Answer:
N = 25795 loops
Explanation:
The magnetic field of a solenoid can be calculated by using the following formula:
[tex]B = \frac{\mu NI}{L}\\N = \frac{BL}{\mu I}[/tex]
where,
N = No. of loops = ?
B = Magnetic Field = 0.78 T
L = Length of solenoid = 32 cm = 0.32 m
I = Current = 7.7 A
μ = permeability of free space = 4π x 10⁻⁷ N/A²
Therefore,
[tex]N = \frac{(0.78\ T)(0.32\ m)}{(4\pi\ x\ 10^{-7}\ N/A^2)(7.7\ A)}\\[/tex]
N = 25795 loops
A ball weighing 100 g is attached to a string and swung around with a speed of 2 m/s. If the centripetal force exerted by the string is
0.5 N, what is the length of the string?
A) 0.08 m
B) 0.8 cm
C) 8 m
D) 80 cm
Assuming the ball is swung around in a circle parallel to the ground, it has a centripetal acceleration a of
a = v ² / R
where v is the tangential speed of the ball and R is the length of the string.
The tension in the string is 0.5 N, so by Newton's second law, the ball has acceleration
F = m a → a = F / m = (0.5 N) / (0.1 kg) = 5 m/s²
where m is the ball's mass.
Solve for R :
a = v ² / R → R = v ² / a = (2 m/s)² / (5 m/s²) = 0.8 m = 80 cm
A child with a mass of 12.32kg weight how much? Show all work including a equation
Answer:
123.2newtons
Explanation:
weight =mass × gravity
w= m×g
gravitational pull is approximately 10N/Kg
w= 12.32kg×10n/kg
=123.2newtons or 12.3N
Use the simulation to determine the relationship between the distance from the magnet and the strength of the magnetic field at that point. Use a ruler to measure distance on the screen. Use a power fit to determine the B vs. r relationship for each location. To simplify your data collection, chose a data-collection axis where either Bx or By = 0. Measure the distance from the nearest edge of the magnet. You will need to obtain a ruler for collecting data.
Explanation:
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Priscilla is driving her car on a busy street and Harvey passes her on his motorcycle. What will happen to the sound from his motorcycle after it passes her car?
A.
The frequency of the sound will decrease.
B.
The amplitude of the sound will increase.
C.
The intensity of the sound will increase.
D.
The wavelength of the sound will decrease.
E.
The velocity of the sound will increase.
A 2kg mass moving at a speed of 3 m/s is stopped by a constant force of 15N. How many seconds must the force act on the mass to stop it.
Answer:
t = 0.4 seconds
Explanation:
Given that,
Mass of the object, m = 2 kg
Initial speed of the object, u = 3 m/s
Finally, it stops, v = 0
Constant force applied to the object, F = 15 N
We know that,
Force, F = ma
[tex]F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{2\times (0-3)}{15}\\\\=0.4\ s[/tex]
So, it will take 0.4 seconds to stop the mass.
can someone help? NO LINKS OR IM REPORTING
Answer:
BjsjsjsiisudujdgjkkgywuuuyyyuwuSomeone who snorts and stop breathing during sleep may be suffering from: a. Catoplexy b. Narcolepsy c. Sleep Apnea d. Insomnia
Answer:
C. Sleep Apnea
Explanation:
Sleep Apnea is when someone who snores and stops breathing while sleeping
Someone who snorts and stop breathing during sleep may be suffering from Sleep Apnea. Hence, option (c) is correct.
What is Sleep Apnea?Breathing repeatedly stops and begins while you sleep, which is a frequent symptom of sleep apnea. Your body may not receive enough oxygen as a result.
There are two different forms of sleep apnea.
When your upper airway is repeatedly closed while you sleep, airflow is reduced or entirely stopped, which is known as obstructive sleep apnea. This kind of sleep apnea is the most prevalent.When your brain fails to deliver the necessary signals for breathing, central sleep apnea develops. Central sleep apnea can be brought on by medical problems that alter how your brain regulates the muscles in your chest and airway.Learn more about sleep apnea here:
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238 U
92 ———————>
The alpha decay of ___ produces an atom with a mass number of...
OA. 234
B. 236
C. 238
D. 240
Answer:
A. 234
Explanation:
An alpha particle is a Helium atom which has a mass number of 4 and atomic number of 2. So, an alpha particle decay cause the mass number to decrease by 4 units.
So 238 - 4 = 234
The answer is A
Three points A, B and C are located along a horizontal line. A positive test charge is released from rest at C and accelerates towards B. Upon reaching B, the test charge continues to accelerate toward A. Assuming that only motion along the line is possible,
a) Which point has the highest potential; A, B or C?
b) What will a negative test charge do when it is released from rest at B?
5. A cart with one fan on It blowing to the left and carrying one block produces the x vs t graph shown If this car were carrying three blocks instead of one, with the
fan still blowing the same direction, what could the x vs t graph look like?
A Graph A
B. Graph B
OC. Graph C
O D. Graph D
Answer:
Graph C
Explanation:
With the same force and more mass, the position in time will still be parabolic
i.e. x = ½at², but the rate of acceleration will be lower so the position curve will be broader.
A 1 kg block of wood is attached to a spring, of force constant 200 N/m, which is attached to an immovable support. The block rests on a frictional surface with a coefficient of kinetic friction of 0.2. A 20 g bullet is fired into the block horizontally compressing the spring a maximum distance of 15 cm. Find the original velocity of the bullet before the collision.
Answer:
[tex]v=15.9499m/s[/tex]
Explanation:
From the question we are told that:
Mass of wood [tex]m=1kg[/tex]
force constants [tex]k= 200N-m[/tex]
Coefficient of kinetic friction [tex]\mu= 0.2[/tex]
Bullet mass [tex]m_b= 20 \approx 0.02kg[/tex]
Spring compresion [tex]y=15cm \approx 0.15 m[/tex]
Generally the equation for kinetic energy of bullet [tex]K>E_b[/tex] is mathematically given by
Complete Question
[tex]K.E_b=spring potential energy+work done against friction[/tex]
[tex]K.E_b=\frac{1}{2} mbv^2[/tex]
[tex]\frac{1}{2} m_b v^2=\frac{1}{2} ky^2+\mu my[/tex]
[tex]\frac{1}{2} (0.02)v^2=\frac{1}{2} (0.2)(0.15)^2+0.2(1)(0.15)[/tex]
[tex]v=15.9499m/s[/tex]
[tex]v\approx16m/s[/tex]
The speed of light is 3 x 10 m/s.
Calculate the frequency of light that is absorbed the most by the 100m length of fibre.
Give your answer in standard form.
Answer:
[tex]3 \times 10 {}^6[/tex]
A glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.50 x 105 Pa. Assuming that the top and bottom surfaces of the cap each have an area of 4.40 x 10-4 m2, obtain the magnitude of the force that the screw thread exerts on the cap in order to keep it on the bottle. The air pressure outside the bottle is one atmosphere
Answer:
[tex]F \approx 19.5 N[/tex]
Explanation:
From the question we are told that:
Pressure of [tex]P_{CO_2}=1.50 * 105 Pa.[/tex]
Bottle cap area [tex]A_b= 4.40 * 10-4 m^2[/tex]
Generally the equation for Resultant pressure [tex]P_r[/tex] is give as is mathematically given by
[tex]P_r=P_{CO_2}-P_a[/tex]
Where
[tex]P_a=atmospheric\ pressure = 1.013*10^5 pa[/tex]
[tex]P_r=1.50 * 105 Pa-1.013*10^5 pa[/tex]
[tex]P_r=0.487*10^5 pa[/tex]
Generally the equation for Force exerted by screw F is give as is mathematically given by
[tex]F = P*A\\F = 0.487*10^5*4.00*10^-4\\ F = 19.48 N[/tex]
[tex]F \approx 19.5 N[/tex]
Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?
A) Θ decrease
B) Θ increase
C) Θ remains the same
D) distant between spheres increases
Answer:
Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?(D)
Explanation:
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Newton's law of universal gravitation is represented by
GMm
where F is the magnitude of the gravitational force
exerted by one small object on another, M and mare
the masses of the objects, and ris a distance. Force has
the SI units kg m/s. What are the SI units of the pro-
portionality constant GP
Answer:
i҈ d҈o҈n҈t҈ k҈n҈o҈w҈ w҈h҈a҈t҈ y҈o҈u҈r҈ s҈a҈y҈i҈n҈v҈ b҈c҈h҈
Answer:
[tex]m^{3}kg^{-1} s^{-2}[/tex]
Explanation:
When turning from your path onto a perpendicular path your speed
SHOULD BE at a STEADY
DRIVERS ED PLEASE HELP
Answer: 5-15MPH
Explanation: Trust me
In an electrical circuit, electrons move from the __________.
A. Negative pole to negative pole B. Negative pole to positive pole
C. Positive pole to positive pole
Answer:
the answer is B from negative pole to positive pole
A car of weight (80 N) been revoked by other car . Find the tnsion force
exerted on that car when it is accelerated by (0.5 m/s2
) .
Answer:
T = 4 N
Explanation:
Given that,
Weight of a car, W = 80 N
We know that,
Weight = mg
80 = 10m
m = 8 kg
If the acceleration of the car is 0.5 m/s², then force becomes,
F = 8 × 0.5
F= 4 N
So, the required tension force is 4 N.
What is responsible for the amount of current in a circuit?
Will mark as Brainliest!!!
Answer:
Voltage is required for there to be a current but resistance can effect the amount of current.
Answer:
the answer is voltage
Explanation:
we just finished this unit in class
The data points you have taken on your lab graphs roughly form a straight line. How do you interpret the slope of this line?
Steeper slopes mean higher speeds.
Steeper slopes mean lower speeds.
Steeper slopes mean higher error.
Steeper slopes mean lower error.
The slope has no relation to speed or error
Answer: Steeper slopes mean lower speeds.
Explanation:
A rock falls from a cliff and hits the ground at a velocity of 28m/s. How long did it take to fall?
Answer:
2.8s
Explanation:
=>a = v-u/t
=> t = v - u / t
= 28-0 / 10
= 2.8 s
A cylinder of gas has a frictionless but tightly sealed piston of mass M. A small flame heats the cylinder, causing the piston to slowly move upward. For the gas inside the cylinder, what kind of process is this?
Answer:
isobaric
Explanation:
According to the attached figure, the process would be isobaric as the gas would be expanded at the time when it maintains the constant pressure
The ideal gas law derives
PV = nRT
As the flame is there at the bottom side so atoms or molecules of gas would get heat up slowly also their temperature would be increased. Thus in the case when piston would not be permitted to move so the pressure would rise having maintaining the constant volume and after this the process could be isochronic but in the given case, the piston would be permitted to move slowly upward so that there is a rise in the volume. However, the gas particles would be adjust themselves in order to maintain constant pressure so the given process represent isobaric
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When the rate of the forward reaction equals the rate of the backward reaction, the system is said to be in :
reverse
dynamic equilibrium
homeostasis
suspended state
Answer:
dynamic equilibrium
Explanation:
Substances transition between the reactants and products at equal rates, meaning there is no net change. Reactants and products are formed at such a rate that the concentration of neither changes.
What are the limitations of sending information using electronic waves
Answer:
The limitations of sending information using electromagnetic waves is that when the electromagnetic waves move outward in all directions, wave transmitters need to be focused to transmit their signals to a single specified location.
In a city with an air-pollution problem, a bus has no combustion engine. It runs on energy drawn from a large, rapidly rotating flywheel under the floor of the bus. The flywheel is spun up to its maximum rotation rate of 4000 rev/min by an electric motor at the bus terminal. Every time the bus speeds up, the flywheel slows down slightly. The bus is equipped with regenerative braking so that the flywheel can speed up when the bus slows down. The flywheel is a uniform solid cylinder with mass 1600 kg and radius 0.650 m. The bus body does work against air resistance and rolling resistance at the average rate of 18.0 hp as it travels with an average speed of 40 km/h. How far can the bus travel before the flywheel has to be spun up to speed again
Answer:
the bus can travel 24.54 km before the flywheel has to be spun up to speed again
Explanation:
Given the data in the question;
mass of wheel m = 1600 kg
radius of the fly wheel r = 0.650 m
angular speed of the wheel ω = 4000 rev/min = 418.879 rad/s
Average speed of the bus v = 40 km/h = 11.1111 m/s
Power p = 18 hp = 13428 watt
So moment of inertia of the fly wheel is;
[tex]I[/tex] = [tex]\frac{1}{2}[/tex]mr²
we substitute
[tex]I[/tex] = [tex]\frac{1}{2}[/tex] × 1600 kg × (0.650 m)²
[tex]I[/tex] = 338 kgm²
So, the rotational energy of the bus will be;
[tex]E_r[/tex] = [tex]\frac{1}{2}[/tex][tex]I[/tex]ω²
we substitute
[tex]E_r[/tex] = [tex]\frac{1}{2}[/tex] × 338 kgm² × ( 418.879 rad/s )
[tex]E_r[/tex] = 29652675.212329 J
relation of power to energy
P = E / t
but we know that time t = distance / velocity
t = d/v
∴
P = E / ( d/v)
we solve for distance (d)
P = Ev / d
Pd = Ev
d = Ev / P
so we substitute
d = [( 29652675.212329 J )( 11.1111 m/s )] / [ 13428 W ]
d = 24536.33 m
d = 24.54 km
Therefore, the bus can travel 24.54 km before the flywheel has to be spun up to speed again
How far are two protons if they exert a force of 0.5 N on one another?
Answer:
5.08 metres
Explanation:
The both protons should be 5.08 meters apart so that force between them is equal to the weight of electron
The two protons will exert a repulsive force of 0.5 N when they are at a distance of [tex]2.146625 \times10^{-14} \,m[/tex] away from each other.
As protons have very little mass the gravitational force will be negligible. So here we will consider the electrostatic force between them.
According to Coulomb's law in electrostatics, the electrostatic force between two charges can be given by;[tex]F=k\frac{q_{1}q_{2} }{r^2}[/tex]Where [tex]k \approx 9 \times 10^9 \, Nm^2 /C^2[/tex]Here, since both the particles are protons;[tex]q_1 = q_2 = 1.6 \times 10^{-19}\,C[/tex]Given that F = 0.5 NSubstituting the known values in the Coulomb's law equation, we get;[tex]0.5\, N = 9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{r^2}[/tex]
ie; [tex]r= \sqrt{9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{0.5\, N} } = 2.146625 \times 10^{-14}\,m[/tex]
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Consider a taut inextensible string. You shake the end of the string with some frequency, causing a wave to travel down the string. In the questions below, assume you only change one aspect of the system at a time.
1. If you shake the end of the string twice as rapidly (double the frequency), what will happen to the speed of the wave?
2. If you double the tension in the string, what will happen to the speed of the wave?
3. If you shake the end of the string twice as rapidly (double the frequency), what will happen to the wavelength of the propagating wave?
4. If you double the tension in the string, without changing the rate at which you're shaking it, what will happen to the wavelength of the wave?
For each question, choose from the following choices:
a. It will double.
b. It will remain unchanged.
c. It will increase by a factor of √ 2.
d. It will increase by a factor of 4.
e. It will be half as fast/long.
Answer:
Part 1:
Option B is correct (It will remain unchanged).
Part 2:
Option C is correct (It will increase by a factor of √ 2)
Part 3:
Option E is correct (It will be half as fast/long.)
Part 4:
Option C is correct (It will increase by a factor of √ 2.)
Explanation:
Formula we are going to use:
V=f*λ
Where:
V is the speed of Sound
f is the frequency of wave
λ is the wavelength.
The speed of wave , tension and linear density have following relation:
[tex]V=\sqrt{F/\rho}[/tex]
Where:
V is the speed of Sound (Initial)
F is the tension in string (Initial)
[tex]\rho[/tex] is the linear density of string (Constant)
Terms:
V' is the new speed
f' is the new frequency
λ' is the wavelength
Solution:
Part 1:
From [tex]V=\sqrt{F/\rho}[/tex]:
Speed of Sound is independent of the frequency of shaking so speed well remain unchanged.
Option B is correct (It will remain unchanged)
Part 2:
If F'=2F then
[tex]V=\sqrt{F/\rho}[/tex]
[tex]V'=\sqrt{F'/\rho}\\V'=\sqrt{2F/\rho}\\V'= \sqrt{2} * \sqrt{F/\rho}\\V'=\sqrt{2}V[/tex]
Option C is correct (It will increase by a factor of √ 2)
Part 3:
Formula we are going to use:
V=f*λ
Given f'=2f,
Even though frequency is doubled we will keep velocities same. V=V' in order to find the changing wavelength.
V'=f'*λ'
f*λ=f'*λ'
f*λ=2f*λ'
Solving above Equation:
λ'=λ/2
Option E is correct (It will be half as fast/long.)
Part 4:
T'=2T means [tex]V'=\sqrt{2}V[/tex] (From Part 1)
f'=f
Now:
V'=f'*λ'
[tex]\sqrt{2}f*\lambda=f'*\lambda '\\\sqrt{2}f*\lambda=f*\lambda '\\ \lambda '=\sqrt{2}*\lambda[/tex]
Option C is correct (It will increase by a factor of √ 2.)
A swift blow with the hand can break a pine board. As the hand hits the board, the kinetic energy of the hand is transformed into elastic potential energy of the bending board; if the board bends far enough, it breaks. Applying a force to the center of a particular pine board deflects the center of the board by a distance that increases in proportion to the force. Ultimately the board breaks at an applied force of 870 N and a deflection of 1.3 cm .
Required:
To break the board with a blow from the hand, how fast must the hand be moving? Use 0.50kg for the mass of the hand.
Answer:
6.726 m/s
Explanation:
Given that
Applied force, F = 870 N
Distance moves by the force, d = 1.3 cm = 0.013 m
Mass of the hand, m = 0.50 kg
From the given values, first thing is to find the work done by the force. Work done is given as
W = fd.
W = 870 * 0.013
W = 11.31 J
To find the velocity, next we use the formula for finding Kinetic Energy
K.E = 1/2mv²
Where K.E = 11.31
11.31 = 1/2 * 0.5 * v²
22.62 = 0.5v²
v² = 45.24
v = √45.24
v = 6.726 m/s
To break the board with a blow from the hand the speed of the hand will be [tex]v=6.726\ \frac{m}{s}[/tex]
What is speed?
Speed is defined as the distance traveled by any object with respect to the time.
Now it is given that
Applied force, F = 870 N
Distance moves by the force, d = 1.3 cm = 0.013 m
Mass of the hand, m = 0.50 kg
From the given values, first thing is to find the work done by the force. Work done is given as
[tex]W=F\times d[/tex]
[tex]W=870\times 0.013[/tex]
W = 11.31 J
To find the velocity, next we use the formula for finding Kinetic Energy
[tex]KE=\dfrac{1}{2}mv^2[/tex]
Where K.E = 11.31
[tex]11.31=\frac{1}2}\times 0.5\times v^2[/tex]
[tex]0.5v^2=22.62[/tex]
[tex]v^2=45.24[/tex]
[tex]v=6.726\ \ \frac{m}{s}[/tex]
Hence to break the board with a blow from the hand the speed of the hand will be [tex]v=6.726\ \frac{m}{s}[/tex]
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A current of 8 A is used to operate a Nespresso coffee machine. Choose the most suitable fuse size from the following
- 3 A
- 5 A
- 13A
-10 A
It needs fuse of size 3A to be operated
Answer: 10 A
Explanation: The 3a and 5 a will blow immediately which would not allow you to use the coffee machine
The 13 a is too high and might lead to damage to the coffee machine or a fire being started
10 A is perfect because its low enough that if their was a power surge it would be blown without damaging anything else and it is high enough to let the coffee machine work without any trouble
PLEASE HELP! I'LL GIVE BRAINLEST
the answer is the first one