Answer: Yes the business made a profit for the month. They made $90,000 net profit. They made a profit of $90,000 after all the taxes were deducted.
Step-by-step explanation: 200 times $1000 = $200,000. $200,000 - $50,000 = $150,000. $150,000 - $40,000 = $110,000. $110,000 - $20,000 = $90,000
Suppose that you roll a die 8 times. What is the probability that you roll a six three or fewer times
Answer:
0.96
Step-by-step explanation:
Given that the a die is rolled 8 number of times.
[tex]n[/tex] = 8
Probability of getting a 6 on roll of a die, [tex]p=\frac{1}{6}[/tex]
Probability of not getting a 6 on roll of a die, [tex]q=1-p=1-\frac{1}{6}=\frac{5}{6}[/tex]
Probability of getting 6 three or fewer times:
[tex]P(r \le 3)=P(r=0)+P(r=1)+P(r=2)+P(r=3)[/tex]
Formula:
[tex]P(r=k)=_nC_k.p^k.q^{n-k}[/tex]
Putting the values using this formula:
[tex]P(r \le 3)=_8C_0.\frac{1}{6}^0.\frac{5}{6}^{8-0}+_8C_1.\frac{1}{6}^1.\frac{5}{6}^{8-1}+_8C_2.\frac{1}{6}^2.\frac{5}{6}^{8-2}+_8C_3.\frac{1}{6}^3.\frac{5}{6}^{8-3}\\\Rightarrow P(r \le 3)=1.\frac{5}{6}^{8}+8.\frac{1}{6}.\frac{5}{6}^{7}+28.\frac{1}{36}^2.\frac{5}{6}^{6}+56.\frac{1}{216}.\frac{5}{6}^{5}\\\Rightarrow P(r \le 3)=0.23+0.37+0.26+0.1=\bold{0.96}[/tex]
If f(x)=x^2 and g(x) =3x-1 find [g • f](x)
Answer:
3x²-1
Step-by-step explanation:
f(x) = x²
g(x) = 3x-1
[g·f](x)
g(f(x))
3(x²)-1
fplzz ans my question
factorize p^4+4
Answer:
Step-by-step explanation:
(p²)²+2²
(p²+2)²-2p²2
(p²+2)²-4p²
(p²+2)²-(2p)²
(p²+2-2p)(p²+2+2p)
Linearize the data. Then find the least squares regression equation
Answer:
C
Step-by-step explanation:
I need to solve for n.
Two angles form a linear pair. The measure of one angle is 6 less then the measure of the other angle. Find the measure of each angle
Answer: one angle would be 50 degrees while the other would be 130 degrees.
Step-by-step explanation:
Hi guys I’m bored can someone talk to me please? :)
Answer:
sure
Step-by-step explanation:
Answer:
hello
Step-by-step explanation:
A florist must make 5 identical
bridesmaid bouquets for a wedding. The budget is
$160, and each bouquet must have 12 flowers. Roses
cost $2.50 each, lilies cost $4 each, and irises cost
$2 each. The florist wants twice as many roses as the
other two types of flowers combined.
Answer:
A. 40x + 10y + 10z = $160
B. 8 Roses, 2 lilies and 2 irises
C.
1. 20x + 5y + 5z = $80
2. 4x + y + z = $16
3. 8x + 2y + 2z = $32
Step-by-step explanation:
Cost for each flower = $160/5 = $32
So we have $32 for each bouquet consisting of 12 flowers each.
Roses = x = $2.50 each
lilies = y = $4 each
irises = z = $2 each
8x + 2y + 2z = $32
8($2.50) + 2($4) + 2($2) = $32
$20 + $8 + $4 = $32
$32 = $32
a. Maximum budget is $160
40x + 10y + 10z = $160
40($2.50) + 10($4) + 10($2) = $160
$100 + $40 + $20 = $160
$160 = $160
b. From above
8x + 2y + 2z = $32
8 Roses, 2 lilies and 2 irises
c. No. There are other solutions If total cost is not limited
1. 20x + 5y + 5z
20($2.50) + 5($4) + 5($2)
$50 + $20 + $10
= $80
2. 4x + y + z
4($2.50) + $4 + $2
$10 + $4 + $2
= $16
3. 8x + 2y + 2z
8($2.50) + 2($4) + 2($2)
$20 + $8 + $4
= $32
Which is a correct way to subtract from a number? (A). Add 100 then subtract 1 (B). Add 100 then add 2. (C). Subtract 100 then add 2 (D). Subtract 100 then add 1.
Answer:
A is the answer
Step-by-step explanation:
According to BODMAS (or DMAS), first we add and then subtract
if both operations are of add, we add it at the same time
An airplane pilot over the Pacific sights a ship wreck at an angle of depression of 5°. At this time, the horizontal distance from the airplane to the wreck is 4629 meters. What is the height of the plane to the nearest meter?
405 m
Answer:
The height of the plane is 405 meters
Step-by-step explanation:
Trigonometric Ratios
The situation can be represented as shown in the image below. The ground, the height H, and the direct distance to the plane to the shipwreck form a right triangle, where the trigonometric ratios stand.
Since the known distance is adjacent to the angle, and the required height is opposite to the given angle, we use the tangent ratio, defined as:
[tex]\displaystyle \tan\ x=\frac{\text{opposite leg}}{\text{adjacent leg}}[/tex]
[tex]\displaystyle \tan 5^\circ=\frac{H}{4629}[/tex]
We need to find H, so we solve for H:
[tex]H=4629\cdot\tan5^\circ[/tex]
H=405 m
The height of the plane is 405 meters
More on Linear Equations & Linear Systems: Question 1
How many solutions does the system of equations below
have?
y - 2x + 2
y-r-1
Select one:
none
infinitely many
O o o o
one
two
Answer:
21
Step-by-step explanation:
show that: (1-sin x)/(cos x)=(sec x - tan x)
This is the step-by-step explanation
I will give brainliest :D
Which equation matches this scenario?
A family buys 8 tickets to a show. They also pay a $5
parking fee. They spend $61 to see the show.
• 5x+8=61
• 61+8x=5
• 8+5x=61
• 8x+5=61
Answer: 8x + 5= 61
Step-by-step explanation: x represents the cost of one ticket for the show, 8 is the amount of tickets, 5 is the extra fee, 61 is the total.
what is the rate of change for the liner relationship modeled in the table?
i'm sorry wheres the picture?
The length of a rectangle is three times the width of the rectangle. The area of the rectangle is 48cm2. Draw the rectangle on the centimetre grid.
Answer:
The width is 4 cm
The length is 12 cm.
Step-by-step explanation:
Area of a rectangle
Given a rectangle of width W and length L, its area is calculated as follows:
[tex]A=W\cdot L[/tex]
The area of the given rectangle is 48 cm^2, and the length is three times the width, thus:
L = 3W
Substituting into the formula of the area:
[tex]W\cdot L=48[/tex]
[tex]W\cdot 3W=48[/tex]
Simplifying:
[tex]3W^2=48[/tex]
Solving:
[tex]W^2=48/3=16[/tex]
[tex]W=\sqrt{16}=4[/tex]
The width is 4 cm. Find the length:
L=3W=3*4= 12
The length is 12 cm.
The image attached shows the rectangle on the centimeter grid
Labor costs. Labor costs for a farmer are $55 per acre for corn and $45 per acre for soybeans. How many acres of each crop should the farmer plant if he wants to spend no more than $6,900 on labor?
Answer:
392984
Step-by-step explanation:
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sub to astronaut gaming i have 27 or 28 subs if you need help finding i will help
Mary used 1/2 of a can of paint to cover 1/8 of the outside of her house. How many cans of paint will Mary need to cover the entire outside of her house?
Answer:
4 cans of paint
Step-by-step explanation:
Half of a can = 1/8 of the outside of the house.
2 halves = whole can of paint
8/2=4
4 cans of paint
Enter the equivalent distance in km in the box.
1 km = 1000 m
1 m = 100 cm
35,000 cm =
km
Answer:
0.350 km
Step-by-step explanation:
Hi there !
35000 cm = 35000/100 m = 350 m
350 m = 350/1000 km = 0.350 km
Good luck !
Use a factor rainbow to determine if 729 is a perfect square. Explain your reasoning.
Answer:
729 is a perfect square
Step-by-step explanation:
because 27 * 27 = 729
Text a friend and write a clear set of instructions on how to find a ratios amount
Answer:
Hi ___
A ratio is created from two numbers it can also be a fraction.
To find a ratio you have to have 2 numbers
You can take these 2 numbers and divide them so they are a unit ratio
For example 3:6 can be reduced to 1:3
Step-by-step explanation:
Hope this helps please give brainliest
please help!!!!!!!!!!!!!!
Answer:
A
Step-by-step explanation:
By solving (x+6)(x-9), we get x^2 - 3x - 54. By looking at our y-intercept, we can see that only option A has the correct intercept.
Answer:
A
Step-by-step explanation:
Review the proof of de Moivre’s theorem (not in order).
Proof of de Moivre's Theorem
[cos(θ) + isin(θ)]k + 1
A = [cos(θ) + isin(θ)]k ∙ [cos(θ) + isin(θ)]1
B = cos(kθ + θ) + isin(kθ + θ)
C = cos(kθ)cos(θ) − sin(kθ)sin(θ) + i[sin(kθ)cos(θ) + cos(kθ)sin(θ)]
D = [cos(kθ) + isin(kθ)] ∙ [cos(θ) + isin(θ)]
E = cos[(k + 1)θ] + isin[(k + 1)θ]
Which steps must be switched to put the proof in order?
steps B and C
steps B and D
steps C and D
steps C and E
Answer:
steps B and D
Step-by-step explanation:
the correct chart is below :)
The steps which must be switched to put the proof in order are steps B and D
Since [cos(θ) + isin(θ)]k + 1
= [cos(θ) + isin(θ)]k ∙ [cos(θ) + isin(θ)]1
= [cos(kθ) + isin(kθ)] ∙ [cos(θ) + isin(θ)]
= cos(kθ)cos(θ) − sin(kθ)sin(θ) + i[sin(kθ)cos(θ) + cos(kθ)sin(θ)]
= cos(kθ + θ) + isin(kθ + θ)
= cos[(k + 1)θ] + isin[(k + 1)θ]
Since the step after A is [cos(kθ) + isin(kθ)] ∙ [cos(θ) + isin(θ)] = D, and the step after C is cos(kθ + θ) + isin(kθ + θ) = B.
So, steps B and D must be switched.
The steps which must be switched to put the proof in order are steps B and D.
Learn more about De Moivre's theorem here:
https://brainly.com/question/11889817
Explain how you would solve -5/8 divided by 2/3 and what the solution is?
Answer:
-15/16
Step-by-step explanation:
-5/8 ÷ 2/3
Copy dot flip
-5/8 * 3/2
Multiply the numerators
-5*3 = -15
Multiply the denominators
8*2 =16
Put the numerator over the denominator
-15/16
6 TH grade math
On a hot day, Myra poured 4 1/8 buckets of water into a plastic wading pool. A few minutes later she added another 3 5/8 buckets. How much water did Myra pour into the pool?
Answer:
7 3/4
Step-by-step explanation:
4 1/8 + 3 5/8
Add the whole numbers, 4 + 3 = 7.
Add the fractions, 1/8 + 5/8 = 6/8.
You get 7 6/8. Simplify 6/8 to get 3/4.
Your answer is 7 3/4.
A system of equations is shown:
2x = -y + 6
--4x + 3y = 8
What is the solution to this system of equations?
0 (-1,-4)
O (1.4)
(4, 1)
(-4,-1)
[tex]\large\underline{\bf \red{Step \:by\: Step \:Explanation:}}[/tex]
Given two equations are :
2x = - y + 6.-4 x + 3y = 8 .We may write them as ,
2x + y - 6 = 0 .................(i) 4x - 3y + 8 = 0 ...............(ii)Multiplying equⁿ (i) by 2 :
⇒ 2(2x + y - 6 ) = 0.
⇒ 4x + 2y - 12 = 0 .....................(iii) .
Subtract equⁿ (ii) from equⁿ (iii) :-
⇒ 4x + 2y - 12 = 0
ㅤ- 4x + 3y - 8 = 0 [ Sign changes ]
__________________
⇒ 5y - 20 = 0.ㅤㅤㅤㅤㅤ
⇒ 5y = 20.
⇒ y = 20/5.
⇒ y = 4
Put this value in (i) to obtain x .
⇒ 2x + y - 6 = 0.
⇒ 2x +4 - 6 = 0.
⇒ 2x - 2 = 0.
⇒2x = 2 .
⇒ x = 2/2.
⇒ x = 1 .
Hence the value of x is 1 & y is 4.
[tex]\boxed{\purple{\bf\pink{\dag}\:Hence\:the\: correct\: option\:is\:[b]\:(1,4)}}[/tex]
7n - 8n - 323
????????????
Answer:
−n−323
Step-by-step explanation:
I WILL BRAINLIST ITS ONLY ONE PROBLEM !!!!!!!!!!!!!!!
Answer:
11/200
Step-by-step explanation:
This is the correct answer boo
in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)
Answer:
The component of [tex]\vec u[/tex] orthogonal to [tex]\vec a[/tex] is [tex]\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)[/tex].
Step-by-step explanation:
Let [tex]\vec u[/tex] and [tex]\vec a[/tex], from Linear Algebra we get that component of [tex]\vec u[/tex] parallel to [tex]\vec a[/tex] by using this formula:
[tex]\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a[/tex] (Eq. 1)
Where [tex]\|\vec a\|[/tex] is the norm of [tex]\vec a[/tex], which is equal to [tex]\|\vec a\| = \sqrt{\vec a\bullet \vec a}[/tex]. (Eq. 2)
If we know that [tex]\vec u =(2,1,1,2)[/tex] and [tex]\vec a=(4,-4,2,-2)[/tex], then we get that vector component of [tex]\vec u[/tex] parallel to [tex]\vec a[/tex] is:
[tex]\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)[/tex]
[tex]\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)[/tex]
[tex]\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)[/tex]
Lastly, we find the vector component of [tex]\vec u[/tex] orthogonal to [tex]\vec a[/tex] by applying this vector sum identity:
[tex]\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}[/tex] (Eq. 3)
If we get that [tex]\vec u =(2,1,1,2)[/tex] and [tex]\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)[/tex], the vector component of [tex]\vec u[/tex] is:
[tex]\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)[/tex]
[tex]\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)[/tex]
The component of [tex]\vec u[/tex] orthogonal to [tex]\vec a[/tex] is [tex]\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)[/tex].