A man lifts a 5 Newton bag of groceries
from the floor to the top of the countertop,
which is 1.1 meters tall. What is the work
done by this person in lifting groceries?
5
5.5
4.5
6
Greg can't remember how tall his 9-month-old niece is. He guesses that she is 100 cm tall. Which of the following is true?
Age (months)
Height (cm)
3 61.1
6 67.8
9 72.3
12 76.1
A.
Based on the data, Greg's guess is reasonable.
B.
Based on the data, Greg's guess is not reasonable.
C.
Based on the data, Greg's niece should be around 61.1 cm tall.
D.
Based on the data, Greg's niece should be around 76.1 cm tall.
Answer:
C
Explanation:
A battery causes a current of 2.0 A to flow through a lamp. The power used by the lamp is 12 watts. What is the voltage?
Answer:
6 v
Explanation:
David put a plant in a black box as shown. The box also had a black lid to cover the front. David only opened the box to add water to the plant. The plant stayed in the box for 10 days. When David took the plant out of the box on the tenth day, the plant was dead. Why did the plant dead only after ten days in the box?
Answer:
the plant died because of lack of sunlight
Explanation:
A plant gets its food from the photosynthesis process, which combines CO₂ and H₂0 into carbohydrates, the two substances are in the box, but for this they need energy from sunlight.
CO₂ + H₂O + Sunlight /chlorophyll → (CH₂0)ₙ + O₂
the extra oxygen is released into the atmosphere.
Therefore the plant died because of lack of sunlight
3. The coefficient of kinetic friction between an object and the surface upon which it is sliding is
0.40. The mass of the object is 3,2 kg. What is the force of friction?
Answer:
2
Explanation:
A rocket pushes exhaust 10, 000 N. Without any other forces acting on the rocket, how much force does the rocket go forward? *
Answer:
10,000 N
Explanation:
Given that a rocket pushes exhaust 10, 000 N. Without any other forces acting on the rocket, how much force does the rocket go forward?
Solution
Since there is no any other additional forces, according to Newton's 3rd law of motion which state that:
In every action there will be equal and opposite reaction.
The action expelled by the rocket through its exhaust system is of 10000N.
The reactive force will be equal and opposite which will be same -10,000 N
Therefore, the rocket will go forward with a force of magnitude 10,000 N
PLZZ IF ANYONE KNOWS SCIENCE HELP ME PLZ I this is so confusing :(
ill liderally make a question with 50 and a brainliest since you helped me ;-;
Answer:
i think it would be either b or c because....
Explanation:
"The desert biome is best adapted for aloe because aloe plant usuallly grows in open area under sunlight exposure where the intensity of sunlight is very high. Its grows in very rocky, dry and open areas."
Which is an example of a trace fossil?
animal burrow
skin of organism
preserved bone
petrified wood
Answer: The correct answer is A). Animal burrow because burrow fossils represent the preserved byproducts of behavior rather than physical remains, they are considered a kind of trace fossil. One common kind of burrow fossil is known as Skolithos, and the similar Trypanites, Ophiomorpha and Diplocraterion.
Animal burrow is an example of a trace fossil.
What is fossil?The preserved remnants of plants and animals that were submerged in sediments like sand and mud beneath ancient seas, lakes, and rivers are known as fossils. Any preserved sign of life that is typically older than 10,000 years is considered a fossil.
After death, soft body parts degrade quickly, while hard body parts, including bones, shells, and teeth, can be replaced by minerals that solidify into rock. Soft components like feathers, ferns, or other signs of life, such footprints or faeces, may also be preserved in extremely rare circumstances. Both less familiar fossils like ammonites and trilobites as well as microscopic-sized ones like single-celled foraminifera or pollen grains can be found in the remains.
What is trace fossil?A trace fossil, also known as an ichnofossil, is a record of biological activity preserved in the fossil record but without the actual preserved plant or animal remains. Contrasting with body fossils, which are the preserved remains of portions of an organism's body that were typically modified by later chemical activity or mineralization, are trace fossils. Ichnology, the study of such trace fossils, is the field of study of iconologists.
Learn more about geology here:
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Assume you have a person with a mass of 65 kg riding a skateboard down a ramp. While they are
still 4.8 m high, they are traveling at a speed of 8.0 m/s.
a) Calculate the Eg. [write here]
b) Calculate theEk [write here]
c) Calculate the Etotal. [write here)
Answer:
a) Eg = 3,060.72 j
b) Ek = 2,080 j
c) Etotal = 5,140.72 j
Explanation:
The given parameters are;
The mass of the person, m = 65 kg
The height of the person, h = 4.8 m
The speed of the person, v = 8.0 m/s
a) The gravitational potential energy, [tex]E_g[/tex] = m·g·h
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
∴ Eg = 65 kg × 9.81 m/s² × 4.8 m = 3,060.72 j
Eg = 3,060.72 j
b) The kinetic energy, Ek = 1/2·m·v²
∴ Ek = 1/2 × 65 kg × (8.0 m/s)² = 2,080 j
Ek = 2,080 j
c) The constant total Mechanical Energy, Etotal = Eg + Ek
∴ Etotal = 3,060.72 j + 2,080 j = 5,140.72 j
Etotal = 5,140.72 j.
Help plz for 25 points !! I only have an hour left !
When the number of gas particles at a constant pressure decreases how will the volume of the gas change?
Function: y = x2 + 5x - 7
Vertex:(
Solutions:(
and
Answer:=7x−7
Explanation:
=2x+5x+−7
=(2x+5x)+(−7)
=7x+−7
what is the name often given to the force exerted by the first objection a second object
Answer:
Newton's Third Law
Explanation:
When one object exerts a force on another object, the second object exerts a force on the first object that is equal in magnitude, but opposite in direction; for every action, there is an equal, but opposite reaction; called the law of action-reaction.
If a 12 kg object's velocity changes from 5 m/s to 10 m/s in 5 s, what amount of force was applied to increase the speed of the object?
Answer:
12 N
Explanation:
Given that a 12 kg object's velocity changes from 5 m/s to 10 m/s in 5 s, what amount of force was applied to increase the speed of the object?
Solution
M = 12 kg
T = 5 s
The formula to use will be
F = ma
Where
Acceleration a = change in velocity/ time
Acceleration a = ( 10 - 5 ) / 5
Acceleration a = 5 / 5
Acceleration a = 1 m/s^2
Substitutes a into the formula above
F = ma
F = 12 × 1
F = 12 N
Therefore, the amount of force applied to increase the speed of the object is 12 N.
Un acróbata de masa M, se impulsa hacia arriba con una velocidad v0 desde un
trampolín. Mientras sube, a una altura h sobre el trampolín, recoge a un mono entrenado de masa m. ¿Cuál es la altura máxima que alcanzan el mono y el acróbata?
Answer:
La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].
Explanation:
Asumamos que tanto el acróbata, el mono y el sistema acróbata-mono son conservativos y que el acróbata comienza su acción a una altura de cero. El estudio se divide en dos etapas: (i) El acróbata se dirige al mono, (ii) El acróbata recoge al mono y alcanzan una altura máxima.
Para resolver esta cuestión, nos valemos del Principio de Conservación de la Energía.
Parte I
La energía cinética traslacional inicial ([tex]K_{1,a}[/tex]) es igual a la suma de la energía cinética traslacional final ([tex]K_{2, a}[/tex]) y la energía potencial gravitacional final ([tex]U_{g,2,a}[/tex]).
[tex]K_{1,a} = K_{2,a} + U_{g,2,a}[/tex] (1)
[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex] (1b)
Donde:
[tex]M[/tex] - Masa del acróbata.
[tex]g[/tex] - Constante gravitacional.
[tex]v_{o}[/tex] - Rapidez inicial del acróbata.
[tex]v_{1}[/tex] - Rapidez del acróbata justo antes de recoger al mono.
[tex]h[/tex] - Altura inicial del mono.
Parte II
La suma de las energías iniciales cinética traslacional ([tex]K_{2, a}[/tex]) y potencial gravitacional de acróbata ([tex]U_{g,2,a}[/tex]) y la energía inicial potencial gravitacional del mono ([tex]U_{g,2,m}[/tex]) es igual a la suma de las energías potenciales gravitacionales iniciales del sistema acróbata-mono ([tex]U_{g,3,a+m}[/tex]), es decir:
[tex]K_{2,a} + U_{g,2,a}+U_{g,2,m} = U_{g,3,a+m}[/tex] (2)
[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex] (2b)
Donde:
[tex]m[/tex] - Masa del mono.
[tex]z[/tex] - Altura máxima del sistema acróbata-mono.
De (1b) tenemos que la rapidez del acróbata justo antes de recoger al mono es:
[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex]
[tex]v_{o}^{2} = v_{1}^{2}+2\cdot g\cdot h[/tex]
[tex]v_{1} = \sqrt{v_{o}^{2}-2\cdot g\cdot h}[/tex]
Finalmente, la altura máxima alcanzada por el sistema acróbata-mono es:
[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex]
[tex]z = \frac{M\cdot v_{1}^{2}}{2\cdot (M+m)\cdot g}+h[/tex]
[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot (v_{o}^{2}-2\cdot g\cdot h)+ h[/tex]
[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex]
La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].
what type of charge will an object have if the object contains less protons than electrons?
Answer:
Hello, I believe it would have a negative charge considering protons have a positive charge while elctrons have a negative charge
Explanation:
What are some ways I can have a good wardrobe without breaking the bank?
Which of the following are strategles that will help you in the process of losing weight?
-watch TV while eating
-monitor your progress
-go to restaurants often to build your will power
- inform your friends about your
weight-loss plan
what two factors directly affect the acceleration of an object?
The acceleration of an object depends on the mass of the object and the amount of the force applied to it. It states that the acceleration of an object increases with increased force and decreases with increased mass.
2-Write True(T) if the sentence is true. Write False(F) if the sentence is
false.
Momentum is a measure of the motion of a body equal to the product of its
mass and acceleration due to gravity.
Impulse is defined as the force times the time interval.
The tendency of an object to resist a change in motion is called Force
If the speed of an object is doubled, its momentum is multiplied by 2
Sudden change in momentum in a collision, results in a large force that can
cause injury.
Safety features of modern cars ensures that energy is not absorbed when vehicles
stop:
Crumple zones are built into cars to increase the duration of crashes.
Calculate the total momentum of the three-sphere system if the three spheres are swung at −1.0 msto the left.
Answer:
, pfx = pix + Jx.
Explanation:
The momentum principle tells us that impulse transfers momentum to an object.
If an object has 2 kgm/s of momentum, a 1 kgm/s impulse delivered to the object
increases its momentum to 3 kgm/s. That is, pfx = pix + Jx.
Just as we did with energy, we can represent this “momentum accounting” with a
momentum bar chart. For example, the bar chart of FIGURE 11.6 represents the ball
colliding with a wall in Figure 11.4. Momentum bar charts are a tool for visualizing
an interaction
Me file can walk a distance of 300 meters in 60 seconds. What is his speed
Answer:
5 m/s
Explanation:
use speed=distance/time
300/60=5
The energy transferred to the water in 100 seconds was 155 000 J. specific heat capacity of water = 4200 J/kg °C
Determine the mass of water in the kettle.
Use Figure 10.
Give your answer to 2 significant figures.
Any help would be appreciated
Answer:
0.37 kg
Explanation:
I'm not a professor myself, but this is how I worked it out:
using the graph, after 100 seconds, the temperature is 100 degrees Celsius.
If we now substitute everything into the specific heat capacity equation, making the mass "m", we would come up with:
4200 = 155000/(m x 100)
If we rearrange and solve for m, we get 0.37 kg.
I'm not sure if I have done this correctly, feel free to correct me.
Hope this helps!
By using the specific heat capacity formula, the mass of water in the kettle is 0.47 kg
Give that the energy transferred to the water in 100 seconds was 155 000 J and the specific heat capacity of water = 4200 J/kg °C
From the graph;
The initial temperature of the water at time zero is 22 degree Celsius
The final temperature of the water at time 100s is 100 degree Celsius
Change in temperature (T) = 100 - 22 = 78 degree Celsius
To determine the mass of water in the kettle, use the heat energy formula below
E = mcT
Substitute all the parameters into the equation
155000 = 4200 x 78 M
Make M the subject of the formula
M = 155000/327600
M = 0.47 kg
Therefore, the mass of water in the kettle is 0.47 kg
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Calculate the weight of a 2.3 kg squirrel
Answer:
Lemme think rq
*inserts writing noises*
*insert intese thinking*
*insert big brain moment*
Well the weight IS 2.3 kg so I think the weight of a squirrel is 2.3 kg
What variable do you think made this airplane fly the farthest?
Answer:
How does the weight of the nose on a paper
airplane affect the distance it will travel
when measured in centimeters?
EXPERIMENT CONCLUSION: (Explain whether or
not your data supports, or fails to support your identified
prediction. Explain why, including facts and details!)
The distance did increase when I added 1 paper clip.
However, I was surprised that the distance decreased
when I added a second paper clip. I believe this
happened because the nose of the plane became too
heavy. When the plane was released, the nose of the
plane descended much quicker. I think the plane was
more balanced in weight when only 1 clip was on the
nose.
A SOUND WAVE WITH ITS CHARACTERISTIC PATTERN OF COMPRESSIONS AND
RAREFACTIONS IS SHOWN BELOW. A CENTIMETER RULER IS INCLUDED BELOW THE
PATTERN THE WAVELENGTH OF THIS SOUND WAVE IS HOW MANY cm?
A 2 cm
B 3 cm
C 35 cm
D. 85 cm
וייייייייייייייייי
U
0
1
2
3
4
5
6
7
8
9
10
Answer:
The wavelength is 1.7cm
Explanation:
Given
See attachment for wave pattern
Required
What is the wavelength
To do this, we simply calculate the distance between successive waves (see attachment 2 for point A and B)
Using the ruler, points A and B are at:
[tex]A = 0.6cm[/tex]
[tex]B = 2.3cm[/tex]
So, the wavelength is:
[tex]\lambda = B - A[/tex]
[tex]\lambda = 2.3cm - 0.6cm[/tex]
[tex]\lambda = 1.7cm[/tex]
If approximated, the wavelength is:
[tex]\lambda \approx 2cm[/tex]
Three resistors of 4.0 ohms, 6.0 ohms, and 12 ohms are connected in parallel to an applied potential difference of 12 volts. (1) Calculate the equivalent resistance. (2) Determine the potential difference across each resistor. (3) Calculate the current through each resistor.
Answer:
(1) 2 ohms
(2) 12 Volts Across each resistor
(3) I₁ = 3 A, I₂ = 2 A, I₃ = 1 A
Explanation:
From the question,
(1) Equilvalent Resistance (Rt) for parallel connection is
1/Rt =(1/R₁)+ (1/R₂) + (1/R₃)
Where R₁ = 4 ohms, R₂ = 6 ohms, R₃ = 12 ohms
1/Rt = 1/4 +1/6 +1/12
1/Rt = (3+2+1)/12
1/Rt = 6/12
1/Rt = 1/2
Rt = 2 ohms.
(2) Since the resistors are connected in parallel, They will have the same potential difference across them,
Hence the P.d across each resistor = 12 Volts.
(3) For R₁,
I₁ = V/R₁ = 12/4
I₁ = 3 A.
For R₂,
I₂ = V/R₂
I₂ = 12/6
I₂ = 2 A
For R₃,
I₃ = V/R₃
I₃ = 12/12
I₃ = 1 A
Volleyball took some of its characteristics from handball and tennis
True
False
Answer:
True Because if we observe carefully we will see that some moves of volleyball are similar to handball and tennis
An 80 kg runner has 3,000 J of kinetic energy. What is her velocity in m/s?
Answer: 8.6m/s
Explanation:From KE=1/2mv^2
In order to make v the subject of the formula we divide both sides by 1/2m. Thus V^2 will be left alone on the RHS. But we are looking for v and not v^2. Thus we find the square root of KE1/2m
Meaning V= sqrt[3000÷1/2 of 80]
=sqrt[3000÷40]
=sqrt(75)
=8.6m/s
A machine designed to stretch a stiff spring uses 1,550 J of energy to stretch the spring. If the work output is 1,200 J, what is the machine’s efficiency?
Answer:
77%
Explanation:
efficiency= work output/work input X 100%
e = 1,200j/ 1,550 j x100%
e = 1,200/1,550= 0.77
e = 0.77 x 100%
e = 77%