-by-step explanation:

That "fixed distance" is the 'radius' of the circle.

Answer:

41°

Step-by-step explanation:

First note that m arc BC = m∠BZC

The reason is because a central angle of a circle is always congruent to its

intercepted arc.

Also m∠BAC is one-half m arc BC, as the measure of an inscribed angle is half the measure of its intercepted arc.

Hence, the calculation is given below:

m∠BZC = 82°

m arc BC = m∠BZC

m arc BC = 82°

m∠BAC = 1/2 × 82°

m∠BAC = 41°

It is important to note that

∠DCA ≅ ∠BAC because alternate interior angles are congruent.

So m∠DCA = m∠BAC.

Therefore, m∠DCA = 41°.

Answer:

The length of the missing segment is 36

Step-by-step explanation:

Given

The figure above

Required

Determine the missing segment

Let the missing segment be represented with x

Given that, there exist parallel lines between the two triangles;

The relationship between the sides of the triangles is as follows;

[tex]\frac{20}{24} = \frac{30+20}{24+x}[/tex]

[tex]\frac{20}{24} = \frac{50}{24+x}[/tex]

Cross Multiply

[tex]20 * (24 + x) = 24 * 50[/tex]

[tex]20 * (24 + x) = 1200[/tex]

Divide both sides by 20

[tex]\frac{20 * (24 + x)}{20} = \frac{1200}{20}[/tex]

[tex](24 + x)= \frac{1200}{20}[/tex]

[tex]24 + x= 60[/tex]

Subtract 24 from both sides

[tex]24 - 24 + x = 60 - 24[/tex]

[tex]x = 60 - 24[/tex]

[tex]x = 36[/tex]

Hence, the length of the missing segment is 36

Answer:

a) x = 128 degrees

b) Angle APD is the arc angle, which is equal to the central angle x subtended by the arc.  Therefore angle APD = 128 degrees (and not 116 degrees)

Step-by-step explanation:

Given:

attached diagram

ABC is a straight line

Solution:

a) Find x

ABC is a straight line

angle ABD = supplement of CBD = 180-CBD = 180-116 = 64 degrees.

x is the central angle of the arc APD

so angle ABD is the inscribed angle which equals half of the arc angle =>

angle ABD = x/2 = 64 degrees

Solve for x

x/2 = 64

x = 2*64

x = 128 degrees

b.

Angle APD is the arc angle, which is equal to the central angle x subtended by the arc.  Therefore angle APD = 128 degrees (and not 116 degrees)

Answer:

the equation of the line in slope-intercept form is;

[tex]y=8x-26[/tex]

Step-by-step explanation:

First use the formula for the slope of the segment that joins the two given points:

[tex]slope=\frac{y_2-y_1}{x_2-x_1} =\frac{6-(-2)}{4-3}=\frac{8}{1} =8[/tex]

now that we have the slope, we can use the point-slope form of a line to find the line with slope 8 that passes through any of the given points, for example through (3, -2):

[tex]y-y_0=m\,(x-x_0)\\y-(-2)=8\,(x-3)\\y+2=8\,(x-3)\\y=8x-24-2\\y=8x-26[/tex]

Answer:

C

Step-by-step explanation:

It is an iscoceles triangle because there are 180 degrees in a triangle and the right angle plus the 45 degree equals 135 and 180 minus 135 is 45.

Since it is an iscoceles triangle that means that n = 3 and the pythagorean theorom says that a^2 + b^2 = c^2 which means that m = 3^2 plus 3^2 with a root.

3^2 is 9 so you get 18

the root of 18 is infinite, however can be simplified to 3 root to 2 because 3 times 3 equals 9 times 2 equals a root of 18

Hope this helps!

Answer:

Step-by-step explanation:

x=✓64*36=✓8^2*6^2

x=8*6

x=48

Answer: draw a straight line trough point B, same thing with the second one,for the third you must draw a straight line from the angle across to the segment. (make sure all of the intersections are 90 degrees

Answer:

x = 3

Inverse matrix:

[tex]A^{-1} = \begin{pmatrix} \frac{1}{9} & \frac{2}{9} \\ \frac{1}{3} & -\frac{1}{3} \end{pmatrix} \quad[/tex]

Step-by-step explanation:

Determinant: ad - bc

a = 3, b = 2, c = 3, d = -1

3 * (-1) - (2 * x) = -9

-3 - 2x = -9

-2x = -6

x = 3

For matrix

[tex]A = \begin{pmatrix}a & b\\c & d\end{pmatrix} \quad[/tex]

the inverse is

[tex]A^{-1} = \dfrac{1}{ad - bc}\begin{pmatrix}d & -b \\-c & a\end{pmatrix}\quad[/tex]

Here we have: det = -9

a = 3, b = 2, c = 3, d = -1

Inverse matrix:

[tex]A^{-1} = \dfrac{1}{-9}\begin{pmatrix} -1 & -2 \\ -3 & 3 \end{pmatrix}\quad[/tex]

[tex]A^{-1} = \begin{pmatrix} \frac{-1}{-9} & \frac{-2}{-9} \\\frac{-3}{-9} & \frac{3}{-9}\end{pmatrix} \quad[/tex]

[tex]A^{-1} = \begin{pmatrix} \frac{1}{9} & \frac{2}{9} \\\frac{1}{3} & -\frac{1}{3}\end{pmatrix}\quad[/tex]

Answer:

Simplifying

41 = 12d + -7

Reorder the terms:

41 = -7 + 12d

Solving

41 = -7 + 12d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-12d' to each side of the equation.

41 + -12d = -7 + 12d + -12d

Combine like terms: 12d + -12d = 0

41 + -12d = -7 + 0

41 + -12d = -7

Add '-41' to each side of the equation.

41 + -41 + -12d = -7 + -41

Combine like terms: 41 + -41 = 0

0 + -12d = -7 + -41

-12d = -7 + -41

Combine like terms: -7 + -41 = -48

-12d = -48

Divide each side by '-12'.

d = 4

Simplifying

d = 4

Answer:

125.6 cubed inches

Step-by-step explanation:

1. 3.14(2)^2(10) - Multiply 3.14 with 2 squared and 10.

2. First find out what is 2 squared, which is 4. Then, multiply 4 with 3.14, which is 12.56.

3. Now, multiply 12.56 with 10 or just move the decimal point one place to the right, which gives you 125.6 cubed inches.

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Quadrilaterals.

Basically we know that, the sum of opposite angles of a quadrilateral inscribed in a circle is always 180°.

so applying this law here, we get as,

2X + (3X-10) = 180°

=> 5X - 10° = 180°

=> 5X = 190°

=> X = 190°/5

=> X = 38°

thus the angle X= 38°.

Answer:

(5a^2-4)*(25a^4+20a^2+16)

Step-by-step explanation:

Answer:

Its B, (5a^2-4)(25a^4+20a^2+16)

Step-by-step explanation:

Edge 2020

Answer:

Greater than the original = 2, 4

Less than the original = 5

Same as the original = 1, 3

Step-by-step explanation:

Let the original value be x.

1. A $30 increase followed by a $30 decrease.

New value [tex]=x+30-30=x[/tex], it is same as original value.

2. A 20% decrease followed by a 40% increase.

Afer 20% decrease.

New value [tex]=x-\dfrac{20}{100}x=x-0.2x=0.8x[/tex]

Afer 40% increase.

New value [tex]=0.8x+\dfrac{40}{100}(0.8x)=0.8x+0.32x=1.12x[/tex], it is greater than original value.

Similarly check the other values.

3. A 100% increase followed by a 50% decrease.

New value [tex]=x+\dfrac{100}{100}x-\dfrac{50}{100}(x+x)=x[/tex], it is same as original value.

4. A 75% increase followed by a 33% decrease

New value [tex]=x+\dfrac{75}{100}x-\dfrac{33}{100}(x+0.75x)=1.1725x[/tex], it is greater than the original value.

5. 55% decrease followed by a 25% increase

New value [tex]=x-\dfrac{55}{100}x+\dfrac{25}{100}(x-0.55x)=0.5625x[/tex], it is less than the original value.

Therefore, Greater than the original = 2, 4, Less than the original = 5, Same as the original = 1, 3 .

A 100% increase followed by a 50% decrease

A $30 increase followed by a $30 decrease

55% decrease followed by a 25% increase

A 20% decrease followed by a 40% increase

A 75% increase followed by a 33 1/3% decrease

Answer:

the amount of fuel consumed every 100 kilometers is 62.5 litres.

Step-by-step explanation:

To determine the amount of fuel consumed every 100 kilometers.

Note: since the graph is a straight line graph (linear graph) the amount of fuel consumed every 100 kilometers is constant (i.e the same for every 100 kilometers). So, we only need to derive the amount of fuel consumed any 100 kilometers on the graph.

From the graph, the amount of fuel consumed for the first 100 kilometers is;

[tex]F = F_0 - F_{100} .........................1[/tex]

[tex]F_0 = 500\\F_{100} \simeq 437.5\\[/tex]

substituting into equation 1.

[tex]F = F_0 - F_{100} \\F = 500 - 437.5\\ F = 62.5 litres\\[/tex]

Therefore, the amount of fuel consumed every 100 kilometers is 62.5 litres.

Answer:500

Step-by-step explanation:got it on Kahn

Answer:

\frac{2\cot \left(-240^{\circ \:}\right)\cos \left(-1050^{\circ \:}\right)-\cot ^2\left(50^{\circ \:}\right)}{\sec ^2\left(40^{\circ \:}\right)}

Step-by-step explanation:

ok

Answer:

Step-by-step explanation:

5. cut the five fruits into 3 equal parts....

5x3=15 pieces

15/3(bowls)=5 pieces in each bowl

cut the fruits in multiples of 5 divisible by 3....that many ways possible

(similarly 4th qstion can be done)!!

Answer:

25/18

Step-by-step explanation:

Additive inverse of a number X is the number which when is added to X =0

ex: additive inverse of 2 is -2 since 2 +(-2)=0

Multiplicative inverse of a number N is the number which when multiplied by N gives 1

ex: multiplicative inverse of 6/7 is 7/6

6/7*7/6=1

Ex of reciprocal is

5/9 & 9/5

7/6 & 6/7

Additive inverse of -5/6=5/6

Multiplicative inverse of 4/12 is 12/4

Reciprocal of 9/5 is 5/9

(5/6)*(12/4)*(5/9)=25/18

Answer:

(5/6)*(12/4)*(5/9)=25/18

Step-by-step explanation:

Answer:

20 units

Step-by-step explanation:

The perimeter of a rectangle is

P = 2(l+w)

P = 2( 3x+2 + 4x)

Adding like terms

P = 2( 7x+2)

We know the perimeter is 74 units

74 = 2 ( 7x+2)

Divide by 2

74/2 = 2/2 (7x+2)

37 = 7x+2

Subtract 2 from each side

37-2 = 7x+2-2

35 = 7x

Divide by 7

35/7 = 7x/7

5 =x

We want to find the length RS = PQ = 4x

RS = 4x = 4*5 = 20

The number of possible outcomes there could be at the end of their game is 6 outcomes

This is a permutation problem since it required arrangement

If Alex, Toby, and Samuel are playing a game together and at the end, they will make a classification with one of them in first  place, one of them in Second place and one of them in Third place, this can be done in 3! ways

Since n! = n(n-1)(n-2)!

Hence 3! = 3(3-1)(3-2)

3! = 3 * 2 * 1

3! = 6 ways

Hence the number of possible outcomes there could be at the end of their game is 6 outcomes

Learn more here: https://brainly.com/question/24115376

Answer:

a) 8

b) 2 1/4 hours

c) 4 7/8 hours

d) 4 1/8 hours

Step-by-step explanation:

a) LCD to be used to solve this problem is calculated as the Lowest common denominator of the above mixed fractions.

We have 1 1/2 hours and 1 1/8 hours

The lowest common denominator is the denominator calculated by

Multiplying the two denominators together and dividing by the common factor of the two denominators

Hence , we have

2 × 8 = 16

The common factor of 2 and 8 = 2

LCD = 16/2 = 8

b) How long did Matt drive?

We are told that Matt drove twice as long as John

John drove for 1 1/8 hours

Hence, the number of hours that Matt drove for =2 × 1 1/8

= 2 × 9/8 = 9/4 hours = 2 1/4 hours

c) How long the Sam, John and Matt drive ?

We are told in the question that

Sam drove for 1 1/2 hours

John drove for 1 1/8 hours

Matt drove for 2 1/4 hours

We would sum up the number of hours that each of them drove.

1 1/2 + 1 1/8 + 2 1/4

The Lowest common multiple of denominators is 8

= (1 + 1 + 2)( 4 + 1 +2/8)

= 4(7/8)

= 4 7/8 hours

d) How many hours is left for Bob to drive

We are told that the entire journey = 9 hours

The number of hours Sam, John and Matt drove for has been calculated in question c as 4 7/8 hours

The number of hours Bob will drive for is calculated as

9 hours - 4 7/8 hours

= 4 1/8 hours

Answer:

A. 41

Step-by-step explanation:

5a - b² + 2c(a-b)

Put a = 2, b = -3, and c = 4.

5(2) - (-3)² + 2(4)(2-(-3))

Evaluate.

10 - 9 + 2(4)(2+3)

10 - 9 + 8(5)

10 - 9 + 40

1 + 40

= 41

Answer:

[tex]41[/tex]

Step-by-step explanation:

Given that,

[tex]a = 2 \\ b = - 3 \\ c = 4[/tex]

Let's solve now,

[tex]5a - {b}^{2} + 2c(a - b) \\ 5 \times 2 - ( { - 3}^{2} ) + 2 \times 4(2 - ( - 3)) \\ 10 - ( - 3 \times - 3) + 8(2 + 3) \\ 10 - 9 + 8 \times 5 \\ 10 - 9 + 40 \\ 1 + 40 \\ = 41[/tex]

Answer:

5/3

Step-by-step explanation:

it should be y/x

you can count 5 up and 3 over

Answer:

8/5

Step-by-step explanation:

You can use the formula [tex]\frac{y_{1}-y_{2}}{x_{1}-x_{2}}[/tex] with a pair of points [tex](x_{1},y_{1})[/tex][tex](x_{2},y_{2})[/tex]. We can use points (1,4) and (-4,-4). Plugging in the equation we get (4-(-4))/(1-(-4)), which simplifies to 8/5, which is the slope.

Answer:

B) 128.3 square yards

Step-by-step explanation:

A = (n/360 deg)(pi)r^2

where n = central angle of sector.

A = (75/360)(3.14159)(14 yd)^2

A = 128.3 yd^2

Answer:

B. 128.3 yards

Step-by-step explanation:

Area of a Sector Formula: A = ∅/360πr²

Simply plug in our variables:

A = 75/360(π)(14)²

A = 5π/24(196

A = 128.3

Answer:

[tex]m = 5 \sqrt{3}[/tex]

[tex]n = 5[/tex]

Step-by-step explanation:

Given

The triangle above

Required

Find the missing lengths

The missing lengths can be calculated by applying trigonometry ratios

From the triangle above,

the Hypotenuse is 10

Angle = 60

Calculating m

The relationship between m, the Hypotenuse and angle 60 is defined as follows;

[tex]sin \theta = \frac{Opp}{Hyp}[/tex]

Where [tex]\theta = 60[/tex]

[tex]Opp = m[/tex]

[tex]Hyp = 10[/tex]

The above formula becomes

[tex]sin60= \frac{m}{10}[/tex]

Multiply both sides by 10

[tex]10 * sin60= \frac{m}{10} * 10[/tex]

[tex]10 * sin60= m[/tex]

In radical from, [tex]sin60 = \frac{\sqrt{3}}{2}[/tex]

[tex]10 * sin60= m[/tex] becomes

[tex]10 * \frac{\sqrt{3}}{2}= m[/tex]

[tex]\frac{10* \sqrt{3}}{2}= m[/tex]

[tex]5 \sqrt{3}= m[/tex]

[tex]m = 5 \sqrt{3}[/tex]

Calculating n

The relationship between n, the Hypotenuse and angle 60 is defined as follows;

[tex]cos\theta = \frac{Adj}{Hyp}[/tex]

Where [tex]\theta = 60[/tex]

[tex]Adj = n[/tex]

[tex]Hyp = 10[/tex]

The above formula becomes

[tex]cos60= \frac{n}{10}[/tex]

Multiply both sides by 10

[tex]10 * cos60= \frac{n}{10} * 10[/tex]

[tex]10 * cos60= n[/tex]

In radical from, [tex]cos60= \frac{1}{2}[/tex]

[tex]10 * cos60= n[/tex] becomes

[tex]10 * \frac{1}{2}= n[/tex]

[tex]\frac{10*1}{2}= n[/tex]

[tex]5 = n[/tex]

[tex]n = 5[/tex]