What is the fundamental different between combustion and nuclear reaction
Answer:
Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclear.
In another experiment, the student titrated 50.0 mL of 0.100 M HC,H,O, with
0.100 M NaOH(aq). Calculate the pH of the solution at the equivalence point
Answer:
Eqv Pt pH = 8.73
Explanation:
HOAc + NaOH => NaOAc + H₂O
50ml(0.10M HOAc) + 50ml(0.10M NaOH) => 100ml(0.05M NaOAc) + H₂O
For neutralized system, 100ml of 0.05M NaOAc remains
NaOAc => Na⁺ + OAc⁻
Na⁺ + H₂O => No Rxn
OAc⁻ + H₂O => HOAc + OH⁻
C(i) 0.05M ----- 0M 0M
ΔC -x ----- +x +x
C(f) 0.05-x
≅ 0.05M ----- x x
Kb = Kw/Ka = [HOAc][OH⁻]/[OAc⁻] = 1 X 10⁻¹⁴/1.7 X 10⁻⁵ = (x)(x)/(0.05M)
=> x = [OH⁻] = SqrRt(0.05 x 10⁻¹⁴/1.7 x 10⁻⁵) = 5.42 x 10⁻⁶M
=> pOH = -log[OH⁻] = -log(5.42 x 10⁻⁶) = 5.27
pH + pOH = 14 => pH = 14 - pOH = 14 - 5.27 = 8.73 Eqv Pt pH
Draw a structural formula for the organic product formed by treating butanal with the following reagent: NaBH4 in CH3OH/H2O You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. Do not include lone pairs in your answer. They will not be considered in the grading. Include counter-ions, e.g., Na , I-, in your submission, but draw them in their own separate sketcher. Do not draw organic or inorganic by-products.
Answer:
Please find the solution in the attachment file.
Explanation:
If I have 7.0 x 10^24 formula units of magnesium chloride, how many grams of chlorine would I have?
Answer:
824 g
Explanation:
First we convert 7.0 x 10²⁴ formula units of magnesium chloride (MgCl₂) into moles, using Avogadro's number:
7.0 x 10²⁴ formula units ÷ 6.023x10²³ formula units/mol = 11.62 mol MgCl₂There are two Cl moles per MgCl₂ moles, meaning that we have (2 * 11.62) 23.24 moles of Cl
Finally we convert 23.24 moles of chlorine into grams, using chlorine's molar mass:
23.24 mol * 35.45 g/mol = 824 gIdentify the Lewis base in this balanced equation: 6 upper H subscript 2 upper O plus UPper C r (upper H subscript 2 upper O) subscript 6 superscript 3 plus. H2O Cr3+ Cr(H2O)63+
The Lewis base that we can see in the equation is [tex]H_{2} O[/tex]
What is the Lewis base?We have to bear in mind that the Lewis base is the substance that is able to donate a pair of electrons. The substances that is able to accept the pair of electrons is what we call the Lewis acid.
The Lewis acid must possess a space for the addition of an electron pair while the Lewis base would have to be a specie that has a lone pair of electrons or has a negative charge. Thus the water molecule would serve as a Lewis base in this regard.
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Answer:
6 upper H subscript 2 upper O plus UPper C r (upper H subscript 2 upper O) subscript 6 superscript 3 plus.
✔ H2O or A.)
Cr3+
Cr(H2O)63+
The diagram shows that the boiling point of water is 100°C At a pressure of one atm.
How could you reduce the boiling point of water in this system?
A. Increase the size of the flame
B. Decrease the volume of the water
C. Decrease the pressure to 0 atm.
D. Increase the pressure to 2 atm
Answer:
I think the answer will be number A
The boiling point of a substance is constant and for water it is 100 degree celsius. However by reducing the surrounding pressure the boiling point can be reduced.
What is boiling point ?Boiling point of a substances is the temperature at which the vapor pressure of the gas phase above the liquid equals to the atmospheric pressure where, the liquid converts to the vapor state.
Boiling point depends on the bond type, molar mass, temperature and pressure. As the and pressure increases, boiling point increases. Similarly with an increasing mass and more strength intermolecular force results in greater boiling point.
As the atmospheric pressure decreases, the temperature needed to equalise the vapor pressure of the gas phase over the liquid also decreases. Hence, boiling point decreases. Therefore, option C is correct.
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Because a water molecule has a negative end and a positive end it displays?
Answer:
A water molecule displays polarity by having negative and positive ends. Due to this charge difference, a water molecule is called a dipole.
Explanation:
Try moving an electron from the metal to the non metal.What happens?
Answer:
Sodium becomes a positive ion and chlorine becomes a negative ion. ... Each atom is neutrally charged, which means that each atom has the same number of protons and electrons.
Explanation:
A chemist titrates 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid. How many mL of NaOH will be required to titrate to the endpoint
[tex](normality \: of \: acid)×(volum \: of \: acid) = (normality \: of \: base)×(volum \: of \: base)[/tex]
0.15N × 50mL = 0.2N × (Vbase)
75mL = Volum of base
37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid to the endpoint.
How to calculate volume?The volume of a solution can be calculated using the following formula:
C1V1 = C2V2
Where;
C1 = initial concentrationC2 = final concentrationV1 = initial volumeV2 = final volumeC1 = 0.200MC2 = 0.150MV1 = ?V2 = 50mL0.2 × V1 = 0.150 × 50
0.2V1 = 7.5
V1 = 7.5/0.2
V1 = 37.5mL
Therefore, 37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 mL of 0.150 M HCI, strong acid to the endpoint.
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pH de un jugo de naranja con [H+]=5.6×10-4M.
Explanation:
[tex]pH = - log[H {}^{ + } ] \\ = - log(5.6 \times {10}^{ - 4} ) \\ = 3.25[/tex]
Can someone help me please!!
Answer:
1. AgNO₃ (aq) + NaCl (aq) ----> NaNO₃ (aq) + AgCl (s)
2. Li₂SO₄ (aq) + BaCl₂ (aq) ----> 2 LiCl (aq) + BaSO₄ (s)
3. 2 NaOH (aq) + MgCl₂ (aq) ----> 2 NaCl (aq) + Mg(OH)₂ (s)
Explanation:
The reaction involving the mixing of two soluble solutions to produce a precipitate is known as a precipitation reaction.
A precipitation reaction is double-replacement reaction (a reaction that exchanges the cations or the anions of two ionic compounds) in which one product is a solid precipitate.
Precipitation reactions at useful in the identification of various ions present in a solution. In order to predict the reactions that will produce a precipitate, solubility rules as given in the solubility table below can be used.
From the tables, the reactions that will produce a precipitate, as well as their balanced molecular equations are as follows:
1. AgNO₃ (aq) + NaCl (aq) ----> NaNO₃ (aq) + AgCl (s)
2. Li₂SO₄ (aq) + BaCl₂ (aq) ----> 2 LiCl (aq) + BaSO₄ (s)
3. 2 NaOH (aq) + MgCl₂ (aq) ----> 2 NaCl (aq) + Mg(OH)₂ (s)
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What kind of weather forms with an occluded front?
Answer:Occluded fronts usually form around areas of low atmospheric pressure. There is often precipitation along an occluded front from cumulonimbus or nimbostratus clouds. Wind changes direction as the front passes and the temperature either warms or cools.
Explanation:
Helen is studying the properties of solids. She is comparing the wooden cube and the steel cube shown in the picture below.
mc065-1
Which property is the same for the two cubes?
color
luster
texture
volume
Only animals and not plants can adapt to their environment true or false
Answer:
true
Explanation:
np have a good day brainliest?
3. How many oxygen atoms are there in 5.0 mol of water?
Answer:
3.01 * 10^23 oxygen atoms
Explanation:
Water is H2O. So there are one oxygen atom for every molecule of water.
So in 5.0 mol of water molecules, there are 5.0 mol of oxygen atoms.
Since 5.0 mol = 5 * 6.02 * 10^23 molecules, there are 3.01 * 10^23 oxygen atoms.
How many moles of OH−(aq) (hydroxide ions)are present in the balanced redox reaction?
NO3−(aq) + ClO−(aq) + H2O(l) → NO(g) + ClO2−(aq) + OH−(aq)
Explain what is meant by a river’s load, and describe how the load is carried.
Please hurry I m timed T-T
Answer:
A rivers load is gravel and sand. It is carried by being dragged, rolled, and bounced along the bed of the river.
Explanation:
Answer:
the amount of gravel and sand at a river
the load is carried by the moving water
What's a house hold item that has nuclear energy
Answer:
Electricity, Weapons, Medicine · Food Treatments, ect.
If the number of moles of a gas doubles, its volume will also double
according to
*
Please hurry! What is the answer to this?
Explanation:
Boyle's Law
A mixture of water and water vapor is present in a closed vessel at 20 degrees Celsius. the total pressure of the system is 755.0 mmHg. Partial pressure of water vapor at 20 degrees Celsius equals 17.5 mm Hg. What is the partial pressure of H2
Answer:
737.5 mmHg
Explanation:
Ptotal=PH2O+PH2
P is the pressure and since we have Ptotal and PH2O, we can solve for PH2
755=17.5+x
755-17.5=x
x=737.5
The initial volume of a gas is 21 L and the final volume is 38.7 L. If the initial temperature was 261 K, what is the final temperature (in Kelvin)?
Answer:
480.9K
Explanation:
V1=21L
V2=38.7L
T1=261K
T2=?
Using Charles law,
V1/T1=V2/T2
Inputting the given values,
21/261=38.7/T2
T2=480.9K
What is the molarity of a 9.79 L solution that contains 0.400 mol HCI
Answer:
0.041 MExplanation:
The molarity of a solution when given the number of moles the substance and it's volume can be found by using the formula
[tex]c = \frac{n}{v} \\ [/tex]
n is the number of moles
v is the volume in L
We have
[tex]c = \frac{0.4}{9.79} \\ = 0.04058...[/tex]
We have the final answer as
0.041 MHope this helps you
Identify the reaction type of the chemical reaction below. Check all that apply.
Mg (s)+2 HCl (aq) MgCl 2 (aq)+H 2 (g)
Answer:
The type of reaction is a single-replacement reaction.
Explanation:
Mg switches places with H, leaving H by itself.
a layer of paint can be used to prevent iron rusting true or false
Answer:
true
Explanation:
This layer will prevent moisture from reaching the metal and therefore prevent rust. oil paint especially
please answer asap!
What is the molarity of a KOH solution if 200 ml of the solution contains 0.6 moles KOH?
a. 0.3 M
b. 0.6 M
c. 3.0 M
d. 6.0 M
A 1.4639-g sample of limestone is analyzed for Fe, Ca, and Mg. The iron is determined as Fe2O3 yielding 0.0357 g. Calcium is isolated as CaSO4, yielding a precipitate of 1.4058 g, and Mg is isolated as 0.0672 g of Mg2P2O7. Report the amount of Fe, Ca, and Mg in the limestone sample as %w/w Fe2O3, %w/w CaO, and %w/w MgO
Answer:
A) w/w % of Fe - 2.44%
B) w/w % of Mg - 4.590%
C) w/w % of Ca - 96%
Explanation:
A) w/w % of Fe in limestone as Fe2O3 = (Mass of Fe2O3 /Mass of limestone) x 100
0.0357/1.4639 X 100
= 2.438 =2.44
B) w/w % of Mg in limestone as Mg2P2O7 = (Mass of Mg2P2O7 /Mass of limestone) x 100
= 0.0672/1.4639 X 100
= 4.590
C) w/w % of Ca in limestone as CaSO4 = (Mass of CaSO4/Mass of limestone) x 100
= 1.4058/1.4639 X 100
= 96
Answer:Fe =1.71% Ma=0.99% Ca=28.24%
Explanation:
2. A plant growing in response to the sunlight.
A.Gravitropism
B.Phototropism
C.Thigmotropism
D.Hydrotropism
Answer:
phototropism
Explanation:
since photo is (light?
the experimental control is the ?
A. Dependent variable
B. Design of the experiment.
C. Outcome of the experiment
D. the standard against which the results are measured .
Answer:
D. In an experiment, one of the variables will be giving a placebo and the other, a treatment
Explanation:
Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy. During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds.
the solubility of PbSO4 is 0.048g/Liter. what is the Ksp of PbSO4? (MMPbSO4 = 303.3)
Answer:
Ksp of PbSO4 is 2.5 *10^-8
Explanation:
Given -
Solubility of PbSO4 = 0.048g/Liter
[Pb+2] * [SO42-] = mass/molecular weight of PbSO4
[Pb+2] * [SO42-] = 0.048g/Liter/303.3g/mol = 0.000158 M
Concentration of PbSO4 = moles/volume = 0.000158 M/1L = 0.000158 M
Ksp = [Pb+2] * [SO42-]
ksp = 0.000158 * 0.000158 = 2.5 *10^-8
Which of the statements below about an acid-base buffer solution is/are true?
I. It can be prepared by combining a strong acid with a salt of its conjugate base.
II. It can be prepared by combining a weak acid with a salt of its conjugate base.
III. It can be prepared by combining a weak base with its conjugate acid.
IV. The pH of a buffer solution does not change when the solution is diluted.
V. A buffer solution resists changes in its pH when an acid or base is added to it.
A. I, II, and IV.
B. II, III, and V.
C. II, III, IV, and V.
D. I, II, IV, and V.
E. II, III, and IV.
Answer:
C. II, III, IV, and V.
Explanation:
Acid buffer is generally formed by the combination of a weak acid as well as the salt of the conjugate base.
Basic buffer is formed the combination of a weak base and also the salt of the conjugate acid.
On dilution the ration of the concentration terms of the salt and weak acid/base does not change. Hence the pH of the buffer solution does not change.
When acid or base is added to buffer, it resists changes in the pH.
Therefore, option (C) is correct.