Write the following decimals as fractions.

Step-by-step explanation:

the inverse of the inverse of a function is the function itself

It's like going and coming back

Answer:

9

Step-by-step explanation:

The inverse of the inverse is the input

f^-1 (f^-1(9))  = 9

As a proof

f(x) = 4x+5

y = 4x+5

Exchange x and y

x = 4y+5

Solve for y

(x+5) = 4y

(x+5)/4 = y

f^-1 (x) =  ( x-5)/4

Then find the inverse of this function

y = ( x-5) /4

Exchange x and y

x = (y-5)/4

4x = y-5

4x+5 = y

Which gives us the original function back

f^-1( input) = 4x+5

Using the value given

f^-1 (9) =  ( 9-5)/4=4/4 =1

Using the 1 from the previous part as the input

f^-1( 1) = 4*1+5  = 4+5 = 9

Answer:

arccsc(x)=1/cos(x)

Step-by-step explanation:

Answer:

the answer to your question is D

Step-by-step explanation:

Answer:

The awnser is 64

Step-by-step explanation:

It is 64 because you devide the perimiter (32) by 4, to get all sides, and then multiply 1 side by the other to get 64

THIS METHOD ONLY WORKS FOR A SQUARE

Answer:

3/10

Step-by-step explanation:

1/5 of total income - spent on car

remainder income = 4/5

3/8 of remainder = 3/8 ×4/5 = 3/10(of total income spent on rent)

the word "of" means you can find it by multiplication

e.g. 2 of 1/2 means 2 × 1/2 which is 1

Answer:

Tina

Step-by-step explanation:

Since Amy owns the dog, she doesn't have the ferret and we know that Jewel doesn't have the ferret so the answer is Tina.

Answer:

C. [tex](5-\frac{1}{2})^6[/tex]

Step-by-step explanation:

Given

[tex]15(5)^2(-\frac{1}{2})^4[/tex]

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

[tex]Sum = 2 + 4[/tex]

[tex]Sum = 6[/tex]

Each term of a binomial expansion are always of the form:

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

Where n = the sum above

[tex]n = 6[/tex]

Compare [tex]15(5)^2(-\frac{1}{2})^4[/tex] to the above general form of binomial expansion

[tex](a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......[/tex]

Substitute 6 for n

[tex](a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......[/tex]

[Next is to solve for a and b]

From the above expression, the power of (5) is 2

Express 2 as 6 - 4

[tex](a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......[/tex]

By direct comparison of

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

and

[tex](a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......[/tex]

We have;

[tex]^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4[/tex]

Further comparison gives

[tex]^nC_r = 15[/tex]

[tex]a^{n-r} =(5)^{6-4}[/tex]

[tex]b^r= (-\frac{1}{2})^4[/tex]

[Solving for a]

By direct comparison of [tex]a^{n-r} =(5)^{6-4}[/tex]

[tex]a = 5[/tex]

[tex]n = 6[/tex]

[tex]r = 4[/tex]

[Solving for b]

By direct comparison of [tex]b^r= (-\frac{1}{2})^4[/tex]

[tex]r = 4[/tex]

[tex]b = \frac{-1}{2}[/tex]

Substitute values for a, b, n and r in

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

[tex](5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

Solve for [tex]^6C_4[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......[/tex]

Check the list of options for the expression on the left hand side

The correct answer is [tex](5-\frac{1}{2})^6[/tex]

Answer: B.

k=3

Step-by-step explanation:

g(x) is 3 units higher than f(x)

so k must be equal to 3

Answer:

it is b i think

k=3

Step-by-step explanation:

Answer:

7 < (third side length) < 37

Step-by-step explanation:

Add these two side lengths together.  We get 37.  Unless the 3rd side is LESS than 37, we cannot form a triangle.  

Next, subtract 15 from 22, obtaining 7.  The 3rd side has to be GREATER than 7 in order for the sides 7+, 15 and 22 to form a triangle.

7 < (third side length) < 37

Answer:

26.63 ??

Step-by-step explanation:

I think you use pythagorean theorum to solve.

do 22^2 and 15^2 and get 709.1569

sqrt of that is 26.63

Answer:

88

Step-by-step explanation:

89+85+95+83= 352,

352/4 = 88

Answer:

Hello There. ☆~\《`°---_●£●__---`°》\~☆

An exponential growth function is represented by

f(x)=a(b)^{x},a>0,b>1.

The given functions can be written as,

A)f(x)=.001(1.77)^x,0.001>0,1.77>1

B)f(x)=2(1.5)^{x/2}=2(\sqrt{1.5} )^x,2>0,\sqrt{1.5} >1

C)f(x)=5(0.5)^{-x}=5(2)^x,5>0,2>1

D) f(t)=5e^{-t}=5(\frac{1}{e} )^x,5>0,1/e.

So the function f(t)=5e^{-t}=5(\frac{1}{e} )^x,5>0,1/e violates the conditions for an exponential growth function. It is an exponential decay function.

The correct choices are (A), (B), (C).

Hope It Helps!~ ♡

ItsNobody~ ☆

The functions that represent exponential growth are choices (A), (B), and (C). The correct option is A, B, and C.

Exponential growth is the process of gradual increase of quantity over time.

An exponential growth function is represented by

[tex]\rm f(x)=a(b)^{x}[/tex],  a>0,b>1

The given functions can be written as,

A)[tex]f(x) = .001(1.77)^x[/tex], 0.001>0,1.77>1

B) [tex]f(x) = 2(1.5)^{x/2} = 2(\sqrt{1.5} )^x,[/tex]   2>0,  [tex]\sqrt{1.5}[/tex] >1

C)[tex]f(x) = 5(0.5)^{-x}=5(2)^x[/tex],    5>0, 2>1

D) [tex]f(t) = 5e^{-t}=5(\frac{1}{e} )^x[/tex],        5>0,  1/e.

So, the function [tex]f(t)=5e^{-t}=5(\frac{1}{e} )^x,5 > 0,1/e[/tex] violates the conditions for an exponential growth function. It is an exponential decay function.

The correct choices are (A), (B), and (C).

Learn more about exponential growth;

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Answer:

mark my answer as the brainliest

Step-by-step explanation:

x = 53/4

Answer:

4×+1-9 (2^)+2)=0

4×+1-9 (4+2)=0

4×+1(-36-18)=0

4×+1 (-54)=0

4×-54=0

4×=54

×=54÷4

×=13.5

Answer:

  8 servings

Step-by-step explanation:

At the ratio of 15:1, the 75 grams of rice in one serving will require 75/15 = 5 g of spice. David's inventory of 40 g of spice is enough for ...

  40 g/(5 g/serving) = 8 servings

Only 8 servings can be made with the available spice.

Rice to spice ratio = 15 : 1

Number of grams per serving = 75 grams

Grams of spice available = 40 grams

Grams of rice, r required for available spice :

15 grams of rice = 1 gram of spice

r grams of rice = 40 grams of spice

Cross multiply :

r = (40 × 15)

r = 600 grams

The grams of rice which can go with the available spice :

Number of servings = grams of rice / grams per serving

Number of serving = 600 grams / 75 grams

Number of grams per serving = 8

Hence, The number of servings which can be made with the available spice is 8 servings

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Answer:

[tex]$\frac{3\pi }{2}$[/tex]

Step-by-step explanation:

Solve for the interval: [tex][0, 2\pi)[/tex]

[tex]4 \csc(\theta)+1=-3[/tex]

[tex]4 \csc(\theta)=-4[/tex]

[tex]\csc(\theta)=-1[/tex]

[tex]$\frac{1}{\sin(\theta)} =-1 \Rightarrow \sin(\theta)=-1$[/tex]

We have [tex]\sin(\theta)=-1[/tex] for coterminal angles [tex]$\frac{3\pi }{2}+2\pi n$[/tex]

Once we just want the interval [tex][0, 2\pi)[/tex]

The solution is [tex]$\frac{3\pi }{2}$[/tex]

Answer:

Total mass of materials = 4.8kg

For gravel

55% of the materials are gravel

So we have

55/100 × 4.8 kg

= 2.64kg

For sand

30% of the materials are sand

We have

30/100 × 4.8

= 1.44kg

For cement

The remaining materials were cement so we add the masses of both the sand and gravel and subtract it from the total mass

That's

4.8 - (2.64 + 1.44)

4.8 - 4.08

= 0.72 kg

She earns £ 800 per week

She receives a raise of 7.5% which is

100 + 7.5 = 107.5%

So we have

107.5 / 100 × £ 800

= £ 860

She now earns £ 860 per week

Hope this helps you

Step-by-step explanation:

1)of 4.8kg concrete 55% is gravel,30% is sand and 15% is cement.

percent=Rate*Base

Pgravel=55%*4.8kg

Pgravel=2.64kg

Psand=30%*4.8kg

Psand=1.44kg

Pcement=15%*4.8kg

Pcement=0.72kg

2)percent=Rate*Base

percent=7.5%*£800

percent=60£

total earn=60£ + £800

total earn=£860

Answer:

62.5°

Hope this helps :)

Answer:

Answer- 3/4 divided by 1/8 = 6/8

[tex]\text{Molly used the addition property of equality}\\\\\text{In the equation shown in the question, you can see that Molly is trying}\\\text{to find the value of "d"}\\\\\text{In order to do this, she must get the "d" variable by itself}\\\\\text{To do this, she adds "3d" to both sides to get the "d" variable on one side}\\\\[/tex]

Part A

House 1: we make exponential can be used to describe the

value of house 1. After 1 year, 253480 = 249000 x 1.02

After 2 years, 259059.6 = 25398×1.02. After 3 years 264240.79 =259059.60x1.02.

House 1: we make linear. 256000=249000 + 1000.263000 = 256000 +7000.270000=263000 + 1000.

Part B.

House 1: f(x)=249000 1.02x [genometic sequence]

House 2: f(X) = 24900 + 1000x [arithmetic progression]

Part C

House 1: f(45)=249000×1.02 45 = 607025.697

House 2: f(45) = 249000 +7000x45 = 564000

"House 1 is an arithmetic sequence that increases in price each year while House 2 is an arithmetic sequence that only increases by 1000 per year.

In computational mathematics, a word problem is a problem of deciding whether two given expressions are equivalent with respect to a set of rewriting identities. A prototypical example is the word problem for groups, but there are many other instances as well.

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Answer:

x<-5 is the correct answer

Answer:

x<-5 is the answer

Step-by-step explanation:

Answer:

The rhombus ABCD has an area of 22 square units.

Step-by-step explanation:

The coordinates of rhombus ABCD are shown in the image attached below. The area of the rhombus can be found in terms of their diagonals, which are now calculated by Pythagorean Theorem:

[tex]AC = \sqrt{[6-(-4)]^{2}+[8-(-4)]^{2}}[/tex]

[tex]AC = 15.620[/tex]

[tex]BD = \sqrt{(4-6)^{2}+[0-(-2)]^{2}}[/tex]

[tex]BD \approx 2.828[/tex]

The area of the rhombus is: ([tex]AC = 15.620[/tex] and [tex]BD \approx 2.828[/tex])

[tex]A = \frac{AC\cdot BD}{2}[/tex]

[tex]A = \frac{(15.620)\cdot (2.828)}{2}[/tex]

[tex]A = 22.087[/tex]

The rhombus ABCD has an area of 22 square units.

Answer:

22 units

Step-by-step explanation:

Answer:

Range of Function :  { - 9, - 5, - 1,  4 }

Step-by-step explanation:

We know that y = 2x - 5 provided the domain ( x - values ) { - 2, 0, 2, 4 }. Let us substitute each element in this set of domain as x in the equation "y = 2x - 5" as to solve for the y - values, otherwise known as the range of the function.

{ - 2, 0, 2, 4 }

y = 2( - 2 ) - 5 = - 9,

y = 2( 0 ) - 5 = - 5,

y = 2( 2 ) - 5 = - 1,

y = 2( 4 ) - 5 = 4

We have the set of y - values as { - 9, - 5, - 1, 4 }. This is the range of our function.

Answer:

HIG=28°

Step-by-step explanation:

HI is a diameter therefore it's measure is 180°

HI-IG=HG

180-128=HG

52°=HG

HIG=1/2HG

HIG=1/2(56°)

HIG=28°

Answer:

C. X=27

Step-by-step explanation:

-11+1/3x+9=7

1/3x=7+11-9

1/3x=9

x=9x3

x=27

Answer:

hope it helps

this is my best

please tell me if I'm wrong

3x+4y=12 is Linear.

y-1/2x+6 is Linear.

y=4x^2 is nonlinear.

y+2=|4| is linear.

y+6=4x is linear.

In order to tell whether an equation is linear or not, you have to first see if there is any variable^2 or more than ^1. If that is the case, it isn't linear. For example the equation x^2=4 or y^5=100 isn't linear. It also isn't linear if the equation is divided by X or Y.For example the equation 1/x=1 isn't linear or 1/y^2=5 isn't linear.

A question is also linear if you can write it in the form y=mx+b , 'm' meaning the slope of the equation and 'b' meaning the y-intercept of the equation.

Answer:

The answer is option B

Step-by-step explanation:

2ln 2 - 2ln3

= ln ( 2²/3²)

= ln (4/9)

Hope this helps you

Answer:

B) 2ln 2 – 2ln 3

Step-by-step explanation:

Answer:

3 dolla

Step-by-step explanation:

Answer:

The second choice

Step-by-step explanation:

So first we would plug in the first term which is 2 so we would get [tex]an=2[/tex] times [tex]rn-1[/tex] so next we would see that the common ration is -3 since every time the number is being multiplied by -3. so then our equation would be [tex]an= 2[/tex] times [tex]-3n-1[/tex]. Now we would just find the choice that matches and it would be the second choice.

Answer:

option 2

Step-by-step explanation:

First term [tex]a_{1} = 2\\[/tex]

common ratio = r = second term ÷ first term

                            = -6 ÷2 = -4

Plug in the values of  [tex]a_{1}[/tex] & r in the formula

[tex]a_{n} = a_{1}*r^{n-1}\\\\\\a_{n}=2 * (-3)^{n-1}[/tex]

Answer:

72cm2 (2 means squared)

Step-by-step explanation:

you add all the sides once you get the are for each side. To do that you multiply l(w)

Answer:

The surface area of the rectangular prism is [tex]136cm^{2}[/tex]

Step-by-step explanation:

What is surface area?

Surface area is the amount of space covering the outside of a three-dimensional shape.

What is rectangular prism?

A rectangular prism can be defined as a 3-dimensional solid shape which has six faces that are rectangles. A rectangular prism is also a cuboid.

Given, length l= 7cm

          breadth b=6cm

          height h=2cm

The surface area of the cuboid is,

=2(lb+bh+lh)

=2(7*6+6*2+2*7)

=2(42+12+14)

=2*68

=136 [tex]cm^{2}[/tex]

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