the wheels of a powerful motorcycle can accelerate from rest to 72.0 rad/s in only 3.60 s. what is the average angukar acceleration
The average angular acceleration is 20 rad/s².
The issue is how quickly the wheels of a powerful motorcycle can accelerate from rest to 72.0 rad/s in 3.60 seconds. The following formula can be used to determine the wheels' average angular acceleration:
(Final angular velocity - Initial angular velocity) / time taken = Average angular acceleration
Here, the wheels begin at rest with a starting angular velocity of 0 rad/s, and the ultimate angular velocity is 72.0 rad/s. The time required is 3.60 seconds.
Thus, the wheels' average angular acceleration can be determined as follows:
(20.0 rad/s2) = (72.0 rad/s - 0 rad/s) / 3.60 s
As a result, the wheels' average angular acceleration is 20.0 rad/s². In each second of the acceleration period, the wheels of the motorcycle gain an average angular velocity of 20.0 radians per second.
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A car with a mass of 1000 kg is traveling east at 4 m/s. Another car with a mass of 500 kg is traveling west at a speed of 3 m/s. The two cars collide. After the collision, the 1000 kg car has a velocity of 1 m/s east. What is the velocity of the 500 kg car after the collision?
Answer: the velocity of the 500 kg car after the collision is 3 m/s to the east.
Explanation:
Initial momentum = (mass of car 1 x velocity of car 1) + (mass of car 2 x velocity of car 2)
Initial momentum = (1000 kg x 4 m/s) + (500 kg x -3 m/s) (Note that we use a negative velocity for car 2 because it is traveling in the opposite direction)
Initial momentum = 4000 kg m/s - 1500 kg m/s = 2500 kg m/s
After the collision, the total mass and total momentum of the system remain the same.
Final momentum = (mass of car 1 x velocity of car 1) + (mass of car 2 x velocity of car 2)
Final momentum = (1000 kg x 1 m/s) + (500 kg x v) (where v is the velocity of the 500 kg car after the collision)
Final momentum = 1000 kg m/s + 500v
Since the total momentum is conserved, we can set the initial momentum equal to the final momentum:
Initial momentum = Final momentum
2500 kg m/s = 1000 kg m/s + 500v
Solving for v, we get:
v = (2500 kg m/s - 1000 kg m/s) / 500 kg
v = 3 m/s
??
a 650 nm laser shines through a diffraction grating. the first bright band is 0.54 m from the center. another laser is only deflected to 0.42 m from the center. what is the wavelength of this light?
The second laser has a wavelength of around 835.71 nm.
What is the diffraction grating's level formula?N = 1/ d, where d is the grating spacing, is the number of slits per metre on the grating. At a given order and wavelength, the angle of diffraction rises as d value falls. In other words, as the number of slits per metre grows, so does the angle of diffraction.
d sinθ = mλ
sinθ₁ = (0.54 m) / d
For the second laser, m = 1 again and the distance from the center is 0.42 m. We can solve for sinθ₂:
sinθ₂ = (0.42 m) / d
Since the spacing of the diffraction grating is the same for both lasers, we can set the two equations equal to each other and solve for λ:
d sinθ₁ = d sinθ₂
(0.54 m) / λ = (0.42 m) / λ
Simplifying, we get:
λ = (0.54 m * 650 nm) / 0.42 m
λ = 835.71 nm
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Question:
A laser with a wavelength of 650 nm shines through a diffraction grating. The first bright band is observed at a distance of 0.54 m from the center. Another laser is shone through the same grating and is deflected to a distance of 0.42 m from the center. What is the wavelength of the second laser?
what focal length of corrective lens should this person use to make the far point distance infinite?
To determine the focal length of a corrective lens required to make the far point distance infinite, we need to follow these steps:
1) Measure the person's far point distance: This can be done by having the person read letters on an eye chart or by using a refractometer.
Let's assume the person's far point distance is 3 meters.
2) Determine the person's current corrective lens prescription: If the person already wears corrective lenses, their current prescription can be used to calculate the required focal length of the corrective lens.
If they do not wear corrective lenses, this step can be skipped.
3) calculate the person's current refractive error: This can be done by subtracting the measured far point distance from infinity (1/∞) and converting the result to diopters.
For example, if the person's far point distance is 3 meters, their refractive error would be -0.33 diopters (1/3m = 0.33 D).
4) Determine the focal length of the corrective lens required to make the far point distance infinite: This can be done by adding the person's refractive error to the desired focal length of infinity (1/0 = 0 D).
For example, if the person's refractive error is -0.33 diopters, the required focal length of the corrective lens would be 0.33 meters or 33 centimeters.
Therefore, the person would need a corrective lens with a focal length of 33 centimeters to make their far point distance infinite.
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how are the masses of supermassive black holes related to the masses of the bulges of their surrounding galaxies and what does this suggest about the role of supermassive black holes in galaxy evolution.
Supermassive black holes are closely related to galactic evolution through their tightly correlated masses with galactic bulges.
How do supermassive black holes and galactic bulges relate, and what does this mean for galaxy evolution?Observations have shown that there is a tight correlation between the mass of the supermassive black hole (SMBH) at the center of a galaxy and the mass of the galactic bulge. This correlation, known as the M-sigma relation, suggests that the formation and evolution of SMBHs and galactic bulges are closely linked.
The M-sigma relation suggests that the growth of the SMBH and the galactic bulge are linked through a process known as "feedback." Feedback occurs when energy or matter is expelled from the central region of the galaxy by the SMBH, which then interacts with the gas and dust in the surrounding region, either preventing or enhancing the formation of new stars. This process helps regulate the growth of both the SMBH and the galactic bulge and also influences the overall evolution of the galaxy.
Furthermore, studies have also shown that the M-sigma relation holds not only for nearby galaxies but also for distant, high-redshift galaxies, suggesting that the correlation between SMBHs and galactic bulges has been in place for most of cosmic history. This highlights the important role that SMBHs play in shaping the evolution of galaxies over time.
Overall, the M-sigma relation and other related observations provide strong evidence for a symbiotic relationship between SMBHs and galactic bulges and suggest that these massive black holes play a crucial role in the formation, evolution, and regulation of their host galaxies.
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. Ima shoved a box horizontally over the end of a cliff. The initial velocity was 10m/s and it took 5.4s to hit
the ground.
+ How tall was the cliff?
+ How far away from the base of the cliff did the box fall?
Based on the provided initial velocity; The cliff was approximately 143.1 meters tall., The box fell approximately 54 meters away from the base of the cliff.
How to solve the questions on velocity?To find the height of the cliff, we can use the following kinematic equation for vertical motion:
y = y0 + v0_yt + 0.5a_y*t⁻².
where:
y = final vertical position
y0 = initial vertical position (0, since we start from the top of the cliff)
v0_y = initial vertical velocity (0, since the box is shoved horizontally)
a_y = vertical acceleration (9.81 m/s², due to gravity)
t = time (5.4 seconds)
Plugging in the values, we get:
y = 0 + 05.4 + 0.59.815.4²
y = 0.59.8129.16
y = 4.90529.16
y = 143.1 m
To find how far away the box fell from the base of the cliff, we can use the following equation for horizontal motion:
x = x0 + v0_x*t
where:
x = final horizontal position
x0 = initial horizontal position (0, since we start from the edge of the cliff)
v0_x = initial horizontal velocity (10 m/s)
t = time (5.4 seconds)
Plugging in the values, we get:
x = 0 + 10*5.4
x = 54 m
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a motorcycle passing by your apartment emits a sound with an intensity level of 70 db. if two identical motorcycles passed by together, what would be the intensity level of the resulting sound?
The intensity level of the resulting sound is approximately 73 dB, the correct option is (e)
To calculate the intensity level of the resulting sound, we use the formula:
L = 10 log(I ÷ I0)
where L is the intensity level in decibels, I is the intensity of the sound wave in watts per square meter, and I0 is the reference intensity, which is equal to 1 x 10⁻¹² watts per square meter.
Since the motorcycles emit identical sound waves, the intensity of each wave is the same. We can calculate the intensity of a single motorcycle's sound wave using the formula:
I = [tex](10^{L/10} )[/tex] x I0
where L is the intensity level of the sound wave in decibels. Substituting L = 70 dB and I0 = 1 x 10⁻¹² watts per square meter, we get:
I = (10⁷) x 1 x 10⁻¹²
= 1 x 10⁻⁵ watts per square meter
To calculate the intensity level of the resulting sound, we use the formula:
L = 10 log(2I ÷ I0)
where 2I is the intensity of the sound waves produced by two identical motorcycles. Substituting I = 1 x 10⁻⁵ watts per square meter and I0 = 1 x 10⁻¹² watts per square meter, we get:
2I = 2 x 1 x 10⁻⁵
= 2 x 10⁻⁵ watts per square meter
L = 10 log(2 x 10⁻⁵ ÷ 1 x 10⁻¹²)
= 10 log(2 x 10⁷)
= 10 (7.301)
= 73.01 dB
Therefore, the correct option is (e)
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The complete question is:
A motorcycle passing by your apartment emits a sound with an intensity level of 70 dB. If two identical motorcycles passed by together, what would be the intensity level of the resulting sound?
a. 80 dB
b. 140 dB
c. 103 dB
d. 70 dB
e. 73 dB
Forces and Motion:Question 5 A force of 20 N acts upon a 5 kg block. Calculate the acceleration of the object
The acceleration of the 5 Kg object, given that a force of 20 N acts upon it, is 4 m/s²
How do i determine the acceleration of the objectFirst, we shall list out the given parameters from the question. This is shown below:
Force acting on object (F) = 20 NMass of object (m) = 5 KgAcceleration of object (a) =?The acceleration of the object can be obtained as illustrated below
Force = mass × acceleration
Divide both side by mass
Acceleration = Force / mass
Inputting the value of force and mass, we have:
Acceleration = 20 / 5
Acceleration = 4 m/s²
Thus, the acceleration of the object is 4 m/s²
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HELP PLEASE Light travels to Earth from space as a/an_________wave.
O Mechanical
OSound
O Electromagnetic
O Longitudinal
Answer:
electromagnetic wave.
Explanation:
You can see light from the moon, distant stars, and galaxies because light is an electromagnetic wave. Electromagnetic waves are waves that can travel through matter or through empty space.
Answer: C) Electromagnetic wave
Explanation: It can't be D) Longitudinal because there is no such thing as a longitudinal wave that has to do with space. It wouldn't be mechanical cuz a mechanical doesn't have anything to do with light, neither sound.
Thus, the answer is C) Electromagnetic
sunlight shining through a thin, cool gas produces a(n) continuous spectrum. emission line spectrum. absorption line spectrum.
Sunlight shining through a thin, cool gas produces an absorption line spectrum.
Which spectrum does sunlight shining through a thin, cool gas produces?When white light passes through a thin, cool gas, some of the light is absorbed by the gas atoms, causing dark lines to appear in the spectrum known as an absorption spectrum. These dark lines represent the wavelengths of light that were absorbed by the gas. This type of spectrum is known as an absorption line spectrum. In the case of sunlight passing through Earth's atmosphere, the gases in the atmosphere absorb specific wavelengths of light, creating a series of dark lines in the spectrum. These dark lines are called Fraunhofer lines and are used to identify the chemical composition of the Sun and other stars.
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a workman carries some lumber up a staircase. the workman moves 9.6 m vertically and 22 m horizontally. if the lumber weighs 45 n, how much work was done by the workman?
The total work done by the workman was 432 joules
The workman lifted the lumber a vertical distance of 9.6 m, which means he did work against gravity. The amount of work done is equal to the force (weight of the lumber) multiplied by the distance it was lifted:
Work = force x distance
Work = 45 N x 9.6 m
Work = 432 joules
In addition to lifting the lumber, the workman also moved it horizontally a distance of 22 m. However, since the lumber was not lifted or lowered during this movement, no work was done against gravity.
Therefore, this distance does not affect the amount of work done by the workman.
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two objects collide under conditions where total momentum is conserved. is the momentum conserved for each object?
Yes, the momentum is conserved for each object in a collision where total momentum is conserved.
This means that the momentum of each individual object before the collision will equal the momentum of that same object after the collision, but in the opposite direction. This conservation of momentum is a fundamental law of physics, stating that in a closed system, the total momentum remains constant unless acted upon by an external force. Yes, each object in the impact maintains its momentum. This is due to the law of conservation of momentum, which stipulates that the overall momentum of a closed system—in this case, the collision of the two objects—remains constant before and after the collision. Every object must conserve its momentum because it is a component of the closed system and is part of the overall momentum. As a result, in the collision, each object's momentum is preserved.
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Yes, the momentum is conserved for each object in a collision where total momentum is conserved.
This means that the momentum of each individual object before the collision will equal the momentum of that same object after the collision, but in the opposite direction. This conservation of momentum is a fundamental law of physics, stating that in a closed system, the total momentum remains constant unless acted upon by an external force. Yes, each object in the impact maintains its momentum
. This is due to the law of conservation of momentum, which stipulates that the overall momentum of a closed system—in this case, the collision of the two objects—remains constant before and after the collision. Every object must conserve its momentum because it is a component of the closed system and is part of the overall momentum. As a result, in the collision, each object's momentum is preserved.
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As a planet orbits a star, it makes a big ellipse, but its gravity has a similar effect on the star, causing the star to make a small star. this is called
As a planet orbits a star, it makes a big ellipse, but its gravity has a similar effect on the star, causing the star to make a small star. This is called the "gravitational wobble" or "stellar wobble".
As a planet orbits a star, it follows an elliptical path due to the gravitational pull of the star. The shape of the planet's orbit is determined by the balance between the gravitational force of the star and the planet's own motion. However, the planet's gravity also affects the star, causing it to move slightly in response to the planet's pull. This motion of the star is much smaller than that of the planet, but it is still measurable and can be observed. This phenomenon is known as the planet's gravitational influence on the star, which causes the star to wobble slightly. This effect is used by astronomers to detect and study exoplanets orbiting distant stars.
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The phenomenon that occurs when a planet orbits a star, causing both the planet and the star to make elliptical motions due to their mutual gravitational effects.
This phenomenon is known as the "wobble" or "stellar wobble" and is caused by the gravitational interaction between a planet and its star. As a planet orbits a star, it exerts a gravitational force on the star, causing it to move slightly in response. This movement results in a small, periodic shift in the star's spectral lines, which can be detected by astronomers.
By analyzing this shift, astronomers can determine the presence, size, and orbital characteristics of planets around other stars. At the same time, the planet's gravity also affects the star, causing the star to make a smaller elliptical motion in response. This mutual gravitational interaction results in the observed stellar wobble.
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Ben and Jerry are standing on an ice rink discussing who has the best skates. Ben says he will go faster due to his superior skates and gives Jerry a shove to prove his point. Ben has a mass of 150 kg and a velocity of 11 m/s after he pushed Jerry. What was Jerry's mass if he has a velocity of 15 m/s>
Therefore, Jerry's mass is approximately 118.4 kg.
What does mass mean in plain terms?It is the most fundamental characteristic of matter and one of the fundamental quantities in physics. Mass is a term used to describe how much matter is there in a body. (kg). The mass of a body is constant over time.
The following is the equation for momentum conservation:
m1v1 + m2v2 = m1v1' + m2v2'
We are aware of Ben's 150 kg mass and 11 m/s post-push velocity. Additionally, we are aware of Jerry's post-push velocity, which is 15 m/s. To find Jerry's mass, we can rewrite the equation as follows:
m2 = (m1v1 + m1v1' - m2v2') / v2
Substituting in the known values:
m2 = (150 kg * 0 m/s + 150 kg * 11 m/s - m2 * 15 m/s) / 15 m/s
Simplifying and solving for m2:
m2 = (150 kg * 11 m/s) / (15 m/s + 1) ≈ 118.4 kg
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Assume a firm closes down in the short run and produces no output. Under these conditions:A. TVC is positive, but TFC and TC are zero.B. TFC is positive, but TVC and TC are zero.C. TFC and TC are positive, but TVC is zero.D. TFC, TVC, and TC will all be positive.
The correct answer is C.
In this case, Total Fixed Costs (TFC) remain positive as they are the expenses that do not change with the level of output, such as rent, salaries, and depreciation. Total Variable Costs (TVC) are zero since there is no production, and variable costs depend on the level of output. Total Costs (TC) remain positive as they are the sum of TFC and TVC, and since TFC is positive, TC will also be positive.
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what is the wavelength of a radio photon from an am radio station that broadcasts at 1270 kilohertz? express your answer to three significant figures and include the appropriate units.
The wavelength of a radio photon from an AM radio station broadcasting at 1270 kilohertz is 236 meters.
To find the wavelength of a radio photon from an AM radio station broadcasting at 1270 kilohertz, we can use the formula:
wavelength (λ) = speed of light (c) / frequency (f)
1. First, we need to convert the frequency from kilohertz to hertz:
1270 kilohertz = 1270 * 10³ hertz = 1,270,000 hertz
2. Next, we will use the speed of light, which is approximately 3.00 * 10⁸ meters per second (m/s).
3. Now, we can plug in the values into the formula:
wavelength (λ) = (3.00 * 10⁸ m/s) / (1,270,000 Hz)
4. Calculate the wavelength:
λ ≈ 236.22 meters
5. Finally, express the answer to three significant figures and include the appropriate units:
λ ≈ 236 meters
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Which of these objects is an insulator?
b. copper coin
d. steel fork
a. gold ring
C. glass rod
Answer:
C
Explanation:
Glass is one of the objects included in an insular so glass rod will be the final ans.
imagne that your friends cat was cloned. would it be the same
If my friend's cat was cloned, the resulting cat would be genetically identical to the original cat. However, this does not mean that the cloned cat would be exactly the same as the original cat in terms of its behavior, personality, or even appearance.
Environmental factors and experiences can have a significant impact on an animal's development and behavior, so even genetically identical cats can have differences in their behavior and personality. Additionally, the cloning process itself can introduce some genetic and epigenetic changes that may affect the cloned cat's development and behavior. Therefore, while the cloned cat may look and behave similarly to the original cat, it would not be exactly the same.
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how many joules of energy does a 100 watt light bulb use per hour? express your answer in joules to two significant figures.
To determine how many joules of energy a 100-watt light bulb uses per hour, you can follow these steps:
Step 1: Identify the power of the light bulb, which is given as 100 watts.
Step 2: Convert the power to joules per second, since 1 watt is equal to 1 joule per second. Therefore, the light bulb has a power of 100 joules per second.
Step 3: Calculate the energy used per hour. There are 3,600 seconds in an hour, so multiply the power (in joules per second) by the number of seconds in an hour:
Energy = Power x Time
Energy = 100 joules/second x 3,600 seconds
Energy = 360,000 joules
So, a 100-watt light bulb uses 360,000 joules of energy per hour.
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if the human body has an average density of 983 kg/m3 , what fraction of a person is submerged when floating gently in fresh water?
Roughly half of a person's body is submerged when they are floating gently in fresh water.
When an object is floating in water, it displaces an amount of water equal to its weight. If the weight of the displaced water is greater than the weight of the object, the object will float, and if it is less, the object will sink.
The fraction of a person that is submerged while floating in fresh water depends on the ratio of their weight to the weight of the water displaced by their body.
Assuming that the volume of a person is constant, we can calculate the weight of a person as:
Weight = density x volume x gravity
where:
density = 983 [tex]kg/m^3[/tex] (average density of human body)
volume = the volume of a person (assumed to be constant)
gravity = 9.81 [tex]m/s^2[/tex] (acceleration due to gravity)
Let's assume the weight of a person is 70 kg, then their volume would be:
Volume = Weight / (density x gravity)
Volume = 70 / (983 x 9.81)
Volume = 0.00716 [tex]m^3[/tex]
Now, let's consider the weight of the water displaced by the person's body. The weight of the water displaced is equal to the weight of the person, which is 70 kg.
Therefore, the fraction of the person's body that is submerged in water is:
Fraction submerged = Weight of water displaced / Total weight
Fraction submerged = 70 / (70 + weight of water in the submerged part of the body)
Since the person is floating gently in water, we can assume that only a small part of their body is submerged, and we can neglect the weight of water in the submerged part of the body.
Thus, we can approximate the fraction submerged as:
Fraction submerged ≈ Weight of water displaced / Total weight
Fraction submerged ≈ 70 / (70 + 70)
Fraction submerged ≈ 0.5 or 50%
Therefore, roughly half of a person's body is submerged when they are floating gently in fresh water.
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a 1 meter long solenoid with 200 turns carries 2a of current . calculate the magnetic field on axis.
The magnetic field on the axis of the solenoid is 5.03 × 10⁻⁴ T.
The magnetic field on the axis of a solenoid can be calculated using the formula:
B = μ₀ * n * I
Where B denotes the intensity of the magnetic field, 0 denotes the permeability of empty space, n denotes the number of turns per unit length, and I is the current flowing through the solenoid.
In this case, the solenoid is 1 meter long and has 200 turns, so n = 200 turns / 1 meter = 200 turns/meter. The solenoid is delivering 2A of current.
The value of μ₀ is a constant, equal to 4π × 10⁻⁷ T·m/A
When we enter these values into the formula, we get:
B = μ₀ * n * I
= 4π × 10⁻⁷ T·m/A * 200 turns/m * 2A
= 5.03 × 10⁻⁴ T
Therefore, the magnetic field on the axis of the solenoid is 5.03 × 10⁻⁴ T.
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magnetic field on the axis of the solenoid is approximately 0.005 T
Solution - Hi! To calculate the magnetic field on the axis of a solenoid, you can use the formula:
Magnetic field (B) = μ₀ * n * I . (applicable for ideal long solenoid)
where μ₀ is the permeability of free space (approximately 4π x 10^-7 Tm/A), n is the number of turns per unit length, and I is the current.
In your case, the solenoid is 1 meter long with 200 turns and carries a 2 A current. To find n, divide the number of turns by the length:
n = 200 turns / 1 m = 200 turns/m
Now, plug the values into the formula:
B = (4π x 10^-7 Tm/A) * (200 turns/m) * (2 A)
B ≈ 0.005 T
The magnetic field on the axis of the solenoid is approximately 0.005 T (Tesla).
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a laser beam takes 45.5 ms to be reflected back from a totally reflecting sail on a spacecraft. how far away is the sail?
The sail is approximately 6,832,500 meters away from the laser source.
To determine the distance between the laser source and the totally reflecting sail on a spacecraft, we'll use the time it takes for the laser beam to be reflected back, which is 45.5 ms (milliseconds).
Since the laser beam travels to the sail and back, we must account for the round trip. The speed of light is approximately 3.0 x 10^8 meters per second (m/s).
First, convert 45.5 ms to seconds: 45.5 ms × (1 s / 1000 ms) = 0.0455 s.
Next, calculate the total distance the laser beam travels during this time: distance = speed × time, so distance = (3.0 x 10^8 m/s) × 0.0455 s ≈ 13,665,000 meters.
Finally, divide the total distance by 2 to find the distance between the laser source and the sail: 13,665,000 meters / 2 ≈ 6,832,500 meters.
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when a high voltage is applied to a low-pressure gas, causing it to glow, it will emit what type of spectrum? a. li
When a high voltage is applied to a low-pressure gas and it starts to glow, it will emit an emission line spectrum.
This spectrum consists of bright, narrow lines at specific wavelengths, which are characteristic of the element or molecules in the gas. This is due to the electrons in the gas being excited to higher energy levels and then falling back down to lower energy levels, emitting photons of light at specific wavelengths corresponding to the energy differences between the levels. The resulting emission spectrum can be used to identify the elements or molecules present in the gas.
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what is the distance the masses on the right of the fulcrum need to be to balance with the two masses on the left?
Distance the masses on the right of the fulcrum need to be to balance with the two masses on the left is (3.5kgm - x kg * d m) / 1kg
In order for a lever to be balanced, the moments on either side of the fulcrum need to be equal. The moment is calculated by multiplying the distance from the fulcrum by the mass of the object. Therefore, to balance the two masses on the left of the fulcrum with the masses on the right, we need to calculate the moment on each side and make them equal.
Let's assume the masses on the left of the fulcrum are 2kg and 3kg, and the masses on the right are x kg and y kg, respectively. If the distance between the fulcrum and the 2kg mass is 1m, and the distance between the fulcrum and the 3kg mass is 0.5m.
we can calculate the moments on each side as follows:
Moment on the left side = 2kg x 1m + 3kg x 0.5m = 2kg + 1.5kg = 3.5kgm
Moment on the right side = x kg * d m + y kg * e m
where d and e are the distances between the fulcrum and the masses on the right.
To make the moments equal, we can set them equal to each other:
3.5kgm = x kg * d m + y kg * e m
If we know the mass of one of the objects on the right, we can solve for the distance needed for the other mass to balance the lever. For example, if we know the mass of the object closest to the fulcrum is 1kg.
we can rearrange the equation to solve for e:
e = (3.5kgm - x kg * d m) / 1kg
Once we know the distance needed for the other mass, we can set up the lever accordingly and it should be balanced.
The Question was Incomplete, Find the full content below :
A balanced lever has two weights on it, the masses on the left of the fulcrum are 2kg and 3kg, and the masses on the right are x kg and y kg. If the distance between the fulcrum and the 2kg mass is 1m, and the distance between the fulcrum and the 3kg mass is 0.5m.what is the distance the masses on the right of the fulcrum need to be to balance with the two masses on the left?
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PLEASE ANSWER ASAP
1. How many atoms are present in 8.500 mole of chlorine atoms?
2. Determine the mass (g) of 15.50 mole of oxygen.
3. Determine the number of moles of helium in 1.953 x 108 g of helium.
4. Calculate the number of atoms in 147.82 g of sulfur.
5. Determine the molar mass of Co.
6. Determine the formula mass of Ca3(PO4)2.
IT WOULD BE HELPFUL
The number of atoms in 147.82 g of sulphur is 2.772 x 10²⁴. In 1.953 x 10⁸ g of helium, there are 4.883 × 10⁷ moles of helium. 15.50 moles of oxygen weigh 248 g. Calcium phosphate's formula mass would be 310.18 g/mol.
How many atoms make up 1 gramme?The quantity of atoms or molecules per gramme of atomic weight is known as Avogadro's number, which is 6.022 × 10²³/mole. One mole of hydrogen comprises 6.022 × 10²³ hydrogen atoms for one gramme of hydrogen with an atomic weight of one gramme.
The Avogadro's number states that 1 mole of any substance contains 6.022 x 10²³ particles. Therefore, 8.500 moles of chlorine atoms would contain:
8.500 moles * 6.022 x 10²³ atoms/mole = 5.1167 x 10²⁴ atoms of chlorine.
The molar mass of oxygen is 16.00 g/mol. Therefore, 15.50 moles of oxygen would have a mass of:
15.50 moles * 16.00 g/mol = 248 g
So the mass of 15.50 mole of oxygen is 248 g.
The molar mass of helium is 4.00 g/mol. Therefore, 1.953 x 10⁸ g of helium would contain:
1.953 x 10⁸ g / 4.00 g/mol = 4.883 x 10⁷ moles of helium.
The molar mass of sulfur is 32.06 g/mol. Therefore, 147.82 g of sulfur would contain:
147.82 g / 32.06 g/mol = 4.6055 moles of sulfur. Therefore, the formula mass of Calcium phosphate would be:
(340.08 g/mol) + (230.97 g/mol) + (8*16.00 g/mol) = 310.18 g/mol.
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1. which angular velocity was non-zero and what was the sign? explain how this makes sense given the right-hand rule for the angular velocity.
Clockwise angular velocity was non-zero and had a positive sign. So, the correct answer is D.
The right-hand rule for angular velocity asserts that if the right hand's thumb is pointing in the direction of the axis of rotation, then the direction of the angular velocity vector is given by the direction in which the right hand's fingers curl.
This makes sense in this situation. As a result, the angular velocity vector will point in the same direction as the rotation's axis, and it will be positive when the angular velocity is positive.
In physics, engineering, and other sciences, the right-hand rule for angular velocity is a helpful tool for visualising the direction of the angular velocity vector.
This rule allows us to quickly ascertain the direction and sign of the angular velocity in any given situation.
Complete Question:
Which angular velocity was non-zero and what was the sign? Explain how this makes sense given the right-hand rule for the angular velocity.
A. Counterclockwise, Positive
B. Clockwise, Negative
C. Counterclockwise, Negative
D. Clockwise, Positive
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the fundamental, resonant wavelength of a pipe open at both ends that is 1 m long and 0.1 m in diameter is:
The fundamental resonant wavelength of a 1-meter long pipe open at both ends is 2 meters.
To find the fundamental resonant wavelength of a pipe open at both ends, we can use the formula:
Wavelength = 2 * Length of the pipe / Harmonic number
Since you're looking for the fundamental resonant wavelength, the harmonic number (n) is 1.
Given that the length of the pipe (L) is 1 meter:
Wavelength = 2 * 1 / 1
Wavelength = 2 meters
So, the fundamental resonant wavelength of a 1-meter long pipe open at both ends is 2 meters. The diameter of the pipe (0.1 meters) doesn't affect the wavelength in this case.
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if at a concert, a wind blows directly from the orchestra toward you, the frequency of the sound you hear will be:A) decreased.
B) increased.
C) neither decreased nor increased.
If at a concert, a wind blows directly from the orchestra toward you, the frequency of the sound you hear will be neither decreased nor increased. Option C is correct.
The frequency of the sound you hear at a concert will not be affected by the direction of the wind blowing from the orchestra toward you. The frequency of sound waves is determined by the source of the sound and the speed of sound in air, and is not affected by the wind blowing in a particular direction.
However, the intensity or volume of the sound may be affected by the wind, especially if it is a strong wind. In this case, the sound waves may be partially blocked or scattered by the wind, leading to a reduction in the volume of the sound that reaches you.
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suppose you have a circular loop of wire sitting in a magnetic field, as shown. the magnitude of the magnetic field is decreasing. what does the curly electric field look like?
The curly electric field look like a circular loop of wire in a decreasing magnetic field
A manifestation of the fundamental relationship between electricity and magnetism, as described by Faraday's and Lenz's laws. When a circular loop of wire is placed in a magnetic field and the magnitude of the magnetic field is decreasing, it causes a change in magnetic flux through the loop.
According to Faraday's law of electromagnetic induction, this change in magnetic flux induces an electromotive force (EMF) in the loop, which in turn causes an electric current to flow in the wire. As a result of the current flowing in the wire, a curly electric field is generated around the loop. The direction of this electric field is such that it opposes the change in magnetic flux that induced the current in the first place. This phenomenon is known as Lenz's law.
The curly electric field is not a constant field, but rather a changing field that varies with time. As the magnitude of the magnetic field continues to decrease, the induced EMF and the corresponding electric field will also decrease, eventually reaching zero when the magnetic field is completely removed.
Overall, when the magnetic field's magnitude decreases, a curly electric field is generated in the circular wire loop due to the change in magnetic flux. This electric field creates a current that opposes the change in the magnetic field, following Faraday's Law of Electromagnetic Induction and Lenz's Law
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What specific evidence does Norton offer for her
belief?