Which of the following is the source of wealth for a nation in a mercantilism system?
a. religion
B. population
c. natural resources
D. land​

The correct answer is ΔS=11.16kJ/K.

m=3kg

p_1=200kPa

m_f1=3/4m=2.25kg

x_2=1

ΔS=?

x_1=m_g/m=(m-_f1)/m=(3-2.25)/3=0.25

p_1=200kPa

v_f1=0.001061m^3/k g

v_g1=0.88578m^3/k g

s_f1=1.5302k J/k gK

s_fg1=5.5968 k J/kgK

With these data, we may solve for particular entropy in state 1 using the following equation:

s_1=s_f1+x_1g=1.5302+(0.25)(5.5968)

=2.9294 kJ/kgK

Entropy will be obtained in stage 2, but in order to do so, we must first compute a particular volume in state 1 that is identical to the one in state 2, as this is a constant volume process.

The formula for a particular volume is:

v_1=v_f1+x_1v_fg=0.001061+0.25(0.88578-0.001061)=0.22m^3/kg=v_2

Now, we may get particular entropy in state 2 using the Molier diagram for water.

p_2=1/v_2=1/0.22=4.55 kg/m^3

x_2=1⇒s_2=6.65kJ/kgK

Final entropy change is:

ΔS=m(s_2-s_1)

=3(6.65-2.9294)

ΔS=11.16kJ/K

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The correct answer is transient airflows under the combined motion of a  door and the force of buoyancy.

However, the combined airflow characteristics generated by door motion, ventilation airflow, and thermal impacts have not yet been thoroughly defined. Door motion has been acknowledged as playing a part in the confined conveyance between indoor and outdoor regions. This study employed dynamic CFD simulation to look at the transient airflow characteristics and amount of air exchange generated by door motions in a thermally stratified environment with displacement ventilation. The results show that at a door angle of 30°, there is a 40% air exchange even though only 15% of the overall door motion process is used during the initial phase. Two important contributing factors are the temperature difference between the air inside and outside, as well as the rotational speed of the  door.

The thermal convective flow may have a considerable impact on the airflow pattern through the doorway when the door motion is slow enough and the temperature difference is greater than 3 °C. The amount of air exchange rises linearly with door motion speed when there is no difference in temperature between the internal and exterior spaces. When buoyant force and door motion are coupled, a modest door speed yields minimal air exchange. Only the air temperatures close to the door are impacted by door movement. In the displacement ventilated room, a single door open and close cycle does not considerably reduce the overall temperature stratification. The research findings may help to improve knowledge of the consequences of dynamic disturbances in thermally stratified environments as well as offer recommendations for decreasing door motion-induced pollutant movement.

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It is necessary to cut off the first few dots because a small distance between dots means the object was moving slow during that time interval.

Uniform velocity is the state in which a body travels the same distance in the same amount of time.

The average velocity of a body is represented by the variable v in the equation (d = v t). If the magnitude and direction of the velocity do not change over time, the body is said to be moving at a uniform speed.

An example of constant velocity, or when a body moves with increasing speed at regular intervals, is the rotation of the Earth.

Uniform velocity is the state in which a body travels the same distance in the same amount of time. The average velocity of a body is given in the equation (d = v t), and its magnitude and direction are constant across time.

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For an object in uniform circular motion, its velocity and acceleration vectors are always perpendicular to each other at every point in the path is true.

Circular motion refers to the movement of a body part around the perimeter of a circle or in a circular motion. It may rotate at a fixed speed and angular rate or it may rotate at a variable rate, making it either uniform or non-uniform. A three-dimensional body's components move in circles as it rotates around a fixed axis. The center of mass of a body moves according to the equations of motion. In circular motion, the distance between the body and a fixed point on the surface stays constant.

Examples of circular motion include an artificial satellite circling the Earth at a constant altitude, ceiling fan blades spinning around a hub, and a rotating disc.

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Both horizontal and vertical acceleration is produced by the jet engines. While it does contribute to vertical acceleration, gravity has no effect on horizontal acceleration.

there's a particular value or velocity for the horizontal component. with out accounting for air resistance, the horizontal factor is regular for the duration of the flight.

Horizontal velocity affects the variety however not the period of an airborne object. Gravity reasons a downward vertical acceleration that has a price of 9.8 m/s/s.

This vertical acceleration reasons a downward projectile's vertical velocity to vary by 9.8 m/s in keeping with 2nd. The movement of a projectile's horizontal axis is unrelated to its vertical axis.

A projectile's trajectory is determined by using pace in two dimensions. The x and y components of the projectile, respectively, describe its horizontal and vertical pace. Meters are the devices used to signify each horizontal and vertical distances (m).

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The correct option is (c) 0.5 .

The magnetic field experienced by the patient's protons is 0.5 Tesla.

What is a magnetic field in simple terms?

The area in which the force of magnetism acts around a magnetic material or a moving electric charge is known as the magnetic field. A diagram that shows the magnetic field and how a magnetic force is distributed inside and outside of a magnetic substance.

While opposite poles (north and south) are drawn to one another, the same poles repel one another. The north-seeking poles of the iron's atoms line up in the same direction when it is rubbed against a magnet. A magnetic field is produced by the force that the aligned atoms produce.

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The complete question is:

"If the precessional frequency of the protons net magnetization is approximately 21 MHz, a ____ Tesla magnetic field is being experienced by the patient's protons?

(a) 2.0

(b) 1.5

(c) 0.5

(d) 0.3"

Edwin Hubble was an American astronomer who discovered a way to determine the rate of expansion of the universe through the relationship between the velocities of remote galaxies and their distances.

Mr. Hubble established what is known as Hubble's law, this law states that the greater the distance of a galaxy, the greater the speed at which it moves away from us, so both the law indicates that the large objects in the universe are moving away from each other steadily causing an unchanging expansion.

It is a mathematical constant that expresses the expansion velocity of the universe at a distance from a point in space. Its value is 69.8 km/s/Mpc.

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Potassium-41, 19 protons, 19 electrons, 22 neutrons is the correct name, number of protons, neutrons, and electrons for the following ₁₉⁴¹K.

The correct option is B.

The chemical element with the atomic number 19 and the letter K is potassium. Potassium is a silvery - white metal that may be cut with a knife quickly and painlessly. After only a few seconds of exposure, atmospheric oxygen and potassium metal combine to form flaky, white potassium peroxide.

Your potassium level may be affected by a medicine you're taking, or it may be brought on by a medical problem that needs to be treated. The underlying cause of low potassium is treated, which may entail potassium supplementation.

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The complete question is -

What is the correct name, number of protons, neutrons, and electrons for the following ₁₉⁴¹K.

A- Potassium -19, 19 protons, 19 electrons, 22 neutrons

B- Potassium-41, 19 protons, 19 electrons, 22 neutrons

C- Potassium-19, 41 protons, 41 electrons, 19 neutrons

D- Potassium-41, 41 protons, 41 electrons, 19 neutrons

Percentage of probability of drawing a black card followed by drawing a heart = 13%

Total cards in a deck of cards = 52

Total black cards in a deck of cards = 26

Probability of drawing a black card = (26/52) = (1/2)

Percentage of probability of drawing a black card = (1/2) × 100 = 50 %

Total hearts in a deck of cards = 13

There are 26 black card in a deck of 52 cards . Once the black card is drawn we are left with total of 51 cards. So, we can write

Probability of then drawing a heart = (13/51)

To get the probability of drawing a black card followed by drawing a heart we need to multiply the fractions together, so we can write

Probability of drawing a black card followed by drawing a heart = (1/2) × (13/51) = (13/102)

Percentage of probability of drawing a black card followed by drawing a heart = (13/102) × 100 = 12.74% = 13% (after round off)

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The charge will be equal to 4.07 x 10⁻¹⁰ coulombs.

The term "electric field" refers to the physical field that surrounds electrically charged particles and pulls or attracts all other charged particles nearby.

Use the following formula E = Kq / r² Since the electric field is 573 N/C

The distance of the midpoint of the charge.

r = 1/2 x 16 = 8 cm = 0.08m.

573 = (8.998 x 10⁹) x q) / (0.08)²

573 x 0.0064 = 8.998 x 10⁹ x q

q = (573 x 0.0064)/ 8.998 x 10^(9)

q =3.6672 / 8.998 x 10⁹

q = 4.07 x 10⁻¹⁰ coulombs

Therefore, the charge will be equal to 4.07 x 10⁻¹⁰ coulombs.

The complete question is given below:-

The electric field midway between two equal but opposite point charges is 573 n/c , and the distance between the charges is 16.0 cm. Calculate the magnitude of the charge.

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Fe/Fg = 4.2 x 10⁴² is the gravitational attraction.

Gm²/r² the gravitational attraction between two electrons is given by, where G is the gravitational constant, m is the electron mass, and r is the distance between the two electrons.

r = the distance between two electrons the size of the charge on each electron, or q, is 1.6 x 1019 C.

The mass of one electron, or m, is 9.1 x 1031.

The Coulomb force of repulsion is expressed mathematically as

Fe equals (9 x 109) k q/r2 (1.6 x 10-19) ²/r²

Fg = Gm2/r2 = 6.67 x 1011 is the formula for the gravitational force of attraction. (9.1 x 10⁻³¹) ²/r²

The formula for calculating Fe/Fg is [(9 x 109) (1.6 x 1019) 2/r2] / [(6.67 x 1011). (9.1 x 10^-31) ⁻³/r²]

Fe/Fg = 4.2x10⁴²

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The charge deposited on the object is 150000 C.

Charge can be defined as the product of current and time. The S.I unit of charge is coulombs (C.)

To calculate the charge deposited on the object, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1\

Hence, the charge deposited on the object is 150000 C.

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It is a false statement that Scientific study can always be categorized as belonging to only one of the three major categories of sciences.

A scientific study involves an investigation into issues that has to do a scientific topic. There are three main branches of science which are physics, chemistry and biology. However most of the research in science is interdisciplinary. It involves a synergy between the various fields of science.

Thus, it is a false statement that Scientific study can always be categorized as belonging to only one of the three major categories of sciences.

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The distance from the milky way galaxy to the most distant galaxies in the observable universe would be approximately 1.34 kilometers on a scale in which the MIlky Way Galaxy was the size of a marble(about 1 cm).

The MIlky Way is the galaxy that includes our solar system along with billions of stars.

To measure distances in space, we use the unit light year. One light year is the distance travelled by light in year. 1 light year is equal to 9.5 trillion km.

The size of MIlky Way is about 1,00,000 light years and the distance from the MIlky Way to the most distant galaxies in the observable is 13.4 billion light years.

Therefore, the distance from the milky way galaxy to the most distant galaxies in the observable universe would be approximately 1.34 kilometers on a scale in which the MIlky Way Galaxy was the size of a marble(about 1 cm).

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Answer:

I think it's A

Explanation:

potential energy is energy waiting to move right?

We must use the principles of the balance of forces to resolve this exercise.

What is centrifugal force?

A hypothetical force called centrifugal force, which is unique to particles traveling in a circle, is a force that has the same strength and dimensions as the centripetal force, but acts in the opposite direction.

The force exerted on the satellite by the planet in this specific instance must be equal to the centrifugal force, that is

Fg =Fe

GMm/ r^2 = mw^2r

Where,

G = Gravitational Universal Constant

M = Mass of earth

m = mass of satellite

r = Distance/Orbit

By changing and rearranging the equation to find the orbit using the idea of Period through the Angular Velocity, we have,

r = 1.44 x 10^7 m

The orbit is 14400 kilometers

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The potential difference is needed to give a helium nucleus (q=2e) 75.0 keV of kinetic energy is 37.5kV.

Potential difference is the difference in amount of energy that charge carriers have between two points in a circuit.

**Measured in Volts: **Potential difference is measured in volts (V) and is also called voltage. The energy is transferred to the electrical components in a circuit when charge carriers pass through them. We use a voltmeter to measure the potential difference (or voltage).

The potential Difference formula:** V = I x R**

The potential difference (which is the same as voltage) is equal to amount of current multiplied by the resistance. A potential difference of one Volt is equal to the one Joule of energy being used by one Coulomb of charge when it flows between two points in a circuit.

For the above question:

The kinetic energy K given to helium nucleus is equal to its potential energy, which is

E=q ∆ V

where q=2e is the charge of helium nucleus, and  is the potential difference applied to it.

Since we know kinetic energy, we have

E= K= 75 keV= q ∆ V

and from this we can find potential difference:

∆V= K/q= 75keV/2e= 37.5 kV

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The net force is in the first case is 13 N and in the second case is 55 N.

All mass-bearing objects are attracted by gravitational force. Because it consistently attempts to bring masses together rather than push them apart, the gravitational force is referred to as attractive.

As we know, the gravitational force is given by:

[tex]\rm F = \dfrac{Gm_1m_2}{r^2}[/tex]

Where G is the gravitational constant.

m1 and m2 are masses.

r is the distance between the masses.

It is given that:

Two forces are given:

The two forces act in opposite directions:

= 34 - 21

= 13 N

Both forces act in the same direction:

= 34 + 21

= 55 N

Thus, the net force is in the first case is 13 N and in the second case is 55 N.

The question is incomplete the complete question is:

find the strength of the net force produced by a 34-n force and a 21-n force in each of these cases.

The two forces act in opposite directions.

Both forces act in the same direction.

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Answer:

Neither of the two options.

Explanation:

Before a bullet is fired, the momentum of the bullet-gun system is zero because of lack of velocity. After the gun is fired, both gun and bullet acquire velocity making them nonzero. Thus, it is impossible for the kinetic energy to be zero because both the bullet and the gun are in motion. Also, the momentum is nonzero momentum is the product of the mass of an object and its corresponding velocity. Once the bullet is fired, both the bullet and the gun gains momentum thus making it nonzero.

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Yes the motion is accelerated.

We have a artificial satellite that moves at a steady 25,000 km/hr in a circular orbit around earth.

We have to determine whether or not it is accelerated.

An artificial Satellite is a man - made artificial body placed in orbit round the earth or moon or another planet in order to collect information or for communication.

According to the question -

v = 25000 km/hr

Now for the motion to be accelerated the velocity must change with respect to time. But, the velocity here is constant. It should be kept in mind that the velocity is a vector quantity, its magnitude is constant but its direction keeps on changing in circular motion, and hence, its acceleration also changes.

Hence, yes the motion is accelerated.

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a. The Earth's average speed relative to the Sun is 2970 m/s

b. The earth's average velocity over a period of one year is 0 m/s

The speed of the earth relative to the sun is given by v = √(GM/r) where

Substituting the values of the variables into the equation, we have

v = √(GM/r)

v = √(6.67 × 10⁻¹¹ Nm²/kg² × 1.989 × 10³⁰ kg/1.5043 × 10¹¹ m)

v = √(13.26663 × 10¹⁹ Nm²/kg/1.5043 × 10¹¹ m)

v = √(8.8191 × 10⁸ Nm²/kg)

v = 2.97 × 10⁴ m/s

v = 2970 m/s

So, the Earth's average speed relative to the Sun is 2970 m/s

The average velocity of the Earth is v = ΔD/T where

Now, since the earth starts and stopps at the same position, D' = D.

So, ΔD = D' - D = 0

Substituting the values of the variables into the equation, we have

v = ΔD/T

v = 0 m/3.1536 × 10⁸ s

v = 0 m/s

So, the earth's average velocity over a period of one year is 0 m/s

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The additional time pass before the ball passes the tree branch on the way back down is 1.913 .

Consider the displacement equation

s(t) = (-g/2)t^2 + v(0)t + s(0)

where g = 9.8 m/s/s is the acceleration due to gravity,

v(0) = 15 m/s is the initial velocity, and

s(0) = 0 is the staring position (the ground).

We want to know when s(t) = 7 m. Thus,

7 = (-9.8/2)t^2 + 15t

We solve for t by solving the quadratic

(-9.8/2)t^2 + 15t - 7 = 0

Using the Quadratic Formula, we get the two roots

t1 = .574 seconds

t2 = 2.487 seconds

These two values represent the times when the ball passes the tree branch. Therefore, the total time between passing the branch is the difference between 2.49 seconds and 0.57 seconds.

Thus, the ball is at 7 meters at both times. The additional time after the first instance is

d = t2 - t1 = 2.487 - .574 = 1.913 seconds

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The sine components of the velocity of the boat will balance out the velocity of the river making an angle of 37° with the vertical.

Every vector can be broken into some components, these components on vector addition would again give the resultant vector.

The components of the vector act independently.

Given:

Velocity of the boat in still water = 20km/h

Velocity of the river stream= 12km/h

We want the boat to go directly opposite to the starting point without any drift. For this one component of the boat's speed should be acting parallel to the speed of the stream and cancelling its effect in the motion of the boat.

Therefore preventing the drift of the boat now with the other perpendicular speed vector component the boat will cross the river.

Assumption:

The boat goes at an angle p with the vertical or perpendicular to the river stream.

v is the resultant speed of the boat

u is the velocity of the stream

According to the question:

v × sin(p) = u

Sin(p) = 0.6

p = 37°

Therefore, The sine components of the velocity of the boat will balance out the velocity of the river making an angle of 37° with the vertical.

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Answer:

671.22 mi/hr

Explanation:

[tex](\frac{300 m}{s} )(\frac{1mi}{1609m} )(\frac{3600s}{1hr} )=\frac{(300)(3600)}{1609} =671.22mi/hr[/tex]

Hope this helps

Answer:

rgg3ge4gg434g4g4g4g44g

Explanation:

grg4g4g4y44h44h

Energy for this electronic transition is ΔE=0.572eV frequency is ν=1.38×[tex]10^{14}[/tex] [tex]s^{-1}[/tex] and wavelength is 2.17×[tex]10^{-6}[/tex] m

The Bohr Model for the energy of an electron in a hydrogen atom gives us:

E=−[tex]\frac{13.6}{n^{2} }[/tex] eV

Where n is the principle quantum no

For the transition 7→4 the difference in energy is given by:

ΔE= -[tex]\frac{13.6}{49}[/tex]+[tex]\frac{13.6}{16}[/tex] eV

ΔE=0.85-0.277

ΔE=0.572eV

To convert this to Joules we multiply by the electronic charge:

ΔE=0.572×1.6×[tex]10^{-19}[/tex]=9.16×[tex]10^{-20}[/tex]J

(b)

To find the frequency of the emitted photon we use the Planck expression:

ΔE=hν

∴ν=ΔE/h=(9.16×[tex]10^{-20}[/tex])÷(6.626×[tex]10^{-34}[/tex])[tex]s^{-1}[/tex]

ν=1.38×[tex]10^{14}[/tex] [tex]s^{-1}[/tex]

To find the wavelength

λ=c/ν

(3×[tex]10^{8}[/tex])/(1.38×[tex]10^{14}[/tex]) m

=2.17×[tex]10^{-6}[/tex] m

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Answer:

It would crash into the thing it's orbiting.

Explanation:

Since it's not going fast enough to counter the pull of gravity.

The period of pendulum is still the same at 1.4 seconds.

We need to know about pendulum experiment to solve this problem. The pendulum is a simple experiment to calculate gravitational acceleration. The gravitational acceleration can be calculated by

g = 4π² . L / T²

where g is gravitational acceleration, L is the length of the string and T is the period.

From the question above, we know that:

L = 0.5 meters

m1 = 1 kg

θ = 12⁰

m2 = 2 . m1

T1 = 1.4 seconds

Find the period of pendulum

g = 4π² . L / T²

T² = 4π² . L / g

T = √(4π² . L / g)

The period of a pendulum does not depend on the mass of the object, hence the period is still the same at 1.4 seconds.

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At the speed of 0.44 c as a fraction of c, the moving rod will have a length of 80% that of an identical rod at rest.

The speed of the light is c.

c = 3.0 × 10⁸ m/a

Let the length of the moving rod be L.

Let the length of the rod at rest be l.

Length contraction of the rod is,

[tex]L= \sqrt{ 1 - \frac{ v ^{2} }{c ^{2} } \times l} [/tex]

The length of the moving rod is,

Length of moving road = 80% of the length of the rod at rest.

L = 80 % of the l.

[tex] = \frac{80}{100} [/tex]

= 0.80 l

The moving rod will have a length 80% that of an identical rod at rest at the speed of,

[tex]L ^{2} = (1 - \frac{ v ^{2} }{c ^{2} } )\times l ^{2} [/tex]

[tex] \frac{L ^{2}}{l ^{2} }= (1 - \frac{ v ^{2} }{c ^{2} } )[/tex]

[tex]v ^{2} = (1 - \frac{L ^{2}}{l ^{2} }) \: {c^{2} } [/tex]

[tex]v ^{2} = ( \sqrt{1 - \frac{L ^{2}}{l ^{2} }}) \: {c^{2} } [/tex]

[tex]= ( \sqrt{ 1 - \ \frac{0.80 \: l^{2}}{l ^{2} }}) \: {c^{2} } [/tex]

[tex] = \sqrt{( 1 - 0.80) } c[/tex]

v = 0.44 c

Therefore, at the speed of 0.44 c as a fraction of c, the moving rod will have a length of 80% that of an identical rod at rest.

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(a) The moment about B is 800 lb.in

(b) The magnitude of the force P is 51.3lb

(c) The smallest force P is 44.4lb

(a)

As we know,

[tex]M_{B} = r_{CIB}F_{N}[/tex]

[tex]M_{B}[/tex] = [tex]4[/tex] × [tex]200[/tex]

= 800 lb.in

The moment about B is 800 lb.in

(b)

By using the formula,

[tex]M_{B} =r_{AIB}Psin[/tex]θ

θ = 120°

Then, [tex]800[/tex] = [tex]18[/tex] × [tex]Psin120[/tex]°

P = 51.3lb

The magnitude of the force P is 51.3lb

(c)

P must be perpendicular to the line connecting points A and B in order for it to be minimal.

Using the formula,

[tex]M_{B} = dP_{min}[/tex]

[tex]800[/tex] = [tex]18[/tex] × [tex]P_{min}[/tex]

[tex]P_{min}[/tex] = 44.4lb

The smallest force P is 44.4lb

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