Why should the oil be removed from a low pressure system at 130F

Answer:

9-10 ppm.

0.2-0.4 ppm.

Explanation:

The proton on the aldehyde group will appear at approximately 9-10 ppm whereas the methylene peak on the alcohol is the only peak 0.2-0.4 ppm for either compound. Aldehydes and aromatics are quite distinctive in the Nuclear magnetic resonance (NMR). Aldehydes show up from 9-10 ppm, usually as a small singlet; aromatic protons show up from 6.5-8.5 ppm. NMR spectroscopy is the use of NMR to study the physical, chemical, and biological properties of matter.

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy ([tex]s_{2} - s_{1}[/tex]), in joules per gram-Kelvin, by the following model:

[tex]s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}}[/tex] (1)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]c_{w}[/tex] - Specific heat of water, in joules per kilogram-Kelvin.

[tex]T_{1}[/tex], [tex]T_{2}[/tex] - Initial and final temperatures of water, in Kelvin.

If we know that [tex]m = 1\,kg[/tex], [tex]c_{w} = 4190\,\frac{J}{kg\cdot K}[/tex], [tex]T_{1} = 373.15\,K[/tex] and [tex]T_{2} = 288.15\,K[/tex], then the change in entropy for the entire process is:

[tex]s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}[/tex]

[tex]s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}[/tex]

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Answer:

Explanation:

Change in entropy,

[tex]\delta S = mCp * In[\frac{T2}{T1}][/tex]

The initial temperature,

[tex]T1 = 100^oC\\\\T1 = 100+273\\\\T1 = 373k[/tex]

Final value of temperature,

[tex]T2 = 15^oC\\\\T2 = 15+273\\\\T2 = 288k[/tex]

where,

[tex]m = 1kg\\\\Cp = 4190 J/kg.k[/tex]

Substitute into [tex]\delta S[/tex]

[tex]\delta S = mCp * In[\frac{T2}{T1}]\\\\\delta S = 1 * 4190 * In[\frac{288}{373}]\\\\\delta S = 4190 * In[0.7721]\\\\\delta S = 4190 * [-0.2586]\\\\\delta S = -1083.534 J/k[/tex]

The negative sign exists because the change in entropy will be decreasing due to cooling.

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Answer:

decreases by 10 gram

Explanation:

Answer:

It is bad

Explanation:

Is nuclear energy good or bad?

Answer:

349.503 g

https://www.convertunits.com/from/moles+Copper/to/grams

here is a link, you can convert moles of copper to grams here

The answer is 5.50 moles of Cu (Copper) has 349.503 grams mass .

A mole is defined as 6.02214076 × 10²³ atoms, molecules, ions, or other chemical units.

and the molar mass of a substance is defined as the mass of 1 mole of that substance, expressed in grams per mole.

It is equal to the mass of 6.022 × 10 23 atoms, molecules, or formula units of that substance.

1 mole of Cu has 63.546 grams of Cu

So 5.50 moles will have 5.50 * 63.546 grams

=349.503 grams

Therefore 5.50 moles of Cu (Copper) has 349.503 grams mass .

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Answer:

[H+] = 10^-2

Explanation:

pH = -log[H+]

2 = -log[H+]

[H+] = 10^-2

Answer:

D) 373 mm Hg.

Explanation:

We can solve this problem by keeping in mind Dalton's law of partial pressures, which states that the total pressure of a mixture of gases is equal to the sum of each gas' partial pressures. In other words, for this case:

The answer is option D) 373 mm Hg.

Answer: Temperature and number of moles are the conditions which remain constant in Boyle's law.

Explanation:

Boyle's law states that at constant temperature the pressure of a gas is inversely proportional to the volume of gas.

Mathematically, it is represented as follows.

[tex]P \propto \frac{1}{V}[/tex]

As equation for ideal gas is as follows.

PV = nRT

And, at constant temperature the pressure is inversely proportional to volume which also means that number of moles are also constant in Boyle's law.

Thus, we can conclude that temperature and number of moles are the conditions which remain constant in Boyle's law.

Answer:

Temperature and number of moles

Explanation:

Answer:

Ok

Explanation:

Answer:

false

Explanation:

this is because , high temperature speeds up the the random motion of particles which leads to high dissolution

Given

Li - 59.7 %

N - 40.3 %

Solution,

First get the molar mass of each Atom,

Li- 6.941

N- 14.00

Second find the moles of both atom,

moles of Li = 59.7/6.941 = 8.60

Moles of N = 40.3/14 = 2.87

Third devide both the moles with smaller mole,

first- 8.6÷2.87 = 2.99 ~ 3

second 2.87÷2.87 = 1

Ratio of Li to N is 3:1

The compound is Li3N.

Answer:

Molarity: 0.522M

Percentage by mass: 2.36 (w/w) %

Explanation:

Formic acid, HCOOH reacts with NaOH as follows:

HCOOH + NaOH → NaCOOH + H₂O

To solve this question we must find the moles of NaOH added = Moles formic acid. Taken into account the dilution that was made we can find the moles -And molarity of formic acid and its percentage by mass as follows:

Moles NaOH = Moles HCOOH:

0.01580L * (0.1322mol / L) =0.002089 moles HCOOH

Moles in the original solution:

0.002089 moles HCOOH * (25mL / 10mL) = 0.005222 moles HCOOH

Molarity of the solution:

0.005222 moles HCOOH / 0.01000L =

Mass HCOOH in 1L -Molar mass: 46.03g/mol-

0.522moles * (46.03g / mol) = 24.04g HCOOH

Mass solution:

1L = 1000mL * (1.02g / mL) = 1020g solution

Mass percent:

24.04g HCOOH / 1020g solution * 100

2.36 (w/w) %

Answer:

"23.896%" is the right answer.

Explanation:

The given values are:

Mass of NaCl,

= 51.56 g

Mass of H₂O,

= 165.6 g

As we know,

⇒  Mass of solution = [tex]Mass \ of \ (NaCl+H_2O)[/tex]

                                 = [tex]51.56+164.2[/tex]

                                 = [tex]215.76 \ g[/tex]

hence,

⇒ [tex]Mass \ percent =\frac{Mass \ of \ NaCl}{Mass \ of \ solution}\times 100[/tex]

                           [tex]=\frac{51.56}{215.76}\times 100[/tex]

                           [tex]=23.896 \ percent[/tex]

Answer:

668.9K is the final temperature

Explanation:

The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:

ΔS = n*Cv*ln (T2/T1)

Where ΔS is change in entropy = 200J/K

n are moles = 20.0mol

Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)

T2 is final Temperature and T1 initial temperature = 300K

Replacing:

ΔS = n*Cv*ln (T2/T1)

200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)

0.80186 = ln (T2/300K)

2.23 = T2 / 300K

Answer:

33.30 grams of CaCl2 will be required

Explanation:

Given,

Volume of solution, V= 250 ml

Molarity of solution, M= 1.20 mol/L

Molecular mass of CaCL2, S= 40+(35.5 X 2)= 111

We know,

Required mass, W= SVM/1000

Now,

W = (111 X 250 X 1.20)/1000

    = 33300/1000

    = 33.30

Therefore, 33.30 grams of Calcium Chloride will be required.

Answer:

it has volume( takes up space).

Explanation:

The characteristics of matter are that it has mass and also exhibits volume (takes up space).Hence Option (C) is Correct.

A physical substance in general, that which occupies space and possesses rest mass, especially as distinct from energy.

Matter is important because it makes up everything around us and matter can not be created or destroyed but instead, they just transformed into a different form.

Any characteristic that can be measured, such as an object's density, colour, mass, volume, length, malleability, melting point, hardness, odour, temperature, and more, are considered properties of matter.

Therefore, The characteristics of matter are that it has mass and also exhibits volume (takes up space).Hence Option (C) is Correct.

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Answer:

a. participate in proton transfer - His

b. acts as a nucleophile - Ser

Explanation:

Enzymes are regulated because they are proteins. They are categorize based on how they catalyze. Heat weakens and inactivates the enzymes because of non covalent interaction. His amino acid participate in proton transfer because it is able to act as an acid as well as a base while Ser amino acid can act as nucleophile.

Answer:

2

Explanation:

Step 1: Write the generic decomposition reaction

KClOₓ ⇒ KCl + O₂

Step 2: Calculate the moles of O₂

At STP, 1 mole of an ideal gas occupies 22.4 L.

50.4 L × 1 mol/22.4 L = 2.25 mol

Step 3: Calculate the mass corresponding to 2.25 moles of O₂

The molar mass of O₂ is 32.00 g/mol.

2.25 mol × 32.00 g/mol = 72 g

Step 4: Determine the value of x

Every 156 g of KClOₓ there are 72 g of oxygen. The mass percent of O is:

%O: 72 g/156 g × 100% = 46.2%

In KClO, the mass percent of O is: 32.00 g/90.5 g × 100% = 35.4%

In KClO₂, the mass percent of O is: 64.00 g/138.5 g × 100% = 46.2%

Then, x = 2

Answer:

If a solution has pH=8 , then its pOH is 14−8=6 and the corresponding concentration of hydroxyl OH− ions is 10−6 mol per litre.

Explanation:

Answer:

87.0%

Explanation:

Step 1: Write the balanced reaction

H₂O₂ ⇒ H₂O + 0.5 O₂

Step 2: Calculate the real yield of oxygen, in grams

We have 375 mL (0.375 L) of O₂ at 42 °C (315 K) and 1.52 atm. First, we will calculate the number of moles using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.52 atm × 0.375 L / (0.0821 atm.L/mol.K) × 315 K = 0.0220 mol

The molar mass of oxygen is 32.00 g/mol.

0.0220 mol × 32.00 g/mol = 0.704 g

Step 3: Calculate the theoretical yield of oxygen, in grams

According to the balanced equation, the mass ratio of H₂O₂ to O₂ is 34.01:16.00.

1.72 g H₂O₂ × 16.00 g O₂/34.01 g H₂O₂ = 0.809 g O₂

Step 4: Calculate the percent yield of oxygen

We will use the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 0.704 g / 0.809 g × 100% = 87.0%

Considering the reaction stoichiometry and the ideal gas law, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

The balanced reaction is:

2 H₂O₂ → 2 H₂O +  O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass, this is the amount of mass a substance contains in one mole, of H₂O₂ is 34 [tex]\frac{g}{mole}[/tex]. Then, the amount of moles of H₂O₂ that decomposes when 1.72 grams of H₂O₂ reacts is calculated as:

[tex]1.72 gramsx\frac{1 mole}{34 grams}= 0.0506 moles[/tex]

Then you can apply the following rule of three: if by stoichiometry 2 moles of H₂O₂ produce 1 moles of O₂, 0.0506 moles of H₂O₂ will produce how many moles of O₂?

[tex]amount of moles of O_{2} =\frac{0.0506 moles of H_{2} O_{2} x1 mole of O_{2} }{2 moles of H_{2} O_{2}}[/tex]

amount of moles of O₂= 0.0253 moles

On the other side, an ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, for O₂ gas you know:

Replacing:

1.52 atm× 0.375 L = n× 0.082 [tex]\frac{atmL}{molK}[/tex]× 315 K

Solving:

[tex]n=\frac{1.52 atmx 0.375 L}{0.082\frac{atmL}{molK}x 315 K }[/tex]

n= 0.022 moles

The percent yield is calculated as

[tex]Percent yield= \frac{real yield}{theoretical yield} x100[/tex]

In this case, for oxygen the percent yield is calculated as

[tex]Percent yield of oxygen= \frac{0.022 moles}{0.0253 moles} x100[/tex]

Percent yield of oxygen= 86.96 %

Finally, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

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Answer:

A. 201 kPa

Explanation:

We can solve this problem by using Boyle's law, which states:

Where subscript 1 stands for the initial Pressure and Temperature, while 2 stands for the final conditions. That means that in this case:

We input the data:

And solve for P₂:

Answer:

HEY CAN YOU POST YOUR LAST QUESTION AGAIN? CAUSE I HAVE THE ANSWER

Answer:

The temperature of the sample increase by 48 Kelvin

Explanation:

The sample is identical.

Hence the heat at constant pressure is equal to the heat at the constant Volume

Q1 = Q2

Q 1 = heat at constant pressure

Q2 = heat at the constant Volume

Substituting the given values, we get -

[tex]\frac{3}{2} nRT_1 = \frac{5}{2} nRT_2\\3 * 80 = 5 * T_2\\T_2 = 48[/tex]

The temperature of the sample increase by 48 Kelvin

Answer:

[tex]V_2=600mL[/tex]

Explanation:

Hello there!

In this case, according to this dilution process, it is possible for us to solve this problem via the following equation:

[tex]V_2M_2=V_1M_1[/tex]

Thus, since we were given the initial and final concentrations but just the initial volume, we calculate the final one as shown below:

[tex]V_2=\frac{V_1M_1}{M_2}\\\\ V_2=\frac{100.0mL*18M}{3.0M}\\\\V_2=600mL[/tex]

Regards!

Answer:

3584.21 J/kg.K

Explanation:

Applying

Q = cm(t₂-t₁)........... equation 1

Where Q = Quantity of heat absorb, c = specific heat capacity of the metal, m = mass of the metal, t₁ = intial temperature, t₂ = Final temperature.

make c the subject of the equation

c = Q/(m(t₂-t₁)........... Equation 2

From the question,

Given: Q = 1362 J, m = 15.2 g = 0.0152 kg, t₁ = 17°C, t₂ = 42°C

Substitute these values into equation 2

c = 1362/0.0152(42-17)

c = 1362/0.38

c = 3584.21 J/kg.K

Answer:

22900 L

Explanation:

Assuming the gas behaves ideally, we can solve this problem by using Boyle's law, which states that:

Where subscript 1 refers to the initial conditions of pressure and volume (within the bomb, namely), while 2 refers to the final conditions.

Meaning that in this case:

We input the data:

And solve for V₂:

N2 + 3H2  -->  2NH3

Answer: 6 moles of hydrogen are needed to react with two moles of nitrogen.

Explanation:

Answer:

Sunlight, Soil, Rocks, Temperature and dead deer

Explanation:

You could say the dead tree is now an abiotic factor because biotic factors refer to living things

Answer:

A

Explanation:

The water potential depends upon the pressure and amount of solute according to the water potential formula.

The following points can be considered:

Therefore, the correct answer is a) pressure and the amount of solute.

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