Answer:
124.5 ft
Step-by-step explanation:
Draw a figure. It is a triangle.
Kite
B | \
| \
| \
| \ string
| \
| \
| \
| \
| __ 50 deg \
C |----|---------------------------------------- A
fence 80 ft you are here
You are at point A. The kite is at point B. The fence is at point C. Angle C is a right angle.
The length of the string is the hypotenuse of the triangle, side AB. The bottom side of the triangle, side AC, the ground, is the adjacent leg for angle A.
The trig ratio that relates the adjacent leg to the hypotenuse is the cosine.
[tex] \cos A = \dfrac{adj}{hyp} [/tex]
[tex] \cos 50^\circ = \dfrac{AC}{AB} [/tex]
[tex] \cos 50^\circ = \dfrac{80}{AB} [/tex]
[tex] AB \cos 50^\circ = 80 [/tex]
[tex] AB = \dfrac{80}{\cos 50^\circ} [/tex]
[tex] AB = 124.5 [/tex]
Answer: 124.5 ft
Solve the following proportion for 17/13=9/u
Answer:
u = 6.88Solution,
[tex] \frac{17}{13} = \frac{9}{u} [/tex]
Sinplify the equation using cross multiplication
[tex]17 \times u = 13 \times 9[/tex]
Calculate the product
[tex]17u = 117[/tex]
Divide both sides of the equation by 17
[tex] \frac{17u}{17} = \frac{117}{17} [/tex]
Calculate
[tex]u = 6.88[/tex]
Hope this helps...
Good luck on your assignment..
Find the point, Q, along the directed line segment AB that
divides AB into the ratio 2:3. The 2:3 ratio means that the line
should be broken up in to 5 equal sections (2 + 3 = 5). This
means that each of the 5 sections can be represented by the
expression AB/5. Therefore, the point that divides AB into the
ratio 2:3 is the distance (AB/5)(2) from A.
Answer:
Point Q is at a distance of 4.7 units from A.
Step-by-step explanation:
From the graph, AC = 10 units and BC = 6 units. Applying the Pythagoras theorem,
[tex]AB^{2}[/tex] = [tex]AC^{2}[/tex] + [tex]BC^{2}[/tex]
= [tex]10^{2}[/tex] + [tex]6^{2}[/tex]
= 100 + 36
= 136
AB = [tex]\sqrt{136}[/tex]
AB = 11.6619
AB = 11.66
≅ 11.7 units
But point Q divides AB into ratio 2:3. Therefore:
AQ = [tex]\frac{2}{5}[/tex] × AB
= [tex]\frac{2}{5}[/tex] × 11.66
= 4.664
AQ = 4.664
AQ ≅ 4.7 units
QB = [tex]\frac{3}{5}[/tex] × AB
= [tex]\frac{3}{5}[/tex] × 11.66
= 6.996
QB ≅ 7.0 units
So that point Q is at a distance of 4.7 units from A.
An item is regularly priced at $83. It is on sale for 95% off the regular price.
Answer:
Step-by-step explanation:
Regular price = $ 83
Discount = 95% of 83
= 0.95 * 83
= $ 78.85
Price after discount = 83 - 78.85
= $ 4.15
Answer:
$4.15
Step-by-step explanation:
Multiply 83 by .05 to get the new price of $4.15. Additionally, multiply 83 by .95 to get the amount taken off ($78.85).
How do I construct bisectors, angles, & segments?
Answer:
Step-by-step explanation:
These come directly from my textbook, so I'm not sure if your teacher will accept this kind of work.
1. Angle construction:
Given an angle. construct an angle congruent to the given angle.
Given: Angle ABC
Construct: An angle congruent to angle ABC
Procedure:
1. Draw a ray. Label it ray RY.
2. Using B as center and any radius, draw an arc that intersects ray BA and ray BC. Label the points of intersection D and E, respectively.
3. Using R as center and the same radius as in Step 2, draw an arc intersecting ray RY. Label the arc XS, with S being the point where the arc intersects ray RY.
4. Using S as center and a radius equal to DE, draw an arc that intersects arc XS at a point Q.
5. Draw ray RQ.
Justification (for congruence): If you draw line segment DE and line segment QS, triangle DBE is congruent to triangle QRS (SSS postulate) Then angle QRS is congruent to angle ABC.
You can probably also Google videos if it's hard to imagine this. Sorry, construction is super hard to describe.
what is 1000 x 10 -5000 +23 - 93 giving brainist thanks!!!
Answer:
Step-by-step explanation:
We must use PEMDAS for this answer.
First, we must multiply 1000 and 10.
10,000-5000+23-93
Next, we must subtract 10,000 and 5,000
5000+23-93
Add 5000 and 23
5023-93
For our final step, subtract and you get your answer.
4,930
Use the data below, showing a summary of highway gas mileage for several observations, to decide if the average highway gas mileage is the same for midsize cars, SUV’s, and pickup trucks. Test the appropriate hypotheses at the α = 0.01 level.
n Mean Std. Dev.
Midsize 31 25.8 2.56
SUV’s 31 22.68 3.67
Pickups 14 21.29 2.76
Answer:
Step-by-step explanation:
Hello!
You need to test at 1% if the average highway gas mileage is the same for three types of vehicles (midsize cars, SUV's and pickup trucks) to compare the average values of the three groups altogether, you have to apply an ANOVA.
n | Mean | Std. Dev.
Midsize | 31 | 25.8 | 2.56
SUV’s | 31 | 22.68 | 3.67
Pickups | 14 | 21.29 | 2.76
Be the study variables :
X₁: highway gas mileage of a midsize car
X₂: highway gas mileage of an SUV
X₃: highway gas mileage of a pickup truck.
Assuming these variables have a normal distribution and are independent.
The hypotheses are:
H₀: μ₁ = μ₂ = μ₃
H₁: At least one of the population means is different.
α: 0.01
The statistic for this test is:
[tex]F= \frac{MS_{Treatment}}{MS_{Error}}[/tex]~[tex]F_{k-1;n-k}[/tex]
Attached you'll find an ANOVA table with all its components. As you see, to manually calculate the statistic you have to determine the Sum of Squares and the degrees of freedom for the treatments and the errors, next you calculate the means square for both and finally the test statistic.
For the treatments:
The degrees of freedom between treatments are k-1 (k represents the amount of treatments): [tex]Df_{Tr}= k - 1= 3 - 1 = 2[/tex]
The sum of squares is:
SSTr: ∑ni(Ÿi - Ÿ..)²
Ÿi= sample mean of sample i ∀ i= 1,2,3
Ÿ..= grand mean, is the mean that results of all the groups together.
So the Sum of squares pf treatments SStr is the sum of the square of difference between the sample mean of each group and the grand mean.
To calculate the grand mean you can sum the means of each group and dive it by the number of groups:
Ÿ..= (Ÿ₁ + Ÿ₂ + Ÿ₃)/ 3 = (25.8+22.68+21.29)/3 = 23.256≅ 23.26
[tex]SS_{Tr}[/tex]= (Ÿ₁ - Ÿ..)² + (Ÿ₂ - Ÿ..)² + (Ÿ₃ - Ÿ..)²= (25.8-23.26)² + (22.68-23.26)² + (21.29-23.26)²= 10.6689
[tex]MS_{Tr}= \frac{SS_{Tr}}{Df_{Tr}}= \frac{10.6689}{2}= 5.33[/tex]
For the errors:
The degrees of freedom for the errors are: [tex]Df_{Errors}= N-k= (31+31+14)-3= 76-3= 73[/tex]
The Mean square are equal to the estimation of the variance of errors, you can calculate them using the following formula:
[tex]MS_{Errors}= S^2_e= \frac{(n_1-1)S^2_1+(n_2-1)S^2_2+(n_3-1)S^2_3}{n_1+n_2+n_3-k}= \frac{(30*2.56^2)+(30*3.67^2)+(13*2.76^2)}{31+31+14-3} = \frac{695.3118}{73}= 9.52[/tex]
Now you can calculate the test statistic
[tex]F_{H_0}= \frac{MS_{Tr}}{MS_{Error}} = \frac{5.33}{9.52}= 0.559= 0.56[/tex]
The rejection region for this test is always one-tailed to the right, meaning that you'll reject the null hypothesis to big values of the statistic:
[tex]F_{k-1;N-k;1-\alpha }= F_{2; 73; 0.99}= 4.07[/tex]
If [tex]F_{H_0}[/tex] ≥ 4.07, reject the null hypothesis.
If [tex]F_{H_0}[/tex] < 4.07, do not reject the null hypothesis.
Since the calculated value is less than the critical value, the decision is to not reject the null hypothesis.
Then at a 1% significance level you can conclude that the average highway mileage is the same for the three types of vehicles (mid size, SUV and pickup trucks)
I hope this helps!
For the binomial distribution with the given values for n and p, state whether or not it is suitable to use the normal distribution as an approximation. n = 24 and p = 0.6.
Answer:
Since both np > 5 and np(1-p)>5, it is suitable to use the normal distribution as an approximation.
Step-by-step explanation:
When the normal approximation is suitable?
If np > 5 and np(1-p)>5
In this question:
[tex]n = 24, p = 0.6[/tex]
So
[tex]np = 24*0.6 = 14.4[/tex]
And
[tex]np(1-p) = 24*0.6*0.4 = 5.76[/tex]
Since both np > 5 and np(1-p)>5, it is suitable to use the normal distribution as an approximation.
Use slopes to determine if the lines 5x−4y=−1 and 4x−y=−9 are perpendicular.
Answer:
Not perpendicular
Step-by-step explanation:
Convert it to y-intercept form first:
5x - 4y = -1
-4y = -5x - 1
y = 5/4x + 1/4
4x - y = -9
-y = -4x - 9
y = 4x + 9
y = 5/4x + 1/4
y = 4x + 9
From the slopes, they are not considered perpendicular because one of the line slope is not a negative reciprocal of the other line slope.
Answer:
The lines are not perpendicular.
Step-by-step explanation:
If the lines are perpendicular, the product of the slopes should be -1.
These equations are in standard form (Ax + By = C), so we can easily find the slopes through using equation: slope= - A / B
For line 5x−4y=−1,
slope = -A / B
= - 5 /- 4
= 5/4
For line 4x−y=−9
slope = -A / B
= - 4 / -1
= 4
Now multiply the slopes to find the product:
5 /4 x 4
= 5
Since 5 ≠ -1, the lines are not perpendicular.
The foundation of a building is in the shape of a rectangle, with a length of 20 meters (m) and a width of 18 m. To the nearest meter, what is the distance from the top left corner of the foundation to the bottom right corner?
Answer:
27m
Step-by-step explanation:
It's the Pythagorean Theorem.
20^2+18^2=c^2
400+324=c^2
724=c^2
take the square root of both sides
26.9m=c
to the nearest meter = 27
Find the Area of this shape
Answer:
42.5
Step-by-step explanation:
see attached image.
Answer:
42.5
Step-by-step explanation:
So first we have to split this shape into many parts
The simplest way we can do that is by simply drawing a line between the small square and the big rectangle.
Now we calculate the area of each part.
1. Big rectangle
--> So we would just simply multiply the length and width for this one which is 3.5 by 9 --> 3.5 x 9 = 31.5
2. (Left) Right Triangle
Since it's a right triangle we can simply multiply it's L and W then divide by 2
--> 2 x 2 = 4 --> 4/2 = 2
3. (Right) Right Triangle
Same way as previous right triangle l x w / 2
--> 2 x 5 = 10 --> 10/2 = 5
4. Square (Bottom)
And lastly, we have the small square at the bottom
--> l x w = area.
-->given 9 = 2 + x + 5,
x = 9 - 7 --> x = 2
so, 2 x 2 = area --> . 4
Calculate the actual area. of the whole entire shape -->
So this is very simple we just add the area of the shapes (area) we calculated below.
--> 31.5 + 2 + 5 + 4
--> Add parenthasees 31.5 + (2 + 5 + 4)
[To make calculating simpler]
=> 11 + 31.5
=> 32.5 + 10
=> 42.5
Hope this helps!
Suppose we write down the smallest positive 2-digit, 3-digit, and 4-digit multiples of 9,8 and 7(separate number sum for each multiple). What is the sum of these three numbers?
Answer:
Sum of 2 digit = 48
Sum of 3 digit = 317
Sum of 4 digit = 3009
Total = 3374
Step-by-step explanation:
Given:
9, 8 and 7
Required
Sum of Multiples
The first step is to list out the multiples of each number
9:- 9,18,....,99,108,117,................,999
,1008
,1017....
8:- 8,16........,96,104,...............,992,1000,1008....
7:- 7,14,........,98,105,.............,994,1001,1008.....
Calculating the sum of smallest 2 digit multiple of 9, 8 and 7
The smallest positive 2 digit multiple of:
- 9 is 18
- 8 is 16
- 7 is 14
Sum = 18 + 16 + 14
Sum = 48
Calculating the sum of smallest 3 digit multiple of 9, 8 and 7
The smallest positive 3 digit multiple of:
- 9 is 108
- 8 is 104
- 7 is 105
Sum = 108 + 104 + 105
Sum = 317
Calculating the sum of smallest 4 digit multiple of 9, 8 and 7
The smallest positive 4 digit multiple of:
- 9 is 1008
- 8 is 1000
- 7 is 1001
Sum = 1008 + 1000 + 1001
Sum = 3009
Sum of All = Sum of 2 digit + Sum of 3 digit + Sum of 4 digit
Sum of All = 48 + 317 + 3009
Sum of All = 3374
The solutions to the inequality y < to -x+1 sre shaded on the graph. Which point is a solution
There are two ways to confirm this is the answer. The first is to note that (3,-2) is on the boundary, so it is part of the solution set. This only works if the boundary line is a solid line (as opposed to a dashed or dotted line).
The second way is to plug (x,y) = (3,-2) into the given inequality to find that
[tex]y \le -x+1\\\\-2 \le -3+1\\\\-2 \le -2[/tex]
which is a true statement. So this confirms that (3,-2) is in the solution set of the inequality.
Kara categorized her spending for this month into four categories: Rent, Food, Fun, and Other. The amounts she spent in each category are pictured here. Rent $433 Food $320 Fun $260 Other $487 What percent of her total spending did she spend on Rent? % (Please enter your answer to the nearest whole percent.) What percent of her total spending did she spend on Food? % (Please enter your answer to the nearest whole percent.) What percent of her total spending did she spend on Fun? % (Please enter your answer to the nearest whole percent.)
Answer: Rent = 29%, Food = 21%, Fun = 17%
Step-by-step explanation:
Rent = $433
Food = $320
Fun = $260
Other = $487
TOTAL = $1500
[tex]\dfrac{Rent}{Total}=\dfrac{433}{1500}\quad =0.2886\quad =\large\boxed{29\%}\\\\\\\dfrac{Food}{Total}=\dfrac{320}{1500}\quad =0.2133\quad =\large\boxed{21\%}\\\\\\\dfrac{Fun}{Total}=\dfrac{260}{1500}\quad =0.1733\quad =\large\boxed{17\%}[/tex]
When 440 junior college students were surveyed, 200 said they have a passport. Construct a 95% confidence interval for the proportion of junior college students that have a passport.
The Confidence Interval is 0.403 < p < 0.497
What is Confidence Interval?The mean of your estimate plus and minus the range of that estimate constitutes a confidence interval. Within a specific level of confidence, this is the range of values you anticipate your estimate to fall within if you repeat the test. In statistics, confidence is another word for probability.
Given:
Sample proportion = 190/425
= 0.45
Now, [tex]\mu[/tex] = 1.96 x √[0.45 x 0.55/425]
[tex]\mu[/tex] = 0.047
So, 95% CI:
0.45-0.047 < p < 0.45+0.047
0.403 < p < 0.497
Learn more about Confidence Interval here:
https://brainly.com/question/24131141
#SPJ5
You can model that you expect a 1.25% raise each year that you work for a certain company. If you currently make $40,000, how many years should go by until you are making $120,000? (Round to the closest year.)
Answer:
94 years
Step-by-step explanation:
We can approach the solution using the compound interest equation
[tex]A= P(1+r)^t[/tex]
Given data
P= $40,000
A= $120,000
r= 1.25%= 1.25/100= 0.0125
substituting and solving for t we have
[tex]120000= 40000(1+0.0125)^t \\\120000= 40000(1.0125)^t[/tex]
dividing both sides by 40,000 we have
[tex](1.0125)^t=\frac{120000}{40000} \\\\(1.0125)^t=3\\\ t Log(1.0125)= log(3)\\\ t*0.005= 0.47[/tex]
dividing both sides by 0.005 we have
[tex]t= 0.47/0.005\\t= 94[/tex]
Suppose the following items were on a menu:_________.
a. Soup - Miso(M) or Lentil Bean (L)
b. Salad - Fresh Greens (G) or Fruit (F)
c. Entrees - Pasta Primavera (P) or Black Bean Burger (B)
If we are to select one of each (soup, salad, entrée), what is the sample space? (show all of the combinations, like in a tree diagram or using the 3 letters)
Answer:
{MGP,MGB,MFP,MFB,LGP,LGB,LFP,LFB}
Step-by-step explanation:
Soup - Miso(M) or Lentil Bean (L): Types of Soup =2
Salad - Fresh Greens (G) or Fruit (F): Types of Salad =2
Entrees - Pasta Primavera (P) or Black Bean Burger (B): Types of Entrees =2
Therefore, the sample space will have a total of 2X2X2=8 combinations.
If we are to select one of each, the sample space will be:
S={MGP,MGB,MFP,MFB,LGP,LGB,LFP,LFB}
what is the product?
(x-3)(2x²-5x+1)
C) 2x³-11x²+16x-3
Answer:
2x^3-11x^2+16x-3
Step-by-step explanation:
1) multiply each term inside the parentheses with all other terms:
(x*2x^2)=2x^3
x*-5x=-5x^2
x*1=x
-3*2x^2=-6x^2
-3*-5x=15x
and
-3*1=-3
so
2x^3-5x^2+x-6x^2+15x-3
is our equation
to simplify:
2x^3-11x^2+16x-3 is the answer
ASAP NEED HELP PRETTY PLEASEAssuming that the petals of the flower are congruent, how many lines of symmetry does the figure have? A. 0 B. 4 C. 6 D. 8
Answer:
Hey there!
This flower has 8 lines of symmetry.
Hope this helps :)
Solve the equation -4x + 7 y equals 20. Y=3x+15
Substitue what y equals for y and solve.
[tex]
-4x+7(3x+15)=20 \\
-4x+27x+105=20 \\
23x=-85 \\
x=-\boxed{\frac{85}{23}}
[/tex]
Hope this helps.
Find the first four nonzero terms in a power series expansion about xequals0 for the solution to the given initial value problem. w prime prime plus 3 xw prime minus wequals0; w(0)equals4, w prime (0 )equals0
Answer:
The first four terms are;
w(x)= 4 + 2x² - ⁵/₆x⁴+ ¹¹/₃₆x⁶ +......
Step-by-step Explanation:
This is the interpretation of the question
w″ + 3xw′ -w=0
W(0)=4
W′(0)=0
CHECK THE ATTACHMENT FOR STEP BY STEP EXPLANATION
Classify the hypothesis test as two-tailed, left-tailed, or right-tailed. At one school, the average amount of time that spend watching television each week is The principal introduces a campaign to encourage the students to watch less television. One year later, the principal wants to perform a hypothesis test to determine whether the average amount of time spent watching television per week has decreased from the previous mean of
Answer:
Left tailed test
Step-by-step explanation:
A two tailed test usually determined by the alternative hypothesis involves both the less than and the greater than option.
A left tailed test corresponds to an alternative hypothesis having just one of either options (less than and the greater than option) usually the less than option.
A right tailed test corresponds to an alternative hypothesis having just one of either options (less than and the greater than option) usually the greatest than option.
In this experiment, the null hypothesis is the average amount of time that spend watching television each week is ---
He introduces a campaign to encourage the students to watch less television and then performs a hypothesis test to determine whether the average amount of time spent watching television per week has decreased. The alternative hypothesis would be: u < ---. This means that this test is a left tailed test.
Evelyn wants to estimate the percentage of people who own a tablet computer she surveys 150 indvidals and finds that 120 own a tablet computer. Identify the values needed to calculate a confidence interval at the 99% confidence level. Then find the confidence interval.
0.10 0.05 0.025 0.01 0.005
1.282 1.645 1.960 2.326 2 576
Answer:
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
Step-by-step explanation:
Confidence interval for the proportion of people who own a tablet:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
[tex]n = 150, \pi = \frac{120}{150} = 0.8[/tex]
99% confidence level
So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.576[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{150}} = 0.7159[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{150}} = 0.8841[/tex]
Percentage:
Multiply the proportion by 100.
0.7159*100 = 71.59%
0.8841*100 = 88.41%
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
What is coefficient of the term of degree of degree 5 in the polynomial below 3x^6+5-x^2+4x^5-9 which one is the right answer and how would i show my work in a explanation.? A. 3 B. 4 C. 6 D. 5
Answer:
B. 4
Step-by-step explanation:
We are looking for the coefficient of the term x⁵. When we see it in the polynomial as 4x⁵, our coefficient and answer would then be 4.
This is an identification problem. You look for the term and you determine the coefficient. It's just look, find, and answer.
What is the simplified form of this expression?
(-3x^2+ 2x - 4) + (4x^2 + 5x+9)
OPTIONS
7x^2 + 7x + 5
x^2 + 7x + 13
x^2 + 11x + 1
x^² + 7x+5
Answer:
Option 4
Step-by-step explanation:
=> [tex]-3x^2+2x-4 + 4x^2+5x+9[/tex]
Combining like terms
=> [tex]-3x^2+4x^2+2x+5x-4+9[/tex]
=> [tex]x^2+7x+5[/tex]
Which statement is true about the steps that Pablo used to simplify the expression?
The monthly profit for a company that makes decorative picture frames depends on the price per frame. The company determines that the profit is approximated by f(p)= -80p + 3440p -36,000, where p is the price per frame and f(p) is the monthly profit based on that price.
Requried:
a. Find the price that generates the maximum profit.
b. Find the maximum profit.
c. Find the price(s) that would enable the company to break even.
Answer:
a. $21.50
b. $980
c. $25 and $18
Step-by-step explanation:
a. The price that generates the maximum profit is
In this question we use the vertex formula i.e shown below:
[tex](-\frac{b}{2a}, f(-\frac{b}{2a} ))\\\\[/tex]
where a = -80
b = 3440
c = 36000
hence,
P-coordinate is
[tex](-\frac{b}{2a}, (-\frac{3440}{2\times -80} ))\\\\[/tex]
[tex]= \frac{3440}{160}[/tex]
= $21.5
b. Now The maximum profit could be determined by the following equation
[tex]f(p) = 80p^2 + 3440p - 36000\\\\f($21.5) = -80(21.5)^2 + 3440(21.5) - 36000\\\\[/tex]
= $980
c. The price that would enable the company to break even that is
f(p) = 0
[tex]f(p) = -80p^2 + 3440p - 36000\\\\-80p^2 + 3440p - 36000 = 0\\\\p^2 -43p + 450 = 0\\\\p^2 - 25p - 18p + 450p = 0\\\\p(p - 25) - 18(p-25) = 0\\\\(p - 25) (p - 18) = 0[/tex]
By applying the factoring by -50 and then divided it by -80 and after that we split middle value and at last factors could come
(p - 25) = 0 or (p - 18) = 0
so we can write in this form as well which is
p = 25 or p = 18
Therefore the correct answer is $25 and $18
(a +2b)2 + 4b² - a²
Answer:
a^2+4b^2+2a+4b
Step-by-step explanation:
(a +2b)2 + 4b² - a²
=2a+4b+4b^2+a^2
=a^2+4b^2+2a+4b
A survey of 400 non-fatal accidents showed that 189 involved the use of a cell phone. Determine a point estimate for p, the population proportion of non-fatal accidents that involved the use of a cell phone.
Answer:
[tex] X= 189[/tex] represent the number of non-fatal accidents involved the use of a cell phone
[tex] n=400[/tex] represent the sample size
And we want to find a point estimate for p, the population proportion of non-fatal accidents that involved the use of a cell phone and we can use the following formula:
[tex]\hat p=\frac{X}{n}[/tex]
And replacing we got:
[tex] \hat p=\frac{189}{400}=0.4725[/tex]
Step-by-step explanation:
For this problem we have the following info given:
[tex] X= 189[/tex] represent the number of non-fatal accidents involved the use of a cell phone
[tex] n=400[/tex] represent the sample size
And we want to find a point estimate for p, the population proportion of non-fatal accidents that involved the use of a cell phone and we can use the following formula:
[tex]\hat p=\frac{X}{n}[/tex]
And replacing we got:
[tex] \hat p=\frac{189}{400}=0.4725[/tex]
The line x + y - 6= 0 is the right bisector
of the segment PQ. If P is the point (4,3),
then the point Q is
Answer:
Therefore, the coordinates of point Q is (2,3)
Step-by-step explanation:
Let the coordinates of Q be(a,b)
Let R be the midpoint of PQ
Coordinates of R [tex]=(\frac{4+a}{2}, \frac{3+b}{2})[/tex]
R lies on the line x + y - 6= 0, therefore:
[tex]\implies \dfrac{4+a}{2}+ \dfrac{3+b}{2}-6=0\\\implies 4+a+3+b-12=0\\\implies a+b-5=0\\\implies a+b=5[/tex]
Slope of AR X Slope of PQ = -1
[tex]-1 \times \dfrac{b-3}{a-4}=-1\\b-3=a-4\\a-b=-3+4\\a-b=-1[/tex]
Solving simultaneously
a+b=5
a-b=-1
2a=4
a=2
b=3
Therefore, the coordinates of point Q is (2,3)
what's the equivalent expression
Answer:
2^52
Step-by-step explanation:
(8^-5/2^-2)^-4 = (2^-15/2^-2)^-4= (2^-13)^-4= 2^((-13*(-4))= 2^52