Answer:
a. Red and Orange
b. Yes, they are
Explanation:
a. This is because, since the yellow light is reflected back into the water, it undergoes total internal reflection and its wavelength in water is not long enough to allow it penetrate the water surface. Since the wavelength decreases from left to right, both the green and blue light have shorter wavelength than the yellow light, so they get reflected back. The red and orange lights are more likely to penetrate since they have longer wavelengths than the yellow light.
b. This is because the red and orange light have longer wavelengths and are thus more likely to penetrate the water surface and not get reflected back.
Which are dangerous places to put a flammable substance? Check all that apply.
near a flame
on a scale
near a ruler
in a sink
near a hot plate
Answer:
near a flame and a hot plate
Explanation:
state the property of plastic that allows it to become electrostatically charged
(please answers ty)
Answer:
when a plastic rod is rubbed with a duster, electrons are transferred from one material to the other. The material that gains electrons becomes negatively charged. The material that loses electrons becomes positively charged.
6.__friction acts on objects that are not moving. *
which one is the answer ? (Science)
rolling
static
sliding
Answer:
STATIC friction acts on objects that are not moving........
Explanation:
DOES THIS HELPS!!
PLZ HELP NO SNEAKY LINK OR I WILL REPORT U OR NON ANSWERS
What is the atomic composition of methane
Answer:
As in chemical formula? It's CH4.
Electromagnetic waves are commonly referred to as _________
O electricity
O magnetism
O light
1. Which statement about data attenuation is true? (1 point)
Data carried on a fiber-optic cable experience more attenuation than data broadcast from a radio tower.
Fiber-optic cables experience very little attenuation over large distances.
Data carried on a fiber-optic cable experience more attenuation than data carried on a copper wire.
Data carried on a copper wire and data broadcast from a radio tower experience very little attenuation over large distances.
2. Which statement is an example of information being carried by an electromagnetic wave that has been interpreted by humans?(1 point)
A sound wave in an ultrasound machine transmits information about the parts of the body it travels through.
A seismic wave changes speed, conveying information about the materials it has passed through.
A wave in the ocean changes, indicating a change in the depth of the water.
A light wave from a distant galaxy experiences redshift, indicating that the galaxy is moving away from Earth.
3. Which statement is true about a parabolic dish? (1 point)
It reflects waves and focuses them to a point.
It refracts waves in the dish.
It absorbs the wave energy.
It filters the type of electromagnetic radiation.
4. Which natural phenomenon describes guitar strings vibrating at certain natural frequencies?(1 point)
interference
beats
oscillation
resonance
5. What will increase the power output when doing work?(1 point)
doing less work in the same amount of time
doing the same work in less time
doing the same work in more time
doing less work and increasing the amount of time
Answer:
1. c
2. d
3. a
4. d
5. c
Explanation:
im pretty sure im right
How many times does the kinetic energy of a car increase when traveling 60 mph as opposed to traveling 15 mph?
K.E. increases
5
4
16
20
Answer:
20
Explanation:
i'm not so sure with my answer
What is f if you have an object 2.0 m from the concave mirror, and the image is 4.0 m from the mirror?
Answer:
the f is 1.3 m
Explanation:
Given that
An object 2.0m is from the concave mirror
And, the image is 4.0m from the mirror
We need to find out the f
So,
u = -2 m
v = -4 m
1 ÷ f = 1 ÷ v + 1 ÷ u
= (-1 ÷ 4) + (-1 ÷ 2)
= -3 ÷4
f = -4 ÷ 3
= |1.3| m
Hence, the f is 1.3 m
A coil of 27 turns is in the shape of an ellipse having a major axis of 12.0 cm and a minor axis of 9.00 cm. The coil rotates at 57rpm in a region in which the Earth's magnetic field is 74.0 microT. What is the maximum voltage induced in the coil if the axis of rotation of the coil is along its major axis and this axis of rotation is aligned perpendicular to the Earth's magnetic field
Answer:
Explanation:
Emf induced e = nBAω sinωt where n is no of turns , B is magnetic field, A is area of the coil ω is angular frequency of rotation .
maximum emf = nBAω
Given n = 27 , B = 74 x 10⁻⁶ T , A = .12 m x .09 m = 108 x 10⁻⁴ m²
ω = 2π x 57/60 = 5.966 rad/s .
Putting the values
maximum emf = 27 x 74 x 10⁻⁶ T x 108 x 10⁻⁴ m² x 5.966 rad/s .
= 1.29 x 10⁻⁴ V .
Usain Bolt is wicked fast. In fact, he is the fastest human in the world and
ran at a crazy 10.1 m/s in the Olympic Games. What is his mass if he had
9.890 Joules of kinetic energy in that race?
Explanation:
KE = (1/2)mv^2 ---> m = 2KE/v^2 = 2(9.890 J)/(10.1 m/s)^2
= 0.194 kg
Note: I think there's something wrong with the energy value given. The mass value for Usain Bolt is too small. That's less than a pound!
It’s bungee jumping skydiving and hiking
How are work and power different
Work is defined as the process of energy transfer to the motion of an object through the application of force. Power is defined as the amount of energy transferred in unit time.
When you perform the skill of _____________, you must track the object before receiving it.
kicking
striking
catching
throwing
Answer:
uhh that is a hard question
Explanation:
cathcing or throwing
When you perform the skill of catching, you must track the object before receiving it. Therefore, option (C) is correct.
What are manipulative skills?Manipulative skills can be described as those skills which require the ability to handle an object or piece of equipment with control. They involve skills such as striking, kicking, dribbling, or catching a ball.
Manipulative skills involve moving an object with the hands or feet to get a goal or fulfill a task. The objects might be used as equipment or toys such as balls, bats, racquets, or jump ropes. Manipulative skills are also called object-control skills.
Types of Manipulative Skills are Bouncing, Catching, Dribbling (moving a ball with the feet), Kicking or rolling, Lifting, Pushing and pulling (the object might be a wheeled toy), Striking (such as swinging a baseball bat), Throwing, and Volleying.
Therefore, we track the object before receiving during catching,
Learn more about Manipulative Skills, here:
https://brainly.com/question/14621320
#SPJ2
In a cloud chamber experiment, a proton enters a uniform 0.260 T magnetic field directed perpendicular to its motion. You measure the proton's path on a photograph and find that it follows a circular arc of radius 6.42 cm.
Required:
How fast was the proton moving?
Answer:
the proton speed of the proton was 1.6 × 10⁶ m/s
Explanation:
Given the data in the question;
Radius r = 6.42 cm = 0.0642 m
magnetic field B = 0.260 T
we know that; charge of proton q = 1.602 × 10⁻¹⁹ C
And mass of proton m = 1.672 × 10⁻²⁷ kg
we know that; Magnetic Force F = qvBsinθ
where q is the charge of proton, v is velocity, B is the magnetic field and θ is angle ( 90° )
Also the Centripetal force experienced by the particle is;
F = mv² / r
where r is radius, m is mass of proton and v is velocity
hence;
qvBsinθ = mv² / r
we solve for v
rqvBsinθ = mv²
divide both sides by mv
rqvBsinθ / mv = mv² / mv
rqBsinθ / m = v
so we substitute
v = [ 0.0642 m × (1.602 × 10⁻¹⁹ C) × 0.260 T × sin(90°) ] / 1.67 × 10⁻²⁷ kg
v = 2.6740584 × 10⁻²¹ / 1.672 × 10⁻²⁷
v = 1.6 × 10⁶ m/s
Therefore, the proton speed of the proton was 1.6 × 10⁶ m/s
A student decides to give his bicycle a tune up. He flips it upside down (so there's no friction with the ground) and applies a force of 34 N over 0.6 seconds to the pedal, which has a length of 16.5 cm. If the back wheel has a radius of 33.0 cm and moment of inertia of 1200 kg cm^2, what is the tangential velocity of the rim of the back wheel in m/s
Answer:
[tex]V=9.2565m/s[/tex]
Explanation:
From the question we are told that:
Force [tex]F = 34 N[/tex]
Time [tex]t = 0.6 s[/tex]
Length of pedal [tex]l_p=16.5cm \approx0.165m[/tex]
Radius of wheel [tex]r = 33 cm = 0.33 m[/tex]
Moment of inertia, [tex]I = 1200 kgcm2 = 0.12 kg.m2[/tex]
Generally the equation for Torque on pedal [tex]\mu[/tex] is mathematically given by
[tex]\mu=F*L\\\mu=34*0.165[/tex]
[tex]\mu=5.61N.m[/tex]
Generally the equation for angular acceleration [tex]\alpha[/tex] is mathematically given by
[tex]\alpha=\frac{\mu}{l}[/tex]
[tex]\alpha=\frac{5.61}{0.12}[/tex]
[tex]\alpha=46.75[/tex]
Therefore Angular speed is \omega
[tex]\omega=\alpha*t[/tex]
[tex]\omega=(46.75)*(0.6)[/tex]
[tex]\omega=28.05rad/s[/tex]
Generally the equation for Tangential velocity V is mathematically given by
[tex]V=r\omega[/tex]
[tex]V=(0.33)(28.05)[/tex]
[tex]V=9.2565m/s[/tex]
A box is at rest on a table. What can you say about the forces acting on the box?
The upward
and the downward
are balanced.
Answer:
normal force and gravitational force
Explanation:
I hope this helps :D
Find the Input force, if the Mechanical Advantage of the simple machine used is 5 and Output force is 50 N.
P.S PLEASE DO NOT POST A LINK THAT I HAVE TO DOWNLOAD EVERY TIME I ASK A QUESTION PEOPLE POST THAT JUST POST A WRITEN ANSWER WITH AN EXPLINATION THAT IS ALL
Answer:
6N
Explanation:
Draw and label where the molecules of the test mixture ended up after the fan was turned off
Answer:
ahhahsvdjdjkd
Explanation:
sbnwtauajababcahajanavgzuz
A standard parallel plate capacitor is connected to a battery and is given enough time to charge fully. After it is fully charged, the capacitor is disconnected from the battery. After that, prankster Bob comes along and pulls the plates further apart from each other, doubling the distance d between the plates. How do the following quantities change? The choices are: quadruple, double, stay the same, halve, or quarter.
a) Capacitance
b) Charge on the capacitor
c) Voltage across the capacitor
d) Electric field within the capacitor
e) Energy stored in the capacitor
f) Does Bob have to do work in order to pull the plates apart? (Yes or no, and a brief explanation)
g) Are parts (e) and (f) consistent, given that the battery was disconnected?
Answer:
a) capacitance is doubled., b) Q = cte, c) oltage doubling the distance doubles, d) ΔE =0, e) U = Q² / 2C, f) W>0
Explanation:
he capacitance of a condensate is
C =[tex]\frac{ Q}{ \Delta V} =\epsilon_o \frac{A}{d}[/tex]
let's use this expression to answer the question
a) Capacitance.
Without distance, the capacitance is doubled.
Answer: Half
b) The charge.
As the battery is disconnected, no more electrons reach the capacitor, so the charge remains the same
Q = cte
c) the voltage
ΔV = E d = ([tex](\frac{Q}{\epsilon_o A}) \ d[/tex]
so the voltage doubling the distance doubles
d) The electric field between parallel plates is constant
E = Q / A eo
E =0
e) The stored energy is described by the expression
U = Q² / 2C
as capacitance decreases and discant increases, stored energy increases
f) The work to separate the positive charge, that the force must be in the same direction as the electric force
g) when the battery is disconnected the energy in the capacitor remains constant
You can see things outside of a beam of light because of? I NEED HELP ASAP
Answer:
Reflected light bounces off of materials that for whatever reason cannot absorb the light. The reflected light is always whatever color it was originally. We do not see things from light that is reflected. We see things from the light that they EMIT.
According the Law of Inertia _____.
the Earth's gravitational pull is less than that of the sun's
the Earth will keep moving unless acted up on by a force
the Earth will stop moving on its own
the Earth's gravitational pull is greater than that of the moon's
Answer:
The Earth will keep moving unless acted up on by a force
Explanation:
Not A because that's not the law of inertia
It's B because that is pretty much the definition of the law of inertia
Not C because Earth will not stop moving on it's own
Again, not the definition of the law of inertia
Answer:
B
Explanation:
You are riding your bicycle down the street at a speed of 14 m/s. Your bicycle frame has a mass of 6.6 kg, and each of its two wheels has mass 2.2 kg and radius 0.35 m. Each wheel can be thought of as a hollow hoop (assuming that the rim has much larger mass than the spokes). What is the total kinetic energy of the bicycle (in Joules), taking into account both the translational and rotational motion
Answer:
1078 Joules
Explanation:
The computation of the total kinetic energy of the bicycle is shown below:
Given that
mass of bicycle's frame (m) = 6.6 kg
mass of each wheel (M) = 2.2 kg
radius of each wheel (r) = 0.35 m
And, the linear speed (v) = 14 ms
Now
As we know that
Angular velocity (ω) = v ÷ r
= 140 ÷ .35
= 40 rads
Total kinetic energy = translational kinetic energy + rotational kinetic energy
= (1 ÷2 × m × v^2) + (2 × 1 ÷ 2×I × ω^2)
= (0.5 × 6.6 × [14]^2) + (M × r2 × ω^2)
= 646.8 + (2.2 × 0.35 × 0.35 × [40]^2)
= 646.8 + 431.2
= 1078 Joules
Part A : A cylindrical water tank 10cm high and 520cm in diameter is filled with solution with a density of 0.75 g/cm^3
a) What is the water pressure on the bottom of the tank? (pressure in psi)
Show calculations
b) What is the average force on the bottom?
Answer: [tex]0.1066\ psi, 15.611\ kN[/tex]
Explanation:
Given
the height of the tank is [tex]h=10\ cm[/tex]
The diameter of the tank is [tex]d=520\ cm[/tex]
Density of solution [tex]\rho=0.75\ g/cm^3\ or\ 750\ kg/m^3[/tex]
[tex](a)[/tex] Water pressure at the bottom of the tank is
[tex]P=\rho gh\\P=750\times 9.8\times 0.1\\P=735\ Pa[/tex]
[tex]1\ Pa=0.000145038\ psi[/tex]
[tex]\Rightarrow P=735\ Pa\ or\ 0.1066\ psi[/tex]
[tex](b) \text{Average force on the bottom is the product of pressure and area of the base}[/tex]
[tex]F_{avg}=735\times \pi \cdot (\frac{520}{200})^2\\\\F_{avg}=735\times 3.142\times 6.76\\F_{avg}=15,611.34\ N\ or\ 15.611\ kN[/tex]
A nurse asks a doctor about medication for a
patient in a hospital. The doctor accidentally tells
the nurse to give the patient the wrong
medication, and the nurse follows the doctor's
orders. Which type of medical error has occurred?
Answer:
medication error thats easy
A force F making an angle with the horizontal is acting on an object resting on the table. Which statement is true for the motion of sliding the object on the table? A. It is independent of all the forces acting on the object. B. It depends only on the forces acting along the x-axis. C. It depends only on the forces acting along the y-axis. D. It depends only on the normal force acting on the object. E. It depends only on the frictional force acting on the object.
Answer:
C
Explanation:
it depends only on the forces acting along the y- axis
Answer:
The statement that is true for the motion of sliding the object on the table is : its independent of all forces acting on the object
Explanation:
A catapult of pole length 4r throws a pumpkin from one
end of a pole which rotates about an axis at the other
end with angular speed w.
A smaller catapult of pole length r throws another
pumpkin from one end of a pole which rotates about an
axis at the other end with the same angular speed was
the first catapult.
How does the linear speed of the larger catapult's
pumpkin Vlarge compare with the smaller catapult's
pumpkin Vsmall?
Answer:
vlarge = 4vsmall
Explanation:
Khan Academy
An ice-making machine inside a refrigerator operates in a Carnot cycle. It takes heat from liquid water at 0.0 degrees Celsius and rejects heat to a room at a temperature of 20.6 degrees Celsius. Suppose that liquid water with a mass of 82.1 kg at 0.0 degrees Celsius is converted to ice at the same temperature. Take the heat of fusion for water to be Lf=3.34×105 J/kg.
A. How much heat |QH| is rejected to the room?
B. How much energy E must be supplied to the device?
Answer:
A. Q = 2.74 x 10⁷ J = 27.4 MJ
B. E = 3.91 x 10⁸ J = 391 MJ
Explanation:
A.
Heat rejected can be found as follows:
[tex]Q = mL[/tex]
where,
Q = Heat rejected = ?
m = mass = 82.1 kg
L = Latent Heat of fusion = 334000 J/kg
Therefore,
[tex]Q = (82.1\ kg)(334000\ J/kg)[/tex]
Q = 2.74 x 10⁷ J = 27.4 MJ
B.
First, we will calculate the efficiency of the Carnot Cycle as follows:
[tex]Efficiency = 1-\frac{T_1}{T_2}[/tex]
where,
T₁ = Heat intake temperature = 0°C + 273 = 273 k
T₂ = Heat rejection temperature = 20.6°C + 273 = 293.6 k
Therefore,
[tex]Efficiency = 1 - \frac{273\ k}{293.6\ k} \\\\Effciency = 0.07[/tex]
Therefore, the energy input required is:
[tex]Efficiency = \frac{Q}{E}\\\\E = \frac{Q}{Efficiency} = \frac{2.74\ x\ 10^7\ J}{0.07}[/tex]
E = 3.91 x 10⁸ J = 391 MJ
I cant solve this problem, and our teacher said that this would be in the test we'll have tomorrow, can someone help me?
A body of m = 6.8kg is launched with a speed of 7.5 m / s towards the top of an inclined plane of 15 ° with respect to the horizontal. in the absence of friction, what displacement does it make before reversing the direction of motion?
Answer:
d = 11.1 m
Explanation:
Since the inclined plane is frictionless, this is just a simple application of the conservation law of energy:
[tex] \frac{1}{2} m {v}^{2} = mgh[/tex]
Let d be the displacement along the inclined plane. Note that the height h in terms of d and the angle is as follows:
[tex] \sin(15) = \frac{h}{d} \\ or \: h = d \sin(15) [/tex]
Plugging this into the energy conservation equation and cancelling m, we get
[tex] {v}^{2} = 2gd \sin(15)[/tex]
Solving for d,
[tex]d = \frac{ {v}^{2} }{2g \sin(15) } = \frac{ {(7.5 \: \frac{m}{s}) }^{2} }{2(9.8 \: \frac{m}{ {s}^{2} })(0.259)} \\ = 11.1 \: m[/tex]
An astronaut in a satellite 1600km above the Earth experience a gravitational force magnitude 700N on earth.The Earth's radius is 6400km calculate the magnitude of the gravitational force which the astronaut experience in satellite
Answer:
The magnitude of the gravitational force which the astronaut experience in satellite [tex]= 448[/tex] Newton
Explanation:
As we know
Gravitational force F = [tex]\frac{GMm}{r^2}[/tex]
Where G is the gravitational constant [tex]6.67 * 10^{-11}[/tex]
M is the mass of earth [tex]= 6* 10^{24}[/tex]
m is not given
r is the radius of earth [tex]6 400*10^3[/tex]
Substituting the given values, we get -
[tex]F = \frac{6.67*10^{−11}*6*10^{24}* m}{(6400*10^3)^2}[/tex]
[tex]m = 71.6[/tex] Kg
Gravitational force in the satellite
[tex]F = \frac{6.67*10^{−11}*6*10^{24}* m}{(6400*10^3 + 1600 *10^3)^2}\\F = 448[/tex]N