will mark as brainlest pls help

Answer:

c

Explanation:

Answer :

Imma just put it in the explanation

Explanation:

Electric to sound : Radio

Chemical to thermal+radiant+sound+kinetic : Fireworks

Gravitational to kinetic+sound : Waterfall

Chemical to thermal+kinetic : Drinking water (not sure what last answer is called but its supposed to match the girl drinking water lol)

hope this helps

Answer:

juuhu

Explanation:

jjj

Answer:

6.52m

Explanation:

The horizontal distance travelled is known as its range. This is expressed as;

Range = u* √2H/g

u is the speed of the pelican

H is the maximum height

g is the acceleration due to gravity

Range = 8.79*√2(2.7)/9.8

Range = 8.79 * √5.4/9.8

range = 8.79*√0.5510

Range = 8.79*0.7423

Range = 6.52

Hence the fish will travel 6.52m before hitting the water below

Answer:

yes you are totally right

I think ....... the answer will be ......

like a theory

Answer:

S = 415.1 meters

Explanation:

Dados los siguientes datos;

Velocidad inicial = 25 m/s

Tiempo, t = 7 segundos

Para encontrar la altura (desplazamiento) de la pelota, usaríamos la segunda ecuación de movimiento;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Dónde;

S representa el desplazamiento o altura medida en metros.

u representa la velocidad inicial medida en metros por segundo.

t representa el tiempo medido en segundos.

a representa la aceleración medida en metros por segundo cuadrado.

Sustituyendo en la ecuación, tenemos;

[tex] S = 25*7 + \frac {1}{2}*(9.8)*7^{2}[/tex]

[tex] S = 175 + 4.9*49 [/tex]

[tex] S = 175 + 240.1 [/tex]

S = 415.1 meters

Answer:

6 m/s

Explanation:

p=mv

p=3 kg.m/s

m=0.5 kg

rearrange and substitute to find v:

(3)=(0.5)v

v=3/0.5

v=6 m/s

Answer:

C. They are too close to the sun.

Explanation:

Answer:

0.25 m/s squared

Explanation:

Mass of the body (m)= 24kg

Applied force on the body(F)= 6N

Acceleration of the body (a)= ?

Solution

F = ma

a = F/m

a = 6N/24kg

a = 0.25m/s^2

Answer: The acceleration of the body is 0.25m/s^2

I hope this helps

Answer:

[tex]\boxed {\boxed {\sf a=\frac {1}{3} \ m/s^2}}[/tex]

Explanation:

Force is the product of mass and acceleration.

[tex]F=ma[/tex]

The mass is 24 kilograms and the force is 8 Newtons. Let's convert the Newtons to make the problem easier.

Substitute the known values into the formula.

[tex]8 \ kg*m/s^2= (24 \ kg )*a[/tex]

Since we are solving for a, we must isolate the variable. It is being multiplied and the inverse of multiplication is division. Divide both sides by 24 kilograms.

[tex]\frac {8 \ kg*m/s^2}{24 \ kg}= \frac{(24 \ kg )*a}{24 \ kg}[/tex]

The kilograms will cancel, hence our earlier unit conversion.

[tex]\frac {8 \ m/s^2}{24 }= a[/tex]

[tex]\frac {1}{3} \ m/s^2=a[/tex]

The acceleration is 1/3 meter per square second.

Answer:

The speed of the car is 14.7m/second or 15 m/second approximately.

Explanation:

A microwave beam at [tex]2.10\times10^1^0Hz[/tex] is generated by a stationary speed gun. It bounces off a car and returns at a higher frequency of 1030 Hz. The car's observed frequency would be the product of adding the two frequencies. That is to say,

       F =[tex]2.1\times10^1^0+1030[/tex] =[tex]2.100000103\times10^1^0Hz[/tex]

Using doppler effect formula

[tex]F=\frac{C}{C-V}\times f[/tex]

Where

F = observed frequency

f = source frequency

C = speed of light = [tex]3\times10^8[/tex]

V = speed of the car

 Putting the values in the formula -

        [tex]2.100000103\times10^1^0=\frac{3\times10^8}{3\times10^8-V}\times2.1\times 10^1^0[/tex]

                 [tex]\frac{2.100000103\times10^1^0}{2.1\times10^1^0}[/tex] [tex]=\frac{3\times10^8}{3\times10^8-V}[/tex]

          [tex]1.000000049=\frac{3\times10^8}{3\times10^8-V}[/tex]

by cross multiplication ,

   300000014.7 - 1.000000049V = [tex]3\times10^8[/tex]

    Collect the like terms  

1.000000049V = 14.71429

      Make V the subject of formula

V = [tex]\frac{14.71429}{1.000000049}[/tex]

V = 14.7 m/s

Therefore , the speed of the car is 15m/second approximately.

Answer: air pressure

Explanation:

Answer: 40.311 m

Explanation:

Given

Ant walks 15 m east

then 40 m North and finally 20 m west

from the figure, ant is 40 m North and 5 m west

Using Pythagoras, we can write

[tex]\Rightarrow d=\sqrt{40^2+5^2}\\\Rightarrow d=\sqrt{1625}=40.311\ m[/tex]

Answer:

3 miles

Explanation:

5 + 2 - 2 - 2 = 3 miles

Answer:

A.  Can the wave transfer matter?

Explanation:

Answer:

As the full spectrum of visible light travels through a prism, the wavelengths separate into the colors of the rainbow because each color is a different wavelength. Violet has the shortest wavelength, at around 380 nanometers, and red has the longest wavelength, at around 700 nanometers.

Explanation:

Answer:

200 N/m²

Explanation:

Pressure = Force / Area

Force =100N

Area = 100cm x 50 cm= 5000cm² =0.5m²

Hence Pressure = 100N / 0.5m²

Pressure = 200N/m²

Answer:

d) 5 Ns

Explanation:

Impulse = Ft = 1,000(0.005) = 5

See the attached diagram for reference and free body diagrams. The acceleration a of each body will be the same since each connecting string is in tension.

By Newton's second law, we have

• net force on the train:

- - horizontal

[tex]\sum F = F - F_{k,T} - T_1 = m_Ta[/tex]

(where F = 12 N)

- - vertical

[tex]\sum F = N_T - m_Tg = 0[/tex]

• net force on wagon 1:

- - horizontal

[tex]\sum F = T_1 - T_2 - F_{k,1} = m_1a[/tex]

- - vertical

[tex]\sum F = N_1 - m_1g = 0[/tex]

• net force on wagon 2:

- - horizontal

[tex]\sum F = T_2 - F_{k,2} = m_2a[/tex]

- - vertical

[tex]\sum F = N_2 - m_2g = 0[/tex]

We want to determine T₂, the tension in the string connecting the two wagons.

For each body, the corresponding normal force has magnitude

N = mg

where m is the respective mass, and the kinetic friction has magnitude

Friction = 0.05 N = 0.05mg

So if µ = 0.05, then the frictional force on each body is

[tex]F_{k,T} = 0.05 (2.7\,\mathrm{ kg}) g = 1.323\,\mathrm N[/tex]

[tex]F_{k,1} = 0.05 (1.8\,\mathrm{ kg}) g = 0.882\,\mathrm N[/tex]

[tex]F_{k,2} = 0.05 (1.0\,\mathrm{ kg}) g = 0.49\,\mathrm N[/tex]

which leaves us with the system of equations,

[1] … 12 N - 1.323 N - T₁ = (2.7 kg) a

[2] … T₁ - T₂ - 0.882 N = (1.8 kg) a

[3] … T₂ - 0.49 N = (1.0 kg) a

Adding [1] and [2] eliminates T₁ :

(12 N - 1.323 N - T₁) + (T₁ - T₂ - 0.882 N) = (2.7 kg) a + (1.8 kg) a

[4] … 9.795 N - T₂ = (4.5 kg) a

Divide through both sides of [3] by 1.0 kg to solve for a :

a = (T₂ - 0.49 N) / (1.0 kg)

Substitute this into [4] and solve for T₂ :

9.795 N - T₂ = (4.5 kg) (T₂ - 0.49 N) / (1.0 kg)

(9.795 N - T₂) (1.0 kg) = (4.5 kg) (T₂ - 0.49 N)

9.795 N - T₂ = 4.5 T₂ - 2.205 N

12 N = 5.5 T₂

T₂ = (12 N) / 5.5 ≈ 2.1818 N ≈ 2.2 N

Answer: 2.21 m/s

Explanation:

Given

Coin reaches a height of  0.25 m above the launch point

Suppose u is the initial speed of the coin

Using the equation of motion

[tex]\Rightarrow v^2-u^2=2as\\[/tex]

Putting values

[tex]\Rightarrow 0^2-u^2=2\times g\times s=2\times (-9.8)\times 0.25\\\Rightarrow u^2=4.9\\\Rightarrow u=2.21\ m/s[/tex]

Thus, the initial velocity is 2.21 m/s

Answer:

B

Explanation:

Answer:

The human arm is a class 3 lever

Explanation:

Answer:

A bent arm is a Class 3 lever. The pivot is at the elbow and the forearm acts as the lever arm. The biceps muscle provides the effort (force) and bends the forearm against the weight of the forearm and any weight that the hand might be holding.

Explanation:

Answer:

During photosynthesis solar energy is converted into chemical energy

Explanation:

During photosynthesis solar energy is converted into chemical energy in the form of energy rich bond of ATP molecule.

ATP (Adenosine triphosphate) and ADP (Adenosine diphosphate) molecules are termed currency of energy. ADP molecule is converted into ATP molecules, whenever energy is available in certain exothermic reactions of metabolism.

ATP molecules are store- house of energy. ATP molecule is broken down into ADP molecule in presence of enzyme ATPase, releasing energy whenever energy is required.

The synthesis of ATP molecules, utilizing solar energy during photosynthesis, is termed photo-phosphorylation.

These ATP molecules produced during light reaction of photosynthesis are utilized in dark reaction of photosynthesis (Calvin cycle).

ATP molecules synthesized during photo-phosphorylation may also be used in other metabolic reactions.

Photo-phosphorylation is of 2 types, i.e. Cyclic and Non-cyclic photo-phosphorylation.

Chlorophyll molecules entrap solar energy . There are 2 types of photo-systems in chlorophyll. These are photo-system -I and photo-system-II .

The electrons of chlorophyll molecule of photo-system I get excited which pass through series of electron carriers in electron transport system arranged in the order of decreasing energy level.

During the passage of electrons from carriers of higher energy level to the carriers of lower energy level, the energy is lost which is utilized for converting ADP molecule into ATP molecule.

Photo-system I is concerned with light reaction of photosynthesis only, constituting cyclic photo-phosphorylation.

The electron transport during Photo-system II results in the synthesis of NADPH2 in presence of enzyme NADP reductase. NADPH2 is used in reduction reaction of Calvin cycle.

Both Photo-systems participate in non-cyclic photo-phosphorylation that results in the synthesis of NADPH2 in addition to the synthesis of ATP molecules.

Answer:

Frequency = 260 Hz and wavelength = 1.31 m

Explanation:

Given that,

A hammer begins vibrating back and forth at approximately 260 cycles per second.

(a) The frequency of an object is the number of vibrations per unit time. The frequency of the sound wave is 260 Hz.

(b) The speed of sound in air is 343 m/s. So,

[tex]v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{343}{260}\\\\\lambda=1.31\ m[/tex]

Hence, this is the required solution.

Answer:

NO ANSWER

Explanation:

there is no tragectory or diagram given

WHICH OBJECT?

Answer:

A) a = 73.304 rad/s²

B) Δθ = 3665.2 rad

Explanation:

A) From Newton's first equation of motion, we can say that;

a = (ω - ω_o)/t. We are given that the centrifuge spins at a maximum rate of 7000rpm.

Let's convert to rad/s = 7000 × 2π/60 = 733.04 rad/s

Thus change in angular velocity = (ω - ω_o) = 733.04 - 0 = 733.04 rad/s

We are given; t = 10 s

Thus;

a = 733.04/10

a = 73.304 rad/s²

B) From Newton's third equation of motion, we can say that;

ω² = ω_o² + 2aΔθ

Where Δθ is angular displacement

Making Δθ the subject;

Δθ = (ω² - ω_o²)/2a

At this point, ω = 0 rad/s while ω_o = 733.04 rad/s

Thus;

Δθ = (0² - 733.04²)/(2 × 73.304)

Δθ = -537347.6416/146.608

Δθ = - 3665.2 rad

We will take the absolute value.

Thus, Δθ = 3665.2 rad

Answer:

313.92w

Explanation:

Formula for power:

P=W/∆t = Fv

Givens:

m=20kg

∆y=4.0m

∆t=2.5s

a=9.81m/s²

In order to find power, we first need to solve for work.

W=Fd (force*displacement), f=mg

W=mg∆y

W=(20kg)(9.81m/s²)(4.0m)

W=784.8J

P=W/∆t

P=784.8J/2.5s

P=313.92 watts

Answer:

Those objects are called transparent objects...

Explanation:

If only some light can pass through them ,it is called translucent....

If no light can pass through them ,it is called opaque.

Answer:

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