Which value for x makes this sentence true? ( 8th Grade math )

Answer:

I believe it's 45

Step-by-step explanation:

Answer:

45

Step-by-step explanation:

270 = 1*225 + 45

225 = 5 * 45 + 0

HCF = 45

The above is Euclid's method for finding the HCF.

The other method is by finding the prime factors:

225 = 3 * 3 * 5 * 5

270 = 2 * 3 * 3 * 5

We pick out common factors:

So the HCF  3 * 3 * 5

= 45.

Answer:

Step-by-step explanation:

11)

A= (B x H)/2

A= (2.9x3.2)/2= 4.64cm²

12)

A= (B+b)H /2

A= (12+10)5.6 /2 = 61.6in

Answer:

I think that the answer might be 9.30 for the first one and the second one I think is 670.

Step-by-step explanation:

To find the area, you have to multiply the height and width for the two figures.

3.2 × 2.9 = 9.28

12 × 10 × 5.6 = 672

I think you round those to the nearest tenth. 9.28 would be 9.30 and 672 would be 670. I hope this answers your question.

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Answer: x=77

Explanation:

5x/7 - 5 = 50

5x/7 = 55

5x = 385

x = 77

I hope this helped!

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Answer:

5x/7 - 5 = 50

5x/7 = 50+5

5x/7=55

5x=55x7

5x = 385

x=385/5

x=77

Answer:

1) The vertices of the hyperbola are (-8, -15), (-8, 3)

2) The foci of the hyperbola are (11, -7) or (1, -7)

Step-by-step explanation:

1) The vertices of a hyperbola given in the form [tex]\dfrac{\left (y - k\right)^2}{a^2} -\dfrac{\left (x - h\right)^2}{b^2} = 1[/tex] is (h, k ± a)

Therefore, for the given hyperbola with the following equation;

[tex]\dfrac{\left (y + 6\right)^2}{81} -\dfrac{\left (x + 8\right)^2}{49} = 1[/tex], we have;

[tex]\dfrac{\left (y + 6\right)^2}{9^2} -\dfrac{\left (x + 8\right)^2}{7^2} = 1[/tex]

Therefore the vertices are;

(-8, -6 ± 9) = (-8, -15), (-8, 3)

2) The equation of the given hyperbola is presented as follows;

[tex]\dfrac{\left (x - 6\right)^2}{16} -\dfrac{\left (y + 7\right)^2}{9} = 1[/tex]

The given hyperbola is of the form;

[tex]\dfrac{\left (x - h\right)^2}{a^2} -\dfrac{\left (y - k\right)^2}{b^2} = 1[/tex]

We get;

[tex]\dfrac{\left (x - 6\right)^2}{4^2} -\dfrac{\left (y + 7\right)^2}{3^2} = 1[/tex]

The foci is then (h ± c, k)

Therefore, by comparison, the foci of the given hyperbola is (6 ± c, -7)

Where c² = a² + b²

∴ c² = 4² + 3² = 25

c = √25 = 5

∴ The foci; (6 ± 5, -7) = (11, -7) or (1, -7).

Answer:

Start by setting it up with the divisor 3 on the left side and the dividend 105 on the right side like this:

   3 ⟌ 1 0 5

Step 2:

The divisor (3) goes into the first digit of the dividend (1), 0 time(s). Therefore, put 0 on top:

       0    

   3 ⟌ 1 0 5

Step 3:

Multiply the divisor by the result in the previous step (3 x 0 = 0) and write that answer below the dividend.

       0    

   3 ⟌ 1 0 5

      0    

Step 4:

Subtract the result in the previous step from the first digit of the dividend (1 - 0 = 1) and write the answer below.

       0    

   3 ⟌ 1 0 5

     - 0    

       1    

Step 5:

Move down the 2nd digit of the dividend (0) like this:

       0    

   3 ⟌ 1 0 5

     - 0    

       1 0  

Step 6:

The divisor (3) goes into the bottom number (10), 3 time(s). Therefore, put 3 on top:

       0 3  

   3 ⟌ 1 0 5

     - 0    

       1 0  

Step 7:

Multiply the divisor by the result in the previous step (3 x 3 = 9) and write that answer at the bottom:

       0 3  

   3 ⟌ 1 0 5

     - 0    

       1 0  

         9  

Step 8:

Subtract the result in the previous step from the number written above it. (10 - 9 = 1) and write the answer at the bottom.

       0 3  

   3 ⟌ 1 0 5

     - 0    

       1 0  

     -   9  

         1  

Step 9:

Move down the last digit of the dividend (5) like this:

       0 3  

   3 ⟌ 1 0 5

     - 0    

       1 0  

     -   9  

         1 5

Step 10:

The divisor (3) goes into the bottom number (15), 5 time(s). Therefore put 5 on top:

       0 3 5

   3 ⟌ 1 0 5

     - 0    

       1 0  

     -   9  

         1 5

Step 11:

Multiply the divisor by the result in the previous step (3 x 5 = 15) and write the answer at the bottom:

       0 3 5

   3 ⟌ 1 0 5

     - 0    

       1 0  

     -   9  

         1 5

         1 5

Step 12:

Subtract the result in the previous step from the number written above it. (15 - 15 = 0) and write the answer at the bottom.

       0 3 5

   3 ⟌ 1 0 5

     - 0    

       1 0  

     -   9  

         1 5

     -   1 5

           0

You are done, because there are no more digits to move down from the dividend.

The answer is the top number and the remainder is the bottom number.

Therefore, the answer to 105 divided by 3 calculated using Long Division is:

35

0 Remainder

Step-by-step explanation:

Answer:

5 half of the e

Step-by-step explanation:

Answer:

Sammy would have 16 friends.

Step-by-step explanation:

Let total number of friends be x, each friend gets 2 balls, this can be denoted as 2x balls.

The final relation can be expressed as:

40 (total number) =2x+8 , here 8 is the remainder after distribution.

Now we can solve for x

40=2x+8

40−8=2x

32=2x

x=16

Answer:

16 friends

Step-by-step explanation:

40 balls - 8 remaining = 32 balls in total

32 b in total / 2 balls each = 16 friends

hope this helps

Answer:

No value because 4π/5 exceeds the domain

Step-by-step explanation:

The domain and range of sin^-1(x) is a domain of [-1,1] and a range of [-π/2,π/2]

Since 4π/5>1, this exceeds the domain and therefore has no value.

Answer:

K= -2J+24

Step-by-step explanation:

Good luck .

Hope this helps .

Answer:y

Step-by-step explanation:

Answer: I would say 6 its a function and 7 its not because in number seven the x value repeats so it can't be a function and number 6 the x-value its not the same

Step-by-step explanation: When the x-value repeats its not a function if the y-value repeats it doesn't matter

Answer:

136 ft^2

Step-by-step explanation:

Surface area = 2 [ (l*w) + (l*h) + (w*h) ]

= 2 [ (8*3) + (8*4) + (4*3) ]

= 136 ft^2

Answer:

-4a

Step-by-step explanation:

Answer:

C:  (0, 5)

Step-by-step explanation:

The x-coordinates are all the same:  0.  In y = 2x + 5, the 2x term would be zero in all those cases, leaving only the y-intercept (5).  

We conclude that the line would pass through (0, 5), which is the y-intercept.

Answer:

The last two

Step-by-step explanation:

Answer:

so it is more than 1 quart, but less than 1.5 quarts, so narrow down the answer choices

1. w could be 3/4? no. 3/4 is less than 1  

2. w could be 1. no. the bottle contains more than 1 quart.

3. w>1 it could be, but it dosent specify what w is, so we have no way of knowing if its over or under 1.5

4. w could be 4/3. yes that works. in mixed form it would be 1 and 1/3, it is more than one, but less than 1.5

5. w could be 5/3 no. 5 over 3 in mixed forn is 1 and 2/3, witch is over 1.5

6. w>1.5 nope. it cant be over 1.5

THE ANSWER IS THE 4TH ANSWER. W COULD BE 4/3

Answer:

17

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√[4 - (-4)]² + [8 - (-7)]²

√(8)² + (15)²

√64 + 225

√289

=17

Answer:

50.26 is the area.

Hope it helps!!!

[tex] \boxed{(6, -3)} [/tex]

Step-by-step explanation:

Given the ratio 5:3

and Points A and B where A is located at (-6, 3), and B is located at (26, -13).

Let point A be [tex] (x_{1}, y_{1}) [/tex], and let point B be [tex] (x_{2}, y_{2}) [/tex].

(-6, 3) → [tex] (x_{1}, y_{1}) [/tex].

(26, -13) → [tex] (x_{2}, y_{2}) [/tex].

Let 5 be n, and 3 be m.

5:3 → n:m

[tex] (\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}) [/tex].

To solve, just substitute these variables into the expressions of these coordinates to get the answer.

[tex] (\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}) [/tex] →

[tex] (\frac{(5)x_{1} + (3)x_{2}}{(5)+(3)}, \frac{(5)y_{1} + (3)y_{2}}{(5) + (3)}) [/tex] →

[tex] (\frac{(5)(-6)+ (3)(26)}{(5)+(3)}, \frac{(5)(3)+ (3)(-13)}{(5) + (3)}) [/tex] →

[tex] (\frac{-30 + 78}{8}, \frac{15+ -39}{8}) [/tex] →

[tex] (\frac{78 – 30}{8}, \frac{15 – 39}{8}) [/tex] →

[tex] (\frac{48}{8}, \frac{-24}{8}) [/tex]

→

[tex] (\frac{6}{1}, \frac{-3}{1}) [/tex]

→

[tex] (6, -3) [/tex].

Thus the coordinates of B are:

[tex] \boxed{(6, -3)} [/tex]

Answer:

Step-by-step explanation:

AB:BC::5:3

let the coordinates be (x,y)

[tex]x=\frac{nx1+mx2}{m+n} \\=\frac{3(-6)+5(26)}{5+3} \\=\frac{-18+130}{8} \\=\frac{112}{8} \\=14\\y=\frac{ny1+my2}{m+n} \\=\frac{3(3)+5(3)}{5+3} \\=\frac{9+15}{8} \\=\frac{24}{8} \\=3\\[/tex]

coordinates of B are (14,3)

Answer:

It is actually called a compass...

Step-by-step explanation:

Answer:

They're called geometrical proportional dividers.

Answer:

16n^2+40n+25

Step-by-step explanation:

answer is x<8

Step-by-step explanation:

Answer:

4 hours

Step-by-step explanation:

is 40 is two hours then 80 must be 4 hours

Answer:

25%

Step-by-step explanation:

We can use a proportion to answer this question:

64 represent the 100% of the games

so:

x : 100 = 16 : 64

x = (16*100)/64 = 1600/64 = 25%

Answer:

13 miles

Step-by-step explanation:

Given that he traveled in a straight line to each destination. Then,

i. distance from his home to soccer field = [tex]\sqrt{x^{2} + y^{2} }[/tex]

                                      = [tex]\sqrt{4^{2} + 3^{2}}[/tex]

                                      = [tex]\sqrt{16 + 9}[/tex]

                                      = [tex]\sqrt{25}[/tex]    = 5 miles

ii. The distance from soccer field to the library = 8 miles.

So that we can say that;

Ryan's total distance from home to the library = 5 + 8

                                                      = 13 miles

Thus, Ryan would have traveled 13 miles by the time he reached the library.

Answer:

$1.50

Step-by-step explanation:

12/8 = 1.50

Answer:

each taco cost $1.50

Step-by-step explanation:

Answer:

$39.36

Step-by-step explanation:

Since its 20% off that means we still have a remaining 80% so first multiply 0.8 to the 82

82x0.8= 65.6

Since there is a additional 40% off multiply by 0.4 to get the discount amount

65.6x0.4= 26.24

Subtract the discount from the price

65.6-26.24= 39.36

Given:

The set is:

[tex]\{2,3,5,7,11\}[/tex]

To find:

The set builder notation for the given set.

Solution:

Consider the given set:

[tex]S=\{2,3,5,7,11\}[/tex]

The element of given set are 2, 3, 5, 7, 11 and so on. These area the prime numbers.

If x defines each element of the set then x must belongs to P which is the set of prime numbers. So, the given set can be written as

[tex]S=\{x|x\in P\}[/tex]

Therefore, the set builder notation for the given set is [tex]\{x|x\in P\}[/tex].