write a numerical expression for the verbal expression
seven more than three times eleven

Answer:

18

Step-by-step explanation:

24=8×3

If F=24 when A=8 then F is directly proportional to A•3

Answer:

24,456 is 2

3 is whatever u say

and 1 is 641,086 divided my 41,616

Answer:

explain more

Step-by-step explanation:

Answer:

x=0, y= 0

Step-by-step explanation:

Answer:

a = B

b = E

c = D

d = A

e = C

Step-by-step explanation:

Answer:

you are a very st*pid very f**cking girl d*mb*ss kid

Step-by- step explanation:

First, apply the distributive property:

-30 = 5(x + 1)

-30 = 5x + 5

Substract 5 from both sides:

-30 - 5 = 5x + 5 - 5

-35 = 5x

Divide both sides by 5:

[tex]\mathsf{\dfrac{-35}{5} = \dfrac{5x}{5}}[/tex]

[tex]\large{\boxed{\mathsf{-7 = x}}}[/tex]

‎      

Let's check the answer:

-30 = 5(x + 1)

-30 = 5(-7 + 1)

-30 = 5(-6)

-30 = -30

The answer is correct.

‎      

Answer:

This is your answer .

Have a good day ..

Answer:

a)3 b)6 c)2 d)8 e)9 f)10

look at the first one in a, the denomenator is 2. to make the denomentator 6 you have to multiply it with 3, since you cant change the denomentor without changing the numerator you also multiply it with 3.

Step-by-step explanation: look at the first one in a, the denomentor is 2, to make it 6 you have to multiply it with 3, since you cant change the denomenator without changing the numerator you have to also multiply with 3. repeat with the others. good luck

Answer:

The awnser is 7/4!!!!!!!!

Answer:

13.5

Step-by-step explanation:

Answer:

C (the third one)

Step-by-step explanation:

Answer:

d c a

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

crab crab crab crab crab

Answer:

10 min.

Step-by-step explanation:

Remember d = rt

The distance from bear's house to beehive = 75m and 225m = distance from beehive to piglet's house

Let r = normal rate of speed

The normal time is 300/r without stopping

75/r = time from bear's house to beehive

225/(r + 15) = time from beehive to piglet's house

So, time from beehive to piglet's house + time at beehive + time from bear's house to beehive = normal time without stopping

225/(r + 15) + 2.5 + 75/r = 300/r

225r + 2.5r(r + 15) + 75(r + 15) = 300(r + 15)

225r + 2.5r^2 + 37.5r + 75r + 1125 = 300r + 4500 Let's remove the deceimal by multiplying thru by 10

2250r + 25r^2 + 375r + 750r + 11250 = 3000r + 45000

25r^2 + 3375r + 11250 =  3000r + 45000

25r^2 + 375r - 33750 = 0

25(r^2 + 15r - 1350) = 0

25(r - 30 )(r + 45) = 0

r = 30 or -45     But, the rate cannot be negative, therefore r = 30

The journey takes 300/30 = 10 min.

By solving a system of equations, we will see that the journey takes 10 minutes.

Let's define the variables:

We have that usually, the bear travels 300 meters in the time T, then we have:

S*T = 300m.

And in this situation, the bear also travels in the same time T, then we have:

First, the bear walks 1/4 of the distance, this is:

S*T/4

Then the bear stops for 2.5 minutes

Then the bear walks at 15m/min faster than usual for a time t..

S*T/4 + (S + 15 m/min)*t = 300m

Such that:

t + T/4 + 2.5 min = T.

Then we can write:

t = T - T/4 - 2.5 min = (3/4)*T - 2.5 min

Replacing that we get:

S*T/4 + (S + 15 m/min)*( (3/4)*T - 2.5 min) = 300m

Then we have a system of equations:

S*T = 300m.

S*T/4 + (S + 15 m/min)*( (3/4)*T - 2.5 min) = 300m

To solve this, we isolate one of the variables in one of the equations, I will isolate S in the first one:

S = 300m/T

Now we can replace this in the other equation:

(300m/T)*T/4 + (300m/T + 15 m/min)*( (3/4)*T - 2.5 min) = 300m

300m/4 +  (300m/T + 15 m/min)*( (3/4)*T - 2.5 min) = 300m

Now we can solve this for T.

75m + 225m + (11.25 m/min)*T - (750m/min)/T - 37.5m = 300m

(11.25 m/min)*T - (750m/min)/T - 37.5m = 0m

If we multiply both sides by T, we get:

(11.25 m/min)*T^2 - (750m/min) - 37.5m*T = 0m

This is a quadratic equation, the solutions are given by:

[tex]T = \frac{37.5m \pm \sqrt{(-37.5m)^2 - 4*(11.25 m/min) (-750m/min)} }{2*(11.25 m/min)} \\\\T = (37.5m \pm 187.5m)/( 22.5 m/min)[/tex]

We only care for the positive solution, which is:

T = (37.5 m + 187.5m)/(22.5 m/min) = 10 min

So the journey takes 10 minutes.

If you want to learn more about systems of equations, you can read:

https://brainly.com/question/13729904

Answer:

B) mean: 79.7 median: 81 mode: 84

Answer:

125 km in 100 minutes

Step-by-step explanation:

In order to solve this problem, you have to divide 7.5 by six to find out how fast it goes per minute. BY doing this you are left with 1.25. You then multiply 1.25 by 100 to find out how far it goes in 100 minutes.

Hope this helped :)

Answer:

$170 was the original price.

Step-by-step explanation:

$42.5 is 25% of $170, and $170-$42.5 is $127.5

Answer:

62.208

Step-by-step explanation:

51.84 + 10.368

Answer:

I think if the total amount was $51.84 after tax, then 51.84 x 0.20 = 10.368. $51.84 - 10.368 = $41.472

I think original price was $41.47. I am not sure.

Step-by-step explanation:

Answer:

20...i think...I tried to save BOB :(

Step-by-step explanation:

Its 22 probably <3

R.i.p BOB

Answer:

B

Step-by-step explanation:

The sum to n terms of a geometric series is

[tex]S_{n}[/tex] = [tex]\frac{a(1-r^{n}) }{1-r}[/tex]

where a is the first term and r the common ratio

Here a = 6144 and r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{3072}{6144}[/tex] = [tex]\frac{1}{2}[/tex] , then

[tex]S_{10}[/tex] = [tex]\frac{6144(1-(\frac{1}{2}) ^{10}) }{1-\frac{1}{2} }[/tex]

     = [tex]\frac{6144(1-\frac{1}{1024}) }{\frac{1}{2} }[/tex]

     = 12288(1 - [tex]\frac{1}{1024}[/tex] ) ← distribute

     = 12288 - 12

     = 12276 → B

Answer:

B. 12,276

Step-by-step explanation:

Answer: 2x - 5

Step-by-step explanation: 2x - 5 does not have anything in common, so therefore it can not be simplified. Then 3x - 3 can be divided by 3 because they have that in common. It can’t be 3x - 3 because it still contains one step left to be in its most simplified form.

Answer:

The slope of the graph of plane A is 430, its speed is 430 miles per hour.

The slope of the graph of plane B is 460, its speed is 460 miles per hour.

Plane B is flying faster.

Step-by-step explanation:

The speed of the airplane is the slope of the function, that is, change in distance by change in time. From table, we notice that curve is a first order polynomial, also known that linear function:

Plane A

The slope of the graph of plane A is 430, its speed is 430 miles per hour.

Plane B

The slope of the graph of plane B is:

[tex]v = \frac{1840\,mi-460\,mi}{4\,h-1\,h}[/tex]

[tex]v = 460\,\frac{mi}{h}[/tex]

The slope of the graph of plane B is 460, its speed is 460 miles per hour.

Therefore, plane B is flying faster.

Answer:

289589874000000000000000

=2.89589874*10²³

The 90th percentile of the distribution of x is 100.64.

Given that,

Here we have

[tex]n=16,\mu=100,\sigma^{2}=4[/tex]

Now we requried z-score that has 0.90 area to its left. z-score 1.28 has 0.90 area to its left.

So required 90th percentile is

[tex]z=\frac{\bar{x}-\mu}{\sigma/\sqrt{n}}\\\\1.28=\frac{\bar{x}-100}{2/\sqrt{16}}\\\\\bar{x}=100.64[/tex]

Learn more about the population here: https://brainly.com/question/905400?referrer=searchResults

Given:

[tex]\to n=16\\\\\to \mu=100\\\\ \to \sigma^{2}=4[/tex]

To find:

distribution [tex]\bar{x}=?[/tex]

Solution:

We require a z-score with such a 0.90 area to its left in this case. The area to the left of the z-score 1.28 is 0.90. As a consequence, the required 90th percentile is

Using formula:

[tex]\to z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}\\\\[/tex]

[tex]\to 1.28=\frac{\bar{x}-100}{\frac{2}{\sqrt{16}}}\\\\\to 1.28=\frac{\bar{x}-100}{\frac{2}{\sqrt{4^2}}}\\\\\to 1.28=\frac{\bar{x}-100}{\frac{2}{4}}\\\\\to 1.28=\frac{\bar{x}-100}{\frac{1}{2}}\\\\\to 1.28=\frac{\bar{x}-100}{0.5}\\\\\to 0.64 =\bar{x}-100\\\\\to \bar{x}=100+0.64\\\\\to \bar{x}=100.64\\\\[/tex]

Therefore, the answer is "100.64".

Learn more about the distribution here:

brainly.com/question/10137107

Answer:

ようrもmづっっっっっっっっhsつぽdねあr

Answer:

0

Step-by-step explanation:

Answer:

90 km, N 46° E

Step-by-step explanation:

A jet flies due North for a distance of 50 km and then on a bearing of N 70° E for a further 60 km. Find the distance and bearing of the jet from its starting point.

Look at the diagram I drew of this scenario. You can see the jet flies North for 50 km, and then turns at a 70° angle to fly another 60 km. We want to find the distance from the starting point, SP, to angle C (labeled).

This will be the jet's distance from its starting point.

In order to find the bearing of the jet from its starting point, we will need to find the angle formed between distances b and c, labeled angle A.

The Law of Cosines will allow us to use two known sides and one known angle to solve for the sides opposite of the known angle.

In this case, the known angle is 110° (angle B) so we will use the Law of Cosines respective to B.

Substitute the known values into the equation and solve for b, the distance from the starting point (A) to the endpoint (C).

The distance of the jet from its starting point is 90 km. Now we can use this b value in order to calculate angle A, the bearing of the jet.

The Law of Cosines with respect to A:

Substitute the known values into the equation and solve for A, the bearing from the starting point (clockwise of North).

The bearing of the jet from its starting point is N 46° E. This means that it is facing northeast at an angle of 46° clockwise from the North.

Answer:

m=1= slope

Step-by-step explanation:

here u do rise/ run

and the dots there are helping you to make it

you need to join them by doing rise over run

you go 3 to the right from the dot at the bottom and 3 up

which is 3/3 that equals to 1

if this is not right, please tell me

if it right then your welcome