WILL MARK BRAINLIEST
A 75 kg cannon ball is fired from a 500 kg cannon. If the cannon balls speed is 4 m/s immediately after leaving the raft what is the recoil speed of the cannon

Answer:

D

Explanation:

Answer:

1.865 * 10^-4 L

Explanation:

The equation of the reaction is:

4OH^-(aq) ----->2H2O(l) + O2(g) + 4e

Since one mole of oxygen which occupies 22.4 L is produced in the electrolysis of water by 4 Faraday of electricity as shown in the equation above;

Then;

4 * 96500 C liberates 22.4 L of oxygen

60 * 60 * 0.0200 C will liberate 60 * 60 * 0.0200 *  22.4/4 * 96500

= 1.865 * 10^-4 L

Answer:

I would say A, I hope this helped ; >

Answer:

7.22×10¹⁰ J

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 7.6 Km/s

Mass (m) = 2500 kg

Energy (E) =?

Next, we shall convert 7.6 Km/s to m/s. This can be obtained as follow:

1 km/s = 10³ m/s

Therefore,

7.6 Km/s = 7.6 Km/s × 10³ m/s / 1 km/s

7.6 Km/s = 7.6×10³ m/s

Finally, we shall determine the energy required as follow:

Velocity (v) = 7.6×10³ m/s

Mass (m) = 2500 kg

Energy (E) =?

E = ½mv²

E = ½ × 2500 × (7.6×10³)²

E = 1250 × 57760000

E = 7.22×10¹⁰ J

Thus, 7.22×10¹⁰ J of energy is required.

Answer:

rama is doing

Explanation:

work done=f×d×g

=60×20×9.8

=11760j

she is doing work against gravity

mark me

The radiation dose absorbed by a person is measured using the conventional unit rad or the SI unit gray. The biological risk of exposure to radiation is measured using the conventional unit rem or the SI unit sievert.

I hope this helps!

Answer:

the workenergy principle is measured in joules

Answer:

The work is done by the force 100 NM.

Explanation:

=5kg * 2 m/s^2

=5* 2 N (kg*m/s^2=N)

=10N

Work done = force* distance

=10N* 10

= 100 NM

For an object of mass 5 kg accelerating at the rate of 2 m/s², then the work done by the force on the object will be 100 Nm.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Mass of the object, m = 5 kg

Acceleration, a = 2 m/s²

Distance, d = 10 m

W = f × d

W = m × a × d

W = 5 × 2 × 10

W = 100 Nm

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Answer:

to find the weight, use the following formula

F= m x g

in Earth---> 45 x 9.8= 441 N

in Moon---> 45 x 1.6= 72 N

Explanation:

I HOPE THIS HELPS!!! :)

The change in gravitational potential energy of a 45 kg weight that is moved from 2 m to 18 m on Earth and Moon are 7.056kJ and 1.152kJ respectively.

Gravitational potential energy is defined as the energy possessed by or acquired by an object due to a change in its position when it is present in a gravitational field. This can be said that gravitational potential energy is the energy which is related to the gravitational force or gravitation.

Gravitational potential energy is expressed as

U=m g h

Where, U = gravitational potential energy

m = mass

g = gravitational field

h = height

For above given example,

The change in gravitational potential energy for Earth

mass= 45kg

Difference in height [tex](H_2-H_1)[/tex]= 18-2= 16m

g= [tex]9.8m/s^2[/tex]

U= 45*16*9.8 = 7056J or 7.056kJ

The change in gravitational potential energy for Moon

mass= 45kg

Difference in height [tex](H_2-H_1)[/tex]= 18-2= 16m

g= [tex]1.6m/s^2[/tex]

U= 45*16* 1.6= 1152J or 1.152kJ

Thus, the change in gravitational potential energy of a 45 kg weight that is moved from 2 m to 18 m on Earth and Moon are 7.056kJ and 1.152kJ respectively.

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Answer:

The correct option is;

d) All of the above

Explanation:

a) In an electric circuit through which electric current flows, it is due to the electric charges which can be the negatively charged electrons or the positively charged protons

b) Voltage is the potential difference that results in current flowing through the circuit, therefore, the voltage is applied across the circuit through which current flows

c) The voltage which is the electric potential difference is the change in potential energy in joules of a given system due to the movement of a test charge (in Coulombs) between points in the electric field, ΔE, divided by the value of the test charge, 'q'

V = ΔE/q

Therefore, all of the above are correct.

Answer:

Tendons: Tendons are cord-like, strong, inelastic structures that join skeletal muscles to bones

ligaments: Ligaments are elastic structures which connect bones to bones in joints.

Explanation:

Answer:

the current flowing through the battery is 4 A.

Explanation:

Given;

resistance of the three resistors in parallel, R₁, R₂ and R₃ = 3.0 Ω, 12 Ω, and 4.0 Ω

voltage of the battery, V = 6.0 V

The equivalent resistance is calculated as follows;

[tex]\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \\\\\frac{1}{R_T} = \frac{1}{3} + \frac{1}{12} + \frac{1}{4} \\\\\frac{1}{R_T} = \frac{4 \ + \ 1 \ + \ 3}{12} \\\\\frac{1}{R_T} = \frac{8}{12} \\\\\frac{1}{R_T} = \frac{2}{3} \\\\R_T = \frac{3}{2} \\\\R_T = 1.5 \ ohms[/tex]

The current flowing through the battery is calculated as follows;

[tex]I = \frac{V}{R_T} \\\\I = \frac{6}{1.5} \\\\I = 4 \ A[/tex]

Therefore, the current flowing through the battery is 4 A.

Answer:

The length traveled by an object moving in any direction or even changing direction is called distance. The location of an object in a frame of reference is called position. For straight line motion, positions can be shown using a number line. The separation between original and final position is called displacement

Explanation:

good luck

Answer:

t = 0.553

Explanation:

The mass has nothing to do with an object falling.

Givens

d = 1.5 m

a = 9.8

vi = 0

t = ?

Formula

d = vi * t + 1/2 a t^2

Solution

1.5 = 0 + 1/2 9.81 * t^2

1.5 = 4.905 t^2

1.5/4.905 = t^2

0.3058 = t^2

sqrt(t^2) = sqrt(0.3058)

t = 0.553

About 1/2 a second which is really surprising wouldn't you think?

Answer:

c

Explanation:

what poping

Answer:

3 m/s²

Explanation:

Acceleration = Change in velocity/ time

= (20 - 5) / 5

= 3 m/s²

Answer:

1. Amplitude.

2. Rarefaction.

3. Wavelength.

4. Compression.

Explanation:

Sound are mechanical waves that are highly dependent on matter for their propagation and transmission. Some of the properties of sound waves as it travels through a medium such as solid, liquid and gas includes the following;

1. Amplitude: the density of the medium's particles at the compressions of the waves.

2. Rarefaction: the part of a wave where the particles of the medium are farther apart. This ultimately implies that, it is part of a longitudinal wave in which the particles that make up the matter for the movement of the wave are separated by a greater distance.

3. Wavelength: the distance between compressions or rarefactions i.e the distance between two successive compressions or refractions.

4. Compression: the part of a wave where the particles of the medium are closer together. This ultimately implies that, it is part of a longitudinal wave in which the particles that make up the matter for the movement of the wave are closer together.

Answer:

here is the answers .......

Answer:

1080000

Explanation:

300 x 60s=18000m/minute

18000 x 60min=1080000m/h

Explanation:

Answer:

9.1 mph

Explanation:

Answer:

The number of air molecules in her lung compared with the number she had in a full breadth at the surface is;

C. Twice as many

Explanation:

The depth at which the scuba diver fills her lungs with air, d = 10 m

Pressure of fluid = Density, ρ × Acceleration due to gravity, 'g' × Depth, 'd'

Where;

ρ = 970 kg/m³

g ≈ 9.81 m/s²

∴ The pressure of the water of the 10 m water column = 970 kg/m³ × 9.81 m/s² × 10 m = 95,157 Pa

The atmospheric pressure, P₁ = 101,325 Pa

The total pressure at the 10 m depth = The atmospheric pressure + The pressure of the water of the 10 m water column

∴ The total pressure at the 10 m depth, P₂ = 95,157 Pa + 101,325 Pa = 196,482 Pa

By the combined gas law, we have;

P₁·V₁/n₁ = P₂·V₂/n₂

Where;

P₁ = The atmospheric pressure

P₂ = The pressure at 10 m depth

V₁ = V₂ = The volume of her lungs

n₁ = The number of air molecules at the surface that fills her lungs

n₂ = The number of air molecules that fills her lungs at the 10 m depth

Therefore, we have;

P₂/P₁ = n₂/n₁ × V₁/V₂

From V₁ = V₂, we have;

P₂/P₁ = n₂/n₁ × V₁/V₁ = n₂/n₁ × 1

∴ P₂/P₁ = n₂/n₁

P₂/P₁ = 196,482/101,325 ≈ 2

∴ P₂/P₁  = n₂/n₁  ≈ 2

n₂ ≈ 2 × n₁

The number of air molecules that fills her lungs at the 10 m depth, n₂ is approximately 2 times (twice) as many as the number of air molecules at the surface that fills her lungs, n₁

Therefore the correct option is twice as many molecules as she had in a full breath at the surface is required to fill her lungs at the 10 m water depth.

This question involves the concepts of pressure, the equation of state, and the number of molecules.

The number of molecules in hr breathe are "C. twice as many" as compared to the number of molecules in her lungs when she had a full breath at the surface.

According to the equation of state:

[tex]\frac{P_1V_1}{n_1}=\frac{P_2V_2}{n_2}[/tex]

where,

n₁ = no. of molecules in lungs at surface

n₂ = no. of molecules in lungs at depth

P₁ = Pressure at surface = Atmospheric Pressure = 101325 Pa

P₂ = Pressure at depth = 101325 Pa + ρgh

P₂ = 101325 Pa + (1000 kg/m³)(9.81 m/s²)(10 m) = 199425 Pa

V₁ = V₂ = V = Volume of lungs

Therefore,

[tex]\frac{(101325\ Pa)V}{n_1}=\frac{(199425\ Pa)V}{n_2}\\\\[/tex]

n₂ = 2 n₁

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Answer:

(b) 490 N downwards

Explanation:

(b) Formula : w= mg

m is the mass of the object

g is a gravitational constant (9.8)

w= mg

= 50×9.8

= 490 N downwards

Answer:

0.52 V

Explanation:

From Nernst equation;

Ecell =E°cell - 0.0592/n log Q

E°cell = +0.63 V

[Zn2+] =1.0 M

[Pb2+] = 2.0 x 10-4 M

n = 2

Ecell = 0.63 - 0.0592/2 log[1.0/2.0 x 10-4]

Ecell = 0.63 - 0.11

Ecell = 0.52 V

Answer:

T = 0.96 seconds

Explanation:

Given that,

The speed of wave, v = 2.6 m/s

The distance between wave crests, [tex]\lambda=2.5\ m[/tex]

We need to find the period of the wave motion. Let T be the period. So,

[tex]v=\dfrac{\lambda}{T}\\\\T=\dfrac{\lambda}{v}\\\\T=\dfrac{2.5}{2.6}\\\\T=0.96\ s[/tex]

So, the period of the wave motion is equal to 0.96 seconds.

The period of the wave motion is 0.96 seconds.  Using the formula:

v = λ / T

where v is the velocity of the wave, λ is the wavelength and T is the period of the wave.

Given that v = 2.60 m/s, λ = 2.5 m, hence:

2.6 = 2.5/T

T = 0.96 s

The period of the wave motion is 0.96 seconds.

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Answer:

humoidity

Explanation:

Answer:

Efficiency has no physical units  (example   .85 = 85%)

The largest number would be 1 or 100%

An example of efficiency is:  work out/work in

or (work in - work lost to friction) / work in    would be an example of the efficiency of the process

Answer:

6km/hr

Explanation:

3km = 30mins

x(km) = 1hr

1hr = 60 x 60 = 3600secs

30min = 30 x 60 = 1800secs

3 x 3,600/x X 1,800

x = 10,800/1,800

x = 6km/hr

To solve the problem we must know about speed, distance, and time.

We know that speed, distance, and time all are in a relationship with each other. this relationship can be given as,

[tex]\rm{Speed = \dfrac{Distance}{Time}[/tex]

Given to us

A student walks 3 km in 30 minutes.

We know distance can be written as the product of speed and time, therefore,

[tex]\rm Distance = \rm speed \times \rm Time[/tex]

Substituting the values we get,

[tex]\rm 3\ km = Speed \times 0.5\ hour[/tex]

[tex]\rm speed = \dfrac{3\ km}{0.5\ hour}[/tex]

speed = 15 km\h

Hence, the speed of the student is 15 km\hour.

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