Write a program that reads in the text file attached, converts all words to lowercase, and prints out all words in the file that begin with that key letter a, the letter b, and so on. Build a dictionary whose keys are the lowercase letters, and whose values are sets of words which begin with that key letter. After processing the data, print the dictionary to the screen in alphabetical order aligned in two fixed sized columns. Such as:
Answers
Answer:
Follows are the code to this question:
def dic_sorted(data):#defining a method print_dic_sorted
s = data.split()#defining a variable that use split method
d = {} #defining a dictionary
alpha = '0123456789abcdefghijklmnopqrstuvwxyz' #defining a variable alpha that hold english alphabets values
for k in alpha:#defining for loop that stores values in the dictionary
d[k]= set()# use dictionary to set value in list
for i in s:# defining for loop to convert value in lower case
i = i.lower() #convert value into lower case by using lower method
a = i[0]# adding value into dictionary
d[a].add(i) # use add method to hold value in dictionary
for k,v in sorted(d.items()):#use for loop to convert value in assending order
if len(d[k])!=0: #use if block to check length of dictionary
print(k,":", sorted(v))#use print to sort value
f_name = 'input.txt'#defining a variable that open file
with open(f_name) as fi:#use open method to read file
data = fi.read() # read file data
dic_sorted(data)#calling method
output:
please find the attached file.
Explanation:
In the code, the "dic_sorted" method is used, which accepts a data variable as a parameter, and inside the method, a split method and an empty dictionary are defined, that converts and holds the value by alphabetical order, for this it defines three for loops.
In the first for loop, it holds a value in the dictionary, and in the second loop it converts a value into the lower case, and in the third loop, it stores the value in its alphabetical order.
Related Questions
What is media framing?
Answers
Answer:
media frame all news items by specific values, facts, and other considerations, and endowing them with greater apparent for making related judgments
Explanation:
The Fast as Light Shipping company charges the following rates. Weight of the item being sent Rate per 100 Miles shipped 2kg or less. $0.25 Over than 2 kg but not more than 10 kg $0.30 Over 10 kg but not more than 20 kg. $0.45 Over 20 kg, but less than 50kg. $1.75 Write a program that asks for the weight of the package, and the distance to be sent. And then displays the charge.
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Answer:
weight = float(input("Enter the weight of the package: "))
distance = float(input("Enter the distance to be sent: "))
weight_charge = 0
if weight <= 2:
weight_charge = 0.25
elif 2 < weight <= 10:
weight_charge = 0.3
elif 10 < weight <= 20:
weight_charge = 0.45
elif 20 < weight <= 50:
weight_charge = 1.75
if int(distance / 100) == distance / 100:
d = int(distance / 100)
else:
d = int(distance / 100) + 1
total_charge = d * weight_charge
print("The charge is $", total_charge)
Explanation:
*The code is in Python.
Ask the user to enter the weight and distance
Check the weight to calculate the weight_cost for 100 miles. If it is smaller than or equal to 2, set the weight_charge as 0.25. If it is greater than 2 and smaller than or equal to 10, set the weight_charge as 0.3. If it is greater than 10 and smaller than or equal to 20, set the weight_charge as 0.45. If it is greater than 20 and smaller than or equal to 50, set the weight_charge as 1.75
Since those charges are per 100 miles, you need to consider the distance to find the total_charge. If the int(distance / 100) is equal to (distance / 100), you set the d as int(distance / 100). Otherwise, you set the d as int(distance / 100) + 1. For example, if the distance is 400 miles, you need to multiply the weight_charge by 4, int(400/100) = 4. However, if the distance is 410, you get the int(400/100) = 4, and then add 1 to the d for the extra 10 miles.
Calculate the total_charge, multiply d by weight_charge
Print the total_charge
Consider an entity set Person, with attributes social security number (ssn), name, nickname, address, and date of birth(dob). Assume that the following business rules hold: (1) no two persons have the same ssn; (2) no two persons have he same combination of name, address and dob. Further, assume that all persons have an ssn, a name and a dob, but that some persons might not have a nickname nor an address.
A) List all candidate keys and all their corresponding superkeys for this relation.
B) Write an appropriate create table statement that defines this entity set.
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Answer:
[tex]\pi[/tex]
Explanation:
Consider the following method.
public int locate(String str, String oneLetter)
{
int j = 0;
while(j < str.length() && str.substring(j, j+1).compareTo*oneLetter < 0)
{
j++;
}
return j;
}
Which of the following must be true when the while loop terminates?
a. j == str.length()
b. str.substring(j, j+1) >= 0
c. j <= str.length() || str.substring(j, j+1).compareTo(oneLetter) > 0
d. j == str.length() || str.substring(j, j+1).compareTo(oneLetter) >= 0
e. j == str.length() && str.substring(j, j+1).compareTo(oneLetter) >= 0
Answers
Answer:
All
Explanation:
From the available options given in the question, once the while loop terminates any of the provided answers could be correct. This is because the arguments passed to the while loop indicate two different argument which both have to be true in order for the loop to continue. All of the provided options have either one or both of the arguments as false which would break the while loop. Even options a. and b. are included because both would indicate a false statement.
During TCP/IP communications between two network hosts, information is encapsulated on the sending host and decapsulated on the receiving host using the OSI model. Match the information format with the appropriate layer of the OSI model.
a. Packets
b. Segments
c. Bits
d. Frames
1. Session Layer
2. Transport Layer
3. Network Layer
4. Data Link Layer
5. Physical Layer
Answers
Answer:
a. Packets - Network layer
b. Segments - Transport layer
c. Bits - Physical layer
d. Frames - Data link layer
Explanation:
When TCP/IP protocols are used for communication between two network hosts, there is a process of coding and decoding also called encapsulation and decapsulation.
This ensures the information is not accessible by other parties except the two hosts involved.
Operating Systems Interconnected model (OSI) is used to standardise communication in a computing system.
There are 7 layers used in the OSI model:
1. Session Layer
2. Transport Layer
3. Network Layer
4. Data Link Layer
5. Physical Layer
6. Presentation layer
7. Application layer
The information formats given are matched as
a. Packets - Network layer
b. Segments - Transport layer
c. Bits - Physical layer
d. Frames - Data link layer
b) Develop a truth table for expression AB+ C.
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What is the relationship between an object and class in an OOP program?
The object contains classes.
The object and class are the same thing.
The object is used to create a class.
The object in a program is called a class.
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Answer:
D. The object in a program is called a class.
Explanation:
Java is a object oriented and class-based programming language. It was developed by Sun Microsystems on the 23rd of May, 1995. Java was designed by a software engineer called James Gosling and it is originally owned by Oracle.
In object-oriented programming (OOP) language, an object class represents the superclass of every other classes when using a programming language such as Java. The superclass is more or less like a general class in an inheritance hierarchy. Thus, a subclass can inherit the variables or methods of the superclass.
Basically, all instance variables that have been used or declared in any superclass would be present in its subclass object.
Hence, the relationship between an object and class in an OOP program is that the object in a program is called a class.
For example, if you declare a class named dog, the objects would include barking, color, size, breed, age, etc. because they are an instance of a class and as such would execute a method defined in the class.
In what way can an employee demonstrate commitment?
Answers
Answer:
Come to work on time ready to work. Always work above and beyond. ... Come to work on time, follow all rules, do not talk about people, and be positive get along with coworkers.
Explanation:
An employee can demonstrate commitment to their job and organization in several ways.
First and foremost, they show dedication and enthusiasm by consistently meeting deadlines, going above and beyond to achieve goals, and taking ownership of their responsibilities.
Being punctual and reliable also reflects commitment. Employees who actively participate in team efforts, support colleagues, and offer innovative ideas exhibit their dedication to the company's success.
Demonstrating a willingness to learn and grow by seeking additional training or taking on new challenges further showcases commitment.
Ultimately, a committed employee is driven by a genuine passion for their work, a strong work ethic, and a sense of loyalty to their organization's mission and values.
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most of the answers for this test is wrong.
Answers
Explanation:
In this programming assignment, you will write a simple program in C that outputs one string. This assignment is mainly to help you get accustomed to submitting your programming assignments here in zyBooks. Write a C program using vim that does the following. Ask for an integer input from the user. Do not print any prompt for input. If the number is divisible by 3, print the message CS If the number is divisible by 5, print the message 1714 If the number is divisible by both 3
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Answer:
In C:
#include <stdio.h>
int main() {
int mynum;
scanf("%d", &mynum);
if(mynum%3 == 0 && mynum%5 != 0){
printf("CS"); }
else if(mynum%5 == 0 && mynum%3 != 0){
printf("1714"); }
else if(mynum%3 == 0 && mynum%5 == 0){
printf("CS1714"); }
else {
printf("ERROR"); }
return 0;
}
Explanation:
This declares mynum as integer
int mynum;
This gets user input
scanf("%d", &mynum);
This condition checks if mynum is divided by 3. It prints CS, if true
if(mynum%3 == 0 && mynum%5 != 0){
printf("CS"); }
This condition checks if mynum is divided by 5. It prints 1714, if true
else if(mynum%5 == 0 && mynum%3 != 0){
printf("1714"); }
This condition checks if mynum is divided by 3 and 5. It prints CS1714, if true
else if(mynum%3 == 0 && mynum%5 == 0){
printf("CS1714"); }
This condition checks if num cannot be divided by 3 and 5. It prints ERROR, if true
else {
printf("ERROR"); }
Mark is a stockbroker in New York City. He recently asked you to develop a program for his company. He is looking for a program that will calculate how much each person will pay for stocks. The amount that the user will pay is based on:
The number of stocks the Person wants * The current stock price * 20% commission rate.
He hopes that the program will show the customer’s name, the Stock name, and the final cost.
The Program will need to do the following:
Take in the customer’s name.
Take in the stock name.
Take in the number of stocks the customer wants to buy.
Take in the current stock price.
Calculate and display the amount that each user will pay.
A good example of output would be:
May Lou
you wish to buy stocks from APPL
the final cost is $2698.90
Answers
ok sorry i cant help u with this
when you look directly at a camera lens, it may seen like there is only one lens, but entering light actually passes through a series of lenses, or_____, that bend the light and send it on its way to be focused on the film or digital. chip
Frame
Optics
Flash
SD cARD
Answers
Answer:
The answer should be optics...
Explanation:
If aa person is known to have look at a camera lens straight and light passes via a number of lenses, or Optics.
What is Optics?This is known to be an aspect of physics that looks at the attributes and properties of light, such as its relationship with matter, etc.
Therefore, If a person is known to have look at a camera lens straight and light passes via a number of lenses, or Optics.
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You can expect to see
Answers
Answer:
what?ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
Answer:
D
Explanation:
You can expect to see ________.
A. STOP signs or traffic lights on limited access highways
B. only traffic lights on limited access highways
C. only STOP signs on limited access highways
D. no STOP signs or traffic lights on limited access highways