Write an equation for each graph

Answer:

F. 100 <= u <= 110.

Step-by-step explanation:

The domain of a function is the set of all possible values of the independent variable (u) for which the function is defined.

In this case, the number of uniforms bought (u) must be at least 100 but not more than 110, since there are at least 100 members but not more than 110 members in the marching band.

Therefore, the domain of the function for this situation is:

100 <= u <= 110

So, the answer is F. 100 <= u <= 110.

Answer:

F: 100 [tex]\leq[/tex] u [tex]\leq[/tex] 110

Step-by-step explanation:

Answer: The best i could come up with was the BLUE figure

Step-by-step explanation:

Sorry if it is wrong

Answer:

12

Step-by-step explanation:

-3(b - 5) + 7a - (9 - a) ^6                   a = 7 and b = -4

-3(-4 - 5) + 7(7) - (9 - 7)^6

= -3(-9) + 49 - (2)^6

= 27 + 49 - (64)

= 27 + 49 - 64

= 76 - 64

= 12      

There are 126 ways in which four people can be chosen to stand up out of nine people sitting in chairs.

We have,
The combination formula is:

C(n, r) = n! / (r! (n-r)!)

In this case,

n = 9 (total number of people) and r = 4 (number of people to be chosen to stand up).

Step 1: Calculate n! (9!): 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 362,880

Step 2: Calculate r! (4!): 4 x 3 x 2 x 1 = 24

Step 3: Calculate (n-r)! (5!): 5 x 4 x 3 x 2 x 1 = 120

Step 4: Plug these values into the combination formula: C(9, 4) = 362,880 / (24 * 120)

Step 5: Calculate the result: C(9, 4) = 362,880 / 2,880 = 126

Thus,

There are 126 ways in which four people can be chosen to stand up out of nine people sitting in chairs.

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Approximately 100 cells will contain values less than or equal to 0.1.
The RAND() function in Excel returns a pseudo-random number between 0 and 1. If you enter this function into 1000 cells, approximately 10% of these cells (0.1 probability) will contain values less than or equal to 0.1. Therefore, a number relatively close to 100 cells will have values less than or equal to 0.1.

The RAND() function is a built-in function in Excel that generates a random decimal number between 0 and 1. Each time the function is used, a new random number is generated.

The syntax for using the RAND() function is: =RAND() The function takes no arguments and simply returns a random decimal number.

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We can say that approximately 95% of the total snowfall per year in Laytonville falls between 71 inches (99 - 2*14) and 127 inches (99 + 2*14).

According to the empirical rule, for a normal distribution, approximately 68% of the data falls within 1 standard deviation of the mean, 95% falls within 2 standard deviations, and 99.7% falls within 3 standard deviations.

Using this rule, we can calculate that the upper limit of 1 standard deviation above the mean is:

99 + 14 = 113 inches

And the upper limit of 2 standard deviations above the mean is:

99 + (2*14) = 127 inches



To answer the specific question, the probability that in a randomly selected year, the snowfall was less than 127 inches is approximately 95%. This can be interpreted as saying that in 95 out of 100 years, the total snowfall in Laytonville is less than 127 inches. As a percentage, this is rounded to 95.00%.

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Minimum score required for the scholarship = 605

To find the minimum score required for the scholarship, we need to find the score that corresponds to the top 6% of scores.

First, we need to find the z-score that corresponds to the top 6%. We can use the standard normal distribution table or calculator to find this.

Using the calculator, we can input:

normalcdf(0.94,9999)

This gives us the area under the curve to the right of z=0.94, which is the z-score that corresponds to the top 6%.

We get: 0.1664

This means that the top 6% of scores correspond to z-scores greater than 0.94.

Now we can use the z-score formula:

z = (x - μ) / σ

where x is the score we want to find, μ is the mean (489), and σ is the standard deviation (112).

Rearranging this formula, we get:

x = z * σ + μ

Substituting in the values we have:

x = 0.94 * 112 + 489

x = 605.08

Rounding this to the nearest whole number, we get:

Minimum score required for the scholarship = 605

To find the minimum score required for the scholarship, we will use the given information about the SAT writing scores being normally distributed with a mean (µ) of 489 and a standard deviation (σ) of 112. We need to find the score that corresponds to the top 6%.

Step 1: Convert the percentage to a decimal. Top 6% = 0.06.

Step 2: Find the Z-score that corresponds to the top 6%. This means we want to find the Z-score that has 1 - 0.06 = 0.94 area to the left. Using a Z-table, you can find that the Z-score is approximately 1.555.

Step 3: Use the Z-score formula to find the minimum score (X):

Z = (X - µ) / σ

1.555 = (X - 489) / 112

Step 4: Solve for X:

1.555 * 112 = X - 489

174.16 = X - 489

X = 663.16

Round to the nearest whole number: X = 663.

So, the minimum score required for the scholarship is 663.

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Answer: 88

Step-by-step explanation:

First, separate into familiar shapes

The area of the triangles at each side is 10 because the formula is length times times width divided by 2, when you plug the numbers in, 5 times 4 divided by two, times 2 because there are two triangles which equals 20.

That leaves the rectangle and the formula for the area of a rectangle is length times width, 17 times 4 which equals 68.

Add them, 20 plus 68 equals 88.

You'll obtain the mean square between and the mean square within, which are crucial for further statistical analyses such as the F-test or ANOVA. To calculate the mean square between and the mean square within after finding the between-group sum of squares and the within-group sum of squares, you can follow these steps:

1. Determine the degrees of freedom between groups (df_between):

Subtract 1 from the number of groups.
2. Determine the degrees of freedom within groups (df_within):

Subtract the number of groups from the total number of observations.
3. Calculate the mean square between (MS_between):

Divide the between-group sum of squares by the degrees of freedom between groups (MS_between = between-group sum of squares / df_between).
4. Calculate the mean square within (MS_within):

Divide the within-group sum of squares by the degrees of freedom within groups (MS_within = within-group sum of squares / df_within).

By following these steps, you'll obtain the mean square between and the mean square within, which are crucial for further statistical analyses such as the F-test or ANOVA.

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We find LM: LM = 4x = 4 * 2 = 8 So, LM is 8 units long.  To solve this problem, we need to use the fact that the opposite sides of a parallelogram are equal in length. Let's start by calling the length of LM "4x", since the ratio of LM to MN is 4:3. That means the length of MN is "3x".

The perimeter of LMNO is the sum of the lengths of all four sides, so we can write an equation:

4x + 3x + 4x + 3x = 28

Simplifying this equation, we get:

14x = 28

Dividing both sides by 14, we find that:

x = 2

Now we can substitute this value of x back into our expressions for the lengths of LM and MN:

LM = 4x = 4(2) = 8

MN = 3x = 3(2) = 6

Since the opposite sides of a parallelogram are equal in length, the other two sides must also have lengths of 8 and 6. Therefore, the perimeter of LMNO is:

8 + 6 + 8 + 6 = 28

So we have found that LM has a length of 8.

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To find E, we take half of the width of the confidence interval, which is (0.55 - 0.27)/2 = 0.14. The confidence interval is p ± E, which is 0.41 ± 0.14.

The confidence interval 0.27 less than p less than 0.55 can be expressed in the form of p with a hat on top plus or minus E as p ± E, where p is the point estimate and E is the margin of error. To find p, we take the average of the upper and lower bounds of the confidence interval, which gives us (0.27 + 0.55)/2 = 0.41. To find E, we take half of the width of the confidence interval, which is (0.55 - 0.27)/2 = 0.14. Therefore, the confidence interval can be expressed as p ± E, or 0.41 ± 0.14.

To express the given confidence interval 0.27 < p < 0.55 in the form of p ± E, follow these steps:

Step 1: Find the midpoint of the interval, which represents the sample proportion p.
Midpoint = (Lower Limit + Upper Limit) / 2
Midpoint = (0.27 + 0.55) / 2 = 0.41

So, p = 0.41.

Step 2: Calculate the margin of error (E) by subtracting the lower limit from the midpoint or the upper limit from the midpoint.
E = Midpoint - Lower Limit = 0.41 - 0.27 = 0.14

Step 3: Express the confidence interval in the desired format.
The confidence interval is p ± E, which is 0.41 ± 0.14.

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well, is a kite so it has two congruent triangles above and two congruent triangles below, for the perimeter is simply the hypotenuse of all four right-triangles.

[tex]\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2\implies c=\sqrt{a^2 + o^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{above}\\ a=\stackrel{adjacent}{4}\\ o=\stackrel{opposite}{3} \end{cases} \\\\\\ above=\sqrt{ 4^2 + 3^2}\implies above=\sqrt{ 16 + 9 } \implies above=\sqrt{ 25 }\implies above=5 \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2\implies c=\sqrt{a^2 + o^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{below}\\ a=\stackrel{adjacent}{3}\\ o=\stackrel{opposite}{7} \end{cases} \\\\\\ below=\sqrt{ 3^2 + 7^2}\implies below=\sqrt{ 9 + 49 } \implies below=\sqrt{ 58 } \\\\[-0.35em] ~\dotfill[/tex]

[tex]5~~ + ~~5~~ + ~~\sqrt{58}~~ + ~~\sqrt{58} ~~ \approx ~~ \text{\LARGE 25.2}[/tex]

In scientific practice, we often use statistical inference to make conclusions about a population based on a sample. The use of confidence intervals is one method of making these inferences. A single 95% confidence interval can be interpreted as follows: we are 95% confident that our interval is one that contains the true population parameter.

This means that if we were to repeat the study many times, we would expect the true population parameter to be within our interval 95% of the time.
It is important to note that this interpretation assumes that the sample was selected randomly and that the assumptions for the statistical test used to construct the interval were met. Additionally, it is important to recognize that the interval is not a guarantee of the true population parameter being within it, but rather a range of values that is likely to contain the true parameter.

Overall, a single 95% confidence interval is a useful tool for making inferences about a population based on a sample, and it provides a range of values that we can be reasonably confident contains the true parameter.

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The solution to the questions on algebra word problem are:

a) 10000 - x²

b) The area of the parking lot decreases

c) when x = 21, the area is 9559 ft²

a) Since the area of the new parking lot is expressed as:

(100 - x)(100 + x)

Expanding this gives:

10000 - x²

b) The original area is 10,000 ft²

The new area is 10000 - x²

Thus:

10,000 - (10000 - x²) = x²

Thus, the area of the parking lot decreases

c) when x = 21, we have:

10000 - 21² = 9559 ft²

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If the midpoint is (-4, 7) then the second end point is (-11, 11).

The formula for calculating the midpoint of coordinates is expressed as:

M(x,y) = {(x₁+x₂/2, y₁+y₂/2}

Given the following coordinate points

M(x, y) = (-4, 7)

(x₁, y₁) = (3, 8)

Substitute into the formula to have:

-4 = x₂+3/2

x₂ + 3 = -8

x₂ = -11

Similarly

7 = y₂+3/2

y₂ + 3 = 14

y₂ = 11

Hence the other end point of if the midpoint is (-4, 7) is (-11, 11)

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Answer:

214 inches

Step-by-step explanation:

Arc length = 2πr(∅/360) = 2π(48)(255/360) = 68π = 213.63 ≈ 214 inches

The quadratic function is C(t) = - t² + 5.

We know the equation of the parabola will be given as,

y = a(x - h)² + k

From the table, the coordinate of the vertex will be at (0, 5).

So, the equation can be

C(t) = a(t - 0)² + 5

C(t) = at² + 5

Since, the equation is passing through the point (1, 4)

4 = a (1²) + 5

4 = a + 5

a = - 1

Thus, the required equation is C(t) = - t² + 5.

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The other endpoint of the line segment with mid-point as( -4,7 ) and end point (3,8) is  (-11, 6).

The midpoint formula is expressed as:

Midpoint = [(x₁ + x₂)/2, (y₁ + y₂)/2]

Where (x₁, y₁) and (x₂, y₂) are the coordinates of the two endpoints of the line segment.

Given that the midpoint is (-4, 7) and one endpoint is (3, 8).

Let the other endpoint be (x, y). T

Hence, we can set up two equations:

(x + 3) / 2 = -4 (equation for x-coordinates)

(y + 8) / 2 = 7 (equation for y-coordinates)

Solving for x and y, we get:

x + 3 = -8

x = -8 - 3

x = -11

For y:

y + 8 = 14

y = 14 - 8

y = 6

Therefore, the other endpoint is (-11, 6).

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In 3rd part, option (c) is not a function. In the 4th part, option (b) is not a function. In the 5th part, option (d) is the parent function for the given y.

For 3rd part,

We have to identify that which relation is not a function. A relation is said to be a function if all the elements of one set have a unique image in another set. In our question, as we can see in option (c), element 1 is connected to 2 elements which are 1 and -1. Element 4 is also connected to two elements which are 2 and -1. Therefore, it is not a function. All the other options are functions as each element has a unique image.

For 4th part,

If we observe option (a), we will get one value of y on equating x to any value. In option (b), y = [tex]\pm\sqrt{36 - x^{2}}[/tex], if we equate x to something, we will get two values of y. In options (c) and (d) also, we will get a unique value of y. Therefore, option (b) is not a function as we do not get a unique image for y.

For 5th part,

y = [tex]3\sqrt{x - 2} + 7[/tex]

To identify the parent function, we strip away all the arithmetic values to leave behind one higher-order operation on just x. Therefore, we will first strip away 3 which is a multiple, and 7 which is being added. Then, we will strip away 2. Now, we are left with just one operation on x which is [tex]\sqrt{x}[/tex]. Therefore, option (d) is the parent function for the given function.

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The number of mice added to the population each year is approximately 15,721. In this situation, we have a population of mice that is growing exponentially with a growth rate (r) of 2.0 and a current population size (n) of 2,500 individuals.

To calculate the number of mice added to the population each year, we can use the formula for exponential growth:

N = N0e^(rt)

Where:
N0 = initial population size
N = final population size
r = growth rate
t = time

In this case, we know that:
N0 = 2,500
r = 2.0 (since it is given as the growth rate)
t = 1 year (since we want to find the number of mice added each year)

So, we can plug these values into the formula and solve for N:

N = 2,500e^(2.0*1)
N = 2,500e^2
N ≈ 18,221

Therefore, the number of mice added to the population each year is approximately 18,221 - 2,500 = 15,721.

It's important to note that the growth rate is a key factor in determining the rate of population growth. A higher growth rate means that the population will increase at a faster rate, while a lower growth rate means that the population will increase more slowly. In this case, a growth rate of 2.0 is relatively high, which is why the population is growing so quickly. Understanding the growth rate can help us make predictions about how a population will change over time and how it might be impacted by various factors such as disease, predation, or changes in habitat.

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The correct conclusion is:

Fail to reject the null hypothesis.

There is not sufficient evidence to warrant rejection of the claim that absences occur on different weekdays with the same frequency.

Option C is the correct answer.

We have,

To test the claim that employee absences occur on different weekdays with the same frequencies, we need to use the chi-squared goodness of fit test.

First, we calculate the expected frequencies for each weekday assuming they have the same frequency.

Since there are 5 weekdays, we divide the total number of absences (130) by 5 to get the expected frequency of 26 for each weekday.

Using the formula for the chi-squared goodness of fit test, we can calculate the test statistic as follows:

χ² = Σ (O - E)² / E

where O is the observed frequency and E is the expected frequency.

Using the sample data, we get:

χ² = [(37-26)^2/26] + [(15-26)^2/26] + [(12-26)^2/26] + [(23-26)^2/26] + [(43-26)^2/26]

χ² = 8.658

The degrees of freedom for this test is (5 - 1) = 4, since we have 5 weekdays and one parameter (the frequency) has been estimated.

Using a chi-squared distribution table with 4 degrees of freedom and a significance level of 0.05, we find the critical value to be 9.488.

Since the test statistic (8.658) is less than the critical value (9.488), we fail to reject the null hypothesis.

Thus,

The correct conclusion is:

Fail to reject the null hypothesis.

There is not sufficient evidence to warrant rejection of the claim that absences occur on different weekdays with the same frequency.

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The expression that represents the circles in the model is 4x

From the question, we have the following parameters that can be used in our computation:

The circles in the model

Represent each circle with x

Where

Using the above as a guide, we have the following:

When the above expressions are combined, we have

+9x - 5x

Evaluating the above expression

So, we have

4x

Hence, the solution is 4x

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The image that shows 1/6 divided by 3 would have a result of 1/18

From the question, we have the following parameters that can be used in our computation:

1/6 divided by 3

The images are not given

However, the expression can be solved

So, we have

1/6 divided by 3

Express as products

1/6 divided by 3 = 1/6 * 1/3

Evaluate the products

1/6 divided by 3 = 1/18

Hence, the result is 1/18

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To write the equation of a line passing through the point (8,4) and parallel to 8x-y=6, we need to first find the slope of the given line. We can rewrite the given line in slope-intercept form y=8x-6, where the slope is 8.

Since the new line is parallel to the given line, it will have the same slope of 8. Now we can use the point-slope form of the equation of a line:

y - y1 = m(x - x1)

where (x1, y1) is the given point and m is the slope.

Substituting in the values, we get:

y - 4 = 8(x - 8)

Expanding and simplifying, we get:

y = 8x - 60

This is the equation of the line in slope-intercept form.

To convert it to standard form, we move all the variables to one side and simplify:

-8x + y = -60

This is the equation of the line in standard form.

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Yes, it is possible to have a nonzero q-module (q-vector space) with finitely many elements. A nonzero q-module has at least two elements, which distinguishes it from the trivial module containing only the zero element. When the module has finitely many elements, it is referred to as a finite q-module.

In a q-module, the elements are combined through operations that follow the module's underlying ring or field structure. For instance, in a q-vector space, the operations are defined over a field, like the rational numbers (Q) or real numbers (R). These operations adhere to certain rules such as associativity, commutativity, and distributivity.

An example of a finite q-module is the integers modulo n (Z/nZ) as a Z-module, where n is a positive integer. In this case, there are n elements (0, 1, 2, ..., n-1), which form a finite set. The operations of addition and scalar multiplication are performed modulo n, making this a finite module.

In summary, it is possible to have a nonzero q-module with finitely many elements, known as a finite q-module. The operations within the module follow the rules set by its underlying ring or field, allowing for a structured combination of its elements.

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The value of the angle B is  56. 64 degrees

Using the law of sines, we have;

sin A/a = sin B/b

Given that the parameters are;

Now, substitute the values, we have;

sin 110/225 = sin B/200

cross multiply the values, we get;

sin B = sin 110(200)/225

find the values

sin B = 0.9396(200)/225

Multiply the values

sin B = 187. 93/225

sin B = 0. 8352

Find the inverse

B = 56. 64 degrees

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Each angle is 53 degrees, 32 degrees, and 95 degrees.

We know that,

A triangle is a three-sided polygon that is sometimes (but not always) referred to as the trigon. Every triangle has three sides and three angles, which may or may not be the same. Triangles are three-sided polygons with three vertices. The angles of the triangle are formed by connecting the three sides end to end at a point. The total of the triangle's three angles equals 180 degrees. A triangle is a three-sided polygon with three vertices. The angle produced within the triangle is 180 degrees. It signifies that the total of a triangle's internal angles equals 180°.

Here,

The sum of angles of triangle is 180 degrees.

4x+5+7x+11+2x+8=180

13x+24=180

13x=156

x=12

T=4x+5

=4*12+5

=53 degree

U=2x+8

=2*12+8

=32 degree

V=7x+11

=7*12+11

=95 degree

The measure of each angle is 53 degree, 32 degree and 95 degree.

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When a cylinder is sliced in such a way that the plane passes through the cylinder in a slanted direction without going through either base, the resulting cross section is an elliptical shape.

To visualize this, imagine a cylinder with circular bases. When a plane intersects the cylinder in a slanted direction, it cuts through the curved surface of the cylinder, creating an elliptical cross section.

The exact shape and size of the elliptical cross section will depend on the angle at which the plane intersects the cylinder and the specific orientation of the cylinder. The major axis of the resulting ellipse will be parallel to the slanted direction of the plane, while the minor axis will be perpendicular to it.

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Answer:

AB = 10

CD = 10

AD = 29

BC = 29

Step-by-step explanation:

perimeter = AD + BC + AB + CD

AD + BC + AB + CD = 78

Let AB = x

Opposite sides of a parallelogram are congruent.

AB = CD = x

AD = BC = 2x + 9

2x + 9 + 2x + 9 + x + x = 78

6x + 18 = 78

6x = 60

x = 10

2x + 9 = 2(10) + 9 = 29

AB = 10

CD = 10

AD = 29

BC = 29

Answer:

AB = 10 CD = 10 AD = 29 BC = 29

Step-by-step explanation:

I did the test

Hope this helps :)