Write a word phrase that represents x + 5.

Answers

Answer 1

Answer:

5 added to a number, x.

Step-by-step explanation:

I phrased it like other ones I saw before so... :) (Also if you ask someone to write it, I'm sure they'd get x+5)

Answer 2

Answer:5 added to a number, x

Step-by-step explanation:


Related Questions

simplify the expression
[tex]8p + 10 + - 2p - 1 + 10[/tex]

Answers

Answer:

6p+19

Step-by-step explanation:

combine like terms:

8p+10+-2p+-1+10

(8p+-2p)+(10+-1+10)

6p+19

HOPE THIS HELPS!!!!!!:)

Help me ASAP for this question the picture are the answers
If triangle BAT is similar to triangle ROD (ABAT AROD), which of the following statements is incorrect?

Answers

Answer:

I'm pretty sure it's the last one that is incorrect

Step-by-step explanation:

Answer:

The first one - “line segment TA is congruent to line segment DO” is incorrect

Step-by-step explanation:

Since the triangles are similar, the angle measurements would be the same (congruent), but the line segments are are only similar, not congruent, as they have different lengths. So the first statement is incorrect.  

Find the path of the numbers from the upper left corner to the bottom right corner. The sum of the numbers must be equal to the number at the exit arrow. You are allowed to move either down or to the right only.

Answers

Answer:

8, 11, 19, 1, 6, 18, 3

Step-by-step explanation:

8+11+19+1+6+18+3=66

Solve the inequality $2x - 5 \le -x +12$. Give your answer as an interval.

Answers

Answer:

[tex]$\left(-\infty, \frac{17}{3} \right]$[/tex]

Step-by-step explanation:

[tex]2x - 5 \le -x +12[/tex]

[tex]2x - 5 +5\le -x +12+5[/tex]

[tex]2x\le -x+17[/tex]

[tex]3x \le17[/tex]

[tex]$x \le \frac{17}{3} $[/tex]

We have

[tex]$\{x \in \mathbb{R}:x \le \frac{17}{3} \}$[/tex]

Interval notation:

[tex]$\left(-\infty, \frac{17}{3} \right]$[/tex]

5. a) A business company made a profit of Rs 24,00,000 in the last year. The management decided to distribute 20 % bonus from the profit to its 30 employees.

( i ) Find the bonus amount received by each employee.

(ii) By what percent should the bonus be increased so that each employee can receive Rs 20,000?

(iii) What should be the profit of the company so that it can provide Rs 20,000 to each employee at 20 % bonus?

Answers

Answer:

a) = Rs 16000

b) = 5%

c) = Rs 30,000,000

10% = 24,000,00/10 = Rs 240,000

20% = 240,000 x 2 = Rs 480,000

480,000/30 = Rs 16000

b) The bonus percentage needs to be increased by 5%

explanation:

Since every worker needs Rs 20000 we need to times it by 30

20000 x 30 = Rs 600,000

600,000 - 480,000 = Rs 120,000

Now we need to find the percentage of Rs 120,000

10% = Rs 240,000

5% = 240,000 divide by 2 = Rs 120,000

This is the best I can do for now please let me know if you understood the answer!

Answer:

1.Rs.16000

2.Bonus rate:25%

3.profit:Rs.3000000

Step-by-step explanation:

Case 1

Profit=Rs.2400000

Bonus Rate:20%

No.of employees =30

Now,

Bonus = (Bonus Rate of Profit) / no. Of employees

= 20% of Rs.2400000 / 30

= Rs. 16000

Case 2

Bonus=Rs.20000

Profit=Rs.2400000

Bonus rate=?

Now,

Bonus=bonus rate of profit / no. Of employees

Or,Rs. 20000 = Bonus rate × Rs. 2400000/30

Or, Rs. 20000=Bonus rate × Rs. 80000

Or,Rs.20000/Rs.80000 = Bonus rate

Bonus rate = 1/4=25%

Case 3

Bonus=Rs.20000

Bonus Rate = 20%

Now,

Bonus = bonus Rate of profit / no.of employees

Or, Rs. 20000 = 20% × Profit / 30

Or, Rs. 20000 × 30 / 0.2 = profit

Profit= Rs. 3000000

I hope it helped you

A sample of 120 local residents reveals that 8 have a post office box for receiving mail. What is the relative frequency that a local resident does not have a post office box for receiving mail?

Answers

Answer:

[tex]\frac{1}{15}[/tex] or 6.67%

Step-by-step explanation:

In practice, the relative frequency of an event happening is the same as the probability that that event happened. In other words, the terms "relative frequency" and "probability" can be used interchangeably.

Now, the probability P(A) of an event A happening is given by;

P(A) = [tex]\frac{number-of-outcomes-in-the-event-A}{number-of-outcomes-in-the-sample-space}[/tex]

From the question;

The event A is the situation of local residents having a post office box. Therefore the;

number-of-outcomes-in-the-event-A = 8   [since only 8 of the local residents have a post office box]

number-of-outcomes-in-the-sample-space = 120 [since there are altogether 120 local residents]

Therefore,

P(A) = [tex]\frac{8}{120}[/tex]

P(A) = [tex]\frac{1}{15}[/tex]

The relative frequency that a local resident does not have a post office box for receiving a mail is therefore, [tex]\frac{1}{15}[/tex]

PS: Sometimes it is much more convenient to express relative frequencies as percentage. Therefore, the result above expressed in percentage gives:

[tex]\frac{1}{15} * 100%[/tex]% = 6.67%

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