why do other gases in the air not condense and change States​

Answer:

1 m/s²

Explanation:

a = (Vf - Vi)/t

a = (3-1)/(2)

a = 2/2

a = 1 m/s²

I might be wrong ‍¯\_(ツ)_/¯

Answer:

MRI and Radio telescopes

MRI and radio telescopes would be unaffected by satellites that are not working properly.

The longest wavelengths in the electromagnetic spectrum are found in radio waves, which typically have frequencies of 300 gigahertz (GHz) and lower. The wavelength for 300 GHz is 1 mm, which is shorter than a grain of rice, while the wavelength for 30 Hz is 10,000 km (6,200 miles) (longer than the radius of the Earth).

Radio waves move at the speed of light in a vacuum, as do all electromagnetic waves, and at a nearly identical speed in the Earth's atmosphere.

Among the given options, space communication and television broadcasting television broadcasting and GPS  and  radio telescopes and space communication​ are affected by satellites that are not working properly because they are operated by satellite technology.

Hence, only MRI and radio telescopes would be unaffected by satellites that are not working properly.

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Answer:

Explanation:

This is a fast plane! At it's takeoff speed, it could fly around the world in 5 seconds!

Acceleration is defined as the change in speed over the change in time.

[tex]a = \frac{v_f - v_o}{t}[/tex]

Where v_f is the final velocity, v_o is the original velocity, and t is the time.

We know v_f = 8820km/s.

v_o = 0 km/s. The plane "starts at rest before it's engine start." So we know it starts from zero velocity.

t = 32.8 seconds.

You can solve the equation from there.

Answer:

a) The bullet will penetrate 0.375 meters into the bag of sand.

b) The average force exerted by the sand is 15 newtons.

Explanation:

The statement is incorrectly written. The correct form is presented below:

A bullet of mass 50 grams travelling with a speed of 15 meters per second penetrates into a bag of sand and is uniformly brought to rest in 0.05 second.

a) How far the bullet will penetrate into the bag of sand?

b) The average force exerted by the sand?

b) The average force exerted by the sand on the bullet ([tex]F[/tex]), measured in newtons, is determined by Principle of Linear Momentum Conservation and Impulse Theorem:

[tex]F = \frac{m\cdot (v_{f}-v_{o})}{\Delta t}[/tex] (1)

Where:

[tex]m[/tex] - Mass of the bullet, measured in kilograms.

[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the bullet, measured in meter per second.

[tex]\Delta t[/tex] - Impact time, measured in seconds.

If we know that [tex]m = 0.05\,kg[/tex], [tex]v_{o} = 15\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex] and [tex]\Delta t = 0.05\,s[/tex], then the average force exerted by the sand is:

[tex]F = \frac{(0.05\,kg)\cdot \left(0\,\frac{m}{s}-15\,\frac{m}{s} \right)}{0.05\,s}[/tex]

[tex]F = -15\,N[/tex]

The average force exerted by the sand is 15 newtons.

a) The distance travelled by the bullet ([tex]\Delta s[/tex]), measured in meters, is determined by application of Principle of Energy Conservation and Work-Energy Theorem:

[tex]\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F }[/tex] (2)

If we know that [tex]m = 0.05\,kg[/tex], [tex]v_{o} = 15\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex] and [tex]F = -15\,N[/tex], then the distance travelled by the bullet is:

[tex]\Delta s = \frac{(0.05\,kg)\cdot \left[\left(0\,\frac{m}{s} \right)^{2}-\left(15\,\frac{m}{s} \right)^{2}\right]}{2\cdot (-15\,N)}[/tex]

[tex]\Delta s = 0.375\,m[/tex]

The bullet will penetrate 0.375 meters into the bag of sand.

Answer:

The weight is distributed throughout the airplane, but we can often think of it as collected and acting through a single point called the center of gravity. In flight, the airplane rotates about the center of gravity, but the direction of the weight force always remains toward the center of the earth.

Explanation:

Answer:

c

Explanation:

Answer:

Please find attached file

Explanation:

The rate of change of velocity with respect to time is known as acceleration. The acceleration of the ball will be 10m/s.

The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The pace at which a body's velocity varies is represented by acceleration, which is a vector quantity.

The given data in the problem is given by ;

u is the initial speed of ball = 0 m/sec

v is the final speed of the ball= 10 m/sec

t is the time interval= 2 second

a is the acceleration of ball=? m/sec²

The formula for acceleration is;

[tex]\rm a=\frac{(v-u)}{t} \\\\ \rm a=\frac{(20-0)}{2} \\\\\rm a=10\ m/sec^2[/tex]

Hence the acceleration of the ball will be 10m/s².

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Answer:

image distance =-6.6 7cm

image size=1.3cm

Explanation:

Answer:

acceleration is the rate of change of velocity

therefore in the above statement, the velocity increases twice per second.

when acceleration is negative, then it is accelerated motion.

ie. the car accelerates twice per second

Answer:

Final temperature, T2 = 314.9 Kelvin

Explanation:

Given the following data:

Mass = 0.9kg

Initial temperature, T1 = 10°C to Kelvin = 10 + 273 = 283K

Quantity of heat = 120,000 J

Specific heat capacity = 4182 j/kgK

To find the final temperature;

Heat capacity is given by the formula;

[tex] Q = mcdt[/tex]

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Making dt the subject of formula, we have;

[tex] dt = \frac {Q}{mc} [/tex]

Substituting into the equation, we have;

[tex] dt = \frac {120000}{0.9*4182} [/tex]

[tex] dt = \frac {120000}{3763.8} [/tex]

dt = 31.9K

Now, the final temperature T2 is;

But, dt = T2 - T1

T2 = dt + T1

T2 = 31.9 + 283

T2 = 314.9 Kelvin

Answer:

C.) To indicate different versions of the same variable.

Explanation:

Variables in physics often include a subscript. These subscripts are used for indicating different versions of the same variable in physics.

Basically, subscripts are used to represent the beginning (initial) and ending (final) position or point of a variable in physics.

For example, we would look at Gay Lussac' Law of gases.

Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

[tex] PT = K[/tex]

[tex] \frac{P1}{T1} = \frac{P_{2}}{T_{2}}[/tex]

Where;

[tex] T_{1} [/tex] represents the initial temperature.

[tex] T_{2} [/tex] represents the initial temperature.

[tex] P_{1} [/tex] represents the initial pressure.

[tex] P_{2} [/tex] represents the initial pressure.

Note: 1 and 2 are the subscript while T and P are the variables.

Answer:

Carbon monoxide

Explanation:

Carbon refers to the "C" which stands for carbon. Monoxide refers to the single molecule of oxygen present in the substance.

Answer:

Carbon monoxide is the answer here

Explanation:

Distance covered = (speed) x (time)

Time = (Distance covered) / (speed)

Time = (48 km) / (32 km/hr)

Time = (48/32) hr

Time = 1.5 hrs (1 hour 30 minutes)

Answer:

The average speed of the blood in the capillaries is 0.047 cm/s.

Note: The question is incomplete. The complete question is as follows:

The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 cm/s. Calculate the average speed of the blood in the capillaries given the total cross section of all the capillaries is about 2000 cm².

Explanation:

From the given values:

radius of the aorta, r₁ = 1 cm

speed of blood, v₁ = 30 cm/s

Area of the aorta, A₁ = πr₁² where π = 3.142

Area of aorta = 3.142 × (1)² = 3.142 cm²

Area of the capillaries, A₂ = 2000 cm²

let the average speed of the blood in the capillaries = v₂

From the continuity equation of fluid flow, the product of cross-sectional area of the pipe and the fluid speed at any point along the pipe is always constant. In formula, A₁v₁ = A₂v₂

Using the continuity equation, the average the average speed of the blood in the capillaries can be calculated thus:

A₁v₁ = A₂v₂

v₂ = (A₁v₁) / (A₂)

v₂ = (3.142 x 30) / (2000)

v₂ = 0.047 cm/s

Therefore, the average speed of the blood in the capillaries is 0.047 cm/s.

Answer:

A. Crust

B. Mantle

C. Outer Core

D. Inner Core

Explanation:

Answer:

A. Crust

B. mantle

C. outer core

D. inner core

Explanation:

because it is

Answer:

the device that transfer thermal energy into to mechanical energy is heat engine.

hope it helps.

Explanation:

heat engine transforms thermal energy to mechanical energy

hope it is helpful to you

Answer:

The answer should be the one on the top in the picture.

Explanation:

Friction is opposing the downward movement of the crate therefore the friction force is pointing upwards. that is why the answer should be the one on the top of the picture.

Answer:

A, B and D

2. A

Explanation:

1.Which of the following statements about light waves is true? check all correct answers

A.They come from sources across space reason is that a light can travels form its source and its moves across the space

B.They travel in a straight line from their source reason is that the type of light that undergo these is called parallel ray of light

C.They can travel through any type of material reason not all materials light can penetrate through e.g wall

D.They can be reflected by some types of material reason is that some materals reflect light rays e.g polished mirror

Explanation:

The reason time zones are 15 degrees wide is because there are 24 hours and 360/24 = 15. As you move east by 15 degrees the sun’s position in the sky changes relative to us and it looks an hour later in the day, so we advance our clocks to match the sun’s position.

So every 15° eastward one hour ahead.

Answer:

wavelength

Explanation:

Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.

Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.

Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.

Basically, as a result of radio waves having long wavelengths, they are mainly used in long-distance communications such as the carriage and transmission of data.

The distance from one peak to the next peak is called wavelength. This distance is also equal to the distance from one trough of a wave to another.

Mathematically, wavelength is calculated using this formula;

[tex] Wavelength = \frac {speed}{frequency} [/tex]

Answer:

sun is the main source while the other object reflect light on the sun

Explanation:

nasa libro yans

Answer:

[tex] \boxed{q = 1.2 \times {10}^{ - 6} C}[/tex]

Explanation:

[tex]f_e = \frac{{q}^{2}k }{ {r}^{2} } \\ q = \sqrt{ \frac{f_e( {r}^{2} )}{k} } = \sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } \\ q =\sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } = \sqrt{ \frac{0.013}{9 \times {10}^{9} } } \\ q = 1.2 \times {10}^{ - 6} [/tex]

Plot a graph, constant speed of movements represented as straight lines. Time on X axis (seconds)  and position on Y axis (metres) , calculated by moving, e.g 4metres in a second.

Answer:

Input Output

1 ft-lb 12 in-lb

1 in-lb 0.113 Nm

1 Nm 0.7376 ft-lb

1 in-lb 0.0833 ft-lb

1 ft-lb 1.3558179 Nm

1 in-lb 15.999999461875 in-oz

1 Nm 8.850746106833 in-lb

1 l-atm 101.325 J

1 Nm 3.72506E-7 hph

1 J 1 Nm

Explanation:

please mark as briliant

Answer:

1N-m

Explanation:

teacher just taught this an hour ago for my class

Answer: c

Explanation: for #5 it can still be moving, just at a constant speed; therefore, it will be c.

If an object has an acceleration of 0 m/s2, then one can be sure that the object is not changing velocity.

If car A passes car B, then car A must be moving faster than car B, but not necessarily accelerating.

The not consistent with a car that is accelerating is a car is moving at a high speed.

A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that he is moving with a constant speed (on average).

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Answer:

C. Sources of electrical current!

Hope this helps :)

Answer:

Sources of electrical current

Explanation:

Got it right on the test.

[tex]\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}[/tex]

An object at rest stays at rest and an object in motion stays in motion at a constant speed and direction unless acted upon by an unbalanced force. ... In the absence of any forces, no force is required to keep an object moving.

In everyday situations, it does seem that a force is needed to keep an object moving at a constant speed in a straight line because the resistive frictional force acted on every objects against their motion.

The resistance provided by surfaces in touch as they move past one another is known as friction.

According to Newton's first law of motion, Unless forced to change its condition by an outside force, every object will continue to be at rest or moving uniformly in a straight line.

But in  everyday situations, it does seem that a force is needed to keep an object, for example the shopping trolley, moving at a constant speed in a straight line because of the frictional resistive force acting opposite to the motion. That's why, a force of equal magnitude and opposite direction must be applied on the object, so that, resultant force becomes zero. It can at a constant speed in a straight line.

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Answer:

1. Endurance activities

Only aerobic source

2. Can contract repeatedly

Speed strength and power.

Both aerobic and anaerobic sources

3. Fast contraction speed

Only anaerobic sources

Produce most force

Fatigue quickly

Speed, strength and power

Explanation:

I hope this helps. Although, I'm about 80% sure of the answer.