Which triangle has three angles less than 90° and exactly two congruent sides?

Answer:

My name is lil uzi vert

Step-by-step explanation:

maybach maybach

Hello!

[tex]\large\boxed{c_{5} = 136}[/tex]

We can begin by solving for c₃ given the equations:

c₃ = 3c₂ + 2c₁ - 2

c₃ = 3(2) + 2(4) - 2

Simplify:

c₃ = 6 + 8 - 2 = 12

We can now find the subsequent terms:

c₄ = 3(12) + 2(2) - 2 = 38

c₅ = 3(38) + 2(12) - 2 = 136

Now we have to,

find the required value of c₅.

Given that,

→ c₁ = 4

→ c₂ = 2

→ [tex] \sf {c_n = 3c_{n-1}+2c_{n-2}-2}[/tex]

Let's solve c₃ first,

→ 3c₂ + 2c₁ - 2

→ 3(2) + 2(4) - 2

→ 6 + 8 - 2 = 12

Then the value of c₃ is

→ [c₃ = 12]

Then find the value of c₄,

→ c₄ = 3(12) + 2(2) - 2

→ c₄ = {36 + 4} - 2

→ c₄ = 40 - 2

→ [c₄ = 38]

Next we can solve for c₅,

→ c₅ = 3(38) + 2(12) - 2

→ c₅ = {114 + 24} - 2

→ c₅ = 138 - 2

→ [c₅ = 136]

Hence, the value of c₅ is 136.

Answer:

Remember that the Pythagorean's theorem says that:

For a triangle rectangle with hypotenuse H and catheti A and B:

H^2 = A^2 + B^2

Here we also need to remember that the area of a square of side length L is:

area = L^2

Now let's solve this.

First, we start with two squares, one of side length a and the other of side length b.

Such that the complete area in the first image is:

area = a^2 + b^2

Now we draw two triangle rectangles with catheti a and b, and with hypotenuse c.

in step 3, we rotate those triangles in order to make a larger square, with side length c, with an area equal to:

area = c^2

Notice that we never added more shapes, so the area of the image did not change in all this process, then the initial area must be equal to the final area:

a^2 + b^2 = area = c^2

a^2 + b^2 = c^2

And remember that a and b are the catheti of the triangles, and c is the hypotenuse, then this is the Pythagorean's theorem.

Answer:

prevents people from effectively socializing

Step-by-step explanation:

social distancing presents the dangers of increasing social rejection, growing impersonality and individualism, and the loss of a sense of community.

Answer:

[tex]Area = 322.0in^2[/tex]

Step-by-step explanation:

Given

[tex]Base = 23in[/tex]

[tex]Height = 28in[/tex]

Required

Determine the area

The area is calculated as:

[tex]Area = 0.5 * Base* height[/tex]

[tex]Area = 0.5 * 23in * 28in[/tex]

[tex]Area = 322.0in^2[/tex]

Answer:

Let's define two transformations.

Vertical translation.

If we have a function f(x), a vertical translation of N untis is written as:

g(x) = f(x) + N

If N is positive, then the translation is upwards

If N is negative, then the translation is downwards.

Horizontal translation.

If we have a function f(x), a horizontal translation of N units is written as:

g(x) = f(x - N)

if N is positive, then the translation is to the right

If N is negative, then the translation is to the left.

Now we have a function g(x) that is a transformation of a parent function f(x) (we actually do not know which parent function, so i assume f(x) = x^2) such that we have a shift right 5 units and up 3 units.

Then:

g(x) = f(x - 5) + 3

and again, using f(x) = x^2

g(x) = (x - 5)^2  + 3

Answer: Don't put if this is't right. based on my calculatios I got B

Step-by-step explanation:

Answer:

im pretty sure what u have ther is right

i would say the answer is 5/8

because c is 3/4

Answer:

1)  H0 :  σ₁ ²≥ σ₂²;   Ha:  σ₁² < σ₂²

2)  χ²= 43.52

3) The critical region is χ²≤ 5.23

4) Reject the alternate hypothesis.

5) We conclude that the alternate hypothesis is false and accept the null hypothesis.

Step-by-step explanation:

The claim is that it fills bottle with a lower variation which is the alternate hypothesis

1)  Ha:  σ₁² < σ₂² where  σ₁² is the variation of the new machine and σ₂² is the variation of the old machine.

The null hypothesis is opposite of alternate hypothesis H0 :  σ₁ ²≥ σ₂²

2) The test statistic is χ²= ns²/σ ² which under H0 has  χ² distribution with n-1 degrees of freedom assuming the population is normal.

The calculated χ²= ns²/σ ² = 68( 0.12)²/ (0.15)²=0.9792/0.0225= 43.52

3) The critical region is entirely in the left tail. χ²≤χ²( 0.99)(15)= 5.23

4) The alternate hypothesis is false hence reject it.

5) The calculated χ²=  43.52 does not lie in the critical region χ²≤ 5.23 therefore H0 is accepted and concluded that new machine does not fill bottles with a lower variation.

Answer: -(m/n) = (m/n)^-1 = 1 / (m/n)

Hence, a^-(m/n) = (1 / a^(m/n)) where m,n are rational numbers.

For example: let 1/2 be rational number and 4 be real number then, 4^-(1/2) = 0.5 = 1/(4^(1/2))

Answer: 45

Step-by-step explanation:

Sum is addition so it would be

28+17=45

Answer:

45

Step-by-step explanation:

there are 47 cows in total !

Answer:

0.211 = 21.1% probability that 2 flights of BlueSky Air arrive late

Step-by-step explanation:

For each flight, there are only two possible outcomes. Either they arrive late, or they do not. The probability of a flight arriving late is independent of any other flight. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

BlueSky Air has the best on-time arrival rate with 80% of its flights arriving on time.

This means that 100 - 80 = 20% are late, which means that [tex]p = 0.2[/tex]

Randomly selecting 16 BlueSky Air flights

This means that [tex]n = 16[/tex]

What is the probability that 2 flights of BlueSky Air arrive late?

This is P(X = 2).

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{16,2}.(0.2)^{2}.(0.8)^{14} = 0.211[/tex]

0.211 = 21.1% probability that 2 flights of BlueSky Air arrive late

Answer:

first evening, 10 calls, second evening 80 calls, third evening, 20 calls.

Step-by-step explanation:

if the number of calls received during the first evening is X, then the number of calls received during the third evening is X+10 as the third evening received 10 more calls than first evening. The second evening received 4 times of third so 4X+10. Add them up together and put them equal to 110.

X+10+X+4X+40=110

6X+50=110

6X=110-50

6X=60

X=10

First evening, 10 calls,

second evening 80 calls; 4X+40, 4(10)+40=80

third evening 20 calls; X+10, (10)+10=20

Answer: The answer is 1st quadrant.

Step-by-step explanation:

Answer:   x = 7

Thus 7 associates and 10 partners were assigned

Step-by-step explanation:

7 associates and 10 partners were assigned

Let "x" be the number of associates assigned to

case

Let "y" be the number of partners assigned to the case

The law firm assigned a total of 17 lawyers to the case

Therefore,

x + y = 17

x = 17 - y --------- eqn 1

daily rate charged to the client for each associate is $800

daily rate for each partner is $1800

They was able to charge the client $23600 per day for these lawyers' services

Therefore,

800x + 1800y = 23600 ------- eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 1 in eqn 2

800(17 - y) + 1800y = 23600

13600 - 800y + 1800y = 23600

1000y = 23600 - 13600

1000y = 10000

Divide both sides by 1000

y = 10

Substitute y = 10 in eqn 1

x = 17 - 10

x = 7

Thus 7 associates and 10 partners were assigned

Step-by-step explanation:

1. simple interest

I= p × r × t

I = 1050 × 4.5 × 2

I = $9450

2. principal

p = I/(rt)

p= 22.50/ (3× 3)

p = 22.50/9

p = $2.5

3. simple interest

I= p × r × t

I = 500 × 5 × 3

I = $7500

4. time

first convert r to decimal

r= r/100, r= 3.5 / 100

r= 0.035

t = i/(pr)

t = 43.75/ (2500× 0.035)

t = 43.75/ 87.5

t = 0.5 year or 6 months

Step-by-step explanation:

3 + (2 * i)) - (5 - (4 * i)) =

-2 + 6 i

Answer:

−8−2i

Step-by-step explanation:

LMJ AND KJM

These are the only alternate interior angles

Answer:

C

Step-by-step explanation:

We can calculate the area of triangles ABD and DBC, and then add them together to get the area of the whole quadrilateral.

[tex]A = \frac{11 \times 3 + 7 \times 9}{2} = \frac{33 + 63}{2} = \frac{96}{2} = 48[/tex]

Answer:

10 cups of water should be used

Step-by-step explanation:

Answer:

2 : 4 : : x : 20

2×20/4

2 × 5 = 10

therefore he should use 10 cups of water

Hope it helps!

Answer:

Ok so the answer is the first option

You're using Newton's method to find the roots to

f(x) = g(x)   →   x ⁶ = cos(x)

Recast this as finding the roots to

h(x) = f(x) - g(x) = x ⁶ - cos(x)

First, get the tangent line approximation L(x) to h(x) at an arbitrary starting point x = x₀ ; in a small neighborhood of x₀, we have

h(x) ≈ L(x) = h(x₀) + h'(x₀) (x - x₀)

Find the root to the tangent line function:

0 = h(x₀) + h'(x₀) (x - x₀)   →   x = x₁ = x₀ - h(x₀)/h'(x₀)

x₁ is the first approximation of a root to h(x). Repeat the process - that is, take the tangent line to h(x) at x₁ to find the next approximation x₂, and so on - until you meet the required condition.

For the smaller root, take x₀ = -π/2 :

x₀ ≈ -1.5708

x₁ = x₀ - h(x₀)/h'(x₀) ≈ -1.31348

x₂ = x₁ - h(x₁)/h'(x₁) ≈ -1.11366

x₃ = x₂ - h(x₂)/h'(x₂) ≈ -0.982446

x₄ = x₃ - h(x₃)/h'(x₃) ≈ -0.928013

x₅ = x₄ - h(x₄)/h'(x₄) ≈ -0.920039

x₆ = x₅ - h(x₅)/h'(x₅) ≈ -0.919887

Stop at x₆ because |x₆ - x₅| ≤ 0.001.

For the larger root, you can start the process over with a different seed for x₀, such as π/2. But since h(x) is an even function and symmetric about the y-axis, the larger root will just be the same root with positive sign, 0.919887.

Answer:

Corson had a better performance at the skills competition.

Step-by-step explanation:

In order to determine which player had a better performance at the skills competition, we need to find the percentage performance of both the players.

Therefore,

Corson's percentage performance

[tex] =\frac{5}{7}\times 100= 71.43%[/tex]

Charleigh's percentage performance

[tex] =\frac{3}{5}\times 100= 60%[/tex]

[tex] \because [/tex] Corson's percentage performance > Charleigh's percentage performance

So, Corson had a better performance at the skills competition.

Answer:

75.36

Step-by-step explanation:

Area of the top of the snowman

A=πr^2

A=3.14(5)^2

A=78.5

A=πr^2

A=3.14(7)^2

A=153.86

The difference of the areas:

153.86-78.5

=75.36

The answer:

15.157059248=15.2(When rounded to the nearest tenth)