Answer:
the school ended at 3:20pm
Step-by-step explanation:
Since Yasmin arrived home from play practice at 4:25 p.m.
The walk home took 15 minutes.
And, The practice starts 20 minutes after the final bell and lasted for a half hour.
Now Total time taken in all activities would be
= 15 + 20 + 30
= 65 minutes
Now deduct 1 hour and 5 minutes from 4:25 pm
i.e.
1 hour prior to 4:25 pm i.e. 3:25 pm
And, 5 minutes prior 3:25 pm i.e. 3:20 pm
So, the school ended at 3:20pm
find x, then find each angle
Answer:
x=8
Step-by-step explanation:
23x=184
x=8
help me with this too please
Answer:
this is a test but its he second one :D
Step-by-step explanation:
Find the value of x
Answer:
x = 121
Step-by-step explanation:
Let the measure of the altitude of the given triangle be h units.
By geometric mean theorem:
[tex]h = \sqrt{23 \times x} \\ \\ h = \sqrt{23x} \\ \\ now \: by \: pythagors \: theorem \\ \\ {(x + 11)}^{2} = {h}^{2} + {x}^{2} \\ \\ \cancel{{x}^{2}} + 22x + 121 = {( \sqrt{23x} )}^{2} + \cancel{{x}^{2}} \\ \\ 22x + 121 = 23x \\ \\ 22x - 23x = - 121 \\ \\ - x = - 121 \\ \\ x = 121[/tex]
The measure of angle ABD is (0.15x+65) and the measure of angle CBD is(0.1x+28) . Find the value of x.
Answer:
x = 348
Step-by-step explanation:
The measure of angle ABD is (0.15x+65) and the measure of angle CBD is(0.1x+28) . Find the value of x.
0.15x + 65 + 0.1x + 28 = 180
0.25x + 93 = 180
0.25x = 180 - 93
0.25x = 87
x = 87/0.25
x = 348
Please solve this and give answer
Answer:
Step-by-step explanation:
ALGEBRICAL EXPRESSIONS
ADD 4y
(3y²+5y-7) and 2(y³-4y²+5)
Answer:
(3y2+5y-7)+2(y3-4y2+5)3y2+5y-7+2y3-8y2+10
3y2-8y2+5y-7+10
-5y2+5y+17
A trapezoid is shown
What is the area of the trapezoid?
A)
21 m2
ing
B)
27 m2
O
34 m2
D)
42 m2
Answer:
what are the letters and numbers by the trapezoid i need them to solve it
Step-by-step explanation:
Answer:
answer 21 m2
Step-by-step explanation:
Area of a trapezoid
side a
5
parallel a,b
side b
9
height h
3
22 digit
area S
21
ASAP PLEASE HELP ME !!!!
Answer:
90 mallards
Step-by-step explanation:
No. of ducks = 200
Mallards = 45%
45% of 200 = 45/100 × 200
=90
what is the sum 3/7 + 1/2
Answer:
13/14
Step-by-step explanation:
3/7+1/2
LCM = 14
6/14+7/14=13/14
Answer:
6/14 + 7/14 = 13/14
A triangle has angle measures of 95° and 65° What is the measure of the third angle
If we work out the question ,
£118.80 divided by 22
on a calculator it comes out as 5.4
How could we write this answer as an amount of money?
Answer:
£5.40
Step-by-step explanation:
just add a zero for it to be pence
marilyns teacher slowed her to take a makeup test she scored 24/60 on the original test and 28/40 on the makeup test by what percentage did marilyn improve her score
Can anyone help me with this question please.
Answer:
Whats the question?
Step-by-step explanation:
I need help asap !!!!! 40 POINTS
Answer:
15
Step-by-step explanation:
x+5/36 = x/27
these are similar triangles
Find the solution of the system of equations.
10x+6y= 16
−10x+5y= 50
Answer:
( − 2 , 6 )
x = − 2
y = 6
Step-by-step explanation:
The volume of a cylinder is 471 cm? If the
height is 6 cm, calculate the radius.
Someone plz help
Answer:
Step-by-step explanation:
Formula for volume of a circle: V=πr²
If you multiply the circle by height, it becomes a cylinder.
Formula for volume of a cylinder: V=πr²h
Plug in the numbers and get r by itself:
471 = πr²(6)
Divide both sides by 6:
78.5 = πr²
Divide both sides by π:
25 = r²
Square root both sides:
[tex]\sqrt{25}[/tex] = [tex]\sqrt{r} \\[/tex]²
5 = r
Radius is 5 cm
Ok can someone please help me? i really need help and no one will help me, its easy middle school math
Answer:
Step-by-step explanation:
7) A
8) D
9) B
10) A
-135/315 x -81/ - 162 x 49/ -27
Assuming that the x is for multiplying, your answer would be 7/18. The decimal is 0.388889. Hope this helped!
NEED Help ASAP I Will GIVE BRAINLIST
What is the measure, in degrees, of angle x?
A
2.3
B
42.7
C
47.3
D
57.3
The sample for a study exhibits undercoverage bias. Select the statement that best describes the bias in the study. O There are not enough subjects in the sample.
O Many of the subjects in the study did not answer every question on the survey.
O The subjects in the study are not representative of the population, because some members of the population were not able to participate in the study.
O The subjects in the study are not representative of the population, because some members of the population refused to take part in the study.
Answer:
The subjects in the study are not representative of the population, because some members of the population were not able to participate in the study.
Step-by-step explanation: i got it right on the test
A sample is said to exhibit undercoverage bias, if some of the portion or category of the population are not adequately represented or exempted from the selected sample. Hence, undercoverage bias exists because, The subjects in the study are not representative of the population, because some members of the population were not able to participate in the study.
Undercoverage bias produces non - representative samples as some category of the population may have been exempeted from the study. Hence, option C is correct.Undercoverage translates that the opinion of some members of the population were not even considered. Hence, the introduction of undercoverage bias.
Learn more : https://brainly.com/question/21774717
30pts + Brainliest to correct answer!!
As indicated below, write the equations of the line passing through the point (2, 2) and perpendicular to the line whose equation is y = x.
Part 1: Point-Slope form of the linear equation
Part 2: Slope-intercept form of the linear equation
Part 3: The general form of the linear equation
Answer:
See answers below
Step-by-step explanation:
Equation of a line in point slope form is expressed as;
y-y0 = m(x-x0)
m is the slope
(x0, y0) is a point on the line
Given the line y = x
The slope of the line is 1.
The slope of the line perpendicular is M = -1
Given the point (2,2)
x0 = 2 and y 0 = 2
Substitute
Recall y-y0 = m(x-x0)
y - 2 = -1(x-2) (Point slope form)
Express in slope intercept form;
y - 2 = -1(x-2)
Make y the subject of the formula;
y -2 = -x + 2
y = -x + 2 + 2
y = -x + 4 (slope intercept form)
The general form of linear equation is expressed as the slope intercept form which is y = -x+4
let y = f(x)
f(x) = -x+4
f(x) = 4-x (Linear equation)
HELPPPPP !!!!!!! Please answer correctly Will mark Brianliest !!!!!!!!!!
Help Please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!111
Answer:8 cups
Step-by-step explanation:
find surface area of this cone
Answer:
SA = 200π cm²
Step-by-step explanation:
The surface area is calculated as
SA = area of base + area of curved surface
= πr² + πrs ( r is the radius and s the slant height )
Using Pythagoras' identity in the right triangle to find s
s² = 15² + 8² = 225 + 64 = 289 ( take square root of both sides )
s = [tex]\sqrt{289}[/tex] = 17
SA = π × 8² + π × 8 × 17
= 64π + 136π
= 200π cm²
what number is halfway between 5.3 and 5.4
Answer:
5.35
Step-by-step explanation:
you can buy 5 cans of black beans for $2.40. What is the unit price?
help me please I beg of you math lords
Answer:
48 cents
Step-by-step explanation:
divsion sorry im not a math lord
An item was sold for Rs 540 with a profit of 5% . What was its cost price?
Write an equation that represents the line.
Use exact numbers.
Answer:
1x-2y
Step-by-step explanation:
You have to go down 2 on the y-axis and over to the right 1 on the x axis
Find the derivative of (3+tan X )( 4+3 Cos X)
The derivative of [tex]f(x) = (3 + \tan x)\cdot (4 + 3\cdot \cos x)[/tex] is [tex]f'(x) = \frac{4+3\cdot \cos x-9\cdot \sin x \cdot \cos^{2}x+3\cdot \sin^{2}x\cdot \cos x}{\cos^{2}x}[/tex].
In this question we shall use the following derivative rules:
Derivative of a sum of functions
[tex]\frac{d}{dt}(f(t) + g(t)) = \frac{df(t)}{dt} + \frac{dg(t)}{dt}[/tex] (1)
Derivative of a product of functions
[tex]\frac{d}{dt}(f(t)\cdot g(t)) = \frac{df(t)}{dt}\cdot g(t) + f(t)\cdot \frac{dg(t)}{dt}[/tex] (2)
Derivative of a constant
[tex]\frac{d}{dt}(k) = 0[/tex], [tex]\forall k \in \mathbb{R}[/tex] (3)
Derivative of a function multiplied by a constant
[tex]\frac{d}{dt}(c\cdot f(t)) = c\cdot \frac{df(t)}{dt}[/tex], [tex]\forall\, c\in \mathbb{R}[/tex] (4)
Derivative of the cosine function
[tex]\frac{d}{dt} \cos t = -\sin t[/tex] (5)
Derivative of the tangent function
[tex]\frac{d}{dt}\tan t = \sec^{2} t[/tex] (6)
Chain rule
[tex]\frac{d}{dt}f[u(t)] = \frac{df(u)}{du}\cdot \frac{du(t)}{dt}[/tex] (7)
Let be [tex]f(x) = (3 + \tan x)\cdot (4 + 3\cdot \cos x)[/tex], then the derivative of [tex]f(x)[/tex] is:
[tex]f'(x) = \sec^{2}x\cdot (4 + 3\cdot \cos x) + (3+\tan x)\cdot (-3\cdot \sin x)[/tex]
[tex]f'(x) = 4\cdot \sec^{2}x+3\cdot \sec x -9\cdot \sin x -3\cdot \sin x\cdot \tan x[/tex]
[tex]f'(x) = \frac{4+3\cdot \cos x}{\cos^{2}x} -\frac{9\cdot \sin x \cdot \cos x+3\cdot \sin^{2}x}{\cos x}[/tex]
[tex]f'(x) = \frac{4+3\cdot \cos x-9\cdot \sin x \cdot \cos^{2}x+3\cdot \sin^{2}x\cdot \cos x}{\cos^{2}x}[/tex]
The derivative of [tex]f(x) = (3 + \tan x)\cdot (4 + 3\cdot \cos x)[/tex] is [tex]f'(x) = \frac{4+3\cdot \cos x-9\cdot \sin x \cdot \cos^{2}x+3\cdot \sin^{2}x\cdot \cos x}{\cos^{2}x}[/tex].
We kindly invite to check this question on derivatives: https://brainly.com/question/21202620
i don’t get scientific notation. can someone help me on this?