Which of the following combinations would result in the least acceleration?
O SN and 0.35 kg
60N and 2.0 kg
O 12N and 1.0 kg
O IN and 0.20 kg

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Answer:

141m

Explanation:

A. The car’s initial kinetic energy is 112500 J

B. The car’s final kinetic energy is 0 J

C. The amount of work done to stop the car is –112500 J

D. The force applied in bringing the car to a stop is –5625 N

KEᵢ = ½mu²

KEᵢ = ½ × 1000 × 15²

KEᵢ = 112500 J

KEբ = ½mv²

KEբ = ½ × 1000 × 0²

KEբ = 0 J

Wd = KEբ – KEᵢ

Wd = 0 – 112500

Wd = –112500 J

We'll begin by calculating the acceleration. This can be obtained as follow:

v² = u² + 2as

0² = 15² + (2 × a × 20)

0 = 225 + 40a

Collect like terms

0 – 225 = 40a

–225 = 40a

Divide both side by 40

a = –225 / 40

a = –5.625 m/s²

Finally, we shall determine the force. This is illustrated below:

F = ma

F = 1000 × –5.625

F = –5625 N

Learn more about energy:

https://brainly.com/question/10703928

Answer:

Resistencia = 12.5 Ohmios

Explanation:

Dados los siguientes parámetros;

Voltaje = 3.5 Volts

Corriente = 0.28 Amps

Para encontrar el resistencia;

La ley de Ohm establece que a temperatura constante, la corriente que fluye en un circuito eléctrico es directamente proporcional al voltaje aplicado en los dos puntos e inversamente proporcional a la resistencia en el circuito eléctrico.

Matemáticamente, La ley de Ohm viene dada por la fórmula;

Voltaje = corriente * resistencia

Resistencia = voltaje/corriente

Resistencia = 3.5/0.28

Resistencia = 12.5 Ohmios

Por tanto, la resistencia del filamento de una linterna de bolsillo es de 12,5 ohmios.

Answer:

The acceleration of the object is -29.12 m/s².

Explanation:

The acceleration of the object can be calculated by Newton's second law:

[tex] \Sigma F = ma [/tex]

[tex] - F - F_{\mu} = ma [/tex]                        

[tex] - F - \mu mg = ma [/tex]                        

Where:

F: is the applied force = 40.0 N

μ: is the coefficient of kinetic friction = 0.25

m: is the mass of the object = 1.5 kg

g: is the acceleration due to gravity = 9.81 m/s²

a: is the acceleration =?

[tex] a = \frac{- F - \mu mg}{m} = \frac{-40.0 N - 0.25*1.5 kg*9.81 m/s^{2}}{1.5 kg} = -29.12 m/s^{2} [/tex]

The minus sign is because means that the object is decelerating due to the applied force and the friction.  

Therefore, the acceleration of the object is -29.12 m/s².

I hope it helps you!  

Answer:

the first statement...

Answer:

The first answer is correct.

Plz mark brainliest.

Hope I helped.

Explanation:

Answer:

heyy tell me ur yo u tube ch annel name I'll subscribe it and how many sub scriber u have friend

Explanation:

and are u from Ireland?

Answer:

m1 v1 + m2 v2 = m1 V1 + m2 V2       conservation of momentum

m1 = 3    m2 = 6

v2 = -4.6

V1 = -4.2

V2 = -1.5

v1 = (m1 V1 + m2 V2 - m2 v2) / m1

v1 = (3 * -4.2 + 6 * -1.5 - 6 * -4.6) / 3

v1 = (-12.6 - 9 + 27.6) / 3 = 2  initial velocity of 3 kg ball

Check:

3 * 2 + 6 * -4.6 = -21.6

3 * -4.2 + 6 -1.5 = -21.6

Answer:

With F = MA Its should take 500 Newtons

Explanation:

F = MA

Answer:

I would say vitamin B-6

Explanation:

it is also known as pyridoxine. it helps ebzymes break down protein and carry the dismantled amino acids to the blood stream

Hope this helps ✌✌

Answer:

The body needs small amount of vitamin B-6 to help enzymes break down protein and carry the dismantled amino acids to the blood stream.

Answer:

a tendency to do nothing or to remain unchanged.

Explanation:

Answer:

Inertia: The resistance an object has to a change in its state of motion.

Explanation:

Hope it helps....

Have a great day!!

Answer:

(a) The time the ball stays in the air is approximately 4.66 seconds

(b) The distance from the cannon at which the ball will hit the ground is approximately 83.18 meters

(c) The maximum altitude of the ball is approximately 26.62 m

Explanation:

The given parameters of the question are;

The initial velocity at which a baseball cannon fires balls, u = 29 m/s

The angle at which the cannon is tilted, θ = 52°

(a) The time duration the ball stays in the air is given by the time of flight of the projected ball as follows;

[tex]2 \cdot t = \dfrac{2 \cdot u \cdot sin (\theta)}{g}[/tex]

Where;

t = The time it takes the baseball to reach maximum height

2·t = The total time of flight = The time the ball stays in the air

θ = The angle at which the ball is tilted = 52°

g = The acceleration due to gravity ≈ 9.81 m/s²

u = The initial velocity = 29 m/s

Therefore, we have;

[tex]2 \cdot t = \dfrac{2 \times 29 \ m/s\times sin (52^{\circ})}{9.81 \ m/s^2} \approx 4.66 \ s[/tex]

The time the ball stays in the air, 2·t ≈ 4.66 seconds

(b) The distance from the cannon at which the ball will hit the ground is given by the horizontal range, 'R', of the projectile as follows;

[tex]Horizontal \ range, R = \dfrac{u^2 \cdot sin(2 \cdot \theta) }{g}[/tex]

∴ The distance from the cannon at which the ball will hit the ground = R

[tex]Horizontal \ range, R = \dfrac{(29 \ (m/s))^2 \cdot sin(2 \times 52^{\circ}) }{9.81 \ m/s^2} \approx 83.18 \, m[/tex]

The distance from the cannon at which the ball will hit the ground = R ≈ 83.18 meters

(c) The maximum altitude of the ball is equal to the maximum height reached by the ball, H, which is given as follows;

[tex]H = \dfrac{u^2 \cdot sin^2 (\theta)}{2 \cdot g}[/tex]

Therefore, we have;

[tex]H = \dfrac{(29 \ m/s)^2 \times sin^2 (52^{\circ})}{2 \times 9.81 \ m/s^2} \approx 26.62 \ m[/tex]

The maximum altitude of the ball ≈ 26.62 m

Answer:

[tex]v = 14.78m/s[/tex]

Explanation:

Given

[tex]KE = 150J[/tex]

[tex]p = 20.3kgm/s[/tex]

Required

Determine the object's speed

Kinetic Energy is calculated as:

[tex]KE = \frac{1}{2}mv^2[/tex]

Make m the subject

[tex]m = \frac{2KE}{v^2}[/tex]

Momentum is calculated as:

[tex]p = mv[/tex]

Make m the subject

[tex]m = \frac{p}{v}[/tex]

So, we have:

[tex]m = \frac{p}{v}[/tex] and [tex]m = \frac{2KE}{v^2}[/tex]

Equate both expressions: [tex]m = m[/tex]

[tex]\frac{2KE}{v^2} = \frac{p}{v}[/tex]

Multiply both sides by v

[tex]v * \frac{2KE}{v^2} = \frac{p}{v}*v[/tex]

[tex]\frac{2KE}{v} = p[/tex]

Make v the subject

[tex]v = \frac{2KE}{p}[/tex]

Substitute [tex]KE = 150J[/tex] and [tex]p = 20.3kgm/s[/tex]

[tex]v = \frac{2 * 150}{20.3}[/tex]

[tex]v = \frac{300}{20.3}[/tex]

[tex]v = 14.78m/s[/tex]

Answer: B  6.2 Hz

Explanation:  Equation for waves v = λf.

Frequency = speed / wavelength    f = v/λ

   f = 74 m/s / 12 m = 6.166... Hz

Answer:

Rounding is necessary: the answer is 6.2 Hz

Explanation:

Answer:

B The resultant force on the satellite is towards the Earth.

Explanation:

In the case when the satellite orbits earth would be at constant speed in the circular orbit so hee the resultant force that on the satellite would be with regard to the earth

So as per the given situation, the option B is correct

And, the rest of the options would be wrong

And, the same would be relevant

Answer:

r = 2.55 m

Explanation:

Given that,

First charge, q₁ = 32.2 μC

Second charge, q₂ = + 12.3 μC

The force between charges, F = 0.544 N

We need to find the distance between charges. The force between two charges is given by the formula as follows :

[tex]F=k\dfrac{q_1q_2}{r^2}\\\\r=\sqrt{\dfrac{kq_1q_2}{F}} \\\\r=\sqrt{\dfrac{9\times 10^9\times 32.2\times 10^{-6}\times 12.3\times 10^{-6}}{0.544}} \\\\r=2.55\ m[/tex]

So, the charges are 2.55 m apart.

Answer:

2.55

Explanation:

Right on Acellus

Give the other guy brainliest

You can only give brainliest if 2 people answer

Answer:

1280Nm

Explanation:

torque= I×alpha(angular acceleration)

so Angular acceleration is found by the following process.

Answer:

Explanation: Pules

Answer: longitudinal (compression)

Explanation:

Answer:

mass= 60kg

velocity= 10m/s

momentum = mass × velocity

p=m×v

p= 60×10

p= 600kgm/s

Answer:

The ampere, symbol A, is the SI unit of electric current. It is defined by taking the fixed numerical value of the elementary charge e to be 1.602 176 634 x 10-19 when expressed in the unit C, which is equal to A s, where the second is defined in terms of ΔνCs.

the device used to measure current in a circuit is ammeter

Answer:

86.5 m

Explanation:

[tex]s = ut + \frac{1}{2} at {}^{2} \\ s = (0)(4.2) + \frac{1}{2} (9.81)(4.2) {}^{2} \\ s = 86.5m [/tex]

Answer:

86.5 m

Explanation:

Answer:

C. Elements with intermediate number of valence electrons are the most chemically stable.

Answer:

100 m

Explanation:

From the question,

R = Lρ/A.................... Equation 1

Where R = resistance of the wire, L = length of the wire, ρ = resistivity of the wire, A = cross sectional area of the wire.

But,

A = πr².................... Equation 2

Where r = radius of the wire.

Substitute equation 2 into equation 1

R = Lρ/πr²

Make L the subject of the equation

L = Rπr²/ρ...................... Equation 3

Given: R = 40 Ω, r = 5×10⁻⁴ m, ρ = 3.14×10⁻⁷ Ωm

Constant: π = 3.14

Substitute these values into equation 3

L = [40×3.14×( 5×10⁻⁴)²]/ (3.14×10⁻⁷)

L = 40×3.14×25×10⁻⁸/(3.14×10⁻⁷)

L = 100 m

Hence the length of the wire is 100 m

Answer:

When object is placed between convex lens and focal point, image formed is virtual and magnified which is shown in the diagram. Was this answer helpful?

Answer:

B and C is the Answer

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Mark brainliest

Answer:

The reason why one cannot hear in space but light can be seen is because light and sound are different kinds of wave

Light is an electromagnetic wave that propagates by a changing magnetic field hat creates a changing electric field. Light is created by a vibrating electric charge, and is transmitted through a medium by the absorption and reemission of the light by the medium particles

Sound is a longitudinal mechanical wave that is propagated by the vibration of the particles of the medium.

Sound requires a medium to propagate and it cannot be propagated or heard through space which is a vacuum.

Sound is created by a source that is vibrating and the vibration is transmitted to particles in the medium including solids, liquids, gases and plasma that the vibrating energy is in direct contact with and the transfer of the sound energy continues between layers of adjacent particles for the medium for the sound to be propagated from place to place

Explanation:

Explanation:

C. neutron.

it does not contain ionizing characteristics.

hope it helps. :)

Answer:

The boy can throw the ball to a height of 3.85 m on Jupiter

Explanation:

We'll begin by calculating the initial velocity at which the ball is thrown on EARTH. This can be obtained as follow:

On Earth:

Acceleration due to gravity (g) = 10 m/s²

Maximum height (h) = 10 m

Final velocity (v) = 0 m/s (at maximum height)

Initial velocity (u) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = u² – 2 × 10 × 10

0 = u² – 200

Collect like terms

0 + 200 = u²

200 = u²

Take the square root of both side

u = √200 m/s

Finally, we shall determine the maximum height of the ball at JUPITER. This can be obtained as followb

On Jupiter:

Acceleration due to gravity (g) = 26 m/s²

Initial velocity (u) = √200 m/s

Final velocity (v) = 0 m/s (at maximum height)

Maximum height (h) =..?

v² = u² – 2gh (since the ball is going against gravity)

0² = (√200)² – 2 × 26 × h

0 = 200 – 52h

Collect like terms

0 – 200 = –52h

–200 = –52h

Divide both side by –52

h = –200 / –52

h = 3.85 m

Thus, the boy can throw the ball to a height of 3.85 m on Jupiter.