Which structure is the naturally occurring form of glucose?

six-sided ring


multiple ring


five-sided ring


linear chain

Answers

Answer 1

Answer: A. Six-Sided Ring

Which Structure Is The Naturally Occurring Form Of Glucose?six-sided Ringmultiple Ringfive-sided Ringlinear

Related Questions

what is an example of a change in genetic traits of an organism do to human affect

Answers

Answer:

A person's skin color, hair color, dimples, freckles, and blood type are all examples of genetic variations that can occur in a human population.

Explanation:

Which of the following
describes the zone of the
ocean where no light reaches?
A. up to 200 meter depth and includes
photosynthetic plants, sea anemones,
sponges, crabs, and clams
B. the "twilight zone" between 200-1000
meters deep and includes whales and octopi
and little life
C. permanent darkness below 1000 meters
with bioluminescent bacteria, bottom
feeders, and angler fish

Answers

Answer:

Bathypelagic

54% of the ocean lies in the Bathypelagic (aphotic) zone into which no light penetrates. This is also called the midnight zone and the deep ocean. Due to the complete lack of sunlight, photosynthesis cannot occur and the only light source is bioluminescence.

Explanation:

The small surface zone that has light is the photic zone. The entire rest of the ocean does not have light and is the aphotic zone.

Permanent darkness below 1000 meters with bioluminescent bacteria, bottom feeders, and angler fish is where no light reaches.

What is Darkness?

This is referred to the state of being dark as a result of absence of light in the area.

The light ray penetration decreases with increase in depth thereby making areas below 1000 meters dark with bioluminescent bacteria, bottom feeders, and angler fish which is why option C was chosen.

Read more about Darkness here https://brainly.com/question/24581271

a. An aqueous solution of Mn(NO3)2 is very pale pink, but an aqueous solution of K4[Mn(CN)6] is deep blue. Explain why the two differ so much in the intensities of their colors.
b. Predict which of the following compounds would be colorless in aqueous solution:

a. K2[Co(NCS)4]
b. Zn(NO3)2
c. [Cu(NH3)4]Cl2
d. CdSO4
e. AgClO3
f. Cr(NO3)2

Answers

Answer:

See Explanation

Explanation:

The colour of many transition metal complexes stem from transitions of electrons between energy levels. These transitions are governed by the spin selection rules and the colour is determined by the magnitude of crystal field splitting.

According to the spin selection rules, transitions in which ΔS = 0 are forbidden. Hence, a Mn^2+high spin compound is expected to be colourless. However, contrary to the spin selection rules Mn^2+high spin compounds do exhibit transitions in which the intensity is only about one-hundredth of the intensity of the spin allowed transitions. Thus many Mn^2+  high spin compounds such as Mn(NO3)2 are very pale pink or off white.

Note also that the crystal field stabilization energy of Mn^2+ which is a d^5 low spin ion is zero hence the very pale colour observed.

K4[Mn(CN)6] is deep blue as a result of charge transfer. Also, the compound exhibits an observed crystal field stabilization energy because it is a d^5 low spin compound hence the observed colour. Its low spin nature is because the cyanide ion is a strong field ligand hence it causes a greater magnitude of crystal filed splitting.

The following compounds are colourless;

Zn(NO3)2

CdSO4

AgClO3

One thing that is common to all the compounds listed above is that they are all d^10 compounds. This means that they all possess completely filled d-orbitals hence they are colourless.

A 0.682 g sample of a weak monoprotic acid, HA was dissolved in sufficient water to make 50.0 mL of solution and was titrated with a 0.135 molar NaOH solution. After the addition of 10.6 milliliters of base, a pH of 5.65 was recorded. The equivalence point was reached after the addition of 27.4 milliliters of the 0.135 molar NaOH.
a. Calculate the number of moles of acid in the original sample.
b. Calculate the molar mass of the acid HA.
c. Calculate the [H3O+] at pH = 5.65
d. Calculate the number of moles of unreacted HA remaining in solution when the pH was 5.65.
e. Calculate the value of the ionization constant, Ka, of the acid HA.
f. Calculate the value of the ionization constant, Kb, and explain how you would use it to determine the pH of a solution of a known mass of the sodium salt (Na)(A) dissolved in a known volume of water.

Answers

I think it would be A

Water can break down to form hydrogen and oxygen gas. Balance the
equation below (hint, always balance oxygen last). What coefficients go in
the blank spaces? *

Answers

Answer:

its 2,2,1

Explanation:

chemical properties of citric acid​

Answers

Answer:

Citric Acid is a weak acid with a chemical formula C6H8O7.

...

Properties of Citric Acid – C6H8O7.

C6H8O7 Citric Acid

Molecular Weight/ Molar Mass 192.124 g/mol

Density 1.66 g/cm³

Boiling Point 310 °C

Melting Point 153 °C

Hope it helps❤️

Chemical formula: C6H8O7
Properties: No color, no smell, Crystal like appearance, Boiling point of 175 C, Melting point of 153 C, Density of 1.66 g/ml, Weak acid

Thermal energy naturally flows from _________ matter to _______ matter.

Answers

Answer:

Warmer

Cooler

Explanation:

What is the pH of a 6.2 x 10-5 M NaOH solution?

Answers

Answer:

4.21

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log [ {H}^{+} ][/tex]

From the question we have

[tex]ph = - log(6.2 \times {10}^{ - 5} ) \\ = 4.207608[/tex]

We have the final answer as

4.21

Hope this helps you

What is the electronegativity difference
between sodium and chlorine?

Answers

Answer: 2.23 is the difference.

Explanation: Sodium has an electronegativity of 0.93 and Chlorine has an electronegativity of 3.16, so when Sodium and Chlorine form an ionic bond, in which the chlorine takes an electron away from sodium, forming the sodium cation, Na+, and the chloride anion, Cl-.

A 0.750 M sample of phosphorus pentachloride decomposes to give phosphorus trichloride and chlorine gases.If the equilibrium concentration of PCl5 is 0.650M,what is the equilibrium constant for the reaction?
PCl5(g) --------> PCl3(g)+ Cl₂(g)
A) Keq = 0.0133
B) Keq = 0.0154
C) Keq = 0.133
D) Keq = 0.154
E) Keq = 65.0

Answers

Answer:

Explanation:

Amount of phosphorus pentachloride reacted = 0.75 M - 0.65 M = 0.10 M

PCl₅(g) --------> PCl₃(g)+ Cl₂(g)

1 mole               1 mole      1 mole

Amount of phosphorus pentachloride reacted = 0.75 M - 0.65 M = 0.10 M

PCl₃(g) and  Cl₂(g) formed are .10 M and .10 M

Keq = [ PCl₃] x [ Cl₂ ] / [ PCl₅ ]

= .10 M x .10 M / .65 M

= .0154

B ) is the correct choice .

Propane is used as a fuel for camp stoves. It undergoes combustion to form carbon dioxide and water.
C3H8 + 5 02- 3 CO2 + 4H2O
How many molecules of dihydrogen monoxide will be produced from 7.328 moles of propane?
How Do i get this answer with steps ?

Answers

Answer:

1.765x10²⁵ molecules

Explanation:

C₃H₈ + 5 O₂ → 3 CO₂ + 4H₂O

First we convert 7.328 moles of propane (C₃H₈) into moles of H₂O, using the stoichiometric coefficients of the balanced reaction:

7.328 mol C₃H₈ * [tex]\frac{4molH_2O}{1molC_3H_8}[/tex] = 29.312 mol H₂O

Then we convert 29.312 moles of H₂O into molecules, using Avogadro's number:

29.312 mol * 6.023x10²³ molecules/mol = 1.765x10²⁵ molecules

3.05 moles of H2O is equivalent to (blank amount) molecules of water.

Show your work.

Answers

Answer:

[tex]1 \: mole \: = 6.02 \times {10}^{23} \: molecules \\ 3.05 \: moles \: = (3.05 \times 6.02 \times {10}^{23} ) \: molecules \\ = 1.8361 \times {10}^{24} \: molecules[/tex]

If the plant population decreased, the amount of carbon in the atmosphere would _______.



Increase


Stay the same


Decrease

Answers

Answer:

increase answer

Explanation:

i hope that is right

how to solve x² in differential​

Answers

Answer:

x² = mutiphy by them self

Explanation:

A balloon can be inflated with 4.23 Liters of O2gas at STP. How much will the balloon weigh in grams?

Answers

Answer: 6.04 g

Explanation: In STP conditions, amoint of substance

n = V / Vm = 4.23 l / 22.41 l/mol = 0.188755 mol

Molar mass M(O2) = 32 g/mol  and

mass m = nM

Calculate the energy of an electron in the n = 2 level of a hydrogen atom.

Answers

Answer: The energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

Explanation:

Given: n = 2

The relation between energy and [tex]n^{th}[/tex] orbit of an atom is as follows.

[tex]E = - \frac{13.6}{n^{2}} eV[/tex]

Substitute the values into above formula as follows.

[tex]E = - \frac{13.6}{n^{2}} eV\\= - \frac{13.6}{(2)^{2}}\\= - 3.40 eV[/tex]

The negative sign indicates that energy is being released.

Thus, we can conclude that the energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

Many enjoys the warm waters of a ______.
Geyser
Volcano
Hot spring
Furmarole
Tectonic​

Answers

Answer:

hot spring

Explanation:

The mineral water in hot springs can also help reduce stress by relaxing tense muscles. Meanwhile as your body temperature rises in the bath, and then cools once you exit can also help you relax and fall into a deeper sleep.

URGENT
Best answer gets Brainliest!
Mg+ 2HCI ——> MgCI2+ H2

Answers

Answer:

Reaction type: Single displacement

Reactant: Magnesium

Product: Dihydrogen - H2

What is the function of a
catalyst?
A. Build enzymes
B. Speed up chemical reactions
C. Regulate the function of an enzyme

Answers

I believe it is to speed up chemical reactions

i also think it is speed up chemical reactions

What is the Ksp expression for the dissociation of calcium oxalate?Immersive Reader
(4 Points)

Ksp=[Ca⁺²] x [C₂O₄⁻²]

Ksp=[Ca⁺²]² x [C₂O₄⁻²]

Ksp=[Ca⁺²]⁴ x [C₂O₄⁻²]

Ksp=[Ca⁺²] x [C₂O₄⁻²]²

Answers

Answer:

Ksp = [Ca⁺²] × [C₂O₄⁻²]

Explanation:

Step 1: Write the balanced reaction for the dissociation of calcium oxalate

CaC₂O₄(s) ⇄ Ca⁺²(aq) + C₂O₄⁻²(aq)

Step 2: Write the expression for the solubility product constant (Ksp) of calcium oxalate

The solubility product constant is the equilibrium constant for the dissociation reaction, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It doesn't include solids nor pure liquids because their activities are 1.

Ksp = [Ca⁺²] × [C₂O₄⁻²]

The spoon's broken appearance is caused by light waves that are
A
Reflected by the glass and then absorbed the water
B
Refracted by the water
С
Absorbed by the metal spoon
D
Reflected by the metal spoon and the water

Answers

Answer:

its b

Explanation:

Q. 8. Which of the following statements about plastics are true?
(i) All plastics do not have the same arrangement of monomer units.
(ii) Melamine resists fire and can tolerate heat better than other plastics.
(iii) Plastics with cross-linked monomers are also known.
(iv) Plastics have limited applications.

a) (i) and (iii) only
b) (iii) and (iv) only
c) (i), (ii) and (iii) only.
d) (i), (iii) and (iv) only

Answers

Answer:

a) (I) and (iii) only

Explanation:

Because different plastics have different size.

2 Al(s) + Fe2O3(aq) - AlO3(aq) + 2 Fe(s)
You react 20.00 grams of aluminum with iron(III) oxide. How many grams of iron should you produce?
What is the percent yield if the experimental yield is 32.67 grams of iron?

Answers

Answer:

78.8%

Explanation:

The equation of the reaction is;

2 Al(s) + Fe2O3(aq) ------> Al2O3(aq) + 2Fe(s)

Number of moles in 20g of Al= 20g/27 g/mol = 0.74 moles

From the reaction equation;

2 moles of Al yields 2 moles of Fe

0.74 moles of Al yields 0.74 moles of Fe

Hence;

Mass of Fe produced = 0.74 moles of Fe * 56 g/mol

Mass of Fe produced = 41.44 g of Fe (This is the theoretical yield of Fe)

percent yield = actual yield/ theoretical yield  * 100

actual yield = 32.67 grams of iron

percent yield = 32.67 g/41.44 g * 100

percent yield = 78.8%

Which molecule will have double bonds?
(4 Points)

Fluorine

Nitrogen

Hydrogen

Oxygen

Answers

I believe its oxygen
hope this helps

1. Calculate and interpret the equilibrium constant. Using the reaction below.

The equilibrium concentrations 0.60 M for E, 0.80 M for F, and 1.30 M for G. (Note: E, F, and G are all gases.) Do not include your solution.

Answers

Answer:

kc = [G]² / [E] [F], kc = [1.30M]² / [0.60M] [0.80M]

Explanation:

The reaction is:

E + F ⇄ 2G

The equilibrium constant, kc, must be written as the ratio of the molar concentrations of products over reactants. Each concentration powered to its coefficient.

For the reaction of the problem, kc is:

kc = [G]² / [E] [F]

Replacing the given concentrations:

kc = [1.30M]² / [0.60M] [0.80M]

At the start of a reaction, there are 0.0249 mol N2,
3.21 x 10-2 mol H2, and 6.42 x 10-4 mol NH3 in a
3.50 L reaction vessel at 375°C. If the equilibrium constant, K, for the reaction:
N2(g) + 3H2(g)= 2NH3(g)
is 1.2 at this temperature, decide whether the system is at equilibrium or not. If it is not, predict in which direction, the net reaction will proceed.​

Answers

Answer:

Explanation:

The reaction is given as:

[tex]N_{2(g)} + 3H_{2(g)} \to 2NH_{3(g)}[/tex]

The reaction quotient is:

[tex]Q_C = \dfrac{[NH_3]^2}{[N_2][H_2]^3}[/tex]

From the given information:

TO find each entity in the reaction quotient, we have:

[tex][NH_3] = \dfrac{6.42 \times 10^{-4}}{3.5}\\ \\ NH_3 = 1.834 \times 10^{-4}[/tex]

[tex][N_2] = \dfrac{0.024 }{3.5}[/tex]

[tex][N_2] = 0.006857[/tex]

[tex][H_2] =\dfrac{3.21 \times 10^{-2}}{3.5}[/tex]

[tex][H_2] = 9.17 \times 10^{-3}[/tex]

[tex]Q_c= \dfrac{(1.834 \times 10^{-4})^2}{(0.0711)\times (9.17\times 10^{-3})^3} \\ \\ Q_c = 0.6135[/tex]

However; given that:

[tex]K_c = 1.2[/tex]

By relating [tex]Q_c \ \ and \ \ K_c[/tex], we will realize that [tex]Q_c \ \ < \ \ K_c[/tex]

The reaction is said that it is not at equilibrium and for it to be at equilibrium, then the reaction needs to proceed in the forward direction.

Please hurry!
*URGENT* *URGENT*

Best answer gets Brainliest!!

Please answer the question ASAP



Please someone answer this question correctly

Consider the following container with particles of a substance within it:

Lucas likes this model to use in a report but decided to add more molecules shorten the arrows and have the particles closer together. What type of matter does Lucas actually want his graphic to portray?

A) plasma

B) gas

C) liquid

D) solid

Answers

Answer:

c. liquid

Explanation:

because the are not very close if the said very closely packed together it would have been a solid

Estimate the volume of a solution of 5M NaOH that must be added to adjust the pH from 4 to 9 in 100 mL of a 100 mM solution of a phosphoric acid?

Answers

Answer:

3mL of 5M NaOH must be added to adjust the pH to 7.20

Explanation:

When NaOH is added to phosphoric acid, H₃PO₄, the reaction that occurs are:

NaOH + H₃PO₄ ⇄ NaH₂PO₄ + H₂O pKa1 = 2.15

NaOH + NaH₂PO₄ ⇄ Na₂HPO₄ + H₂O pKa2 = 7.20

NaOH + Na₂HPO₄ ⇄ Na₃PO₄ + H₂O pKa3 = 12.38

We can adjust the pH at 7.20 = pKa2 if NaH₂PO₄ = Na₂HPO₄. To make that, we must convert, as first, all H₃PO₄ to NaH₂PO₄ and the half of NaH₂PO₄ to Na₂HPO₄. To solve this question we need to find the moles of phophoric acid in the initial solution. 1.5 times these moles are the moles of NaOH that must be added to fix the pH to 7.20:

Moles H₃PO₄:

100mL = 0.100L * (0.100mol / L) = 0.0100 moles H₃PO₄

Moles NaOH:

0.0100 moles H₃PO₄ * 1.5 = 0.0150 moles NaOH

Volume NaOH:

0.0150 moles NaOH * (1L / 5moles) = 3x10⁻³L 5M NaOH are required =

3mL of 5M NaOH must be added to adjust the pH to 7.20

3 mL of 5 Molar NaOH is required to adjust the pH of phosphoric acid.

What is pH?

It is the negative log of the concentration of Hydrogen ions in the solution.

To calculate the volume of NaOH first, calculate the moles of NaOH and H₃PO₄.

Moles of H₃PO₄.

[tex]\rm moles \ of \ H_3PO_4 = 100\rm \ mL = 0.100\rm \ L \times (0.100 \ mol / L)\\\\\rm moles \ of \ H_3PO_4 = 0.01[/tex]

The moles of NaOH:

[tex]\rm Moles \ of \ NaOH =0.01 \ moles \ H_3PO_4\times 1.5 \\\\\rm Moles \ of \ NaOH= 0.0150[/tex]

The volume of NaOH:

[tex]\rm Volume\ of \ NaOH = \rm 0.0150\ moles\ NaOH \times (1 \ L / 5 \ moles) \\\\\rm Volume\ of \ NaOH = 3\times 10^{-3} L[/tex]

Therefore, 3 mL of 5 Molar NaOH is required to adjust the pH of phosphoric acid.

Learn more about pH:

https://brainly.com/question/3262317

How did life begin? Are we alone in the universe? What makes us human?

Answers

Answer:

This really depends on what you belive in honestly, as a christian i belive a supreme being created all but school says something happend with bacteria and evolution or something lol. If this was a serious question and you need an answer for school just search up the evolution theory

Explanation:

Please help
Apply your knowledge and understanding of equilibrium constant in solving the following problems:

The equilibrium constant Kc for the reaction below is 170 at 500 K.

Determine whether the reaction mixture is at equilibrium when the concentrations of the components at this temperature are as follows:
[N2]=1.50
[H2]=1.00
[NH3]=8.00

If it is not at equilibrium, state and explain in which direction the reaction will proceed.Multi Line Text.
2()+32() ⇄ 23()

Answers

Answer:

The reaction will proceed to the right to attain the equilibrium.

Explanation:

Step 1: Write the balanced equation

2 N₂(g) + 3 H₂(g) = 2 NH₃(g)

Step 2: Calculate the reaction quotient

The reaction quotient (Qc) is calculated in the same way as the equilibrium constant (Kc) but it uses the concentrations at any time.

Qc = [NH₃]² / [N₂]² × [H₂]³

Qc = 8.00² / 1.50² × 1.00³ = 28.4

Since Qc ≠ Kc, the reaction is not at equilibrium.

Since Qc < Kc, the reaction will proceed to the right to attain the equilibrium.

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