Answer: d
Explanation: took the test got it right
A solution of nitric acid has a [H3O+] = 2.8 x 10-6 M. What is the pH?
Answer:
5.55
Explanation:
see explanation attached
hope it helps
Why do atoms connect to eachother?
Answer:
To keep from falling apart
Explanation:
How many moles of solute are in 53.1 mL of 12.5M HCI?
which wet land is known for the large trees in the water known as bottomland hardwoods?
A. Central Texas
B.South Texas
C. East texas
The tablets were crushed, and 4.9993 g of the powder was transferred to a beaker and reacted with HCl. After filtration, the filtrate was transferred to a 100-mL volumetric flask and diluted with water. 20.00 mL of this stock solution were combined with 0.2 M Na3PO4. The resulting precipitate weighed 0.3451 g after drying. Calculate the moles of BiPO4 precipitated, the moles of Bi3 in the stock solution, and the mass of BSS per tablet.
Answer:
Explanation:
From the information given:
Mass of BiPO₄ = 0.3451 g
Number of moles of BiPO₄ = [tex]0.3451 \ g \ BiPO_4 \times \dfrac{1 \ mol \ BiPO_4}{303.95 \ g \ BiPO_4}[/tex]
[tex]= 0.001135 \ mol[/tex]
The number of moles of Bi³⁺ in 20.00 mL is:[tex]= 0.001135 \ mol \ BiPO_4 \times \dfrac{1 \ mol \ of \ Bi^{3+}}{1 \ mol \ BiPO_4}[/tex]
= 0.001135 mol of Bi³⁺
The number of moles of Bi³⁺ in 100 mL stock solution
[tex]= 0.001135 \ mol \ Bi^{3+} \times \dfrac{100 \ mL}{20.0 \ mL}[/tex]
[tex]= 0.005675 \ mol[/tex]
Mass of BSS in 4.9993 g tablets
[tex]m = 0.005675 \ mol \ Bi^{3+} \times \dfrac{1 \ mol \ BSS}{1 \ mol \Bi^{3+}} \times \dfrac{362.1 \ g \ BSS}{1 \ mol \ BSS}[/tex]
m = 2.055 g BSS
Mass of BSS in 5.0103 g (5 tables)
[tex]m = 2.055 g \ BSS \times \dfrac{5.0103 \ g}{4.9993 \ g}[/tex]
= 2.06 g
∴
The mass of BSS per tablet is [tex]=\dfrac{2.06 \ g}{5 \ tablet}[/tex]
= 0.412 g BSS/ tablet
Sandy is conducting an investigation to find out which
food his dog likes best. Which is the dependent variable
in his investigation?
color of the
dog's dish
BROWN
amount of
food eaten
the type of
food given
PINK
LIGHT GREEN
Answer: Whats the question?
A balloon originally has 0.100 moles of helium and has a volume of 0.500 L. If 0.590 grams of He are added to the balloon, what will the new volume be, in L? (Assume temperature and pressure do not change.)
Answer:
1.24 L
Explanation:
Avogadro's Law
[tex]\frac{V_{1} }{n_{1} } = \frac{V_{2} }{n_{2} }[/tex]
Convert 0.590 g of He to moles.
0.590 g x (1 mol/4.00 g) = 0.1475 mol He
Add 0.1475 mol to 0.100 mol since the initial moles (n1) increases by this amount.
0.100 mol + 0.1475 mol = 0.2475 mol He
This will represent the final moles (n2)
The initial volume is given, 0.500 L. Plug in the values.
[tex]\frac{0.500 L}{0.100 mol} = \frac{V_{2} }{0.2465 mol}[/tex]
[tex]V_{2} = \frac{(0.500 L)(0.2475 mol)}{(0.100 mol)} \\V_{2} = 1.2375\\V_{2} = 1.24 L[/tex]
Taking into account the Avogadro's law, the new volume will be 1.24 L.
Avogadro's law establishes the relationship between the amount of gas and its volume when the temperature and pressure are held constant. Remember that the amount of gas is measured in moles.
This law states that constant pressure and temperature, the same amount of gas has the same volume regardless of the chemical element that forms it.
On the other hand, Avogadro's law establishes that the volume is directly proportional to the quantity of gas: if the quantity of gas increases, the volume will increase; whereas if the amount of gas decreases, the volume decreases.
Mathematically, this law states that the ratio between the volume and the quantity of gas is constant:
[tex]\frac{V}{n} =k[/tex]
Assuming that you have an initial state 1 and the conditions are modified to a final state 2, it is true:
[tex]\frac{V1}{n1} =\frac{V2}{n2}[/tex]
In this case, being the molar mass of He 4 g/mole, 0.590 grams of He are contained in the following amount of moles:
[tex]0.590 gramsx\frac{1 mole}{4 grams} =0.1475 moles[/tex]
Then, you know:
V1= 0.500 Ln1= 0.100 molesV2= ?n2= 0.100 mol + 0.1475 mol = 0.2475 mol He because 0.590 grams are added, this is 0.1475 moles, of He to the balloonReplacing in Avogadro's Law:
[tex]\frac{0.500 L}{0.100 moles} =\frac{V2}{0.2475 moles}[/tex]
Solving:
[tex]V2=0.2475 molesx\frac{0.500 L}{0.100 moles}[/tex]
V2= 1.2375 L≅ 1.24 L
Finally, the new volume will be 1.24 L.
Learn more:
https://brainly.com/question/15737923?referrer=searchResultshttps://brainly.com/question/4147359?referrer=searchResultsWhich is the correct statement regarding the relative Rf values of the starting methyl benzoate vs the product, methyl m-nitrobenzoate on a silica gel TLC plate. The product has a higher Rf value on a silica gel TLC plate because it is less polar than the starting methyl benzoate. The product has a lower Rf value on a silica gel TLC plate because it is less polar than the starting methyl benzoate. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate. The product has a lower Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate. 1.5 points QUESTION 2 Methyl benzoate is more reactive than benzene in Electrophilic Aromatic Substition [EAS] reactions. True False 1 points QUESTION 3 Methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition [EAS] reactions. True False
Answer:
1. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate.
2. False
3. True
Explanation:
In chromatography, there is a stationary phase and a mobile phase. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).
Since silica gel is a polar solvent, it will retain the more polar product methyl m-nitrobenzoate compared to the methyl benzoate starting material.
In comparing the electrophillic aromatic substitution of m-nitrobenzoate and methyl benzoate, we must remember that the presence of electron withdrawing groups (such as -NO2 and -CHO) on the aromatic compound deactivates the compound towards electrophillic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substition
The final result has a higher Rf value because the TLC plate has more polarity than the other compound.
The answer to the following question is as follows:-
False True
In chromatography, it is a process that is used to separate the different components on the basis of their votality. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).
In comparing the electrophilic aromatic substitution of m-nitrobenzoate and methyl benzoate, we must remember that the presence of electron-withdrawing groups on the aromatic compound deactivates.
The compound towards electrophilic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substitution and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substitution.
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that create stars, scientists understand more and more about how the universe came into existence. The ne
little green men up in space, think about all the great astronomers who have studied the night sky in search
Question 1
Using the information in the passage, rank the types of galaxies by their ability to form new stars, from most to
least activity
.
Elliptical, spiral, irregular
Irregular, elliptical, spiral
Spiral, irregular, elliptical
Irregular, spiral, elliptical
Son
Answer:
i would have to read the artical but i would say the first one
Explanation:
A cylinder contains hydrogen gas at 20 atm. How many balloons of 500 ml capacity can be filled up completely from the gas cylinder at the external atmospheric pressure of 640 mm of Hg at constant temperature? The volume of empty cylinder is 20 liters.
Answer:
950 balloons
Explanation:
P1 = pressure inside cylinder = 20atm
P2 = pressure outside = 640mmhg = 0.842105 atm
V1= volume of cylinder =20L = 20,000 ml
V2 = volume of a single balloon= 500ml
n = number of balloons
[tex]P_{1}V_{1} =n P_{2}V_{2}\\20* 20000 =n 0.842105 * 500\\n = 950.[/tex]
1. The octane present in gasoline burns according to the following equation:
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
(a) How many moles of O2 are needed to react fully with 27.5 moles of octane?
Answer:
[tex]n_{O_2}=343.75molO_2[/tex]
Explanation:
Hello there!
In this case, according to the combustion of octane:
[tex]2C_8H_1_8+25O_2\rightarrow 16CO_2+18H_2O[/tex]
We can see there is a 2:25 mole ratio of octane to oxygen; therefore, we can calculate the moles of oxygen via the following stoichiometric factor:
[tex]n_{O_2}=27.5molC_8H_1_8*\frac{25molO_2}{2molC_8H_1_8} \\\\n_{O_2}=343.75molO_2[/tex]
Best regards!
Which equation is correct if the
volume of a block is 64 cm3?
A. 5 cm x 5 cm x 5 cm = 64 cm3
B. 8 cm x 4 cm x 2 cm = 64 cm3
C. 5 cm + 5 cm + 5 cm = 64 cm3
D. 8 cm + 4 cm + 2 cm = 64 cm3
Answer:
B.
Explanation:
it's B because 4 x 2 is 8 and we all know 8 x 8 is 64. So the answer is B.
The equation that is correct if the volume of a block is 64 cm³ is 8 cm x 4 cm x 2 cm = 64 cm³. The correct option is B.
What is volume?Volume is the space occupied by any three-dimensional object. The volume is also considered as the total weight of the object. The volume is calculated as mass is divided by the density.
A block will be a rectangle because it contains length, breadth, and height. The formula will be V = L x B x H
As take all the options, and multiply them, we can calculate the actual volume of the box;
5 cm x 5 cm x 5 cm = 125
8 cm x 4 cm x 2 cm = 64 cm3
5 cm + 5 cm + 5 cm = 15
8 cm + 4 cm + 2 cm = 14
So, the correct option will be B, 8 cm x 4 cm x 2 cm = 64 cm. All others are incorrect.
Thus, the correct option is B. 8 cm x 4 cm x 2 cm = 64 cm.
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what is the answer to this question?
Answer:
A
Explanation:
According to Charles Law, volume is directly proportional to absolute temperature so because temperature is being decreased in this case, the volume will also decrease.
Use the drop-down menus to answer the questions.
Which organism begins this food chain and is a producer?
Which organism gains energy from eating the frog?
Which organism has the most available energy in this food chain?
Answer:
grass
snake
grass
Explanation:
just did it :)
#7 which of the following decreases the rate of solubility of solid molecules in a solution?
Answer:
7. Option D
Explanation:
Solubility increases with the increase in temperature of the solution. It is so because the increase in temperature leads to increase in kinetic energy which then breaks the solute particles held together by intermolecular attractions.
Hence, option D is correct
How many molecules of H20 are present in 7.30 g of water?
Answer:
2.44×10²³ molecules
Explanation:
From the question given above, the following data were obtained:
Mass of H₂O = 7.30 g
Number of molecules of H₂O =?
From Avogadro's hypothesis:
1 mole of H₂O = 6.02×10²³ molecules
1 mole of H₂O = (2×1) + 16
= 2 + 16
= 18 g
Thus,
18 g of H₂O = 6.02×10²³ molecules
Finally, we shall determine the number of molecules present in 7.3 g of H₂O. This can be obtained as follow:
From Avogadro's hypothesis:
18 g of H₂O = 6.02×10²³ molecules
Therefore,
7.3 g of H₂O = 7.3 × 6.02×10²³ / 18
7.3 g of H₂O = 2.44×10²³ molecules
Thus, 7.3 g of H₂O contains 2.44×10²³ molecules
A student prepared a stock solution by dissolving 20.0 g of NaOH in enough water to make 150. mL of solution. She then took 15.0 mL of the stock solution and diluted it with enough water to make 65.0 mL of a final solution. What is the concentration of NaOH for the final solution
Answer:
[tex]0.769\ \text{M}[/tex]
Explanation:
Mass of stock solution = 20 g
Molar mass of NaOH = 40 g/mol
Volume of stock solution = 0.150 mL
[tex]M_2[/tex] = Concentration of NaOH for the final solution
[tex]V_1[/tex] = Amount of stock solution taken = 15 mL
[tex]V_2[/tex] = Total volume of solution = 65 mL
Molarity is given by
[tex]M_1=\dfrac{\text{Mass}}{\text{Molar mass}\times \text{Volume}}\\\Rightarrow M_1=\dfrac{20}{40\times 0.15}\\\Rightarrow M_1=\dfrac{10}{3}[/tex]
We have the relation
[tex]M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{\dfrac{10}{3}\times 15}{65}\\\Rightarrow M_2=0.769\ \text{M}[/tex]
The concentration of NaOH for the final solution is [tex]0.769\ \text{M}[/tex].
PLEASE HELP
How many chlorine atoms are needed to satisfy the octet rule when forming an ionic compound with a cation of charge 3+?
Answer:
not the right answer but I need this for the answer the question thing
250 mL of 1.5 M nitric acid is mixed with 250 mL of 2.5 M sodium hydroxide. Calculate the pH of the resulting mixture.
Answer:
pH = 13.7.
Explanation:
Hello there!
In this case, as we set up the chemical reaction between nitric acid and sodium hydroxide:
[tex]NaOH+HNO_3\rightarrow NaNO_3+H_2O[/tex]
It is possible to realize there is a 1:1 mole ratio of acid to base, thus, we next compute the moles of each one:
[tex]n_{acid}=0.25L*1.5mol/L=0.375mol\\\\n_{base}=0.25L*2.5mol/L=0.625mol[/tex]
In such a way, since the base react with more moles, there is leftover that we compute as shown below:
[tex]n_{base}^{leftover}=0.25mol[/tex]
Afterwards, we compute the concentration given the new volume of 500 mL (0.500 L), as both volumes are added up:
[tex][base]=0.25mol/0.500L=0.5M[/tex]
Now, since sodium hydroxide is such a strong base, we compute the pOH first:
[tex][OH^-]=[base]=0.5M[/tex]
[tex]pOH=-log([OH^-])=-log(0.5M)\\\\pOH=0.30[/tex]
And the pH:
[tex]pH=14-0.30\\\\pH=13.7[/tex]
Best regards!
4) Which of the following can cause erosion?
- Glaciers, wind, and animals
- Acid rain, animals, and ice wedging
- Wind, water, glaciers
- Glaciers, wind, and acid rain
5) Which factors affect the rate of weathering?
- Temperature, ocean currents, and tides
- Type of rock and amount of precipitation
- Type of plants and animals
- Amount of sunlight
Water, air, and even ice are fluids because they tend to flow from one place to another due to the force of gravity.
Rainfall and temperature can affect the rate in which rocks weather. High temperatures and greater rainfall increase the rate of chemical weathering. 2. Rocks in tropical regions exposed to abundant rainfall and hot temperatures weather much faster than similar rocks residing in cold, dry regions.
Use the reaction below for the decomposition of sodium azide
to sodium metal and nitrogen gas.
2NaN3 (s) → 2Na(s) + 3N2(8)
What volume of nitrogen at STP is generated by the
decomposition of 130.0 g NaN3 ?
Answer:
34.05dm^3 of nitrogen gas
Explanation:
First things first, we need to find the number of moles of Sodium azide. We can do that by using the formula m=nM, mass = no. moles x Molar Mass
Rearrange to solve for no. moles and substituting in the known values and we have:
n = m/M
no. moles = 130.0g / (2x(22.99+3x14.01))
no. moles = 130.0/130.0 (4.s.f.)
no. moles = 1
Now we can use the ratio given in the equation to find the number of moles of Nitrogen that will be made:
1 x 3/2 = 1.5 moles of Nitrogen
Now we use the constant that 1 mole of any gas will always have a volume of 22.7dm^3 at STP.
1.5 x 22.7 = 34.05dm^3 of nitrogen gas.
Hope this helped!
The oxidation state/number for X in XO3- is:
Answer:
We can Observe that the Compound does not have the Positive or the negative Charge thus it is Neutral. Hence, the Oxidation Number of the Compound Will be 0. Thus, the Highest Oxidation Number of the X is 6.
The oxidation state/number for X in XO3 is determined as +6.
Oxidation state of X in XO3
The oxidation state/number for X in XO3 is determined from the overal charge of the compound and the charge of oxygen atom.
Overall charge of the compound = 0Oxidation state of oxygen (O) is -2The oxidation state of "X" is calculated as;
X + (3 x -2) = 0
X - 6 = 0
X = +6
Thus, the oxidation state/number for X in XO3 is determined as +6.
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The following containers have the same number of molecules and temperature. Which container has the most collisions?
Answer:
Container 1 I think.
The containers have the same number of molecules and temperature. The container 1.
What is collision?Collision is the encounter between two particles or object. There are three type of collision: perfectly elastic collision, inelastic collision, perfectly inelastic collision.
Container 1 is smallest, so there will be less distance between the molecules, so they will collide most.
Thus, the containers have the same number of molecules and temperature. The container 1.
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What are the two types of bonding we have studied?
a. Metallic and covalent
b. Covalent and ionic
c. lonic and metallic
d. Molecular and metallic
Answer:
B: Covalent bond and Ionic bond
What does H2o mean in chemistry?
<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3
Answer:
Water (chemical formula: H2O) is a transparent fluid which forms the world's streams, lakes, oceans and rain, and is the major constituent of the fluids of organisms. As a chemical compound, a water molecule contains one oxygen and two hydrogen atoms that are connected by covalent bonds.
<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3
Plzzz help me plz I am timed!!
Answer:
Explanation:
pretty sure its gaillieo
Answer:
Galileo
Explanation:
he was the first one to use a telescope
The correct name for HIO2?
Answer:
iodous acid
Explanation:
iodous acid would also be known as HIO2
10 points pls help!!
Answer:
Question 16: I'm not sure but most likely #3
Question 17: #4
Explanation: Hope this Helps
Answer:
A for first one and second one is A
How do you decrease the amount of energy storage molecules there are in an ecosystem?
a) increase sunlight
b) decrease sunlight
c) burn dead matter
d) bury dead matter
e) trap carbon dioxide
Decreasing sunlight will decrease the amount of energy storage molecules in an ecosystem.
What is Photosynthesis?This is the process in which green plants manufacture food in the presence of sunlight. Primary producers are involved in this process of providing energy to the ecosystem.
This therefore means that a decrease in sunlight means a decrease in photosynthesis and energy production.
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PLEASE HELP ASAP
A sample of a gas has a volume V1 = 3L at a temperature T1 = 290K. Determine V2 when the temperature is T2
= 700K, while the pressure remains constant.
a.- 7.00L
b.- 7.24L
c.-2.74L