X+3y+2z=1
2x-2y-5z=0
-x+2y+4z=1

Answer:

y=-3

Step-by-step explanation:

This is a horizontal line

Horizontal lines are of the form

y=

The y value is -3

y=-3

━━━━━━━☆☆━━━━━━━

▹ Answer

A. y = -3

▹ Step-by-Step Explanation

Y is represented by a horizontal line and it passes through the point -3 therefore, the answer is y = -3.

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

Answer:

1/2 or 0.5

Step-by-step explanation:

Saying that there is a 50-50 chance of an event happening is equivalent to saying there is a 1 in 2 chance. Therefore, expressing that degree of likelihood as a value between 0 and 1:

[tex]\frac{1}{2}=0.50[/tex]

There is a 1/2 or 0.5 chance that a randomly selected adult has pierced ears.

Answer:

1/2 or 0.5

Step-by-step explanation:

50-50 chance between 0-1 means half of 0-1 which is 1/2 or 0.5

1/2 or 0.5!

Answer:

166.6666 metres/second

Step-by-step explanation:

1 km/hr = 5m/18s

600*5/18

Answer:

(x+6)(x^2+8)

D

Step-by-step explanation:

x^3 + 6x^2 + 8x + 48=

x2(x+6)+8(x+6)= take x+6 common factor

(x+6)(x^2+8)

Answer:

The history instructor has made a computational error.

Step-by-step explanation:

We have that the data represents the linear correlation coefficient and notes it is 1.15

The linear correlation coefficient value which is 1.15 does tell the instructor that the history instructor has made a computational error due to the linear correlation coefficient value falls in the range -1 to +1.

Therefore, the history instructor has made a computational error.

Answer:

-19

Step-by-step explanation:

-19 is the absolute value of 19

hope this helps

Answer:

sum = +13

Step-by-step explanation:

The possible factors of 48 are

{1,2,3,4,6,8,12,16,24,48}

Of these, the pair 3,16 gives a sum of 19 and a product of 48.

We are given that 16 (greater absolute value) is positive, so 3 is negative.

The sum of the two is therefore 16-3 = 13

Answer:

992

Step-by-step explanation:

You must convert the meter the kilometer by miltiplying by 1000

and when you do it you must multiply 0.992 by 1000 since it is a fraction .

or you can work it this way :

Answer:

72

Step-by-step explanation:

We are assuming that all girls in the group bought the same number of items.

Therefore, we need to find the highest common factor of 72, 144 and 216.

HCF

72 = 2 * 2 * 2 * 3 * 3

144 = 2 * 2 * 2 * 2 * 3 * 3

216 = 2 * 2 * 2 * 3 * 3 * 3

The product of the emboldened numbers is the highest common factor.

That is:

2 * 2 * 2 * 3 * 3 = 72

Therefore, the largest possible number of girls in the group is 72.

Step-by-step explanation:

_22greater than minus 2 x minus minus 72 minus 3

72 minus 22 minus 3greathan than 2x

49greatern than 2 x

Answer:

[tex](fof^{-1})(x)=x[/tex]

Step-by-step explanation:

Composition of two functions f(x) and g(x) is represented by,

(fog)(x) = f[g(x)]

If a function is,

f(x) = (-6x - 8)² [where x ≤ [tex]-\frac{8}{6}[/tex]]

Another function is the inverse of f(x),

[tex]f^{-1}(x)=-\frac{\sqrt{x}+8}{6}[/tex]

Now composite function of these functions will be,

[tex](fof^{-1})(x)=f[f^{-1}(x)][/tex]

                  = [tex][-6(\frac{\sqrt{x}+8}{6})-8]^{2}[/tex]

                  = [tex][-\sqrt{x}+8-8]^2[/tex]

                  = [tex](-\sqrt{x})^2[/tex]

                  = x

Therefore, [tex](fof^{-1})(x)=x[/tex]

Answer:

The missing reason in step 5 is;

The linear pair postulate

Step-by-step explanation:

The information given are;

Column 1,                                                 Column 2

Statements,                                             Reasons

Line AB intersect DE at C,                      Given

∠DCB and ∠BCE are linear pair,           Definition of linear pair

∠DCB is supplementary to ∠BCE,         Linear pair postulate

∠BCE and ∠ECA are linear pair,           Definition of linear pair

∠BCE is supplementary to ∠ECA,         Linear pair postulate

∠DCB ≅ ∠ECA,                                      Congruent to supplementary theorem  

Therefore, the missing reason in step 5 is the linear pair postulate.

Answer:

itS A

Step-by-step explanation:

Answer:

the answer shoudl be OB 4

Answer:

The mean length of the 13 people's big finger is 15.45 cm

Step-by-step explanation:

Given;

mean length of 4 childrens' big finger, x' = 14cm

mean length of 9 adults' big finger is 16.1cm, x'' = 16.1cm

Let the total length of the 4 childrens' big finger = t

[tex]x' = \frac{t}{n} \\\\x' = \frac{t}{4}\\\\t = 4x'\\\\t = 4 *14\\\\t = 56 \ cm[/tex]

Let the total length of the 9 adults' big finger = T

[tex]x'' = \frac{T}{N} \\\\x'' = \frac{T}{9}\\\\T = 9x''\\\\T = 9*16.1\\\\T = 144.9 \ cm[/tex]

The total length of the 13 people's big finger = t + T

                                                                           = 56 + 144.9

                                                                            =200.9 cm

The mean length of these 13 people's big finger;

x''' = (200.9) / 13

x''' = 15.4539 cm

x''' = 15.45 cm (2 DP)

Therefore, the mean length of the 13 people's big finger is 15.45 cm

Hey there! :)

Answer:

B. The volume of Cylinder B is larger.

Step-by-step explanation:

Find the volumes of each cylinder using the formula V = πr²h:

Cylinder A:

V = π3² · 5

V = 9π · 5

V = 45π units³

Cylinder B:

V = π5²· 3

V = 25π · 3

V = 75π units³

75π u³ > 45π u³, so the volume of Cylinder B is larger.

Answer:

196 tickets

Step-by-step explanation:

The total expenses to put on a 3-day production of a play is $980. Each ticket to go and watch the play is going to be sold for $5. The producer sells x number of tickets, x number of tickets would cost 5x. Therefore to find the number of tickets the producer must sell so as to make a profit the money generated from selling the tickets must be more than the cost of production. Therefore we use the formula:

5x ≥ 980

Dividing through by 5:

x ≥ 980

x ≥ 980/5

x ≥ 196

Therefore the producer must sell at least 196 tickets so as to make a profit

Answer:

choice c

Step-by-step explanation:

y axis shows value of computer

v-intercept; x axis = 0

show initial value of the computer

Answer:

2

Step-by-step explanation:

-(1-√2) -(2-√3) + 1/√3 + 2+1/2+√5-(√5-√6)-(√6-√7)+ 1/√7+2√2+1/2√2+3

-1+√2-√2+√3-(√3-2)-(2-√5)-√5+√6-√6+√7-(√7-2√2)-(2√2-3)

-1+√2-√2+√3-√3+2-2+√5-√5+√6-√6+√7-√7+2√2-2√2+3

2

Answer:

Step-by-step explanation:

hello,

for [tex]ax^2+bx+c=0[/tex]

[tex]\Delta = b^2-4ac[/tex]

so here

[tex]\Delta = b^2-4*(-4)*(-11)=b^2-176[/tex]

to have two complex solutions we need [tex]\Delta < 0\\[/tex]

so [tex]b^2<176[/tex]

[tex]<=> b < \sqrt{176}=13.266...[/tex]

for instance we can take b = 0

hope this helps

Answer:

The correct answer is 12.

Step-by-step explanation:

i got it correct on my test, thanks to comment on the question above.

Answer:

(a) Shown below.

(b) Shown below.

(c) The probability that a person does not learn Spanish is 0.18.

(d) The probability that method B was used given that a student learned the Spanish successfully is 0.83.

Step-by-step explanation:

(a)

Consider the provided data.

[tex]P(A)=0.20\\P(B)=0.80\\P(L|A)=0.70\\P(L|B)=0.85[/tex]

Then the probability of not learning Spanish using the respective methods are:

[tex]P(L'|A)=1-P(L|A)=1-0.70=0.30\\\\P(L'|B)=1-P(L|B)=1-0.70=0.15[/tex]

(b)

The Probability Tree representing each of the probabilities mentioned above is attached below.

(c)

Compute the probability that a person does not learn Spanish as follows:

[tex]P(L')=P(L'|A)P(A)+P(L'|B)P(B)[/tex]

         [tex]=(0.30\times 0.20)+(0.15\times 0.80)\\\\=0.06+0.12\\\\=0.18[/tex]

Thus, the probability that a person does not learn Spanish is 0.18.

(d)

Compute the probability that method B was used given that a student learned the Spanish successfully as follows:

[tex]P(B|L)=\frac{P(L|B)P(B)}{P(L|A)P(A)+P(L|B)P(B)}[/tex]

            [tex]=\frac{(0.85\times 0.80)}{(0.70\times 0.20)+(0.85\times 0.80)}\\\\=\frac{0.68}{0.14+0.68}\\\\=0.82927\\\\\approx 0.83[/tex]

Thus, the probability that method B was used given that a student learned the Spanish successfully is 0.83.

Answer: B

Step-by-step explanation: In algebra, we use the word slope to describe how steep a line is and slope can be found using the ratio rise/run between any two points that are on that line.

Answer:

a) Probability that haul time will be at least 10 min = P(X ≥ 10) ≈ P(X > 10) = 0.0455

b) Probability that haul time be exceed 15 min = P(X > 15) = 0.000

c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10) = 0.6460

d) The value of c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)

c = 2.12

e) If four haul times are independently selected, the probability that at least one of them exceeds 10 min = 0.1700

Step-by-step explanation:

This is a normal distribution problem with

Mean = μ = 8.46 min

Standard deviation = σ = 0.913 min

a) Probability that haul time will be at least 10 min = P(X ≥ 10)

We first normalize/standardize 10 minutes

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69

To determine the required probability

P(X ≥ 10) = P(z ≥ 1.69)

We'll use data from the normal distribution table for these probabilities

P(X ≥ 10) = P(z ≥ 1.69) = 1 - (z < 1.69)

= 1 - 0.95449 = 0.04551

The probability that the haul time will exceed 10 min is approximately the same as the probability that the haul time will be at least 10 mins = 0.0455

b) Probability that haul time will exceed 15 min = P(X > 15)

We first normalize 15 minutes.

z = (x - μ)/σ = (15 - 8.46)/0.913 = 7.16

To determine the required probability

P(X > 15) = P(z > 7.16)

We'll use data from the normal distribution table for these probabilities

P(X > 15) = P(z > 7.16) = 1 - (z ≤ 7.16)

= 1 - 1.000 = 0.000

c) Probability that haul time will be between 8 and 10 min = P(8 < X < 10)

We normalize or standardize 8 and 10 minutes

For 8 minutes

z = (x - μ)/σ = (8 - 8.46)/0.913 = -0.50

For 10 minutes

z = (x - μ)/σ = (10 - 8.46)/0.913 = 1.69

The required probability

P(8 < X < 10) = P(-0.50 < z < 1.69)

We'll use data from the normal distribution table for these probabilities

P(8 < X < 10) = P(-0.50 < z < 1.69)

= P(z < 1.69) - P(z < -0.50)

= 0.95449 - 0.30854

= 0.64595 = 0.6460 to 4 d.p.

d) What value c is such that 98% of all haul times are in the interval from (8.46 - c) to (8.46 + c)?

98% of the haul times in the middle of the distribution will have a lower limit greater than only the bottom 1% of the distribution and the upper limit will be lesser than the top 1% of the distribution but greater than 99% of fhe distribution.

Let the lower limit be x'

Let the upper limit be x"

P(x' < X < x") = 0.98

P(X < x') = 0.01

P(X < x") = 0.99

Let the corresponding z-scores for the lower and upper limit be z' and z"

P(X < x') = P(z < z') = 0.01

P(X < x") = P(z < z") = 0.99

Using the normal distribution tables

z' = -2.326

z" = 2.326

z' = (x' - μ)/σ

-2.326 = (x' - 8.46)/0.913

x' = (-2.326×0.913) + 8.46 = -2.123638 + 8.46 = 6.336362 = 6.34

z" = (x" - μ)/σ

2.326 = (x" - 8.46)/0.913

x" = (2.326×0.913) + 8.46 = 2.123638 + 8.46 = 10.583638 = 10.58

Therefore, P(6.34 < X < 10.58) = 98%

8.46 - c = 6.34

8.46 + c = 10.58

c = 2.12

e) If four haul times are independently selected, what is the probability that at least one of them exceeds 10 min?

This is a binomial distribution problem because:

- A binomial experiment is one in which the probability of success doesn't change with every run or number of trials. (4 haul times are independently selected)

- It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (Only 4 haul times are selected)

- The outcome of each trial/run of a binomial experiment is independent of one another. (The probability that each haul time exceeds 10 minutes = 0.0455)

Probability that at least one of them exceeds 10 mins = P(X ≥ 1)

= P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

= 1 - P(X = 0)

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 4 haul times are independently selected

x = Number of successes required = 0

p = probability of success = probability that each haul time exceeds 10 minutes = 0.0455

q = probability of failure = probability that each haul time does NOT exceeds 10 minutes = 1 - p = 1 - 0.0455 = 0.9545

P(X = 0) = ⁴C₀ (0.0455)⁰ (0.9545)⁴⁻⁰ = 0.83004900044

P(X ≥ 1) = 1 - P(X = 0)

= 1 - 0.83004900044 = 0.16995099956 = 0.1700

Hope this Helps!!!

Answer:

y = 10 - 0.5x for 0 &le;  x &le; 20

Step-by-step explanation:

Initial value = (0,10)

final value = (20,0)

Cost per trip = debit of 0.50 = slope

equation : y = 10 - 0.5x for 0 <=  x <= 20

Answer:

A. The triangles are congruent by SAS.

Step-by-step explanation:

Two sides of one triangle are congruent to two sides of the other triangle. The included angles of the two triangles are congruent.

The triangles are congruent by SAS.

Answer:

35

Step-by-step explanation:

f(x)=5x^3-2x^2+3

f(2)=5x2^3-2x2^2+3

=5x8-2x4+3

=40-8+3

=40-5

=35

Answer:

35

Step-by-step explanation:

F(x) = 5x^3 -2x^2 + 3

Let x=2

F(2) = 5(2)^3 -2(2)^2 + 3

       = 5*8 -2(4) +3

       = 40 -8+3

       = 32+3

      = 35

Answer: 1,2,3,4

Step-by-step explanation:

The domain consists of every x value

Answer:

A, B, and E are all less than 1/8

Answer:

Step-by-step explanation:

hello,

how many students ? 14 + 2 + 5 +3 = 24

how many students who had C and S ? 14 + 2 + 5 = 21

so P(C∪S)=21/24=(7*3)/(8*3)=7/8

hope this helps

Answer:

9x-3 or 3(3x-1)

Step-by-step explanation:

A triangle has three sides. To find the perimeter, add those side lengths together.

3x-3+(4x-1)+(2x+1)

Add your common terms (xs and constants) together.

3x+4x+2x=9x

-1+-3+1=-3

9x-3

If you want to, you can factor the expression.

3(3x-1)

Answer:

9x - 3

Step-by-step explanation:

The perimeter is all the sides added together.

4x - 1 + 2x + 1 + 3x - 3

Rearrange.

4x + 2x + 3x - 1 + 1 - 3

Combine like terms.

9x - 3