which statement regarding the number of solutions for the linear equation shown below is true?
1/4x - 13 = 1/4(x + 13) ​

Answer:

Yes, they are equal because of distributive property

Step-by-step explanation:

6(1 + m) = 6 + 6m

Answer:

1st group contains triangles that are similar

Step-by-step explanation:

since its opposite corresponding angle are equal.

Answer:

x = 3

y = 2

Step-by-step explanation:

Diagonals of a parallelogram bisect each other into two equal segments. Therefore:

3x - 1 = 2(x + 1)

Solve for x

3x - 1 = 2x + 2

Collect like terms

3x - 2x = 1 + 2

x = 3

Also:

5y + 1 = 6y - 1

Collect like terms

5y - 6y = -1 - 1

-y = -2

Divide both sides by -1

y = -2/-1

y = 2

According to the table, the solutions to the system of equations are x = 0 and x = 1.

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the equations are:

[tex]y_1 = 0.25^x[/tex]

[tex]y_2 = -0.75x + 1[/tex]

The solutions are the values of x for which:

[tex]y_1 = y_2[/tex]

Looking at the table, the solutions to the system of equations are x = 0 and x = 1.

More can be learned about a system of equations at https://brainly.com/question/24342899

Answer:

the answer is 558175

may it help you

Answer:

[tex]CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}[/tex]

Step-by-step explanation:

Given

[tex]n = 200[/tex]

[tex]x_1 = 34[/tex] -- City C

[tex]x_2 = 54[/tex] --- City K

Required

Determine the 90% confidence interval

This is calculated using:

[tex]CI = \bar x \± z\frac{\sigma}{\sqrt n}[/tex]

Calculating [tex]\bar x[/tex]

[tex]\bar x = \bar x_1 - \bar x_2[/tex]

[tex]\bar x = \frac{x_1}{n} - \frac{x_2}{n}[/tex]

[tex]\bar x = \frac{34}{200} - \frac{54}{200}[/tex]

[tex]\bar x = 0.17 - 0.27[/tex]

For a 90% confidence level, the ​z-score is 1.65.  So:

[tex]z = 1.65[/tex]

Calculating the standard deviation [tex]\sigma[/tex]

[tex]\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }[/tex]

So:

[tex]\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }[/tex]

[tex]\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}[/tex]

So:

[tex]CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}[/tex]

[tex]CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}[/tex]

The dependent is the one your mesuaring and that is the Total Weight. Independent is the one you change (I remember it as the is a I in independent which 'I' change) and that would be the toy weight

Answer:

About V≈113.1ft³

Step-by-step explanation:

Answer:

950 kilograms

Step-by-step explanation:

Fruit: vegetables = 5:7

Fruit = 5

Vegetable = 7

Total ratio = 5 + 7 = 12

If Hassan sells 1.33 tones of vegetables

1 tonne = 1000 kilograms

1.33 tonnes of vegetables = 1330 Kilograms of vegetables

how many kilograms of fruits did he sell?

Let kilograms of fruits sold = x

Fruit: vegetables = 5:7

Fruit: vegetables = x : 1330

5 : 7 = x : 1330

5/7 = x/1330

Cross product

5 * 1330 = 7 * x

6,650 = 7x

x = 6,650/7

x = 950 kilograms

kilograms of fruits sold = 950 kilograms

Answer: 51

Step-by-step explanation: QTR is the inscribed angle, so QTR = 1/2 * QSR, so QSR = 78. QSR is an isosceles triangle, since it uses the radius of the circle twice, so QRS = (180 - 78)/2 = 51

4000 mcmcnxmamnxmxmnxnxns

9514 1404 393

Answer:

  $541.32

Step-by-step explanation:

Putting the given values into the given formula, you have ...

  V = P·e^(rt)

  V = $277e^(0.067·10) ≈ $541.32

Answer:

52

Step-by-step explanation:

hmm

Answer: C. O $8/hr

Step-by-step explanation:

To solve this, we divide 112 by 14.The answer is 8.

$100 - $20 = $80

Understand?

Answer:

I'm pretty sure this is obtuse because when you add all sides it gives you 135 and it has a 90-degree angle so if it's greater than 90 it's 100% obtuse.

Step-by-step explanation:

Answer:

There are 160 cats at the store.

Step-by-step explanation:

There are 40 black cats, which is 25% of all the cats. You are trying to find all the cats at the store, or 100% of the cats at the store. So:

40 = 25%

40(4) = 25% (4)

160 = 100%

There are 160 cats at the store.

Answer:

160

Step-by-step explanation:

25%=1/4=0.25

=40×4

=160

Answer:

[tex]t = 0.875[/tex]

Step-by-step explanation:

Given

Brand A            Brand B

[tex]n_ 1= 12[/tex]               [tex]n_2 = 12[/tex]

[tex]\bar x_1 = 21.8[/tex]            [tex]\bar x_2 = 18.9[/tex]

[tex]\sigma_1 = 8.7[/tex]              [tex]\sigma_2 = 7.5[/tex]

Required

Determine the test statistic (t)

This is calculated as:

[tex]t = \frac{\bar x_1 - \bar x_2}{s\sqrt{\frac{1}{n_1} + \frac{1}{n_2}}}[/tex]

Calculate s using:

[tex]s = \sqrt{\frac{(n_1-1)*\sigma_1^2+(n_2-1)*\sigma_2^2}{n_1+n_2-2}}[/tex]

The equation becomes:

[tex]s = \sqrt{\frac{(12-1)*8.7^2+(12-1)*7.5^2}{12+12-2}}[/tex]

[tex]s = \sqrt{\frac{1451.34}{22}}[/tex]

[tex]s = \sqrt{65.97}[/tex]

[tex]s = 8.12[/tex]

So:

[tex]t = \frac{\bar x_1 - \bar x_2}{s\sqrt{\frac{1}{n_1} + \frac{1}{n_2}}}[/tex]

[tex]t = \frac{21.8 - 18.9}{8.12 * \sqrt{\frac{1}{12} + \frac{1}{12}}}[/tex]

[tex]t = \frac{21.8 - 18.9}{8.12 * \sqrt{\frac{1}{6}}}[/tex]

[tex]t = \frac{21.8 - 18.9}{8.12 * 0.408}}[/tex]

[tex]t = \frac{2.9}{3.31296}}[/tex]

[tex]t = 0.875[/tex]

Answer:

All angles in a quadrilateral = 360°

b =?

b = 360 - (128 + 61 + 57)

b = 360 - 246

b = 114°

Answer:

0.7 = 70% probability they'll eat lunch at Carl's Jr. Wednesday.

Step-by-step explanation:

We have that:

Carl's Jr on Monday.

On Tuesday:

40% probability of Carl's Junior.

100 - 40 = 60% probability of Wendy's.

On Wednesday:

If on Tuesday it was on Carl's Junior, 40% probability of Carl's Junior on Wednesday.

In on Tuesday it was on Wendy's, 100 - 10 = 90% probability of Carl's Junior on Wednesday.

What is the probability they'll eat lunch at Carl's Jr. Wednesday?

[tex]p = 0.4*0.4 + 0.6*0.9 = 0.7[/tex]

0.7 = 70% probability they'll eat lunch at Carl's Jr. Wednesday.

Answer:

it is b              furqufhrfhquh quf hqhf

Step-by-step explanation:bfygefy eyfeyfyewfyefwef eqf  

\fn qf7f

The value of the matrix X is X =  [tex]\left[\begin{array}{ccc}-7&-2\\7&0\\\end{array}\right][/tex].

Matrices are a set of numbers arranged in such a way that the numbers are arranged in rows and columns.

Each number is called element in a matrix.

Given are two matrices.

A = [tex]\left[\begin{array}{ccc}2&-7\\6&1\\\end{array}\right][/tex] and B = [tex]\left[\begin{array}{ccc}-9&5\\1&-1\\\end{array}\right][/tex]

We have given that, a matrix X exists such that,

X - A = B

We can rearrange this as,

X = A + B

Adding the two matrices,

The entries will be,

2 - 9 = -7

-7 + 5 = -2

6 + 1 = 7

1 - 1 = 0

X =  [tex]\left[\begin{array}{ccc}-7&-2\\7&0\\\end{array}\right][/tex]

Hence the X is option A.

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Answer:

The area is changing at 15.75 square feet per second.

Step-by-step explanation:

The triangle between the wall, the ground, and the ladder has the following dimensions:

H: is the length of the ladder (hypotenuse) = 10 ft

B: is the distance between the wall and the ladder (base) = 6 ft

L: the length of the wall (height of the triangle) =?

dB/dt = is the variation of the base of the triangle = 9 ft/s        

First, we need to find the other side of the triangle:  

[tex]H^{2} = B^{2} + L^{2}[/tex]

[tex] L = \sqrt{H^{2} - B^{2}} = \sqrt{(10)^{2} - B^{2}} = \sqrt{100 - B^{2}} [/tex]

Now, the area (A) of the triangle is:            

[tex] A = \frac{BL}{2} [/tex]  

Hence, the rate of change of the area is given by:

[tex] \frac{dA}{dt} = \frac{1}{2}[L*\frac{dB}{dt} + B\frac{dL}{dt}] [/tex]      

[tex] \frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} + B\frac{d(\sqrt{100 - B^{2}})}{dt}] [/tex]        

[tex]\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} - \frac{B^{2}}{(\sqrt{100 - B^{2}})}*\frac{dB}{dt}][/tex]  

[tex]\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - 6^{2}}*9 - \frac{6^{2}}{\sqrt{100 - 6^{2}}}*9][/tex]      

[tex]\frac{dA}{dt} = 15.75 ft^{2}/s[/tex]  

Therefore, the area is changing at 15.75 square feet per second.

I hope it helps you!                                    

The rate of change (ROC) of the area with respect to (w.r.t.) time can be

found from the ROC of the area w.r.t. x and the ROC of x w.r.t. time.

Reasons:

The length pf the ladder = 10 feet

Rate at which the ladder is pulled from the wall, [tex]\displaystyle \frac{dx}{dt}[/tex] = 9 feet per second

Required:

The rate at which the area of the triangle formed by the ladder, the wall

and the ground, is changing at the instant the ladder is 6 feet from the wall.

Solution:

The area the triangle, A = 0.5·x·y

Where;

x = The distance of the ladder from the wall

y = The height of the ladder on the wall

By Pythagoras's theorem, we have;

10² = x² + y²

Which gives;

y = √(10² - x²)

Therefore;

The area the triangle, A = 0.5 × x × √(10² - x²)

By chain rule, we have;

[tex]\displaystyle \frac{dA}{dt} = \mathbf{\frac{dA}{dx} \times \frac{dx}{dt}}[/tex]

[tex]\displaystyle \frac{dA}{dx} = \frac{d\left(0.5 \cdot x \cdot \sqrt{10^2 - x^2} }{dx} = \mathbf{\frac{\left(x^2 - 50\right) \cdot \sqrt{100-x^2} }{x^2-100}}[/tex]

[tex]\displaystyle \frac{dA}{dx} = \frac{\left(x^2 - 50\right) \cdot \sqrt{100-x^2} }{x^2-100}[/tex]

Therefore;

[tex]\displaystyle \frac{dA}{dt} = \mathbf{\frac{\left(x^2 - 50\right) \cdot \sqrt{100-x^2} }{x^2-100} \times 9}[/tex]

When the ladder is 6 feet from the wall, we have;

x = 6

[tex]\displaystyle \frac{dA}{dt} = \frac{\left(6^2 - 50\right) \cdot \sqrt{100-6^2} }{6^2-100} \times 9 = \mathbf{15.75}[/tex]

At the time the ladder is 6 feet from the wall, the area is increasing at 15.75 ft.²/sec.

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Answer:

(x+2.25) ×24

This is how it is written

Answer:

Step-by-step explanation:

y = 24*(x + 2.25)

There, that's an algebraic expression for 24 times the sum of a number and 2.25.

Answer:

$98.4.

Step-by-step explanation:

Since the university has decided that for the following year lecture costs will increase by 20%, workshop costs by 10%, and examination costs will stay the same, and that for level 2 the current hourly costs are 10, 24, and 60 respectively To determine how much the level 2 course cost in the following year, the following calculation must be performed:

10 x 1.2 + 24 x 1.1 + 60 = X

12 + 26.4 + 60 = X

98.4 = X

Thus, the level 2 course will cost $ 98.4 next year.

Answer:

C

Step-by-step explanation:

Answer: z=29 so Now: Cary is 38 years old while Dan is 29 years old.

In 5 years: Cary is 43 years old while Dan is 34 years old.

Step-by-step explanation: z=29 because 29+9=38 and 38+29=67 so 38+5=43 and 29+5=34.

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