Answer:
y = sin(4(x+π/8)) + 1
Step-by-step explanation:
For a trigonometric equation of form
y = Asin(B(x+C)) + D,
the amplitude is A, the period is 2π/B, the phase shift is C, and the vertical shift is D (shifts are relative to sin(x) = y)
First, the amplitude is the distance from the center to a top/bottom point (also known as a peak/trough respectively). The center of the function given is at y=1, and the top is at y=2, Therefore, 2-1= 1 is our amplitude.
Next, the period is the distance between one peak to the next closest peak, or any matching point to the next matching point. One peak of this function is at x=0 and another is at x= π/2, so the period is (π/2 - 0) = π/2. The period is equal to 2π/B, so
2π/B = π/2
multiply both sides by b to remove a denominator
2π = π/2 * B
divide both sides by π
2 = 1/2 * B
multiply both sides by 2 to isolate b
4 = B
After that, the phase shift is the horizontal shift from sin(x). In the base function sin(x), one center is at x=0. However, on the graph, the closest centers to x=0 are at x=± π/8. Therefore, π/8 is the phase shift.
Finally, the vertical shift is how far the function is shifted vertically from sin(x). In sin(x), the centers are at y=0. In the function given, the centers are at y=1, symbolizing a vertical shift of 1.
Our function is therefore
y = Asin(B(x+C)) + D
A = 1
B = 4
C = π/8
D = 1
y = sin(4(x+π/8)) + 1
Answer(s):
[tex]\displaystyle y = sin\:(4x + \frac{\pi}{2}) + 1 \\ y = -cos\:(4x \pm \pi) + 1 \\ y = cos\:4x + 1[/tex]
Explanation:
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{8}} \hookrightarrow \frac{-\frac{\pi}{2}}{4} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 1[/tex]
OR
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 1[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = sin\:4x + 1,[/tex] in which you need to replase “cosine” with “sine”, then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{8}\:unit[/tex] to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACK [tex]\displaystyle \frac{\pi}{8}\:unit,[/tex] which means the C-term will be negative, and perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{8}} = \frac{-\frac{\pi}{2}}{4}.[/tex] So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = sin\:(4x + \frac{\pi}{2}) + 1.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [0, 2],[/tex] from there to [tex]\displaystyle [\frac{\pi}{2}, 2],[/tex] they are obviously [tex]\displaystyle \frac{\pi}{2}\:unit[/tex] apart, telling you that the period of the graph is [tex]\displaystyle \frac{\pi}{2}.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex] in which each crest is extended one unit beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
SOVE, REDUCE TO LOWEST TEERMS SIMPLIFY IMPROPER FRACTIONSAS MIXED FRACTIONS
Find the missing probability.
P(A) = 23,P(An B)= P(B|A) =?
Answer:
the formular is
p(B/A)=P(AnB)/P(A)
so the missing probability is:-
P(AnB)=P(B/A)×23
And the other missing probablility is:-
p(B/A)=P(AnB)/23
change 4 5/9 from a mixed number to an improper fraction
Step-by-step explanation:
Hello, there!!
The answer would be 41/9.
The reason for above answer is to change any mixed fraction into improper fraction we should follow a simple step:
multiply the denominator with whole number.Add the answer (after mutiplied ).look here,
=[tex] \frac{4 \times 9 + 5}{9} [/tex]
we get 41/9.
Hope it helps...
The given fraction into the improper fraction should be [tex]\frac{41}{9}[/tex]
Given that,
The mixed number fraction is [tex]4 \frac{5}{9}[/tex]Computation:[tex]= 4\frac{5}{9}\\\\ = \frac{41}{9}[/tex]
Here we multiply the 9 with the 4 it gives 36 and then add 5 so that 41 arrives.
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plz help me on this question best and right answer gets brainliest
Answer:
| - 5| 5
| 6 | 6
| - 9 | 9
the numbers will be positive when they come out from the absolute value
Answer and Step-by-step explanation:
The absolute value of a value is the positive version of that value.
| | <- Brackets are used to show that a value is being absolute.
|-5| = 5 The negative 5 with absolute brackets becomes a positive 5.
|6| = 6 A positive 6 with absolute brackets stays a positive 6.
|-9| = 9 A negative 9 with absolute brackets becomes a positive 9.
#teamtrees #PAW (Plant And Water)
a westward moving motorcycle slows down from 24.0 m/a to 12.0 m/s in 3.0 seconds. what is the magnitude and direction of the acceleration
Answer:
0
Step-by-step explanation:
The arc length apothem shown below is 15 feet. Part 1) State the equation that relates arc length to central angle. Part 2) Find the angle apothem in radians. Part 3) Convert your answer from Part 2 to degrees and write it to the nearest hundredth of a degree
Answer:
ans right down there
Step-by-step explanation:
Here,Part 1
if the circle has a radius r so,
15 = r theta
here, theta is in radian.
Part 2
[tex]theta = \frac{15}{6} = 2.5[/tex]
part 3
[tex]theta = \frac{2.5 \times 180}{\pi} [/tex]
or theta =
143.2394487827058021919953870352629258310136811664108038729006
Can the sides of a triangle be in the given ratio? 3:4:5
Answer:
Yes
Step-by-step explanation:
Yes, and it’s a right triangle.
3²+4²=5²
9+16=25
25=25
Answer:
Yes
Step-by-step explanation:
In order to determine if a triple of values will form a triangle, we must apply the Triangle Inequality Theorem, which states that for a triangle with lengths a, b, and c:
a + b > c
a + c > b
b + c > a
Here, let's suppose that since the ratio of the sides is 3 : 4 : 5, then let the actual side lengths be 3x, 4x, and 5x, where x is simply a real value.
With loss of generality, set a = 3x, b = 4x, and c = 5x. Plug these into the Triangle Inequality to check:
a + b > c ⇒ 3x + 4x >? 5x ⇒ 7x > 5x ⇒ This is true
a + c > b ⇒ 3x + 5x >? 4x ⇒ 8x > 4x ⇒ This is also true
b + c > a ⇒ 4x + 5x >? 3x ⇒ 9x > 3x ⇒ This is true
Since all three conditions are satisfied, we know that a true triangle can be formed given that the ratio of their sides is 3 : 4 : 5.
~ an aesthetics lover
James stand at the centre of a regular field. he first take 50 steps North then 25 step West and finally 50 steps on the bearing of 315°.
i. sketch James movement
ii. how far west is James final point from the centre?
iii. how far north is James final point from the centre?
iv. describe how you would guide a jhs student to find the bearing and distance of James final point from the centre.
Answer:
Step-by-step explanation:
i. For navigation purposes, bearing is measured clockwise from north. In (x, y) coordinates, a distance D at a bearing B will have coordinates ...
(x, y) = (Dsin(B), Dcos(B))
Then 50 steps north (bearing 0°) will put James at coordinates ...
(x, y) = (50sin(0), 50cos(0)) = (0, 50)
The movement 25 steps west (bearing 270°) will add a displacement of ...
(x, y) = (25sin(270°), 25cos(270°)) = (-25, 0)
Finally, the movement of 50 steps on bearing 315° will add a displacement of ...
(x, y) = (50sin(315°), 50cos(315°)) = (-25√2, 25√2)
These movements are shown by the arrows to N, W, and F in the attached diagram.
__
ii. James's final displacement is the sum of the individual displacements:
(0, 50) +(-25, 0) +(-25√2, 25√2) = (-25(1+√2), 25(2+√2))
James is 25(1+√2) ≈ 60.4 steps west of center.
__
iii. James is 25(2+√2) ≈ 85.4 steps north of center.
__
iv. The distance can be found using the Pythagorean theorem (or distance formula). The distance from the origin to the final position (OF in the diagram) will be the root of the sum of the squares of the north and west displacements:
distance = √(85.355² +60.355²)
distance ≈ 104.5 steps
The bearing can be found using the arctangent function. The diagram shows you the reference angle (relative to the +y direction) has an opposite side equal to the west displacement, and an adjacent side equal to the north displacement. Then the bearing angle (β) will be ...
tan(β) = opposite/adjacent = -60.355/85.355
β ≈ arctan(-0.707106) ≈ -35.3°
The positive bearing angle is 360° added to this, or
bearing = 324.7°
Hello again. if someone gives me a hand with this book thickness excercise please thanks
Answer:
Known:
• a book have front, back and 200 pages
• front= 0.7 mm
• back= 0.7 mm
• each page= 0,14 mm
ask:
calculate the minimum thickness...?
answer:
a. 200 p × 0,14 = 28 mm
b. front + back = 0.7+0.7= 1.4 mm
Thickness= 28+1,4 = 29,4 mm
I hope this helps
if u have question let me know in comments^_^
when graphed on a coordinate plane , point a and point b are reflections across the x-axis. Point a is located at (5, 2). Which ordered pair describes the location of point b
Answer:
Point b has coordinates (5, -2)
Step-by-step explanation:
If point a has coordinates (5, 2) then its reflection across the x axis would have the same value for the x-coordinate, and exactly opposite value for the y-coordinate (that is y-coordinate = -2.
then point's a reflection is: (5, -2)
since its reflection is point b then point b has this coordinates.
Solve the equation for x by graphing.-4x-1 5x=4
Answer: Undefined
Step-by-step explanation:
slope is undefined
no y intercept
This line is vertical
Solve the equation for solutions in the interval [0, 2 π). Use algebraic methods and give exact values. Support your solution graphically. cos2x = 0
Answer:
45° or 135°
Step-by-step explanation:
Cos 2x = 0
2x = cos^-1 0
2x = 90° or 270°
x= 45° or 135°
Answer:
Step-by-step explanation:
● cos 2x = 0
We khow that Pi/2 equals 0.
So
● 2x = Pi/2 or 2x= -Pi/2
Then:
● x = Pi/4 or x = -Pi/2
So the solutions are:
● x = Pi/4 + 2×k×Pi
● or x = -Pi/4 + 2×k×Pi
Where k is an integer
The picture below has a graphical solution
● Pi/4 is approximatively 0.785 and -Pi/4 is approximatively -0.785
● the output of both Pi/4 and -Pi/4 is 0
So our answer was righr
What's the measure of an arc with a central angle of 120°?
Answer:
the answer is 240 degrees
if 80% of 2 is 200.what is 70% of 27
Answer:
18.90
Hope i got it right
1. If a bug can flap its wings at a rate of 92 times in 6 seconds, how many times do they flap their wings in 2.34 minutes? Round to 1 decimal.
Answer:
2152.8
Step-by-step explanation:
First, 2.34 minutes is 140.4 seconds. Next, the bug can flap its wings at a pace of 15.333..... flaps per second. Multiplying this, we get 2152.8
look at the image below forr the question plz
Answer:
[tex]308 \ m^3\\[/tex]
Step-by-step explanation:
The volume of a three-dimensional shape is the amount of space the figure takes up. This can be found by multiplying all of the dimensions of a figure together. In essence, the following formula can be used to find the volume.
[tex]A=l*w*h[/tex]
Where (l) represents the figure's length; (w) is the width: and (h) the height. Substitute the given values into the formula and solve for the volume.
[tex]A=l*w*h[/tex]
[tex]A=7*4*11[/tex]
Simplify,
[tex]A=7*4*11[/tex]
[tex]A=28*11[/tex]
[tex]A=308[/tex]
At what point on the curve x = 6t2 + 6, y = t3 − 2 does the tangent line have slope 1 /2 ?
Answer:
Hello,
P=(30,6)
Step-by-step explanation:
[tex]x=6t^2+6\\y=t^3-2\\\\\dfrac{dx}{dt}= 12t\\\dfrac{dy}{dt}= 3t^2\\\\\dfrac{dy}{dx} =\dfrac{\dfrac{dy}{dt} }{\dfrac{dx}{dt} } =\dfrac{3t^2}{12t} =\dfrac{t}{4} \\\\\dfrac{t}{4} =\dfrac{1}{2} \Longrightarrow t=2\\\\\\x=6t^2+6=6*2^2+6=30\\\\y=t^3-2=2^2-2=8-2=6\\\\\\Tangence\ point=(30,6)\\[/tex]
The point on the curve x = 6t² + 6, y = t³ - 2 where the tangent line have slope 1/2 is (30, 6).
How to depict the point on the curve?From the information given, x = 6t² + 6, y = t³ - 2. We'll find the first order derivative of x and y which will be:
dx/dt = 12t
dy/dt = 3t²
Therefore, 3t²/12t = t/4, t = 2.
We'll put the value of t back into the equations.
x = 6t² + 6,
x = 6(2)² + 6
x = 24 + 6 = 30
y = t³ - 2.
y = (2)³ - 2
y = 8 - 2 = 6
In conclusion, the correct options is (30, 6).
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PLEASE HELP 40 POINTS
Express each logarithm in terms of ln 3 and ln 5.
ln 81 / 125
The solution is 4ln3 - 3ln5, which is correct option(C).
What are the properties of logarithms?There are four basic properties of logarithms:
logₐ(xy) = logₐx + logₐy.
logₐ(x/y) = logₐx - logₐy.
logₐ(xⁿ) = n logₐx.
logₐx = logₓa / logₓb.
What are Arithmetic operations?Arithmetic operations can also be specified by the subtract, divide, and multiply built-in functions.
The operator that perform arithmatic operation are called arithmatic operators .
Operators which let do basic mathematical calculation
+ Addition operation : Adds values on either side of the operator.
For example 4 + 2 = 6
- Subtraction operation : Subtracts right hand operand from left hand operand.
for example 4 -2 = 2
* Multiplication operation : Multiplies values on either side of the operator
For example 4*2 = 8
/ Division operation : Divides left hand operand by right hand operand
For example 4/2 = 2
According to the problem, we will use some of the basic logarithmic properties,
Given expression,
⇒ ln81/125
⇒ ln81 - ln125 [used property : logₐ(x/y) = logₐx - logₐy]
⇒ ln3⁴ - ln5³ [ 81 =3⁴ and 125 = 5³ ]
⇒ 4ln3 - 3ln5 [used property : logₐ(xⁿ) = nlogₐx]
Hence, the solution is 4ln3 - 3ln5
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A box of chocolates contains five milk chocolates, three dark chocolates, and four white chocolates. You randomly select and eat three chocolates. The first piece is milk
chocolate, the second is white chocolate, and the third is milk chocolate. Find the probability of this occuring.
Answer:
60/220
Step-by-step explanation:
we use combination,
[tex] (\frac{5}{1} ) \times ( \frac{4}{1} ) \times ( \frac{3}{1} )[/tex]
[tex]5 \times 4 \times 3 = 60[/tex]
then, all divided by,
[tex] (\frac{12}{3}) = 220 [/tex]
[tex]60 \div 220[/tex]
The probability of the first piece being milk chocolate, the second being white chocolate, and the third being milk chocolate is 0.06.
What is Probability?The probability helps us to know the chances of an event occurring.
[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]
The sample contains five milk chocolates, three dark chocolates, and four white chocolates. Therefore, the probability that the first piece is milk chocolate is
[tex]\rm Probability=\dfrac{\text{Number of Milk choclates}}{\text{Total number of choclates}}[/tex]
[tex]\rm Probability=\dfrac{5}{12}[/tex]
Now, since the chocolate is been eaten the sample size will reduce from 12 chocolates in total to 11 chocolates in total (four milk chocolates, three dark chocolates, and four white chocolates). Therefore, the probability of the second piece being white chocolate is
[tex]\rm Probability=\dfrac{\text{Number of White choclates}}{\text{Total number of choclates}}[/tex]
[tex]\rm Probability=\dfrac{4}{11}[/tex]
Now, as the chocolate is been eaten the sample size will reduce from 11 chocolates in total to 10 chocolates in total (four milk chocolates, three dark chocolates, and three white chocolates). Therefore, the probability of the third piece being milk chocolate is
[tex]\rm Probability=\dfrac{\text{Number of Milk choclates}}{\text{Total number of choclates}}[/tex]
[tex]\rm Probability=\dfrac{4}{10}[/tex]
Thus, the probability of the first piece being milk chocolate, the second being white chocolate, and the third being milk chocolate is
[tex]\rm Probability=\dfrac{5}{12}\times \dfrac{4}{11} \times \dfrac{4}{10} = \dfrac{80}{1320} = 0.06[/tex]
Hence, the probability of the first piece being milk chocolate, the second being white chocolate, and the third being milk chocolate is 0.06.
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Show that the set of functions from the positive integers to the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} is uncountable. [Hint: First set up a one-to-one correspondence between the set of real numbers between 0 and 1 and a subset of these functions. Do this by associating to the real number 0.d1d2 . . . dn . . . the function f with f(n).
Answer:
since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its off functions
Step-by-step explanation:
set = {0,1,2,3,4,5,6,7,8,9}
setting up a one-to-one correspondence between the set of real numbers between 0 and 1
The function : F(n)= {0,1} is equivalent to the subset (sf) of (n) , this condition is met if n belongs to the subset (sf) when f(n) = 1
hence The power set of (n) is uncountable and is equivalent to the set of real numbers given
since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its offfunctions
Dividing integers
7. (-154) ➗ (-14) =
11. (-40) ➗10=
15. 90 ➗ (-15)=
16. 108 ➗ (-9)=
17. (-48) ➗ (-6)=
18. (-105) ➗ 7=
first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.
here,
7. (-154) ➗ (-14) =11
11. (-40) ➗10=-4
15. 90 ➗ (-15)=-6
16. 108 ➗ (-9)=-12
17. (-48) ➗ (-6)=8
18. (-105) ➗ 7=-15
hope it helps you......
1) Find the volume and surface area of the composite figure below
2) Find the surface area of the composite figure below
1.
[tex]volume = 64(21 + 4\pi) = 2148.5714 \: cubic \: feets[/tex]
[tex]surface \: area = 752 + 64\pi = 953.143 \: square \: feets[/tex]
2.
[tex]surface \: area = 220 + 9\pi = 248.257 \: square \: feets[/tex]
What is the equation of the line that passes through the point (8,3) and has a slope
of
1/4
Answer:
y = 1/4x+1
Step-by-step explanation:
Using slope intercept form
y = mx+b
where m is the slope and b is the y intercept
y =1/4 x+b
Substituting in the point
3 = 1/4(8)+b
3 = 2+b
Subtract 2 from each side
3-2 = b
1 =b
y = 1/4x+1
Answer:
y=1/4x+1
Step-by-step explanation:
the equation for a line is y=mx+b
where m is the slope and b is the y-intercept. since we have our slope given and and x,y given we can use that to solve for b. we get:
3=1/4(8)+b
3=2+b
1=b
therefore the y-intercept is b
so the equation is y=1/4x+1
what is 12x^3-9x^2-4x+3 in factored form?
Answer: (3x^2-1)(4x-3)
============================
Work Shown:
Use the factor by grouping method
12x^3-9x^2-4x+3
(12x^3-9x^2)+(-4x+3)
3x^2(4x-3)-1(4x-3)
(3x^2-1)(4x-3)
Find an equation of the circle whose diameter has endpoints , (−6,−1) and (2,3).
Answer:
first... You think and Conceptualize
A diameter divides a circle into equal halves
We're given the end points of the Diameter.
With this we can fine the Center of the circle.
The End Points are
(-6, -1) and ( 2, 3)
Half-way through the diameter gives the center of the circle
So We'd apply the Mid-Point formula to get the co-ordinate of the center.
X= x₁ + x₂/2 , Y = y₁ + y₂/2
X = -6 + 2/2, Y = -1 + 3/2
X= -2. Y = 1
The Midpoint is (-2, 1)
The Radius would be the distance between the center and a point on the circumference.
We already have 2 points of the circumference (Which are the endpoints of the diameter).
So we can pick any of them arbitrarily.
I'd go with (2,3)
So We'd apply the distance between Points formula to get the magnitude of the radius
(-2,1) (2,3)
D = √(x₁ - x₂)² + (y₁ - y₂)²
D = √(-2-2)² + (1-3)²
D=√(-4)² + (-2)²
D=√20.
Our Radius is √20.
Equation of Circle =
(x-h)² + (y-k)² = r²
Where h and k are the center of the circle(-2,1)
(x-(-2))² + ( y - 1 )²= (√20)²
(x + 2)² + ( y - 1)² = 20
Our Answer
(x + 2)² + (y - 1)² = 20.
This should be it.
Have a great day!
Please answer this correctly without making mistakes
Answer:
10 9/20
Step-by-step explanation:
Hey there!
If Hillsboro to Campbell is 16 2/20 and Hillsboro to Oxford is 5 13/20,
we’ll do
16 2/20 - 5 13/20
Imrpoper form
322/20 - 113/20
322 - 113
209/20
10 9/20 miles from Oxford to Campbell.
Hope this helps :)
When a number is tripled, its value increases by 10. What is the original value?
[tex]3x=x+10[/tex]
We tripple something and get 10 more than something.
Put the x-es on the left and non x-es to the right,
[tex]2x=10[/tex]
Divide both sides by 2,
[tex]x=5[/tex]
Et Viòla.
Hope this helps :)
When a number is tripled, its value increases by 10 then the original number is 5.
Let's call the original number "x". According to the problem, when this number is tripled, its value increases by 10. Mathematically, we can represent this as an equation:
3x = x + 10
Now, we can solve for "x" step by step:
1. Subtract "x" from both sides of the equation:
3x - x = 10
2. Simplify the left side:
2x = 10
3. Divide both sides by 2 to solve for "x":
x = 10 / 2
x = 5
So, the original number "x" is 5.
In other words, if you take a number, triple it (multiply by 3), and then increase the result by 10, you would end up with the value 5. This can be verified by checking:
3 * 5 = 15
15 + 10 = 25
The equation 3x = x + 10 represents the relationship between the original number and its tripled value with an increase of 10. Solving this equation helps us find the original value that satisfies the given condition.
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You and your friends have tickets to attend a music concert. While standing in line, the promoter states he will give a gift card for a free album download to each person that is a multiple of 2. He will also give a backstage pass to each fourth person and floor seats to each fifth person. Which person will receive the free album download, backstage pass, and floor seats? Explain the process you used to determine your answer.
9514 1404 393
Answer:
20th
Step-by-step explanation:
The person will receive all gifts if the are all of a multiple of 2, a multiple of 4, and a multiple of 5. Since 4 is already a multiple of 2, the person who will receive all is the one who is a multiple of 4 and 5.
20 is 4×5, so is a multiple of both numbers. There is no smaller number that is a multiple of both 4 and 5.
The 20th person will receive all gifts.
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The value we have determined here is called the "least common multiple" (LCM). It is the product of the unique prime factors of the numbers of interest, raised to the highest power that appears in any of the numbers.
2 = 2¹
4 = 2²
5 = 5¹
LCM(2, 4 5) = 2² × 5¹ = 20
Please Help I will give you a lot of points if you do!
Recall that a ⇒ b ⇔ ¬a ∨ b. So we can write
q ⇒ (p ∧ r ) ⇔ ¬q ∨ (p ∧ r )
Then the negation of this would be, for instance,
¬(¬q ∨ (p ∧ r )) ⇔ ¬(¬q) ∧ ¬(p ∧ r )
… ⇔ q ∧ (¬p ∨ ¬r )
… ⇔ (¬p ∧ q) ∨ (q ∧ ¬r )
… ⇔ ¬(p ∨ ¬q) ∨ (q ∧ ¬r )
… ⇔ (p ∨ ¬q) ⇒ (q ∧ ¬r )
It's impossible to tell what kind of statement your program is expecting, but since there are 5 slots available, my money would be on q ∧ (¬p ∨ ¬r ), so long as ¬p and ¬r are options.
convert 16,000 feet per second into kilometres per hour
Answer:
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Step-by-step explanation:
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