WILL GIVE BRAINLEST The following data shows the grades that a 7th grade mathematics class received on a recent exam.

{98, 93, 91, 79, 89, 94, 91, 93, 90, 89, 78, 76, 66, 91, 89, 93, 91, 83, 65, 61, 77}

Part A: Determine the best graphical representation to display the data. Explain why the type of graph you chose is an appropriate display for the data. (2 points)

Part B: Explain, in words, how to create the graphical display you chose in Part A. Be sure to include a title, axis label(s), scale for axis if needed, and a clear process of how to graph the data. (2 points)

The exact values of cosecant, secant, and cotangent ratios of -pi/4 radians is:

[tex]csc=\frac{\pi }{4}=\frac{hypontenuse}{opposite}=\frac{\sqrt{2} }{1}=\sqrt{2}[/tex]

[tex]sec=\frac{\pi }{4}=\frac{hypotenuse}{adjacent}= \frac{\sqrt{2} }{1}=\sqrt{2}[/tex]

[tex]cot=\frac{\pi }{4}=\frac{adjacent}{opposite}=\frac{1}{1}=1[/tex]

[tex]\frac{\pi }{4}[/tex] radians is the same as 90 degrees. So, first draw a right triangle with an angle of [tex]\frac{\pi }{4}[/tex]:

This creates a 45-45-90 triangle, also known as a right isosceles triangle. This is a very special triangle, and we know that both of its legs will be the same length, and the hypotenuse will be the length of one of the legs times √2.

The  three functions are just the inverses of the first three. Cosecant is the inverse of sine, secant is the inverse of cosine, and cotangent is the inverse of tangent.

[tex]csc=\frac{\pi }{4}=\frac{hypontenuse}{opposite}=\frac{\sqrt{2} }{1}=\sqrt{2}[/tex]

[tex]sec=\frac{\pi }{4}=\frac{hypotenuse}{adjacent}= \frac{\sqrt{2} }{1}=\sqrt{2}[/tex]

[tex]cot=\frac{\pi }{4}=\frac{adjacent}{opposite}=\frac{1}{1}=1[/tex]

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The exponential model for the population can be written as P = 17000(1 + 0.197)^t, where P represents the population after t years of growth.

Based on your given information, the population starts at 17,000 organisms and grows by 19.7% each year. To represent this growth using an exponential model, you can write the equation in the form P(t) = P₀(1 + r)^t, where P(t) is the population after t years, P₀ is the initial population, r is the growth rate, and t is the number of years.

In this case, P₀ = 17,000 and r = 0.197. So, the exponential model for the population can be written as:

P(t) = 17,000(1 + 0.197)^t

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The value of the function f(x) =  ( x² + 7 ) / ( x² + 4x - 21 )  for x = 5 is equal to 4/3.

The function is equal to,

f(x) =  ( x² + 7 ) / ( x² + 4x - 21 )

find the value of f(x) at x=5 by substituting x=5 into the given function we have,

⇒ f(5) = ( 5² + 7 ) / ( 5² + 4(5) - 21 )

⇒ f(5)  = ( 25 + 7 ) / ( 25 + 20 - 21 )

⇒ f(5)  = 32 / 24

Now reduce the fraction by taking out the common factor of the numerator and the denominator we get,

⇒ f(5)  = ( 8 × 4 ) / ( 8 × 3 )

⇒ f(5)  = 4/3

Therefore, the value of the function f(x) at x=5 is 4/3.

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The given question is incomplete, I answer the question in general according to my knowledge:

Find the value of the function f(x) at x = 5.

f(x) =  ( x² + 7 ) / ( x² + 4x - 21 )

The correct SOR formula for the boundary condition Y'(0) = 1 is:

OY₁ = (1 - ω/4)(Y₁ - Y₂) / 6 + (1 - ω/4)(Y₁ + Y₂) / 3 + (ω/4)(∆²f₁ + Yᵢ₊ₙ + Yᵢ₋ₙ - ∆)

To derive the correct SOR formula for the boundary condition Y'(0) = 1, we start with the standard SOR formula:

OYᵢ = (1 - ω)Yᵢ + (ω/4)(Yᵢ₊₁ + Yᵢ₋₁ + Yᵢ₊ₙ + Yᵢ₋ₙ - ∆²fᵢ)

where i and j are indices corresponding to the discrete coordinates in the x and y directions, ω is the relaxation parameter, and ∆ is the grid spacing in both directions.

To incorporate the boundary condition Y'(0) = 1, we use a forward difference approximation for the derivative:

Y'(0) ≈ (Y₁ - Y₀) / ∆

Substituting this into the original equation gives:

(Y₁ - Y₀) / ∆ = 1

Solving for Y₀ gives:

Y₀ = Y₁ - ∆

Now we can use this expression for Y₀ to modify the SOR formula at i = 1:

OY₁ = (1 - ω)Y₁ + (ω/4)(Y₂ + Y₀ + Yᵢ₊ₙ + Yᵢ₋ₙ - ∆²f₁)

Substituting the expression for Y₀, we get:

OY₁ = (1 - ω)Y₁ + (ω/4)(Y₂ + Y₁ - ∆ + Yᵢ₊ₙ + Yᵢ₋ₙ - ∆²f₁)

Simplifying:

OY₁ = (1 - ω/4)(Y₁ - Y₂) / 6 + (1 - ω/4)(Y₁ + Y₂) / 3 + (ω/4)(∆²f₁ + Yᵢ₊ₙ + Yᵢ₋ₙ - ∆)

So the correct SOR formula for the boundary condition Y'(0) = 1 is:

OY₁ = (1 - ω/4)(Y₁ - Y₂) / 6 + (1 - ω/4)(Y₁ + Y₂) / 3 + (ω/4)(∆²f₁ + Yᵢ₊ₙ + Yᵢ₋ₙ - ∆)

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Answer:

C

Step-by-step explanation:

The reason I would choose C is that the penny doubling each day might seem small but the amount would continue to grow exponentially giving you a might higher payoff than the rest of the options. I don't know the exact amount you would get by it is around 3 mill.

Option B gives you linear growth, which means that by the end of 30 days, you would only have 750,000.

Option A is the worst potion only leaving you with 1 million.

The correct expansion of (3x – 2)(2[tex]x^2[/tex]  + 5) is 3x *  2[tex]x^2[/tex] + 3x * 5 + (–2) * 2[tex]x^2[/tex]  + (–2) * 5. Thus option A is the most appropriate option as the answer the above question

The expansion of the given algebraic expression follows the distributive rule of multiplication that is (a + b)(c + d) = ac + ad + bc + bd.

Thus the first term of the first expression which is 3x is multiplied by the the second expression and we get 3x • 2[tex]x^2[/tex] + 3x • 5 + (–2)

Then the second term that is -2 is multiplied by the second expression and we get 5 + (–2) • 2[tex]x^2[/tex]  + (–2) • 5

Then we add both expressions and get the answer 3x * 2[tex]x^2[/tex] + 3x * 5 –2 * 2[tex]x^2[/tex]  –2 * 5.

After further simplification of the above expression we get, 6[tex]x^3[/tex] + 15x - [tex]4x^2[/tex] - 10.

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Answer:

The answer is D.2

Step-by-step explanation:

Can Ihave brainliest bc you said it was worth 13 but it's worth 7 :l

This means that there are 3 students who scored within that range. Therefore, the correct answer is C. 3.

The histogram displays the test scores for the 19 students in the geometry class. To determine how many students scored from 110 to 119 points, we need to look at the height of the bars in that range.

A histogram is a graphical representation of data that displays the frequency or distribution of a set of continuous or discrete variables. It consists of a series of bars, where each bar represents a specific category or range of values, and the height of the bar corresponds to the frequency or count of observations falling within that category or range.

Based on the histogram, we can see that the bar representing the range from 110 to 119 points has a height of 3. This means that there are 3 students who scored within that range. Therefore, the correct answer is C. 3.

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We have shown that if b = 0(mod a) and c = 0(mod b), then c = 0(mod a).

The statement "If b = 0(mod a) and c = 0(mod b), then c = 0(mod a)" is true.

To prove this, we need to show that if b is a multiple of a and c is a multiple of b, then c is a multiple of a.

Suppose that b = ak and c = bk' for some integers k and k'. Then, we have:

c = bk' = (ak)k' = a(kk')

Since k and k' are both integers, their product kk' is also an integer. Therefore, we can write c = a(kk'), which shows that c is a multiple of a.

Hence, we have shown that if b = 0(mod a) and c = 0(mod b), then c = 0(mod a).

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The values of x and y are given as follows:

x = y = 5.

The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.

The theorem is expressed as follows:

c² = a² + b².

In which:

The diagonal length of the rectangle is the hypotenuse of a right triangle of sides 6 and 8, hence:

d² = 6² + 8²

d² = 100

d = 10.

The segments x and y are each half the length of the diagonal, and the two diagonals have the same length for a rectangle, hence:

x = y = 5.

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Each of the statements should be marked correctly as follows;

The sum of −9 and 18/2 ​ is equal to 0: True.

The sum of −14/2 ​ and 7 is greater than 0: False.

The sum of 6, −4, and −2 is equal to 0: True.

The sum of 7, −9, and 2 is less than 0: False.

In Mathematics and Geometry, an inequality simply refers to a mathematical relation that is typically used for comparing two (2) or more numerical data and variables in an algebraic equation based on any of the inequality symbols;

Next, we would evaluate each of the statements as follows;

-9 + 18/2 = -9 + 9 = 0

Therefore, the sum of −9 and 18/2 ​is truly equal to 0.

-14/2 + 7 = -7 + 7 = 0.

Therefore, the sum of −14/2 ​and 7 is not greater than 0.

6 - 4 - 2 = 0

Therefore, the sum of 6, −4, and −2 is truly equal to 0.

7 - 9 + 2 = 0

Therefore, the sum of 7, −9, and 2 is not less than 0.

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If A and B are mutually exclusive, then the correct answer is c. P(A ∩ B) = 0. This is because mutually exclusive events cannot occur at the same time, meaning the intersection of the events is empty. Therefore, the probability of A and B occurring together is zero.

To explain further, if A represents the event of flipping heads on a coin and B represents the event of flipping tails on the same coin, then these events are mutually exclusive because both cannot occur at the same time. The probability of flipping heads or tails on a coin is 1, but the probability of flipping heads and tails simultaneously is 0. Therefore, P(A ∩ B) = 0.

It is important to note that if A and B are mutually exclusive, then P(A) + P(B) = 1, which is answer choice d. This is because one of the events must occur, but not both. Therefore, the total probability of either A or B occurring is 1. However, this does not directly answer the question about the probability of the intersection of A and B.

Overall, when working with mutually exclusive events, it is important to recognize that they cannot occur at the same time and therefore have no intersection, which makes the probability of A and B occurring together equal to 0.

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If A and B are mutually exclusive events, this signifies that they cannot both happen simultaneously. Therefore, the probability of both events occurring, expressed as P(A ∩ B), is equal to 0.

If A and B are mutually exclusive, it means that events A and B cannot occur at the same time. In terms of probability, we express this statement as: the probability that both A and B occur, denoted by P(A ∩ B), is equal to 0. Hence the correct answer is: c. P(A ∩ B) = 0.

This is fundamental in the study of probability and is crucial for understanding more complex concepts such as conditional probability and independence of events.

It's important to note that answers a, b and d are incorrect. Answer a, P(A) + P(B) = 0, implies that neither event can happen which contradicts the definition of mutually exclusive events. Answer b, P(A ∩ B) = 1, implies that A and B must always occur together, which is the exact opposite of what mutual exclusivity means. Answer d, P(A) + P(B) = 1, would be correct if A and B were exhaustive events, which means that either event A or event B is certain to occur.

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The slope of the graph is 50, and it represents the rate of change of the total cost of the gym membership per month.

To write an equation for C, the total cost of the gym membership, we can use the slope-intercept form of a linear equation, which is y = mx + b. In this case, y represents the total cost, m represents the slope, x represents the number of months, and b represents the y-intercept (the initial cost of joining the gym).

From the graph, we can see that the initial cost of joining the gym is $700 (the y-intercept), and the monthly fee is $50 (the slope of the line connecting the dots). So, the equation for C is:

C = 50t + 700

where t is the number of months.

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The  limit of the function as x approaches infinity is infinity.

To evaluate this limit, we can use L'Hospital's rule, which says that if we have an indeterminate form of the type 0/0 or infinity/infinity, we can differentiate the numerator and denominator separately with respect to the variable of interest, and then take the limit again.

In this case, we have infinity/infinity, so we can apply L'Hospital's rule:

\begin{aligned}
\lim_{x\rightarrow\infty} \frac{8x}{2\ln(12e^x)} &= \lim_{x\rightarrow\infty} \frac{8}{\frac{2}{12e^x}}\\
&= \lim_{x\rightarrow\infty} \frac{8}{\frac{1}{6e^x}}\\
&= \lim_{x\rightarrow\infty} 48e^x\\
&= \infty
\end{aligned}

Therefore, the limit of the function as x approaches infinity is infinity.

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The domain of rational function f(x) = (x² - 36) / (x - 6) is x ∈ (- ∞, + ∞).

In this question we must determine what function has a domain, that is, the set of all x-values, that comprises all real numbers. According to algebra, polynomic functions have a domain that comprises all real numbers.

Herein we need to determine what rational function is equivalent to a polynomic function. Polynomic functions are expression of the form:

[tex]y = \sum\limits_{i = 0}^{n} c_{i}\cdot x^{i}[/tex]

Where:

Now we check the following expression by algebra properties:

f(x) = (x² - 36) / (x - 6)

f(x) = [(x - 6) · (x + 6)] / (x - 6)

f(x) = x + 6

The rational function f(x) = (x² - 36) / (x - 6) is equivalent to polynomial of grade 1 and, thus, its domain comprises all real numbers.

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To determine the partial fraction expansion for a rational function, we need to express it as a sum of simpler fractions. However, the general process for finding the partial fraction expansion of a rational function is as follows:

1. Factor the denominator of the rational function into linear and/or quadratic factors.
2. Write the rational function as a sum of fractions, one for each factor of the denominator. For each linear factor, use a constant numerator. For each quadratic factor, use a linear numerator.
3. Solve for the constants using algebraic manipulation and equating the numerators of the partial fractions with the original numerator of the rational function.
4. Write the partial fraction expansion as the sum of the fractions found in step 2 with the constants found in step 3.

For example, if the rational function is (3x^2 + 5x + 2)/(x^2 + 4x + 3), we would first factor the denominator as (x + 3)(x + 1). Then we would write the partial fraction expansion as:

(3x^2 + 5x + 2)/(x^2 + 4x + 3) = A/(x + 3) + B/(x + 1)

To solve for A and B, we would equate the numerators:

3x^2 + 5x + 2 = A(x + 1) + B(x + 3)

Expanding and equating coefficients, we get:

3 = B + A
5 = 3B + A

Solving for A and B, we get:

A = 1
B = 2

Therefore, the partial fraction expansion of (3x^2 + 5x + 2)/(x^2 + 4x + 3) is:

(3x^2 + 5x + 2)/(x^2 + 4x + 3) = 1/(x + 3) + 2/(x + 1)

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The range of f(x) = 2x -3 include the following: {-7, -3, -2, 7}.

In Mathematics and Geometry, a domain is the set of all real numbers for which a particular function is defined.

When the domain is -2, the range of this function can be calculated as follows;

f(x) = 2x - 3

f(-2) = 2(-2) - 3

f(-2) = -7.

When the domain is 0, the range of this function can be calculated as follows;

f(x) = 2x - 3

f(0) = 2(0) - 3

f(0) = -3.

When the domain is 1/2, the range of this function can be calculated as follows;

f(x) = 2x - 3

f(1/2) = 2(1/2) - 3

f(1/2) = -2.

When the domain is 5, the range of this function can be calculated as follows;

f(x) = 2x - 3

f(5) = 2(5) - 3

f(5) = 7.

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The recurrence relation for the total amount of money in the savings account at the end of n months can be expressed using a recursive formula that takes into account the monthly deposits and the compounded interest. Let A_n be the total amount of money in the account at the end of the nth month. Then, we have:

A_n = A_{n-1} + 100 + (0.06/12)*A_{n-1}

Here, A_{n-1} represents the total amount of money in the account at the end of the (n-1)th month, which includes the deposits made in the previous months and the accumulated interest. The term 100 represents the deposit made at the beginning of the nth month.

The term (0.06/12)*A_{n-1} represents the interest earned on the balance in the account at the end of the (n-1)th month, assuming a monthly interest rate of 0.06/12.

Using this recursive formula, we can calculate the total amount of money in the account at the end of each month, starting from the initial balance of $0. For example, we can calculate A_1 = 100 + (0.06/12)*0 = $100, which represents the balance at the end of the first month.

Similarly, we can calculate A_2 = A_1 + 100 + (0.06/12)*A_1 = $206, which represents the balance at the end of the second month. We can continue this process to calculate the balances at the end of each month up to the nth month.

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Answer:

Sure, I can help you with that. Here are the steps on how to solve the problem:

1. Let x be the height of the balloon on the left and y be the height of the balloon on the right.

2. Using the tangent function, we can write the following equations:

```

tan(38) = x/700

tan(26) = y/1050

```

3. Solve the first equation for x:

```

x = 700tan(38)

```

4. Substitute this value of x into the second equation:

```

y/1050 = tan(26)

y = 1050tan(26)

```

5. Subtract the two equations to find the difference between the heights of the two balloons:

```

y - x = 1050tan(26) - 700tan(38)

```

6. Evaluate this expression using a calculator and round your answer to the nearest tenth:

```

y - x = 266.51 meters

```

Therefore, the balloon on the right is 266.51 meters higher than the balloon on the left.

Step-by-step explanation:

The amount of space within the cylinder not taken up by the tennis balls is 18.9 [tex]inches^3[/tex]

The volume of a tennis ball:

The circumference of the tennis ball is 8 inches.

The tennis ball is the form of sphere whose circumference is given by formula [tex]2\pi r[/tex], where r is the radius.

Thus, if r is the radius then according to condition,

[tex]2\pi r[/tex] = 8 or

r = 8/2[tex]\pi[/tex] inches.

Now, the volume of the sphere of radius r is [tex]\frac{4}{3}\pi r^3[/tex] hence, find the volume of the given tennis ball by substituting r  = 8/2[tex]\pi[/tex] inches in  [tex]\frac{4}{3}\pi r^3[/tex] and simplify:

Volume = [tex]\frac{4}{3}\pi[/tex] × [tex](\frac{8}{2\pi } )^3[/tex]

Volume = 8.65[tex]inches^3[/tex]

Hence the required volume of the tennis ball is 8.65[tex]inches^3[/tex]

The volume of three tennis balls is (3 × 8.65) [tex]inches^3[/tex] = 25.96 [tex]inches^3[/tex]

Find the volume of the cylinder:

The volume of the cylinder with radius r units and height h units is given by [tex]\pi r^2h[/tex] Hence the volume of the given cylinder with radius 1.32 inches , 8.2 height inches is:

[tex]\pi (1.32)^2[/tex] × 8.2

= 3.14 × [tex](1.32)^2[/tex] × 8.2

= 44.86 [tex]inches^3[/tex]

Hence the volume of the cylinder is 44.86 [tex]inches^3[/tex]

Find the amount of space within the cylinder not taken up by the tennis balls.

The required volume can be obtained by subtracting the volume three tennis balls from the volume of the cylinder as follows:

Volume of cylinder - volume of three tennis balls = (44.86 - 25.96) = 18.9 [tex]inches^3[/tex]

Hence, the amount of space within the cylinder not taken up by the tennis balls is 18.9 [tex]inches^3[/tex]

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a. the inverse function g(x) is: g(x) = (x + 2)/3

b. the inverse function g(x) is: g(x) = [tex]x^2 + 3[/tex]

What is inverse fucntion?

An inverse function is a function that "undoes" the action of another function. More specifically, if a function f takes an input x and produces an output f(x), then its inverse function, denoted f^(-1), takes an output f(x) and produces the original input x.

a. f(x) = 3x - 2

To find the inverse of f(x), we first replace f(x) with y:

y = 3x - 2

Next, we solve for x in terms of y:

y + 2 = 3x

x = (y + 2)/3

So the inverse function g(x) is:

g(x) = (x + 2)/3

To sketch f(x) and g(x) and show that they are symmetric with respect to the line y=x, we plot them on the same coordinate plane.

Graph of f(x) and g(x):

The blue line represents f(x) and the green line represents g(x). As we can see, the two lines are symmetric with respect to the line y=x, which is the dashed diagonal line passing through the origin. This means that if we reflect any point on the blue line across the line y=x, we will get the corresponding point on the green line, and vice versa.

[tex]b. f(x) = \sqrt(x - 3)[/tex]

To find the inverse of f(x), we first replace f(x) with y:

[tex]y = \sqrt(x - 3)[/tex]

Next, we solve for x in terms of y:

[tex]y^2 = x - 3\\\\x = y^2 + 3[/tex]

So the inverse function g(x) is:

[tex]g(x) = x^2 + 3[/tex]

To sketch f(x) and g(x) and show that they are symmetric with respect to the line y=x, we plot them on the same coordinate plane.

Graph of f(x) and g(x):

The red curve represents f(x) and the blue curve represents g(x). As we can see, the two curves are symmetric with respect to the line y=x, which is the dashed diagonal line passing through the point (3,0). This means that if we reflect any point on the red curve across the line y=x, we will get the corresponding point on the blue curve, and vice versa.

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Answer:

Step-by-step explanation:

80%

The correct answer is (b) "Because vertex L' is located at (–2, 6) and vertex N' is located at (4, –2), the length of a side is 10 units."

First, we perform a translation 3 units right and 2 units down. This means we add 3 to the x-coordinates and subtract 2 from the y-coordinates of each vertex:

L' = (-1, 3)

R' = (-2, 1)

N' = (2, -1)

Next, we perform a dilation centered at the origin with a scale factor of 2. This means we multiply the coordinates of each vertex by 2:

L" = (-2, 6)

R" = (-4, 2)

N" = (4, -2)

Now, we can use the distance formula to calculate the lengths of the sides of triangle L'N'R':

L'N' = √[(4+2)² + (-2-6)²] = √[100] = 10

Therefore, the correct answer is (b) "Because vertex L' is located at (–2, 6) and vertex N' is located at (4, –2), the length of a side is 10 units."

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The area of the trapezoid in this problem is given as follows:

C. [tex]A = 96\sqrt{3}[/tex] mm².

The area of a trapezoid is given by half the multiplication of the height by the sum of the bases, hence:

A = 0.5 x h x (b1 + b2).

The bases in this problem are given as follows:

11 mm and 15 + 6 = 21 mm.

The height of the trapezoid is obtained considering the angle of 60º, for which:

We have that the tangent of 60º is given as follows:

[tex]tan{60^\circ} = \sqrt{3}[/tex]

The tangent is the division of the opposite side by the adjacent side, hence the height is obtained as follows:

[tex]\sqrt{3} = \frac{h}{6}[/tex]

[tex]h = 6\sqrt{3}[/tex]

Thus the area of the trapezoid is obtained as follows:

[tex]A = 0.5 \times 6\sqrt{3} \times (11 + 21)[/tex]

[tex]A = 96\sqrt{3}[/tex] mm².

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The circumference of the area of a circle is 4π in² using the formula A = πr², in inches is 4π inches.

The formula for the area of a circle is A = πr², where A is the area and r is the radius. Given that the area is 4π in², we can solve for the radius by taking the square root of both sides:

√(A/π) = √(4π/π) = 2 in

The formula for the circumference of a circle is C = 2πr, where C is the circumference and r is the radius. Substituting the value of r, we get:

C = 2π(2 in) = 4π in

Therefore, the circumference of the circle is 4π inches.

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The expression to calculate the length in minutes of the phone call is:

(length of call in minutes) = (total cost - fixed cost) / (cost per minute)

Where the fixed cost is $1.00 and the cost per minute is $0.15.

Mona's mobile phone plan charges a fixed cost of $1.00 for the first call of the day and an additional $0.15 per minute for the length of the call. To calculate the length of the call in minutes, we need to subtract the fixed cost of $1.00 from the total cost of the call and then divide the result by the cost per minute of $0.15. This gives us the equation:

(length of call in minutes) = (total cost - fixed cost) / (cost per minute)

Substituting the values given in the problem, we get:

Simplifying this expression, we have:

Dividing $1.95 by $0.15 gives us the answer:

Therefore, Mona's phone call lasted 13 minutes.

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The expected number of sample means falling between 174.2 and 177.2 can be estimated as:

Expected number = A * Total number of sample means.

(a) The mean of the sampling distribution of X is given as 176.5 and the standard deviation is 1.28.

(b) To determine the expected number of sample means that fall between 174.2 and 177.2 centimeters inclusive, we need to calculate the z-scores corresponding to these values and find the area under the normal curve between these z-scores.

The z-score for 174.2 can be calculated as:

z1 = (174.2 - 176.5) / 1.28

Similarly, the z-score for 177.2 can be calculated as:

z2 = (177.2 - 176.5) / 1.28

Using a standard normal distribution table or a calculator, we can find the area between these two z-scores.

Let's assume the area between z1 and z2 is A. The expected number of sample means falling between 174.2 and 177.2 can be estimated as:

Expected number = A * Total number of sample means.

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We cannot rule out the null hypothesis that the population means the weight is equal to 100 lb based on the critical value rule at = 0.01.

A one-sample t-test can be used to evaluate whether we can rule out the null hypothesis that the population's average weight is 100 lb.

First, we need to calculate the test statistic t:

[tex]$t = \frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}}}$[/tex]

[tex]$t = \frac{(102 - 100)}{\frac{10}{\sqrt{25}}} = 2$[/tex]

The critical value for the t-distribution with 24 degrees of freedom and a significance level of 0.01 must then be determined. To determine this value, we can utilize a t-table or statistical software.

We establish the critical value to be 2.492 using a t-table. We are unable to reject the null hypothesis because our calculated t-value (2) is smaller than the crucial value (2.492).

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Answer: Taylor will run out of money first after 9 months, while Danny will run out of money after 8 months.

Step-by-step explanation:

To solve this problem, we can set up two equations to represent Taylor and Danny's savings over time, where x is the number of months that have passed:

Taylor: 900 - 100x

Danny: 1200 - 150x

To find out when they have the same amount of money in their accounts, we can set the two equations equal to each other and solve for x:

900 - 100x = 1200 - 150x

50x = 300

x = 6

Therefore, Taylor and Danny will have the same amount of money in their accounts after 6 months. To find out how much money they will have at that time, we can substitute x = 6 into either equation:

Taylor: 900 - 100(6) = 300

Danny: 1200 - 150(6) = 300

So after 6 months, both Taylor and Danny will have $300 in their accounts.

To determine who runs out of money first, we can set each equation equal to zero and solve for x:

Taylor: 900 - 100x = 0

x = 9

Danny: 1200 - 150x = 0

x = 8

Therefore, Taylor will run out of money first after 9 months, while Danny will run out of money after 8 months.

The left side of Green's theorem for this vector field and rectangular path is 32.28 ay.

To evaluate the left side of Green's theorem, we need to compute the line integral of the vector field F along the boundary of the region enclosed by the rectangular path C.

First, let's parameterize the rectangular path C as follows:

r(t) = (x(t), y(t)), where 2.8 ≤ x ≤ 8 and 2.1 ≤ y ≤ 7.5.

The boundary of the rectangular path C is composed of four line segments:

From (2.8, 2.1) to (8, 2.1): r(t) = (t, 2.1), where 2.8 ≤ t ≤ 8.

From (8, 2.1) to (8, 7.5): r(t) = (8, t), where 2.1 ≤ t ≤ 7.5.

From (8, 7.5) to (2.8, 7.5): r(t) = (t, 7.5), where 8 ≤ t ≤ 2.8 (note the reverse order).

From (2.8, 7.5) to (2.8, 2.1): r(t) = (2.8, t), where 7.5 ≥ t ≥ 2.1 (note the reverse order).

We can now evaluate the line integral of F along each of these line segments using the parameterization r(t) and the definition of the line integral:

∫_C F · dr = ∫_(C1) F · dr + ∫_(C2) F · dr + ∫_(C3) F · dr + ∫_(C4) F · dr,

where the dot product F · dr is given by:

F · dr = (x dx + y dy) · (dx ax + dy ay) = x dx^2 + y dy^2.

Let's evaluate each of the line integrals separately:

∫_(C1) F · dr = ∫_(2.8)^8 (t ax + 2.1 ay) · dt = (8 - 2.8) ax + 2.1 (0) ay = 5.2 ax

∫_(C2) F · dr = ∫_(2.1)^7.5 (8 ax + t ay) · dt = 8 (7.5 - 2.1) ay + 8 (0) ax = 46 ay

∫_(C3) F · dr = ∫_(8)^2.8 (t ax + 7.5 ay) · (-dt) = (8 - 2.8) ax + 7.5 (0) ay = -5.2 ax

∫_(C4) F · dr = ∫_(7.5)^2.1 (2.8 ax + t ay) · (-dt) = 2.8 (2.1 - 7.5) ay + 2.8 (0) ax = -13.72 ay

Therefore, the line integral of F along the boundary of the rectangular path C is:

∫_C F · dr = ∫_(C1) F · dr + ∫_(C2) F · dr + ∫_(C3) F · dr + ∫_(C4) F · dr = 5.2 ax + 46 ay - 5.2 ax - 13.72 ay = 32.28 ay.

So the left side of Green's theorem for this vector field and rectangular path is 32.28 ay.

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Answer:

-15 and -2

Step-by-step explanation:

Two negatives multiply to be a positive. We know -15 • -2 = +30

Combine (add) them and you get -17.