Answer:
Because Sulphuric acid(H2SO4) is one of the substance which have a very high vigourous reaction if mix with chemicals thats why we take the same sulphuric acid but having lighter effects known to be as Dil.Sulphuric And so it is generally use for precaution while during experimentations Thats why we use it.
Hope it helps
Meera added blue copper sulphate crystals to some water in a beaker.
The copper sulphate dissolved in the water.
1 give one way meera could see that the copper sulphate had dissolved in the
Answer:
The solid crystals disappeared
Explanation:
When a soluble solid solute is added to water, the solid solute disappears after a little while. The disappearance of this solute indicates that the solute has been dissolved in water.
In this case, blue copper sulphate crystals are added to water, the blue crystals disappear leaving only a blue solution. The disappearance of these blue copper sulphate crystals indicates that the substance has dissolved in water.
what is the name of the shape that is a quadrilateral where all 4 sides are the same length
HELP QUICK
Answer:
Square
Explanation:
A square is a quadrilateral with r sides the same length
If 1.25 g of water is heated from 20.0 degrees Celsius to 45.0 degrees Celsius and has a specific
heat of 4.18 J/gC, how much heat energy does it contain?
Answer: Heat energy contained by water is 130.625 J.
Explanation:
Given: Mass = 1.25 g
Specific heat = [tex]4.18 J/g^{o}C[/tex]
Initial temperature = [tex]20.0^{o}C[/tex]
Final temperature = [tex]45.0^{o}C[/tex]
Formula used to calculate heat energy is as follows.
[tex]q = m \times C \times (T_{2} - T_{1})[/tex]
where,
q = heat energy
m = mass of substance
[tex]T_{1}[/tex] = initial temperature
[tex]T_{2}[/tex] = final temperature
Substitute the values into above formula as follows.
[tex]q = m \times C \times (T_{2} - T_{1})\\= 1.25 g \times 4.18 J/g^{o}C \times (45.0 - 20.0)^{o}C\\= 130.625 J[/tex]
Thus, we can conclude that heat energy contained by water is 130.625 J.
A jar is filled to the top with water, and a piece of cardboard is slid over the opening so that there is only water in the . If the jar is now turned over, will the cardboard fall off? What will happen if there is any air in the jar?
Answer:
it will all fall unless these is air
Explanation:
Answer:
If you do it carefully enough, a small amount of water will pour out of the glass — that's supposed to happen. But try not to let any air bubbles get into the glass. Finally, slowly remove the hand holding the cardboard in place.
Past due! Help please I choose the middle picture for my hypothesis being inclusive can you help explain why and how it shows it’s being inclusive?
Answer:
Explanation:
its supposed to be not supported not inclusive because you said mix
¿Cómo se llama el grupo IIA de la tabla periódica?
Answer:
los metales alcalinotérreos: berilio (Be), magnesio (Mg), calcio (Ca), estroncio (Sr), bario (Ba) y radio (Ra).
o simplemente llamado grupo 2A
Explanation:
if an atom has 4 protons, 5 neutrons, and 4 electrons, what would its atomic mass be?
Answer:
4
Explanation:
If I remember correctly, the atomic # will always be the same as the # of electrons
Potassium hydroxide is partially soluble as shown by the
following reaction:
KOH(s) K+ (aq) + OH(aq)
What is the poH of a 3.32 x 10-5 M KOH solution?
pOH =
Your answer should be rounded to three significant figures. Do not Include
units in your answer.
Answer: 4.48 or 4.47
Which element, when combined with Fluorine, would form an COVALENT compound?
A.Lithium
B.Iron
C.Phosphorus
D.Sodium
Answer:
Explanation:
A covalent compound is a compound formed by covalent bonds. A covalent bond is formed between two atoms where electrons are shared between the two atoms. This forms a molecule.
What determines whether two elements will form a covalent compound or not is the number of valence electrons present in each of the elements.
Fluorine will form a covalent compound with phosphorous because fluorine has 5 electrons in its outermost shell. It needs 3 more to become stable.
Phosphorous also has 5 valence electrons. It needs 3 more to become stable.
What happens is that 3 atoms of FLuorine combine with one atom of Phosphorus, sharing the valence electrons between themselves. This leads to the formation of the PF3 molecule.
Both the Phosphorous and the Fluorine are now stable.
Answer: Phosphorus
Explanation: since both are non-metals they would both create a covalent bond.
Four satellites are in orbit around the Earth. The heights of their four orbits
are identical. The masses of the four satellites are given in the table. For
which satellite is the gravitational pull of Earth the strongest?
What is the frequency of a wave that has a wavelength of 0.50 m and a speed of 380 m/s?
Answer: f = 760 Hz
Explanation: speed = frequency · wavelength v = fλ.
frequency f = v/ λ = 380 m/s / 0.50 m = 760 Hz
Oxygen has 6 valence electrons. how many hydrogen atoms (who have 1 valence electrons) can bond with it? remember the octet rule.
Answer:
two hydrogen can bonded with oxygen to form H2O
Select the correct structure that
corresponds to the name.
2,2-dimethyl-3-hexyne
A. CH3CH2C=CC(CH3)3
B. CH3CH(CH3)C = CCH(CH3)2
C. both
Answer: A
Explanation:
The correct structure of the name of the compound given is CH₃CH₂C=CC (CH₃)₃.
What is 2,2-dimethyl- 3- hexyne?Dimethyl hexyne is an organic compound. Its chemical formula is C8H14. The compound hexyne is used to make a complex compound, agrochemical, and pharmaceutical compounds.
Thus, the correct option is A, CH₃CH₂C=CC (CH₃)₃.
Learn more about 2,2-dimethyl- 3- hexyne
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When carbon disulfide, CS2, forms from its elements. Heat is absorbed. How much heat would be required to produce 5.0 moles of carbon disulfide
Answer:
5.9 × 10² kJ
Explanation:
When carbon disulfide, CS₂, forms from its elements, heat is absorbed. The corresponding value for the standard enthalpy of formation of carbon disulfide is 117.36 kJ/mol. The thermochemical equation that represents this process is:
C(graphite) + 2 S(s, rhombic) ⇒ CS₂(g) ΔH°f = 117.36 kJ/mol
117.36 kJ of heat are absorbed when 1 mole of CS₂ is formed. The amount of heat absorbed when 5.0 moles of CS₂ are formed is:
5.0 mol × 117.36 kJ/mol = 5.9 × 10² kJ
What will the change in temperature be when 90 J are applied to 15 g of gold. (Cgold = 0.126 J/gºC)
Round your answer to the nearest whole number.
°C
E
3
4
5
Next
O
I 17
Answer:
48 °C
Explanation:
q = 90J
m = 15 g
C = 0.126 J/gºC
q = mct
90 = (15)(0.126)t
t = 47.62 °C = 48 °C
Answer:
Explanation:
Formula
E = m * c * Δt
Δt is what you seek.
Givens
E = 90 joules
m = 15 grams
c = 0.126
Solution
90 = 15 * 0.126 * Δt Divide by 15
90/15 = 15/15 * 0.126 * Δt
6 = 0.126 * Δt Divide by 0.126
6/0.126 = Δt
47.619 = Δt
Δt = 48 oC
Which is NOT part of the male reproduction system of a flower? stamen pollen anther pistil
Answer:
Pistil
Explanation:
I believe it is the pistil, because the pistil is part of the female reproductive system of a flower. A stamen is for the male reproductive system.
When writing the formulas for a compound that contains a polyatomic ion, ... ?
Answer:
The cation is written first in the name; the anion is written second in the name. Rule 2. When the formula unit contains two or more of the same polyatomic ion, that ion is written in parentheses with the subscript written outside the parentheses.
When writing the formula of a compound that contains polyatomic ion, the metal is written first followed by the central atom in the ion and then other atoms that surround the central atom.
A poly atomic ion refers to an ion that comprises of more than one atom. Such ions are common in chemistry. Examples of polyatomic ions include; PO4^3-, BH4^- etc.
When writing the formula of a compound that contains a polyatomic ion, the metal is written first then the central atom in the ion follows before other atoms that surround the central atom in the ion.
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How would you find the density of a can of soda pop?
A. Find the mass of the can of soda pop and then multiply by the number of cubic centimeters in the can
B. Find the mass of the can of soda pop and then divide by the number of cubic centimeters in the can
C. Convert a gallon into cubic centimeters and then divide by the mass of the can of soda pop
D. Convert a gallon into cubic centimeters and then subtract the mass of the can of soda pop
Answer:
it's A.
Explanation:
have uh good day ma :)))))))
Find the hydroxide concentration of a LiOH soultion that has a pOH of 8.65.
[OH] = _____ (round to 2 decimal places)
Answer: i need help
Explanation:
(10 POINTS!!!!!!!!!!!
What environmental change will take place when harmful substances get into the food and water supply of animals or plants?
A Climate change
B Increased predators
C Lack of food
D Pollution
need asap
Answer:
A climate change
Explanation:
the surrounding area would be effected in all ways imaginable, such as change in air, soil, water, plants, animals. and if you eat those said animals those harmful things can transfur into you
A chemist observed bubbling and fizzing after adding an acid solution to a
white powdery substance in a beaker. Which of the following can be
inferred?
Answer:
a chemical reaction occured
Explanation:
bubbling and fizzing after adding a substance, most offten means a chemical reaction is happening
2. Identify the limiting reactant when 4.68 g of iron reacts with 2.88 g of sulfur to produce Fes.
Fe +
_Sg → FeS
B
C с
A
+
Help please I’ll mark brainliest
Answer:
Iron is limiting reactant
Explanation:
Based on the reaction:
Fe + S → FeS
1 mole of iron reacts per mole of Sulfur
To solve this question we must convert the mass of each reactant to moles using molar masses of each reactant. As the reaction is 1:1, the reactant with the lower amount of moles is limiting reactant.
Moles Fe -Molar mass: 55.845g/mol-
4.68g * (1mol / 55.845g) = 0.0838 moles
Moles S -Molar mass: 32.065g/mol-
2.88g * (1mol / 32.065g) = 0.0898 moles
As the amount of moles of Fe < Moles S,
Iron is limiting reactant
When 4.68 g of iron reacts with 2.88 g of sulfur to produce FeS, iron is the limiting reagent.
What is limiting reagent?
If in a chemical reaction two reactants are present and one of them is present in less quantity as compared to other, is known as limiting reagent.
Given chemical reaction is:
Fe + S → FeS
From the stoichiometry of the reaction it is clear that equal moles of both reactant is required for the formation of product, so their mole ratio is 1:1.
Now we calculate the moles by using the formula:
n = W/M, where
W = given mass
M = molar mass
Moles of 4.68g of iron = 4.68g / 55.845g/mole = 0.0838 moles
Moles of 2.88 of sulfur = 2.88g / 32.065g/mole = 0.0898 moles
Moles of iron is less as compare to the sulfur, so it is the limiting reagent.
Hence, iron is the limiting reagent.
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(hurry pls)Carl plugs in a lamp that has 0.67 of resistance and 8.1 volts running through it. What is the amount of current running through the lamp? C 543 A C 0.08 A C 12.09 A C743 A
Answer:
C)12.09 Ampere
Explanation:
V= IR
Where I= current of the system
R= resistance= 0.67 ohm
V= potential difference=8.1 volts
Substitute the values
8.1= I× 0.67
I= 8.1/0.67
=12.09 Ampere
(part 1 of 3) Copper reacts with silver nitrate through a single replacement. If 1.29 g of silver are produced from the reaction, how much copper(II) nitrate is also produced? Answer in units of mol. (part 2 of 3) How much Cu is required in this reaction? Answer in units of mol. (part 3 of 3) 1.0 points How much AgNO3 is required in this reaction? Answer in units of mol.
Answer:
See explanation.
Explanation:
Hello there!
In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:
[tex]Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2[/tex]
Thus, we proceed as follows:
Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:
[tex]m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2} \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2[/tex]
Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:
[tex]m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu} \\\\m_{Cu}=0.380gCu[/tex]
Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:
[tex]m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3} \\\\m_{AgNO_3}=2.03gAgNO_3[/tex]
Best regards!
What are the two limitations of earth plates
Answer:
The tectonic style and viability of modern plate tectonics in the early Earth is still debated. Field observations and theoretical arguments both in favor and against the uniformitarian view of plate tectonics back until the Archean continue to accumulate. Here, we present the first numerical modeling results that address for a hotter Earth the viability of subduction, one of the main requirements for plate tectonics. A hotter mantle has mainly two effects: 1) viscosity is lower, and 2) more melt is produced, which in a plate tectonic setting will lead to a thicker oceanic crust and harzburgite layer. Although compositional buoyancy resulting from these thick crust and harzburgite might be a serious limitation for subduction initiation, our modeling results show that eclogitization significantly relaxes this limitation for a developed, ongoing subduction process. Furthermore, the lower viscosity leads to more frequent slab breakoff, and sometimes to crustal separation from the mantle lithosphere. Unlike earlier propositions, not compositional buoyancy considerations, but this lithospheric weakness could be the principle limitation to the viability of plate tectonics in a hotter Earth. These results suggest a new explanation for the absence of ultrahigh-pressure metamorphism (UHPM) and blueschists in most of the Precambrian: early slabs were not too buoyant, but too weak to provide a mechanism for UHPM and exhumation.
Explanation:
17 moles of oxygen is equals to how many grams
17 × ( 2 × 16 ) = 17 × 32 = 544 grams
___________________________
Use the given Nernst equation and reaction to solve this problem. What is the potential of this cell with the given conditions?
2Li (aq) + F2(g) 2Li+(aq) + 2F- (aq)
E° = +5.92 volts
T = 200°C
[Li+] = 10.0 molar
[F-] = 10.0 molar
Answer:
The 2nd one is the one
Explanation:
and it isn't writen out all the way
Which formula represents an isomer of this compound?
Answer:
Explanation:
I can’t explain but this is the answer LOL
Ammonia gas (NH3) combines with oxygen gas (O2) to form diatomic nitrogen gas and water vapor. If 4.0 grams of ammonia react, how many liters of nitrogen gas are produced? The gas is collected at 32.00°C and a pressure of 2.6 atmospheres.
Answer:
1.13 L
Explanation:
First, we have to write the chemical equation for the reaction between ammonia gas (NH₃) and oxygen gas (O₂) to give nitrogen gas (N₂) and water (H₂O), as follows:
NH₃(g) + O₂(g) → N₂(g) + H₂O(g)
Then, we have to balance the equation (we write first the coefficient 2 for NH₃ to balance N atoms, then a coefficient of 3 for H₂O to balance H atoms, and finally 1/3 to balance the O atoms):
2 NH₃(g) + 3/2 O₂(g) → N₂(g) + 3 H₂O(g)
In the balanced equation, we can see that 1 mol of N₂ is produced from 2 moles of NH₃. We convert the moles of NH₃ to grams by using its molecular weight (MW):
MW(NH₃) = 14 g/mol N x 1 + (1 g/mol H x 3) = 17 g/mol
grams of NH₃ = 17 g/mol x 2 = 34 g
Thus, we have the stoichiometric ratio:
1 mol of N₂/2 mol NH₃ = 1 mol of N₂/34 g NH₃
To calculate how many moles of N₂ are produced from 4.0 of NH₃, we multiply the mass by the conversion factor:
4.0 g NH₃ x 1 mol of N₂/34 g NH₃ = 0.1176 moles N₂
Finally, we calculate the liters of N₂ gas by using the ideal gas equation:
PV = nRT ⇒ V = nRT/P
We introduce the data in the equation:
T = 32.00°C + 273 = 305 K
P = 2.6 atm
R = 0.082 L.atm/K.mol (is the gas constant)
n= 0.1176 moles
⇒ V = nRT/P = (0.1176 mol x 0.082 L.atm/K.mol x 305 K)/(2.6 atm)
= 1.13 L
2). A student collects 425 L of oxygen at a temperature of 24.0°C and a pressure
of 0.899 atm. How many moles of oxygen did the student collect?
Answer:
15.5 moles
Explanation:
Applying,
PV = nRT.................. Equation 1
Where P = pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.
Make n the subject of the equation
n = PV/RT............... Equation 2
From the question,
Given: P = 0.899 atm, V = 425 L, T = 24 °C = (273+24) K = 297 K.
Constant: R = 0.083 L.atm/K.mol
Substitute these values into equation 2
n = (0.899×425)/(297×0.083)
n = 15.5 moles