You have learned how to take steps that are exactly 1m long. You take 12 steps north, then 15 steps north, 35 steps south, 11 steps south, then 16 steps north. What distance have you walked? What is your total displacement?

Answer: The mass of [tex]H_2[/tex] produced is 0.153 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of zinc = 5.0 g

Molar mass of zinc = 65.38 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of zinc}=\frac{5.0g}{65.38g/mol}=0.0765mol[/tex]

Given mass of HCl = 10.0 g

Molar mass of HCl = 36.46 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of HCl}=\frac{10.0g}{36.46g/mol}=0.274mol[/tex]

The given chemical equation follows:

[tex]Zn+2HCl\rightarrow ZnCl_2+H_2[/tex]

By stoichiometry of the reaction:

If 1 mole of zinc reacts with 2 moles of HCl

So, 0.0765 moles of zinc will react with = [tex]\frac{2}{1}\times 0.0765=0.153mol[/tex] of HCl

As the given amount of HCl is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, zinc is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 1 mole of zinc produces 1 mole of [tex]H_2[/tex]

So, 0.0765 moles of zinc will produce = [tex]\frac{1}{1}\times 0.0765=0.0765mol[/tex] of [tex]H_2[/tex]

We know, molar mass of [tex]H_2[/tex] = 2 g/mol

Putting values in above equation, we get:

[tex]\text{Mass of }H_2=(0.0765mol\times 2g/mol)=0.153g[/tex]

Hence, the mass of [tex]H_2[/tex] produced is 0.153 g

Answer:

this is a required answer. look it once.

Answer:

Part (1a): The number of moles are 2.14 moles.

Part (1b): The number of moles are 12.2 moles.

Part (1c): The number of moles are 0.545 moles.

Part 2: The number of molecules are 1.38 × 10²⁵.

Part 3: The number of moles are 5.65 moles.

Part 4: The number of atoms are 1.81 × 10²⁴.

Part 5: The number of molecules are 1.20 × 10²⁶.

Explanation:

According to the mole concept:

1 mole of substance contains 6.022 × 10²³ number of atoms or molecules.

Part (1a): 1.29 × 10²⁴ hydrogen atoms in H

As, 6.022 × 10²³ number of hydrogen atoms present in 1 mole

So, 1.29 × 10²⁴ number of hydrogen atoms present in [tex]\frac{1.29\times 10^{24}}{6.022\times 10^{23}}=2.14[/tex] mole

Part (1b): 7.36 × 10²⁴ oxygen atoms

As, 6.022 × 10²³ number of oxygen atoms present in 1 mole

So, 7.36 × 10²⁴ number of oxygen atoms present in [tex]\frac{7.36\times 10^{24}}{6.022\times 10^{23}}=12.2[/tex] mole

Part (1c): 3.28 × 10²³ Na atoms

As, 6.022 × 10²³ number of Na atoms present in 1 mole

So, 3.28 × 10²³ number of Na atoms present in [tex]\frac{3.28\times 10^{23}}{6.022\times 10^{23}}=0.545[/tex] mole

Part 2:

As, 1 mole of oxygen contains 6.022 × 10²³ number of molecules

So, 23.0 moles of oxygen contains 23.0 × 6.022 × 10²³ = 1.38 × 10²⁵ number of molecules

Part 3:

As, 6.022 × 10²³ number of H₂SO₄ molecules present in 1 mole

So, 3.4 × 10 number of H₂SO₄ molecules present in [tex]\frac{3.4\times 10}{6.022\times 10^{23}}=5.65[/tex] mole

Part 4:

As, 1 mole of Na contains 6.022 × 10²³ number of atoms

So, 3.0 moles of Na contains 3.0 × 6.022 × 10²³ = 1.81 × 10²⁴ number of atoms

Part 5:

As, 1 mole of O₃ contains 6.022 × 10²³ number of molecules

So, 200 moles of O₃ contains 200 × 6.022 × 10²³ = 1.20 × 10²⁶ number of molecules

Answer:

Both Arrhenius Base and Bronsted Lowry Base

Both Arrhenius Acid and Bronsted Lowry Acid

Arrhenius Acid Only

Arrhenius Base Only

Bronsted Lowry Acid Only

Bronsted Lowry Base Only

Explanation:

Answer:

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Explanation:

iwjwyaab77w92 and a wherever whatever wueetwb eiw

uwyiwgwkewbekkwuw jwywue kwuwiwywh

kwywiwyw iwtwigw eiywgwiw it wow

bwwneo

Answer:

is your answe b?

Explanation:

Im really asking

mmmmmmmmmmhhhhhhhhhhhhhhhhhhhh

Answer:

Explanation:

Ultimately, milk can be described as both. The actual description depends on the individual and/or company involved. For example, in many places milk if extracted from cows, bottled, and delivered to the end consumer. In this case, milk would be considered as natural because nothing has been done to change its nutritional composition. This changes when companies begin to pasteurise and homogenize the milk so that it has a longer shelf life and create different variations. The milk in this case no longer has the same nutritional composition and has been altered, and is therefore considered as processed.

[tex]mass \: of \: the \: car \: = 1250 \: kg \\ \\ velocity \: of \: the \: car \: is \: = 2.3m/s \\ \\ formula \: to calculate \: momentum \: \\ \\ \: \: \: \: p = mv \: \: \: (m = mass \: and \: v = velocity) \\ \\ momentum \: = 1250 \times 2.3 = 2875m/s[/tex]

Answer:

use grahamns law to get the answer

Answer:

22

Explanation:

3x4+  5x2

Answer:

1.21 mol KClO₃

General Formulas and Concepts:

Atomic Structure

Stoichiometry

Explanation:

Step 1: Define

Identify variables

[rxn] 2KClO₃ → 2KCl + 3O₂

[Given] 58.3 g O₂

[Solve] mol KClO₃

Step 2: Identify Conversions

[rxn] 2 mol KClO₃ → 3 mol O₂

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of O₂: 2(16.00) = 32.00 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.21458 mol KClO₃ ≈ 1.21 mol KClO₃

Answer:

Examples of physical change include changes in the size or shape of matter. Changes of state—for example, from solid to liquid or from liquid to gas—are also physical changes. Some of the processes that cause physical changes include cutting, bending, dissolving, freezing, boiling, and melting.

Explanation:

Answer:

a neutral solution has a pH of 7.

ph=-log(H+)

Explanation:

hence (H+)

=10⁷mol/dm³

Answer:

Heterogeneous mixture...is the answer

The dude above me is right. I thought he was wrong, so I put A but it turns out he was right!

The molar mass of the unknown nonelectrolyte compound is

Using the formula;

∆T = K m i

Where;

K = freezing point depression constant

m = molality of the solution

i = Van't Hoft factor

Note that i = 1 since the compound is a nonelectrolyte.

To find molality;

Number of moles = 0.520 g/Molar mass

Let the molar mass of the unknown compound be MM

Number of moles = 0.520 g/MM

Number of kilograms of solvent = 4.12 g/1000 = 0.00412 Kg

Molality = 0.520 g/MM * 1/0.00412 Kg

Freezing point depression is 4.20 °C

To find the molar mass of the compound;

4.20 °C = 3.90 °C/m *  0.520 g/MM * 1/0.00412 Kg

4.20  = 492.23/MM

MM = 492.23/4.20

MM = 117.19 g/mol

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Answer:

205.12 atm

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

R = 0.0821 Latm/perK)

T = temperature (K)

n = number of moles (mol)

According to the information in this question;

P = ?

V = 34.25 mL = 34.25 ÷ 1000 = 0.03425L

n = 0.215 mol

T = 125.0°C = 125 + 273 = 398K

Using PV = nRT

P = nRT ÷ V

P = (0.215 × 0.0821 × 398) ÷ (0.03425)

P = 7.025 ÷ 0.03425

P = 205.12 atm

Answer:

CH₂

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 1 g

Mass of CO₂ = 3.14 g

Mass of H₂O = 1.29 g

Empirical formula =?

Next, we shall determine the mass of Carbon and hydrogen present in the compound. This can be obtained as follow:

For Carbon, C:

Mass of CO₂ = 3.14 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Molar mass of C = 12 g/mol

Mass of C =?

Mass of C = molar mass of C/ Molar mass of CO₂ × Mass of CO₂

Mass of C = 12/44 × 3.14

Mass of C = 0.86 g

For hydrogen, H:

Mass of C = 0.86 g

Mass of compound = 1 g

Mass of H =?

Mass of H = (Mass of compound) – (mass of C)

Mass of H = 1 – 0.86

Mass of H = 0.14 g

Finally, we shall determine the empirical formula of the cyclopropane. This can be obtained as follow:

Mass of C = 0.86 g

Mass of H = 0.14 g

Divide by their molar mass

C = 0.86 / 12 = 0.07

H = 0.14 / 1 = 0.14

Divide by the smallest

C = 0.07 / 0.07 = 1

H = 0.14 / 0.07 = 2

Thus, the empirical formula of cyclopropane is CH₂

Answer:

2. 181.25 K.

3. 0.04 atm.

Explanation:

2. Determination of the temperature.

Number of mole (n) = 2.1 moles

Pressure (P) = 1.25 atm

Volume (V) = 25 L

Gas constant (R) = 0.0821 atm.L/Kmol

Temperature (T) =?

The temperature can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

1.25 × 25 = 2.1 × 0.0821 × T

31.25 = 0.17241 × T

Divide both side by 0.17241

T = 31.25 / 0.17241

T = 181.25 K

Thus, the temperature is 181.25 K.

3. Determination of the pressure.

Number of mole (n) = 10 moles

Volume (V) = 5000 L

Temperature (T) = –10 °C = –10 °C + 273 = 263 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

The pressure can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

P × 5000 = 10 × 0.0821 × 263

P × 5000 = 215.923

Divide both side by 5000

P = 215.923 / 5000

P = 0.04 atm

Thus, the pressure is 0.04 atm

Answer:

All ionic compounds with alkali metals are soluble.

Explanation:

Certain elements always form soluble substances. Most of those elements are alkali metals/group 1 metals.

Answer:

the answer is 1.1grams is the currect ans

According to the law of conservation of mass, 1.1 grams of calcium carbonate are formed  if 2.2 grams of CaO are used for this reaction.

According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .

Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.

Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Antoine Lavoisier in the year 1789.If 56 g CaO gives 46.2 g calcium carbonate then  2.2 g CaO will give 2.2×46.2/56=1.1 g.

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Answer:

approximately 1.772 grams

Explanation:

molecular mass of AlCl3 is 132 g per mole and of Al(OH)3 is 78 g per mole

the reaction is

AlCl3 + 3 NaOH ---> Al(OH)3 + 3 NaCl

from the reaction it is clear that 1 mole AlCl3 makes 1 mole Al(OH)3

implies 132g AlCl3 gives 78g Al(OH)3

Implies 3g AlCl3 gives

[tex]3 \times \frac{132}{78} = 1.772 \: g \: al(oh)3[/tex]

Answer:

Metilaminas

Explanation:

Las metilaminas a menudo están presentes en los tejidos corporales de organismos marinos como crustáceos, moluscos y en todos los peces marinos como N-óxido de trimetilamina, donde actúan para estabilizar la proteína que se desestabiliza por la presión y también se cree que actúa como un depresor del punto de congelación. en peces polares

Las metilaminas tienen olor a pescado podrido, basura o huevos podridos, de modo que una acumulación de metilamina en el cuerpo da como resultado la liberación de un olor a pescado en la amplitud, el sudor y la orina de un individuo

Answer:

it may also become impure,I think.

Answer:

To produce a solution that frees at -50°C we need 1668.5 g of ethylene glycol

Explanation:

Formula for freezing point depression is:

Freezing T° of pure solvent - Freezing T° of solution = Kf . m . i

Our solute is the ethylene glycol, then water is our solvent.

As ethylene glycol is a non ionic compound, i = 1 (Van't Hoff factor, numbers of ions dissolved)

Kf = Cryoscopic constant. For water is 1.86 °C/m

We replace data:

0°C - (-50°C) = 1.86 °C/m . m . 1

To determine grams of ethylene glycol needed, we need to find m (molality)

50°C / 1.86 m/°C = m → 26.8 mol/kg

As this moles of solute are contained in 1kg, definetely we need 26.8 moles of ethylene glycol.

To find the answer, we convert moles to mass:

26.8 mol . 62.07g / mol = 1668.5 g

Answer:

Molecular mass of NH3 = ( 14 + 3 ) = 17 g

[tex]PV = \frac{m}{m _{r}} RT \\ P \times 50.0 \times {10}^{ - 6} = \frac{68.0}{17} \times 8.314 \times (30.0 + 273) \\ P = \frac{68.0 \times 8.314 \times 303}{17 \times 50.0 \times {10}^{ - 6} } \\ P = 2.02 \times {10}^{8} \: Pascals[/tex]