why is plastic a better choice for the slide than aluminum?

Answer:

An infographic is a collection of imagery, charts, and minimal text that gives an easy-to-understand overview of a topic. As in the example below, infographics use striking, engaging visuals to communicate information quickly and clearly. Infographics are a valuable tool for visual communication.

Explanation:

For ICl²-, the central iodine atom is bonded to the 2 chlorine atoms and has 3 lone electron pairs.

Altogether it has 5 electron domains, which means it is sp3d hybridized. (C)

Answer:

[tex]$MnO^-_4$[/tex]  is a strong oxidizing agent.

Explanation:

The 5d orbitals of Re are higher in energy than 3 d orbitals of Mn. So an LMCT ligand to metal charge transfer excitation requires more energy of [tex]$ReO^-_4$[/tex].

Also, since the molecular orbitals are derived primarily from  3d orbitals of [tex]$MnO^-_4$[/tex] are lower in energy than the corresponding MO's of   [tex]$ReO^-_4$[/tex], [tex]$MnO^-_4$[/tex]  is better able to accept the electrons.

So it is a better oxidizing agent.

The ligand to metal charge transfer band in ReO4- occurs in the near UV region hence ReO4 - appears colorless.

The electron configuration of Re is Xe 4f14 5d5 6s2 and the electron configuration of Mn is [Ar] 3d5 4s2. We can see that Mn^7+ and Re^7+ have empty d orbitals.

The color of MnO4 - must result from ligand to metal charge transfer hence the purple color of MnO4 -. In the case of ReO4 -, the ligand to metal charge transfer occurs at a much higher energy owing to the fact that 5d orbitals are involved. This transition occurs in the near UV region hence ReO4 - appears colorless. The ligand to metal charge transfer in MnO4- involves lower energy 3d orbitals hence it occurs in the visible region of the spectrum.

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Answer:

3iron + chlorine=iron3 chloride

nitrogen +3hydrogen

Answer:

a) Iron + chlorine → Iron (iii) chloride

3fe+cl__fe3cl

b) Nitrogen + hydrogen → Ammonia

2N+3h2------2NH3

c) Phosphoric acid + sodium carbonate → sodium phosphate + water + carbon dioxide

2H3PO3+3Na2CO3-----2Na3PO4+3H2O+3CO2

d) Nitrogen dioxide + water + oxygen → Nitric acid

NO2+H2O+O2--NOH

sorry if mistake

Explanation: solids are frozen like if you freeze tea it becomes a solid , liquids is like tea and gases is like when you boil water and it becomes a gas

Answer:

True.

Explanation:

When the number of molecules, atoms or ions of any element is in the hundreds of millions, we can safely speak of concentrations and analyze a standard behavior, and can even specify the different dilutions used, if there are dilutions. This allows analyzes to be clearly understood by any individual. However, it is not possible to do this if the number of molecules, atoms and ions is very small.

Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 1.98×10²²molecules of aspartame are present in 10.00 grams of aspartame.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.

Mathematically,

mole =given mass ÷ molar mass

       =10.00  ÷ 294.30

       =0.033moles

number of molecules= Avogadro's number × number of moles

                                   =6.022×10²³× 0.033

                                 = 1.98×10²²molecules

Therefore, 1.98×10²²molecules of aspartame are present in 10.00 grams of aspartame.

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Answer:

Li2S

Explanation:

Hope this helps.

Answer:

can u do an real answer pls so i can help u thanks

Answer:

im not doing your whole homework. but ill give you  one cent ;>, whats ur paypal

Explanation:

Answer:

[tex]Y=12.2 \frac{gpm}{ft}[/tex]

Explanation:

Hello!

In this case, since we can find that the well produces 280 gpm, and the given drawdown is 23 ft, we need to divide 280 by 23 to obtain the yield in gmp/ft as shown below:

[tex]Y=\frac{280gpm}{23ft} \\\\Y=12.2 \frac{gpm}{ft}[/tex]

Best regards!

Answer:

[tex]Q=-15.3kJ[/tex]

Explanation:

Hello!

In this case, since the enthalpy of vaporization is the contrary of the enthalpy of condensation, we have:

[tex]\Delta _{cond}H=-\Delta _{vap}H=-38.0kJ/mol[/tex]

Now, we convert the grams of CH3OH to moles:

[tex]n=12.9g*\frac{1mol}{32.05g}=0.402mol[/tex]

Thus, we compute the energy as shown below:

[tex]Q=n*\Delta _{cond}H=0.402mol*-38.0\frac{kJ}{mol}\\\\Q=-15.3kJ[/tex]

Which means 15.3 kJ of energy must be back down from the system.

Best regards!

Enthalpy is the measure of the energy that is not available to work. 15.27 kJ of energy is needed to condence 12.9 g of methenol.

Enthalpy:

It is the measure of the energy that is not available to work. It is denoted by [tex]\bold{ \Delta H}[/tex].

The energy of a system can be calculated by the formula,

[tex]\bold{Q = n \times \Delta H}[/tex]

Where,

Q - energy( in kJ)

n - Number of moles

[tex]\bold{ \Delta H}[/tex] - enthalpy

Given here,

[tex]\bold{CH_3OH = 12.9 g}[/tex]

[tex]\bold{\Delta Hvap = 38.1 kJ/mol}[/tex]

molar mass of the [tex]\bold{CH_3OH}[/tex] -

The number of moles of [tex]\bold{CH_3OH}[/tex]

[tex]\bold{n = \frac{w}{m}}\\\\\bold{n = \frac{12.9}{32.03}} \\\\\bold{n = 0.402}[/tex]

Put the values in the formula,

[tex]\bold{Q = 0.402\times 38.0}\\\\\bold{Q =15.27 }[/tex]

Therefore, the 15.27 kJ of energy is needed to condense 12.9 g of methenol.

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Answer:

See explanation

Explanation:

The ability of a gas to function as a green house gas depends on its ability to absorb infra red rays. In turn, the absorption of infrared red rays depends on whether or not the molecule is IR active.

The triatomic molecules such as methane and water are IR active. Only IR active molecules can lead to green house effect.

Note that for a molecular vibrational mode to be IR active, the dipole moment of the molecule is changed as the vibration occurs .

Answer:

250 grams = 0.25 liter

Explanation:

Answer:

B.a fire hydrant

hope it helps!

Answer:

a veterinarian

Explanation:

i think

Answer:

See explanation below

Explanation:

Let's answer this by parts.

a) As the reaction is naturally exothermic (Exerts heat), increasing temperature means that the reaction will move forward the direction where its absorbing heat

, so the equilibrium will be favored to the reactant side.

b) In this case, the addition of CO, which is a reactant will favor the reaction to the product side. This is because putting more quantity in the reactants will cause that the equilibrium constant K, increase it's innitial value, and this favors the product side.

c) In this case, it happens something similar to case b. This will cause that the reaction will have to work to cover the loss of methanol, therefore, equilibrium will move to the product side too.

d) In this case, we are adding another substance that reacts with CO, so it means that the other reactant is being removed, therefore, the reaction will work to cover this loss but also to cover the adding of the new substance, causing that the K decrease it's value, so equilibrium will be favored to the reactants side.

Hope this helps

Answer:

D H2PO4– + HPO42–

Explanation:

The acid dissociation constant for [tex]\mathbf{H_3PO_4 , H_2PO^{-}_4 , HPO_4^{2-}}[/tex] are [tex]\mathbf{7\times 10^{-3}, \ \ 8\times 10^{-8} ,\ \ 5\times 10^{-13}}[/tex] respectively.

[tex]\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}[/tex]

[tex]\mathbf{pka (H_2PO_4^-) = -log (8\times 10^{-8} )=7.1}[/tex]

[tex]\mathbf{pka (HPO_4^{2-}) = -log (5\times 10^{-13} )=12.3}[/tex]

The reason while option D is the best answer is that, the value of pKa for both

[tex]\mathbf{H_2PO^{-}_4 ,\ \& \ HPO_4^{2-}}[/tex] lies on either side of the desired pH of the buffer. This implies that one is slightly over and the other is slightly under.

Using Henderson-Hasselbach equation:

[tex]\mathbf{pH = pKa + log \Big( \dfrac{HPO_4^{2-}}{H_2PO_4^-} \Big)}[/tex]

The compounds that are used for the formulation of the pH 9 buffer are [tex]\rm H_2PO_4^-\;and\;HPO_4^+[/tex]. Thus, option D is correct.

The buffers are the solutions of acids and base of appropriate pH, that are able to limit the change in pH in the reaction mixture.

The buffer pH is adjusted with the compounds that has been able to add base or acid to the solution.

For the formulation of buffer of specific pH, the acid and base solutions are required.

The compounds that are used for the formulation of the pH 9 buffer are [tex]\rm H_2PO_4^-\;and\;HPO_4^+[/tex], as they are able to provide acid and base to the solution.

Thus, option D is correct.

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Answer and Explanation:

When using simulations, it is important that the researcher knows some limitations. This is because the simulations do not behave exactly like what they represent, in addition to not presenting very important details for analysis and without approximations of what really happens with what they are representing. When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.

When using simulations, it is important that the researcher knows some limitations. This is because the simulations do not behave exactly like what they represent, in addition to not presenting very important details for analysis and without approximations of what really happens with what they are representing. When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.

Answer:

What is the functional groups of CH3CH2CH(OH)CH2C(CH3)2Br?

Answer:

9

Explanation:

V=I*R

3*3

Thats the answer

When hydrogen and oxygen combine, they form water or hydrogen peroxide, and energy is released in the process.

Oxygen and hydrogen are the chemical elements of the periodic table, and they both are gas. Oxygen is the most important gas, which is needed for breathing. It is present at 21% in the atmosphere.

Hydrogen is another gas present in nature. It is the lightest gas, and it has diatomic molecules. It remains gas at normal pressure and temperature, but it becomes liquid at low temperature.

The oxygen and hydrogen readily react and for water, and hydrogen peroxide, the process of reaction of hydrogen and oxygen releases an amount of energy.

Hence, Energy is released during the creation of water or hydrogen peroxide when hydrogen and oxygen mix.

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Answer:

The naturally acidic rain will gradually wear the mountain of limestone away.

Hope it helps!

Answer:

3 hours

Explanation:

To know the the correct answer to the question given above, it is important we know the definition of half-life.

The half-life of a substance is simply defined as the time taken for half the substance to decay.

Considering the diagram given above, the initial mass of the substance is 100 g.

Half of the initial mass = 100 / 2 = 50 g

Now, we shall determine the time from the graph taken to get to 50 g.

Considering the diagram given above, the time taken to get to 50 g is 3 hours.

Therefore, the half-life of the material is 3 hours.

Explanation:

The reaction is given as;

Br2(g) + Cl2(g) ----> 2BrCl(g)

From the equation;

1 mol of Br2 reacts with 1 mol of Cl2

Converting the masses given to moles, using the formular;

Number of moles = Mass / Molar mass

Br2;

Number of moles = 33.7 g / 159.808 g/mol = 0.21088 mol

Cl2;

Number of moles = 13.0 g / 70.906 g/mol = 0.18334 mol

From the values;

0.18334 mol of Cl2 would react with 0.18334 mol of Br2 with an excess of 0.02754 mol of Br2

What is the maximum amount of bromine monochloride that can be formed? __________grams

1 mol of Cl2 produces 2 mol of Bromine Monochloride

0.18334 mol of Cl2 would produce x

Solving for x;

x = 0.18334 * 2 = 0.36668 mol

Converting to mass;

Mass = Number of moles * Molar mass = 0.36668 mol * 115.357 g/mol

Mass = 42.299 g

What is the FORMULA for the limiting reagent?

The limiting reagent is Cl2 as it determines the amount of product formed. The moment the reaction uses up Cl2, the reaction stops.

What amount of the excess reagent remains after the reaction is complete? __________grams

The excess reagent is Br2

The number of moles left is;

0.02754 mol of Br2

Converting to mass;

Mass = Number of moles * Molar mass = 0.02754 mol  * 159.808 g/mol

Mass = 4.401 g

Answer:

depends on what molecule you are looking for

Explanation:

In one mole of stuff (atoms, molecules, eggses), there are NA individual items of that stuff. So, there are 4.5 × NA BCl3 molecules; i.e. 4.5 × 6.022×1023 ≅ 27×1023 individual molecules of BCl3

Answer:

donate unused food to food banks

Explanation:

Becuse food banks processes food to make very fine particles which is mixed with soil and can be given to the plants

Answer:

B. They bind to carrier proteins in order to be transported in the blood to

their target cells.

Explanation:

Steroid hormones are belongs to the class of chemical compound called steroid. Steroid hormones are majorly secreted by three glands - ovaries, testes and adrenal cortex.

Steroid hormones are released in the blood and are allowed to bind to the specific carrier proteins such as corticosteroid-binding globulin and albumin which helps them to carry to the target cells for the functioning.

The steroid hormone binds to receptor proteins in the target cell and not in the plasma membrane

Hence, the correct answer is "B. They bind to carrier proteins in order to be transported in the blood to  their target cells."

Answer:4m/s

Explanation:The reason why that the answer is because I am Smart.