You have available three blocks of different material, at various temperatures. They are, respectively, a 2 kg block of iron at 600 K, a 3 kg block of copper at 800 K and a 10 kg block of granite at 300 K. The heat capacities for the three materials are 0.460 (iron), 0.385 (copper), and 0.790 (granite), in kj/(kg*K), all independent of temperature. For solids, the heat capacities at constant pressure and constant volume can be assumed to be equal, Cp=Cv. what is the minimum temperature that could be obtained in any one of the block? what is the maximum temperature that could be obtained? no heat or work interactions with the enviroment are allowed.
Answers
Answer:
max temp = 711.32 k
mini temp = 331.29 k
Explanation:
Given data:
2kg block of Iron : temperature = 600k , C = 0.460 kJ/kgk
3 kg block of copper : temp = 800k , C = 0.385 KJ /kgk
10 kg block of granite : temp = 300k , C = 0.790 KJ/kgk
Cp = Cv at constant pressure and constant volume
Determine the minimum temperature that is obtained in any one of the block
considering the heat transfer equation
Q = mC ( T2 - T1 )
attached below is a detailed solution of the problem
Related Questions
A continuous and aligned fiber-reinforced composite is to be produced consisting of 30 vol% aramid fibers and 70 vol% of a polycarbonate matrix; mechanical characteristics of these two materials are as follows:
Modulus of Elasticity [GPa] Tensile Strength [MPa] Aramid fiber 131 3600 Polycarbonate 2.4 65
Also, the stress on the polycarbonate matrix when the aramid fibers fail is 45 MPa. For this composite, compute the following:
(a) the longitudinal tensile strength, and
(b) the longitudinal modulus of elasticity
Answers
Answer:
1. 1111.5MPa
2. 56.1GPa
Explanation:
1. Longitudinal tensile stress can be obtained by obtaining the strength and volume of the fiber reinforcement. The derived formula is given by;
σcl = σm (1 - Vf) + σfVf
Substituting the figures, we will have;
45(1 - 0.30) + 3600(0.30)
45(0.70) + 1080
31.5 + 1080
= 1111.5MPa
2. Longitudinal modulus of elasticity or Young's modulus is the ability of an object to resist deformation. The derived formula is given by;
Ecl = EmVm + EfVf
Substituting the formula gives;
= 2.4 (1 - 0.30) + 131 (0.30)
= 2.4(0.70) + 39.3
= 16.8 + 39.3
= 56.1GPa
Using the appropriate relation, the longitudinal tensile stress and the longitudinal modulus are 1111.50 and 56.10 respectively.
Longitudinal tensile stress can be obtained using the relation :
σcl = σm (1 - Vf) + σfVfSubstituting the values into the relation:
45(1 - 0.30) + 3600(0.30)
45 × 0.70 + 1080
31.5 + 1080
= 1111.50 MPa
2.)
Longitudinal modulus of elasticity is obtained using the relation :
Ecl = EmVm + EfVfSubstituting the values thus :
2.4 (1 - 0.30) + 131 (0.30)
= 2.4 × 0.70 + 39.3
= 16.8 + 39.3
= 56.10 GPa
Hence, the longitudinal tensile stress and the longitudinal modulus are 1111.50 and 56.10 respectively.
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Most methods of transportation rely on some sort of infrastructure to drive, steer, navigate, or direct at some point or another in a journey. Which category of transportation system is least reliant on infrastructure?(1 point)
Answers
Answer:
Most methods of transportation rely on some sort of infrastructure to drive, steer, navigate, or direct at some point or another in a journey. Which category of transportation system is least reliant on infrastructure?(1 point). road
Explanation:
Hard steering can be caused by
Answers
Answer:
Lack of fluid oil – lack of fluid oil in your vehicle, or a fluid leakage, can lead to heavy steering. If there is a lack of fluid oil, or a leak, this can reduce the pressure in the system, meaning the steering wheel does not receive enough supply of fluid to perform freely.
if you are running and you fall and everyone↓↓↓↓↓↓↓ passes you how can you still be in first place??
ik the answer but lets see if you know it twooo
Answers
A runner ran a 600 m race in 2 min 17 seconds. Calculate his average speed in m/sec.
Answers
Please help me it’s for science I only have a few minutes
Answers
Answer:
Rocks
Explanation:
I am not sure tho bc they are made out of coal and I think coal is a kind of rock
Answer:
I'm taking a guess for ya I shall say Metal or and Minerals
Explanation:
Good luck
How does the length and direction of a shadow change from sunrise to noon in the northern hemisphere? A: The shadow gets shorter and points more east B: The shadow gets shorter and points more north C: The shadow gets longer and points more north D: The shadow gets shorter and points more west E: The shadow gets longer and points more south F: The shadow gets longer and points more east
Answers
Answer: the answer is A
Explanation: because the sun rises in the west and goes down in the east
An interior beam supports the floor of a classroom in a school building. The beam spans 26 ft. and the tributary width is 16 ft. Dead load is 20 psf. Find:
a. Basic floor live load Lo in psf
b. Reduced floor live load L in psf
c. Uniformly distributed total load to the beam in lb/ft.
d. Compare the loading in part c with the alternate concentrated load requried by the Code. Which loading is more critical for bending, shear, and deflection.?
Answers
Answer:
a. [tex]L_o[/tex] = 40 psf
b. L ≈ 30.80 psf
c. The uniformly distributed total load for the beam = 812.8 ft./lb
d. The alternate concentrated load is more critical to bending , shear and deflection
Explanation:
The given parameters of the beam the beam are;
The span of the beam = 26 ft.
The width of the tributary, b = 16 ft.
The dead load, D = 20 psf.
a. The basic floor live load is given as follows;
The uniform floor live load, = 40 psf
The floor area, A = The span × The width = 26 ft. × 16 ft. = 416 ft.²
Therefore, the uniform live load, [tex]L_o[/tex] = 40 psf
b. The reduced floor live load, L in psf. is given as follows;
[tex]L = L_o \times \left ( 0.25 + \dfrac{15}{\sqrt{k_{LL} \cdot A_T} } \right)[/tex]
For the school, [tex]K_{LL}[/tex] = 2
Therefore, we have;
[tex]L = 40 \times \left ( 0.25 + \dfrac{15}{\sqrt{2 \times 416} } \right) = 30.80126 \ psf[/tex]
The reduced floor live load, L ≈ 30.80 psf
c. The uniformly distributed total load for the beam, [tex]W_d[/tex] = b × [tex]W_{D + L}[/tex] =
∴ [tex]W_d[/tex] = = 16 × (20 + 30.80) ≈ 812.8 ft./lb
The uniformly distributed total load for the beam, [tex]W_d[/tex] = 812.8 ft./lb
d. For the uniformly distributed load, we have;
[tex]V_{max}[/tex] = 812.8 × 26/2 = 10566.4 lbs
[tex]M_{max}[/tex] = 812.8 × 26²/8 = 68,681.6 ft-lbs
[tex]v_{max}[/tex] = 5×812.8×26⁴/348/EI = 4,836,329.333/EI
For the alternate concentrated load, we have;
[tex]P_L[/tex] = 1000 lb
[tex]W_{D}[/tex] = 20 × 16 = 320 lb/ft.
[tex]V_{max}[/tex] = 1,000 + 320 × 26/2 = 5,160 lbs
[tex]M_{max}[/tex] = 1,000 × 26/4 + 320 × 26²/8 = 33,540 ft-lbs
[tex]v_{max}[/tex] = 1,000 × 26³/(48·EI) + 5×320×26⁴/348/EI = 2,467,205.74713/EI
Therefore, the loading more critical to bending , shear and deflection, is the alternate concentrated load
What causes the charging system warning lamp to go out when the engine starts up?
Select one:
a. It turns off when ground is supplied to the lamp.
b. It turns off because voltage is applied to both sides of the lamp.
c. It turns off automatically after about 5 seconds.
d. It turns off because voltage is applied to one side of the bulb and ground to the other side.
Answers
The alternator must be operated with the battery disconnected or with the terminals at the back of the alternator
disconnected.
True or false
Answers
Answer:
true
Explanation:
I think so
Hope it helps
What is the tallest building ever made
Answers
Answer:
Burj Khalifa
Explanation:
The world's tallest artificial structure is the 829.8-metre-tall (2,722 ft) Burj Khalifa in Dubai (of the United Arab Emirates). The building gained the official title of "tallest building in the world" and the tallest self-supported structure at its opening on January 9, 2010.
a brainliest would be appriciated
Answer:
Burj khalifa
Explanation:
829.8 meters tall