Answer:
c
Explanation:
:)
Users of E85 see a drop in gas mileage because ethanol can't produce the same
amount of energy gasoline can. How much of a drop do they see?
Select one:
a. They see a 10-20% drop in gas mileage
b. The statement is wrong. There is no drop in gas mileage.
c. They see a 30-40% drop in gas mileage
d. They see a 20-30% drop in gas mileage
Answer:
A
Explanation:
Due to ethanol's lower energy content, FFVs operating on E85 get roughly 15% to 27% fewer miles per gallon than when operating on regular gasoline, depending on the ethanol content.
Sarah and Raj take/takes me to a baseball game every year.
Either the Cubs or the Orioles play/plays the Yankees tonight.
There is/are nine players on a baseball team.
The home team sit/sits in the dugout on the third-base side of the field.
One of the players called the catcher crouch/crouches behind home plate
I learned how to play soccer from my sister.
Last year, I bought myself season tickets to the local team’s matches.
Only the goalie can use their hands to catch the ball.
The players must quickly move the ball down the field.
This year, my sister gave me my favorite player’s jersey for Christmas.
Answer:
take
play
are
sits
crouches
direct
indirect
direct
direct
indirect
Explanation:
i had just taken the test
Select the correct answer. Which statement best describes a hydrogen fuel cell? A This device uses bioethanol as an additive to power an automobile. B. O C. This device uses photovoltaic cells to capture solar energy and generate electrical energy from it. This device uses fossil fuels to generate heat energy that machines can then convert into mechanical energy. This device converts the chemical energy of hydrogen into electricity through a chemical reaction with oxygen or another oxidizing agent. O D. E. This device converts the kinetic energy of an electric turbine into electricity based on Faraday's law.
Answer:
Explanation:
The correct answer is "D. This device converts the chemical energy of hydrogen into electricity through a chemical reaction with oxygen or another oxidizing agent."
A talks about bio-ethanol fuel.
B is solar.
C is fossil.
E is electricity generation.
Answer:
Explanation:
ans is:
This device converts the chemical energy of hydrogen into electricity through a chemical reaction with oxygen or another oxidizing agent. O D
This String method removes beginning and ending spaces of the given string.
Solactone
Answer:
The trim() method will remove both leading and trailing whitespace from a string and return the result. The original string will remain unchanged. If there is no leading or trailing whitespace to be removed, the original string is returned. Both spaces and tab characters will be removed.
This is very useful when comparing user input with existing data. A programmer often racks his brain for hours trying to figure out why what he enters is not the same as a stored string, only to find out that the difference is only a trailing space. Trimming data prior to comparison will eliminate this problem.
Answer:
String result = str. trim(); The trim() method will remove both leading and trailing whitespace from a string and return the result.
Explanation:
The electron concentration in silicon at T = 300 K is given by
n(x) = 10^16exp(-x/18) cm^-3
where x is measured in μm and is limited to 0 ≤ x ≤ 25 μm. The electron diffusion coefficient is Dn = 25 cm2/s and the electron mobility is μn = 960 cm2/V-s. The total electron current density through the semiconductor is constant and equal to Jn = -40 A/cm2. The electron current has both diffusion and drift current components. Determine the electric field as a function of x which must exist in the semiconductor.
Answer:
[tex]E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m[/tex]
Explanation:
From the question we are told that:
Temperature of silicon [tex]T=300k[/tex]
Electron concentration [tex]n(x)=10^{16}\exp (\frac{-x}{18})[/tex]
[tex]\frac{dn}{dx}=(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})[/tex]
Electron diffusion coefficient is [tex]Dn = 25cm^2/s \approx 2.5*10^{-3}[/tex]
Electron mobility is [tex]\mu n = 960 cm^2/V-s \approx0.096m/V[/tex]
Electron current density [tex]Jn = -40 A/cm^2 \approx -40*10^{4}A/m^2[/tex]
Generally the equation for the semiconductor is mathematically given by
[tex]Jn=qb_n\frac{dn}{dx}+nq \mu E[/tex]
Therefore
[tex]-40*10^{4}=1.6*10^{-19} *(2.5*10^{-3})*(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})+(10^{16}\exp (\frac{-x}{18}))*1.6*10^{-19}*0.096* E[/tex]
[tex]E=\frac{-2.5*10^-^7 exp(\frac{-x}{18})+40*10^{4}}{1.536*10^-4exp(\frac{-x}{18} )}[/tex]
[tex]E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m[/tex]
Heat transfer from a transistor may be enhanced by
inserting it in an aluminium sleeve (k = 200 W/m −
K) having integrally machined longitudinal fins on its
outer surface. Transistor radius and height are r1 =
2 mm & H = 6 mm respectively, while the fins are of
length L = r3 − r2 = 10 mm of uniform thickness t =
0.7 mm. The thickness of the sleeve base is r2 − r1 =
1 mm. Contact resistance of the sleeve transistor
interface is Rt,c
′′ = 10−3 m2
.K/W. Air at T∞ = 20°C
flows over the fin surface providing uniform
convection with h = 25 W
m2−K
. Assume 1-D radial heat
transfer,
a) Sketch the equivalent thermal circuit for heat
transfer from transistor case (r = r1) to the air.
Label each resistance. [1]
b) Evaluate each resistance. [2]
c) If the temperature of the transistor case is T1 = 80 °C, what is the rate of heat transfer from
the sleeve?
Answer:
Heat transfer from a transistor may be enhanced by
inserting it in an aluminium sleeve (k = 200 W/m −
K) having integrally machined longitudinal fins on its
outer surface. Transistor radius and height are r1 =
2 mm & H = 6 mm respectively, while the fins are of
length L = r3 − r2 = 10 mm of uniform thickness t =
0.7 mm. The thickness of the sleeve base is r2 − r1 =
1 mm. Contact resistance of the sleeve transistor
interface is Rt,c
′′ = 10−3 m2
.K/W. Air at T∞ = 20°C
flows over the fin surface providing uniform
convection with h = 25 W
m2−K
. Assume 1-D radial heat
transfer,
Explanation:
Explain the importance of wearing appropriate protective clothing and equipment (PPE), and keeping the work area safe and tidy
Answer:
The wearing of appropriate protective clothing and equipment (PPE) and the keeping of the work area safe and tidy achieve the following for the employees and employers: safety from physical and biological harm that may occur as a result of their contact with the work environment; reduces the cost of insurance and other risk management activities.
Explanation:
The personal protective equipment (PPE) is a safety equipment that protects workers from health or safety risks at their various workplaces. The main purpose is to reduce the workers' exposure to environmental hazards. PPE reduces accidents, improves the health of workers, and reduces the spread of contagious diseases. Above all, it creates safe, secure, and healthy work environments for all.
A venture tube is used to measure the flow rate of a liquid in a pipe (liquid density is 800 kg/m3). The pipe has a diameter of 10 cm and the smallest diameter of the venture has a diameter of 4 cm. A manometer with a manometer fluid of mercury (specific weight of 133 kN/m3) is used to calculate the flow rate which is connected to the venture section such that one leg is far upstream and the second leg is at the minimum diameter of the venture tube. If the flow rate is 0.05 m3/s determine the elevation change in the manometer fluid.
a. 14.6 m
b. 9.28 m
c. 4.64 m
d. 2.32 m
Answer:
[tex]\triangle h=4.935m[/tex]
Explanation:
From the question we are told that:
Liquid density [tex]\rho=800[/tex]
Diameter of pipe [tex]d=4cm \approx 0.004m[/tex]
Diameter of venture [tex]d=10cm \approx 0.010m[/tex]
Specific weight of mercury P_mg [tex]133 kN/m^3[/tex]
Flow rate [tex]r=0.05 m^3/s[/tex]
Area A:
[tex]A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\[/tex]
Generally the Bernoulli's equation is mathematically given by
[tex]\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\[/tex]
Where
[tex]V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}[/tex]
Therefore
[tex]P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})[/tex]
Generally the equation for pressure difference b/w manometer fluid is given as
[tex]P_1-P_2=(p_mg-pg)\triangle h[/tex]
Therefore
[tex](p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})[/tex]
[tex]\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}[/tex]
[tex]\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}[/tex]
[tex]\triangle h=4.935m[/tex]
Therefore elevation change is mathematically given by
[tex]\triangle h=4.935m[/tex]
A continuous and aligned hybrid composite consists of aramid and glass fibers embedded within a polymer resin matrix. Compute the longitudinal modulus of elasticity of this material if the respective volume fractions of the aramid and glass fibers are 0.24 and 0.28, given the following data:
Material Modulus of Elasticity (GPa)
Polyester 2.5
Aramid fibers 131
Glass fibers 72.5
(A) 5.06 GPa
(B) 32.6 GPa
(C) 52.9 GPa
(D) 131 GPa
Answer:
probably b but not sure
Explanation:
The longitudinal modulus of elasticity of this material if the respective volume fractions of the aramid and glass fibers are 0.24 and 0.28, given the following data is 32.6 GPa.
What is elasticity?Elasticity is defined as after the forces producing the deformation are eliminated, a material body that has been distorted has the ability to revert to its original size and shape. Metals' atomic lattices undergo size and form changes when forces are applied. When forces are removed, the lattice returns to its initial, lower energy condition. Rubbers and other polymers are elastic because stretching of polymer chains occurs when forces are applied.
Longitudinal modulus are defined as the proportion of a material's length change caused by applied force to its initial length. Young's modulus is a measurement of a material's capacity to endure changes in length when subjected to compression or tension along its length.
Thus, the longitudinal modulus of elasticity of this material if the respective volume fractions of the aramid and glass fibers are 0.24 and 0.28, given the following data is 32.6 GPa.
To learn more about elasticity, refer to the link below:
https://brainly.com/question/28790459
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