You are driving on the highway at a speed of 40 m/s (which is over the speed limit) when you notice a cop in front of you. To avoid a ticket, you press on the brake and slow to a speed of 30 m/s over the course of 5 seconds. What is the acceleration of the car? SHOW WORK OR GET REPORTED(have 5 accounts)
What is your car's initial velocity?

What is your car's final velocity?

How long does it take the car to slow down?

Write the equation you will use to solve this problem.

What is the acceleration of your vehicle?
+ 2.0 m/s^2
- 2.0 m/s^2
+ 8.0 m/s^2
- 6.0 m/s^2

Answer:

m = 0.164 kg

Explanation:

T (period)

k (force/spring constant)

m (mass)

T = 2*Pi*sqrt(m/k)

T/(2*Pi) = sqrt(m)/sqrt(k)

(T/(2*Pi))*sqrt(k) = sqrt(m)

m = ((T/(2*Pi))*sqrt(k))^2

m = 4.5*((1.2/(2*Pi)))^2

m = 0.1641403175

Complete Question

The diagram of with this question is shown on the first uploaded image

Answer:

The value is  [tex]v = -6.543 \^ i + 9.47 \^ j + 0 \^ k[/tex]

Explanation:

From the question we are told that

   The mass of the rock is  [tex]m = 0.250 \ kg[/tex]

    The length of the string is  [tex]L = 0.75 \ m[/tex]

    The angle the string makes horizontal is  [tex]\theta = 11.9^o[/tex]

     The angle which the projection of the string onto  the xy -plane makes with the positive x-axis is  [tex]\phi = 34.6^o[/tex]

    The angular velocity of the rock is  [tex]w = 2.50 rev/s = 2.50 * 2\pi =15.7 \ rad/s[/tex]

Generally the radius of the circle made by the length of the string is mathematically represented as

               [tex]r = L cos(\theta )[/tex]

=>            [tex]r = 0.75 cos(11.9 )[/tex]

=>            [tex]r = 0.734 \ m[/tex]

Generally the resultant tangential velocity is mathematically represented as

      [tex]v__{R}} = w * r[/tex]

=>  [tex]v__{R}} = 15.7 *0.734[/tex]

=>  [tex]v__{R}} = 11.5 \ m/s[/tex]

Generally the tangential velocity along the x-axis is  

      [tex]v_x = -v__{R}} * sin(\phi)[/tex]

=>   [tex]v_x =- 11.5 * sin(34.6)[/tex]

=>   [tex]v_x = -6.543 \ m/s[/tex]

The negative sign show that the velocity is directed toward the negative x-axis

Generally the tangential velocity along the y-axis is  

      [tex]v_y = v__{R}} * cos(\phi)[/tex]

=>   [tex]v_y = 11.5 * cos(34.6)[/tex]

=>   [tex]v_y = 9.47 \ m/s[/tex]

Generally the tangential velocity along the y-axis is  

      [tex]v_z = v__{R}} * cos(90)[/tex]

=>   [tex]v_z = 0 \ m/s[/tex]

Generally the tangential velocity at that instant is mathematically represented as

       [tex]v = -6.543 \^ i + 9.47 \^ j + 0 \^ k[/tex]

Answer:

255N

Explanation:

Given parameters:

Mass of barrel  = 75kg

Acceleration  = 3.4m/s²

Unknown:

Force exerted  = ?

Solution:

Force is the product of mass and acceleration according to Newton's second law of motion.

  Force  = mass x acceleration

Now insert given parameters and solve,

       Force  = 75 x 3.4  = 255N

The net force on the barrel is the sum of the pulling force (magnitude p, acting upward) and the barrel's weight (mag. w, opposing p ). So by Newton's second law,

∑ F = p - w = m a

p = w + m a

p = m g + m a

p = m (g + a)

p = (75 kg) (9.80 m/s² + 3.4 m/s²)

p = 990 N

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Answer:

i) a = 0.977 [m/s²]

ii) x = 115.06 [m]

Explanation:

In order to determine the acceleration, we must use the following equation of kinematics.

[tex]v_{f} ^{2} =v_{o} ^{2} -2*a*x[/tex]

where:

Vf = final velocity = 7 [m/s]

Vo = initial velocity = 15 [m/s]

a = acceleration [m/s²]

x = displaciment = 90 [m]

Now replacing:

[tex](7)^{2} =(15)^{2} -2*a*90\\2*a*90 = 15^{2} - 7^{2} \\180*a=176\\a=0.977[m/s^{2}][/tex]

When the bus coming to rest.

[tex]v_{f}^{2} =v_{o} ^{2} -2*a*x\\0 = 15^{2} -2*0.977*x\\x = 115.06[m][/tex]

Answer:

that is cool and i have one interesting fact

Explanation: North Korea and Cuba are the only places you can't buy Coca-Cola

Answer:

4

Explanation:

As you can see in the free body diagram there are 4 forces acting on the body.

Answer:

tetrahedral shape.

Explanation:

Answer:

Molecular Geometries. The VSEPR theory describes five main shapes of simple molecules: linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral. Apply the VSEPR model to determine the geometry of molecules where the central atom contains one or more lone pairs of electrons.