The density of silicon is [tex]2.33 * 10^{-9} kg.m^{3}[/tex]
Given density of silicon is 2.33 gram centimeter cube.
We know that:
100 cm = 1 m
1cm = 1/100m = [tex]10^{-2} m[/tex]
[tex]1 cm^{3} = 10^{-6} m^{3}[/tex]
Also,
1000 gram = 1 kg
1 gram = 1/1000 kg = [tex]10^{-3} kg[/tex]
Now, to convert gram centimeter cube into kilogram meter cube we should multiply by these values.
So, By putting these values we get:
Density = 2.33 * [tex]10^{-3} kg * 10^{-6} m^{3} = 2.33 * 10^{-9}kg. m^{3}[/tex]
The density of material shows the denseness of that material in a specific given area. A material’s density is defined as its mass per unit volume. Density is essentially a measurement of how tightly matter is packed together. It is a unique physical property of a particular object. The principle of density was discovered by the Greek scientist Archimedes. It is easy to calculate density if you know the formula and understand the related units The symbol ρ represents density or it can also be represented by the letter D.To know more about density visit:
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The total rating of utilization equipment fastened in place, other than luminaires, is not permitted to exceed ____ of the branch-circuit rating if the branch circuit also supplies lighting, other cord-and-plug-connected equipment, or both types of loads
Where lighting units, cord- and plug-connected utilization equipment not fastened in place, or both, are also supplied, the overall rating of fastened-in utilization equipment, excluding luminaires, shall not be greater than 50% of the branch-circuit ampere rating.
What is the appliance's maximum permitted load when it is secured in place? Where lighting units, cord- and plug-connected utilization equipment not fastened in place, or both, are also supplied, the overall rating of fastened-in utilization equipment, excluding luminaires, shall not be greater than 50% of the branch-circuit ampere rating.Branch circuits must be rated in accordance with the overcurrent protection device's setting or the maximum permissible ampere rating.The rating for circuits other than individual branch circuits shall be 15, 20, 30, 40, and 50 amperes.A 15-amp circuit is often served by 14-gauge wire and is protected by a 15-amp circuit breaker or fuse.A 20-amp circuit must be serviced by 12-gauge or 10-gauge wire and protected by a 20-amp breaker or fuse.To learn more about branch-circuit refer
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If two identical conducting spheres are in contact, any excess charge will be evenly distributed between the two. Three identical metal spheres are labeled A, B, and C. Initially, A has charge q, B has charge -q/2, and C is uncharged.
Charges on two connected spheres will balance out until they are equal on all of them. Answer:A: 3/4, B: -q/4, C:3/8q.
When the two identical spheres come into contact with one another, what happens to their charges?When two conducting spheres touch, the charge on them is redistributed such that the potential on the two spheres is the same:
V1 = V2
Q1/C1= Q2/C2
where Q stands for the charge and C for the sphere's capacitance. For identical spheres, the capacitance is the same, so the previous equation becomes
Q1 =Q2
This indicates that the two spheres receive an equal distribution of the charge.
Here initially we have:
Sphere A: charge of q
Sphere B: charge of -q/2
Sphere C: charge of 0
Sphere B is initially contacted by sphere C.
Given that the two spheres' combined charge was
q/2 +0 = -q/2
After touching each sphere will have a charge half of this value:
qA= qC = 1/2(-q/2) = -q/4
Sphere C (charge -q/4) then makes contact with sphere A (charge +q).
The overall cost is therefore
-q/4+q = +3/1q
Since the charge distributes equally, each sphere will receive 1/2 of this charge:
qB = qc =1/2 (+3/1 q)= 3/8q
So the final charge on the 3 spheres will be
A: 3/4, B: -q/4, C:3/8q
b. A: 1/2, B: 0, C:0
After touching each sphere will have a charge half of this value:
qA = qC = 1/2(q) = q/2
After that, sphere C (charge q/2) makes contact with sphere B (charge -q/2).
The overall cost is therefore
-q/2+q/2=0
Since the charge distributes equally, each sphere will receive 1/2 of this charge, which simply means a charge of zero:
qB= qC= 0
So the final charge on the 3 spheres will be
A:1/2 , B: 0, C: 0
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Rock B ha a ma of 100 kg and i travelling at 7 m/ in the ame direction a rock A. Rock B ha a momentum of 700 kg m/. Rock A and rock B collide and join together. Calculate the velocity of the two rock after the colliion. Show your working.
Velocity is 700kg.If you know the other values of an object's properties, you may determine its momentum or velocity using the momentum equation p is m•v.
After two objects collide, how can you determine their respective velocities?Equation v′=m1v1+m2v2m1+m2 m1 is the mass of object 1, v1 is the initial velocity of item 1, m2 is the mass of object 2, and v2 is the starting velocity of object 2, with v′ = m 1 v 1 + m 2 v 2 m 1 + m 2. v' is the final velocity of the two objects once they move as one unit following the collision.If you know the other values of an object's properties, you may determine its momentum or velocity using the momentum equation p = m•v.If a particle A with mass m is travelling toward a particle B that is stationary with velocities u from infinity, collides with B with final velocities v, and then deflects away with final velocities v, then VR=v- u is the particle's relative velocity.
Explanation:
m*v =100 * 7 = 700 kg.
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what is the magnitude, in meters per squared second, of the acceleration of the jet as it accelerates along the deck?
With a=11.43 m/s2, option 4 is the proper response. The airplane accelerates to 160+ mph in less than two seconds during a catapult launch.
What is the most straightforward explanation of acceleration?The speed about which velocity decreases is known termed accelerating. Acceleration typically indicates that the speed is changing, but not necessarily. An item that is moving in a circle while maintaining a constant speed is still accelerating because the direction of its motion is shifting.
What are two instances of acceleration?An object's velocity may alter depending on whether it is moving faster, slower, or in a different direction. The moon orbiting the earth and an apple falling to the ground are two instances of acceleration.
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using the principle of conservation of mechanical energy answer the following question. during a jump, a 75 kg individual reaches a height of 0.6 meters which is not at their max height. at this point their vertical velocity is equal to 0.9 m/s. during the up concentric phase of the jump they have an average grf of 1800 newtons directed up and slightly to the right at an angle of 80 degrees above the horizontal. what is their initial vertical velocity at the point of take off and what is their average velocity from the bottom of their countermovement jump to take off?
Athletes are asked to immediately squat to a depth of their choosing and then jump as high as they can in the Countermovement Jump (CMJ), a vertical jump test.
What does a vertical jump countermove?Athletes are asked to immediately squat to a depth of their choosing and then jump as high as they can in the Countermovement Jump (CMJ), a vertical jump test. It is the first leap in our force plate evaluation and is used to gauge lower body power via jump height as well as lower limb asymmetries.With beginning leaping angles of 21 and 38 degrees, respectively, the running jump and standing jump in conventional sports have initial velocities of 9.15 and 2.70 m/s. The initial velocity's maximum strength, the force's angle of engagement, and height are all strongly related to the 9.15 m/s maximum horizontal speed.To learn more about Countermovement refer to:
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10. Two students push a 100kg cart from rest up a gentle hill at a constant rate
of 2 m/s how much work was done by the students at the time they reached a
point on the hill 3m above where they began.
After 10 seconds, the final speed is 32 m/s.After 10 seconds, the displacement is 170 m.
How to determine the final velocity ?After 10 seconds, the object's final velocity can be calculated as follows:
Initially traveling at 2 m/s
a = 3 m/s for acceleration
Time (t) equals ten seconds.
Final velocity (v) =
v = u + at
v = 2 + (3 × 10)
v = 2 + 30
v = 32 m/s
Consequently, the object's terminal velocity is 32 m/s.
2. Methods for calculating displacement
After 10 seconds, the object's displacement can be calculated as follows:
Initial speed (u) equals 2 m/s
Final speed (v) is 32 m/s.
The speed of sound is 3 m/s2.
Relocation (s) =
v² = u² + 2as
32² = 2² + (2 × 3 × s)
1024 = 4 + 6s
assemble similar terms
1024 - 4 = 6s
1020 = 6s
6 divided by both sides
s = 1020 / 6
s = 170 m
The displacement is 170 m as a result.
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a group of students are analyzing their results for this activity. they come up with the following explanation: the reason the velocity we measured was lower than the velocity we predicted is that some of the kinetic energy of the marble was converted to thermal energy during the collision. also, after the collision, air friction and bending in the pendulum rod converted more kinetic energy into thermal energy. does this explanation match with the your results? explain your reasoning.
Yes, this explanation matches with the results. The lower velocity that was measured is likely due to some of the kinetic energy of the marble being converted to thermal energy during the collision.
What is kinetic energy?Kinetic energy is the energy of motion. It is the energy associated with an object's movement, or the energy of a system due to the motion of its parts. Kinetic energy is defined as the work needed to accelerate an object of a given mass from rest to its stated velocity.
This is because when two objects collide, some of the kinetic energy is converted to thermal energy. Additionally, air friction and bending in the pendulum rod can also reduce the velocity of the marble by converting more of its kinetic energy into thermal energy. Thus, both of these factors could explain the discrepancy between the measured and predicted velocities.
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A projectile of mass 0.419 kg is shot from
a cannon, at height 6.2 m, as shown in the
figure, with an initial velocity v; having a
horizontal component of 6.7 m/s.
The projectile rises to a maximum height
of 1.6 m above the end of the cannon's barrel
and strikes the ground a horizontal distance
past the end of the cannon's barrel.
Find the magnitude of the initial vertical
velocity vector of the cannon-ball at the end
of the cannon's barrel. The acceleration of
gravity is 9.8 m/s².
The initial vertical velocity of the cannon-ball is 5.6 m/s.
What is the initial vertical velocity of the cannon-ball?The initial vertical velocity of the cannon-ball is calculated by applying the formula for a projectile to reach the maximum height.
Vf² = Vi² - 2gH
where;
Vi is the initial vertical velocityVf is the final vertical velocityg is the acceleration due to gravityH is the maximum vertical height reached by the cannon ballAt maximum height, the final vertical velocity = 0
0 = Vi² - 2gH
Vi² = 2gH
Vi = √ ( 2gH )
Vi = √ ( 2 x 9.8 x 1.6 )
Vi = 5.6 m/s
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latitude lines: a. measure angular distances north and south of the equator. b. measure east-west surface distances from the prime meridian. c. converge at the poles. d. always form a great circle.
The parallels of latitude refer to the angular distance, in degrees, minutes and seconds of a point north or south of the Equator.
Define latitude lines?
Lines of latitude, also called parallels, are imaginary lines that divide the Earth. They run east to west, but measure your distance north or south. The equator is the most well known parallel. At 0 degrees latitude, it equally divides the Earth into the Northern and Southern hemispheres.The imaginary lines that run from East to West are called Parallels or Lines of Latitude. The imaginary lines that run North to South from the poles are called Meridians or the lines of Longitude. Lines of Latitude are east-west circles around the globe.Latitudes are imaginary lines that run from west to east, ranging from zero to 90 degrees. Another imaginary line on the globe that divides it into two equal parts at zero degree latitude is called the equator. The equator divides the earth into the Northern Hemisphere and the Southern Hemisphere.
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how is a beach ball and infrared energy alike
A beach ball and infrared energy are not alike in many ways, as they are quite different things. However, one similarity that can be drawn between them is that they both involve energy.
A beach ball is a physical object made of rubber or plastic and filled with air, that can be bounced or thrown around. It requires energy to move it and make it move.
Infrared energy, on the other hand, is a form of electromagnetic radiation that has a longer wavelength than visible light. It is also known as heat energy and it can be emitted by any object that has a temperature above absolute zero. It can be used for heating, sensing and communication, but also to detect heat from objects and therefore detect objects themselves.
Both the beach ball and infrared energy are forms of energy that can be used in different ways and for different purposes. Although it is not a direct comparison, the beach ball and infrared energy can both be described as having the property of energy.
1/15 - 1/10 = 1/di
focal length is 15 and distance of object is 10. what is the distance of the image?
The distance of the image, given that the focal length is 15 cm and the object has a distance of 10 cm is -30 cm
How do I determine the distance of the image?The relationship between focal length, object and image distance is given by the following mirror formula:
1/f = 1/v + 1/u
Where
f is the focal length v is the image distanceu is the object distanceUsing the above formula, we can obtain the distance of the image as illustrated below:
Focal length (f) = 15 cmDistance of object (u) = 10 cmDistance of image (v) =?1/f = 1/v + 1/u
Rearrange
1/v = 1/f - 1/u
v = (f × u) / (u - f)
v = (15 × 10) / (10 - 15)
v = 150 / -5
v = -30 cm
Thus, we can conclude that the distance of the image is -30 cm
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Two balls of unequal mass traveling at different speeds collide head-on and rebound in opposite
directions.
1) How does the force that ball A exerts on ball B compare to the force that ball B exerts on ball A?
2) How do the impulses received by both balls compare?
3) How do the sums of the momenta of the balls before and after the collision compare?
Can someone please answers these for me i need help.
Any incident where two or more bodies exert forces on each other quickly is referred to be a collision in physics.
When two objects collide Which of these is are true?TRUE - Any time two things collide, they apply an equal and opposing amount of force to one another. Simple Newton's law of action-reaction, this.Concussion, impact, and shock are a few typical synonyms for collision. Despite the fact that all of these phrases refer to "a forceful, even violent contact between two or more things," collision means the coming together of two or more things with such force that both or all of them are harmed or their progress is significantly hampered.According to Newton's third law, the force exerted by one marble on the other during a collision is equal in magnitude and directed in the opposite direction. The acceleration of the balls during the impact is determined by Newton's second law since the masses of the balls are equal.To learn more about collision refer to:
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What force is needed to give a 0.25 kg arrow an acceleration of 196 m/s² question 10 options: 0.25n 49n 196n 748n
The force that is needed to accelerate the arrow is 49 Newtons.
To determine magnitude of the force needed to give a 0.25 kg arrow an acceleration of 196 m/s², we can use the equation of force:
F = ma
where F is the force, m is the mass, and a is the acceleration.
Given that m = 0.25 kg and a = 196 m/s², we can substitute these values into the equation and solve for F:
F = (0.25 kg)(196 m/s²)
F = 49 N
So the force needed to give a 0.25 kg arrow an acceleration of 196 m/s² is 49 N. This is the correct answer out of the options given.
To arrive at this answer we used Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. Thus, we were able to use the equation "F = ma" (where F is force, m is mass and a is acceleration) to solve for the force required to accelerate the arrow at 196 m/s².
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In 1992, Ukrainian Sergei Bubka ued a hort pole to jump to a height of 6.13 m. If the maximum potential energy aociated with Bubka wa 4.80 kJ at the midpoint of hi jump, what wa hi ma?
At the middle of his jump, Ukrainian Sergei Bubka had a mass of 79.8 kJ.
What is mass's straightforward definition?The amount of matter in a particle or object is represented by its mass, which is denoted by the symbol m. In the International System (SI), the kilogram serves as the default unit of mass (kg).
The resistance of the body to acceleration (change of velocity) when a net force is applied is known as inertia, and inertia may be measured experimentally using mass.
h=6.13 meters, mg=9.81 m/s2,
PEg= 4.80 ×10^3J
We will use the equation for gravitational potential energy and rearrange it to solve for mass because the mass is unknown.
PEg = mgh as a result.
PEg/gh = mass
mass = 4.80 ×10^3 / 9.81 x 6.13
79.8 kJ / mass.
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stars rise in the east and set in the west for everyone living in the southern hemisphere. group of answer choices true false
In both hemispheres, the star ascends in the east then sets in the west. This results from the rotational motion of the earth. Additionally, they spin in that direction.
In the southern hemisphere, can stars rise towards the east and set inside the west?The planets rise from the east, set in the west, and move counterclockwise all around North celestial pole in the northern hemisphere. The stars inside the southern hemisphere rise in the east, set in the west, and rotate counterclockwise around the celestial equator.
Do the stars constantly rise and set inside the east and the west, respectively?Its Sun, Moon, stars, and celestial bodies are seen to rise inside the east to set inside the west every day. Actually, Earth is travelling more faster than these heavenly bodies. Every 24 hours or so, it rotates on its axis form west to east. We move along because we are on the surface of the Earth.
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while at rest on a hillside, army the armadillo rolls up into a ball. as a result, they begin to roll down the hill. at a certain moment during the roll, their gravitational potential energy has decreased by 40 j, and their translational kinetic energy has increased by 15 j. by how much has their rotational kinetic energy changed?
The rotational kinetic energy of the armadillo has increased by 25 joules.
This is because the armadillo is rolling down the hill, which means that it is rotating around its center of mass. As it rolls, it is converting its gravitational potential energy into translational and rotational kinetic energy.
Since the gravitational potential energy has decreased by 40 joules and the translational kinetic energy has increased by 15 joules, the remaining 25 joules must have been converted into rotational kinetic energy. This means that the armadillo's rotational kinetic energy has increased by 25 joules.
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Some devices use electromagnetic waves to find the location and speed of an object. In these devices, the waves are emitted and then reflected off of the object and returned back toward the device. By knowing the speed of the wave and the time it takes the wave to return to the device, the distance that the wave traveled can be calculated. Which type of wave would be safest to use in this type of device?
The type of wave that would be safest to use in this type of device would be radio waves.
Other types of electromagnetic waves such as microwaves, infrared, visible light, ultraviolet, X-rays and Gamma rays have a higher frequency and shorter wavelength and more energy per photon, thus they can be ionizing and potentially harmful to humans if exposed to high intensity for a long time.
That's why devices such as radar and sonar, which use radio waves to locate and determine the speed of objects, are considered safe for human use.
What is Radio Waves?Radio waves are a type of electromagnetic wave that have the longest wavelength and lowest frequency of all electromagnetic waves. They are a form of energy that travels through space at the speed of light (about 299,792,458 meters per second).
The wavelength of radio waves ranges from about 1 millimeter to 100 kilometers, and their frequency ranges from about 3 kilohertz (kHz) to 300 gigahertz (GHz). The part of the electromagnetic spectrum that contains radio waves is called the radio frequency (RF) spectrum.
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a large boulder has a volume of 1000 cubic meters and a mass of 3,200,000 kilograms. what is the density of the boulder, in grams per cubic centimeter?
The density of the boulder in gram per centimeter cube is found to be 3.2g/cm³.
The density of the object us calculated as the mass of the body divided by the volume of the body.
So, we can write,
Density = mass/volume
Here, it is given that the mass of the body is 3200000 kg and the volume of that large boulder is 1000 cubic meter.
Now, in order to find the density is grams per cubic centimeter, we use the relation,
1 kg/m³ = 0.001 g/cm³
Now, density of the boulder is,
= 3200000/1000
= 3200
The density in g/cm³.
3200kg/m³ = 3200 x 0.001 g/cm³
Density = 3.2 g/cm³
So, the density of the boulder is 3.2g/cm³.
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in a liquid with a density of 1500 kg/m3 , longitudinal waves with a frequency of 410 hz are found to have a wavelength of 8.00 m . calculate the bulk modulus of the liquid. express your answer in pascals.
The bulk modulus of the liquid in pascals is 1.26 x 10⁹Pa.
what is bulk modulus?The bulk modulus is a measure of a substance's resistance to compression. It is a mechanical property of a material and is defined as the ratio of change in pressure to the fractional change in volume. In other words, it measures the ability of a substance to withstand changes in volume due to an applied pressure. The greater the bulk modulus, the more resistant the material is to changes in volume. It is typically measured in units of pressure, such as pascals (Pa) or gigapascals (GPa). The bulk modulus is an important property for materials used in engineering and construction, as it affects how well a material can withstand loads and stresses.
To calculate the bulk modulus of a liquid, we can use the equation:
Bulk modulus = (density of the liquid) × (speed of sound in the liquid) ²
First, we need to calculate the speed of sound in the liquid.
The speed of sound in a liquid is given by:
Speed = (wavelength × frequency) / (2 × pi)
To calculate the bulk modulus of the liquid, we can use the equation:
Bulk Modulus = (density × (speed of sound)) ²
The speed of sound in the liquid can be calculated using the equation:
Speed of Sound = (frequency × wavelength)
By substituting the given values into these equations, we can calculate the bulk modulus as follows:
Speed of Sound = (410 Hz × 8.00 m) = 3280 m/s
Bulk Modulus = (1500 kg/m³) × (3280 m/s) ² = 1.26 x 10⁹ Pa
So the bulk modulus of the liquid is 1.26 x 10⁹ Pa.
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In a liquid with a density of 1500 kg/m3 , longitudinal waves with a frequency of 410 hz are found to have a wavelength of 8.00 m. The liquid has a bulk modulus of 1.26 x 10⁹ Pa in pascals.
How does bulk modulus work?A substance's compression resistance is measured by its bulk modulus. A material's mechanical property is the ratio of a change in pressure to a change in volume fractionally. To put it another way, it measures a substance's capacity to withstand changes in volume caused by pressure. The material's resistance to changes in volume is inversely proportional to its bulk modulus.
It is typically measured in pascals (Pa) or gigapascals (GPa) pressure units. Because it influences how well a material can withstand loads and stresses, the bulk modulus is an important property for materials used in engineering and construction.
Evaluating :The equation can be used to determine a liquid's bulk modulus:
Bulk modulus = (density of the liquid) × (speed of sound in the liquid) ²
The speed of sound in the liquid must first be determined before we can calculate the bulk modulus, which is equal to the liquid's density divided by its speed of sound.
The following equation can be used to determine the liquid's bulk modulus: Speed = (wavelength x frequency) / (2 pi)
The following equation can be used to determine the liquid's sound speed: Bulk Modulus = (density/speed of sound)/2
The bulk modulus can be calculated as follows by substituting the given values into these equations: Speed of Sound = (frequency wavelength).
The liquid's bulk modulus is therefore 1.26 x 109 Pa.
Speed of Sound = (410 Hz 8.00 m) = 3280 m/s.
Bulk Modulus = (1500 kg/m3) (3280 m/s) 2 = 1.26 x 10⁹ Pa
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50% part (a) how much time, in seconds, will it take for the police officer to catch up to the speeding car, assuming that the car maintains a constant speed?
The police officer will take 38.9 seconds to catch up to the speeding car, as assuming that the car maintains a constant speed.
The pace at which an object's velocity with regard to time changes is referred to as acceleration in mechanics. They are endogenous variables, accelerations. The direction of the total force exerted on an object determines the direction of its acceleration.
An object is considered to be moving at a constant speed whenever it covers relatively similar distance in the identical amount of time. When moving at a constant pace, an object covers a certain distance in a fixed amount of time. S = d t is a formula that can be used to express the speed.
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A car speeds past a stationary police officer while traveling 140 km/h. The officer immediately begins pursuit at a constant acceleration of 10.9 km/h/s, just as the driver passes her. A. How much time, in seconds, will it take for the police officer to catch up to the speeding car, assuming that the car maintains a constant speed?
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after it i releaed, the electric field intantaneouly change to a contant, uniform electric field 2
pointing due outh. 8.49
after the field change, the proton ha returned to it tarting point. What i the ratio of the magnitude of 2
to the magnitude of 1?
You may neglect the effect of gravity on the proton.
The ratio of magnitude 2 to magnitude 1 after the electric field change when the proton returned to its starting point.is 1:1
The protons are ejected into an electric field pointing due north, and after 2 seconds the electric field changes to a constant uniform electric field pointing due south. 8.49 seconds after the field change, the proton returned to its starting point.
The protons were initially stationary and accelerated by the electric field. A proton's acceleration is directly proportional to its electric field and inversely proportional to its mass.
Two oppositely directed fields act on the protons, implying a net acceleration of zero. Therefore, the ratio of the magnitude of electric field 2 to the magnitude of electric field 1 is 1:1.
The ratio of magnitude 2 to magnitude 1 is 1:1
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an atomic nucleus has a net charge of 52e. what is the magnitude of the electric field (in nn/c) at a distance of 3.87 m from the center of the nucleus?
The electric field due to the net charge of the atomic nucleus is found to be 5 x 10⁻¹⁸ C.
The formula for the electric field is,
E = Kq/r²
K is the constant,
q is the charge of the source,
r is the distance from the center of the nucleus.
The charge on the atomic nucleus is given to be 52e and the distance is given to be 3.87 m.
Now, putting values,
E = 9 x 10⁹ x 52 x 1.67 x 10⁻¹⁹/(3.87)²
E = 5 x 10⁻¹⁸ C.
So, the electric field is found to be 5 x 10⁻¹⁸ C.
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A 500- m -long ski slope drops at an angle of 6.4∘ relative to the horizontal.
If 20% of the gravitational potential energy change is converted into kinetic energy, how fast is the skier traveling at the bottom of the slope?
The speed of the skier at the bottom of the slope is 15.1 m/s.
What is the speed of the skier at the bottom of the slope?
The speed of the skier at the bottom of the slope is calculated by applying the principle of conservation of energy.
Kinetic energy at bottom = percentage of potential energy converted into kinetic energy.
K.E = 20%P.E
K.E = 0.2P.E
¹/₂mv² = 0.2 mgh
¹/₂v² = 0.2gh
v² = 2 (0.2gh)
v = √2(0.2gh)
where;
h is the height of the slopesin (6.4) = h /L
h = L x sin(6.4)
h = 500m x sin (6.4)
h = 58.28 m
v = √2(0.2 x 9.8 x 58.28 )
v = 15.1 m/s
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a ball is thrown from 1.0 m above the ground. the initial velocity is 20 m/s at an angle of 40 degrees above the horizontal. what is the maximum height of the ball above the ground?
1.0 m above the earth, a ball is hurled. 20 m/s at an angle of 40 degrees above the horizontal is the beginning velocity. The ball may rise 9.4 metres above the earth.
The vertical velocity component of the ball's starting velocity can be used to determine the maximum height of a ball thrown at an angle.
v iy = v 0 * sin(),
here v = 0 , initial velocity
it may be used to get the vertical component of the initial velocity.
maximum height , H = v iy2 / (2 * g),
where g = 9.8m/s2
H = (20 sin 40°)²/ 2 X 9.8
H = 165.27/ 19.6
H = 8.4 m
therefore, the maximum height is = 1+ 8.4m = 9.4
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an electrostatic paint sprayer has a 0.400 m diameter metal sphere at a potential of 23.0 kv. (a) what charge is on the sphere?
To calculate the charge on the metal sphere, we can use the formula:
Q = V × C
where Q is the charge, V is the potential difference, and C is the capacitance.
The capacitance of a sphere is given by:
C = 4 × [tex]\pi[/tex] × ∈ × R
where R is the radius of the sphere, epsilon (∈) is the electric constant and pi is the mathematical constant.
Substituting the given values, we have:
Q = 23000 V × (4 × [tex]\pi[/tex] × 8.854 x 10⁻¹² F/m × (0.4 m / 2))
Solving for Q, we get:
Q = 2.5 x 10⁻⁸ Coulomb
So, the charge on the metal sphere is 2.5 x 10⁻⁸ Coulomb.
What is Coulomb?A coulomb (C) is the unit of electric charge in the International System of Units (SI). It is defined as the amount of electric charge transferred by a constant current of one ampere in one second. Electric charge is a fundamental property of matter, and it is the charge that causes the attraction and repulsion of electric charges. The charge of an electron is -1.60 x 10⁻¹⁹ Coulombs, and the charge of a proton is +1.60 x 10⁻¹⁹Coulombs. Coulombs are used to measure the amount of charge on an object, the amount of charge flowing through a circuit, and the amount of charge stored in a capacitor.
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find the measure of each interior angle and each exterior angle of a regular 45-gon.
Each Interior angle of a regular 45-gon is 172° and each exterior angle is 188°.
A polygon is defined as the closed 2-D shape with straight sides. For example a pentagon is the closed of 5 straight sides. Interior angle is defined as the angle subtended by two straight sides inside the traverse. Whereas exterior angle defined as the angle subtended by two straight sides outside the closed traverse. A 45-gon is closed traverse with 45 straight sides.
The sum of all the interior angles of a polygon is (2n-4)×90.
The sum of all the exterior angles of a polygon is (2n+4)×90
Where n number of straight sides.
So the sum of all interior angles of 45-gon is (2×45-4)×90 = 7740
Each interior angle is 7740/45 = 172°
So the sum of all exterior angles of 45-gon is (2×45+4)×90 = 8460
Each exterior angle is 8460/45 = 188°
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what is the repulsivee electrical force between two protons 5.0*10^-15m apart from each other in an atomic nucleus?
The repulsive electrical force between two protons is 3.6 × 10³⁹ N. The result is obtained by using the formula for electrostatic.
What is the formula for electrostatic force?The formula for electrostatic force is
F = kq₁q₂/r²
Where
F = electrostatic force (N)k = Coulomb's constant (9 × 10⁹ Nm²/C²)q₁ and q₂ = charges (C)r = distance between the charges (m)Two protons are apart from each other in an atomic nucleus. The distance between them is 5.0 × 10⁻¹⁵ m.
Find the repulsive electrical force!
Proton has a charge of +1. So, the electrostatic force would be
F = kq₁q₂/r²
F = 9 × 10⁹(1)(1)/(5.0 × 10⁻¹⁵)²
F = (9 × 10⁹)/(2.5 × 10⁻³⁰)
F = 3.6 × 10³⁹ N
Hence, the two protos has repulsive electrical force of 3.6 × 10³⁹ N.
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A ball has a mass of 3,526 grams and is rolling down a hill at 3 m/s2. what is the force the ball is rolling down the hill with?
The force acting on the ball rolling down the hill is 10578N.
How to calculate force?Force in physics is a physical quantity that denotes ability to push, pull, twist or accelerate a body. The force acting on a body can be calculated using the following expression;
Force = mass × acceleration
According to this question, a ball has a mass of 3,526 grams and is rolling down a hill at 3 m/s². The force acting on the ball can be calculated as follows:
Force = 3526 × 3
Force = 10,578N
Therefore, 10578N is the force acting on the ball.
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a puck slides with speed v on a frictionless sheet of ice at the north pole. in the non-inertial rotating frame of the earth the puck moves in a circle. a) what is the radius of the circle? b) what is the period of rotation? c) now let the puck slides with speed v toward the south on a frictionless sheet of ice at the equator. what is the radius of the circle? d) now let the puck slides with speed v toward the south on a
a) The North Pole is equal to the Earth's radius (6.371 x 10⁶ m).
b) The period of rotation is 24 hours.
c) The puck moves in a circle with a radius of zero.
d) The circle's radius would be R cos(45).
What is rotation, exactly?The process by which an object spins around its own axis is referred to as "rotation." The process by which an object moves around another object is referred to as a "revolution." The Earth's rotation on its own axis, for instance, is what creates the 24-hour day.
a) In the non-inertial rotating frame of the Earth, This is because objects at the poles move in circles with a radius that is equal to the Earth's. This is caused by the Earth's rotation.
b) The puck's period of rotation, or the time it takes for the puck to complete one full revolution, is approximately the length of a day. This is due to the fact that the puck moves as a result of the Earth's rotation, which takes one day to complete.
c) When moving at a speed of v toward the south on frictionless ice at the equator, the puck moves in a circle with a radius of zero. The puck would not travel in a circular path because the Earth's rotation does not cause objects to move in circles at the equator.
d) Because it is the projection of the earth's radius onto the plane perpendicular to the axis of rotation, the circle's radius would be R cos(45). The radius projected at 45 degrees latitude is shorter than the radius projected at the equator.
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The complete question is:
A puck slides with speed v on a frictionless sheet of ice at the North Pole. In the non-inertial rotating frame of the Earth the puck moves in a circle.
a) What is the radius of the circle?
b) What is the period of rotation?
c) Now let the puck slides with speed v toward the south on a frictionless sheet of ice at the equator. What is the radius of the circle?
d) Now let the puck slide with speed v toward the south on a frictionless sheet of ice a ta latitude of 45o. What is the radius of the circle?
If the seat weighs 305 N and a 875 N person is sitting in it, find the tension Thorizontal in the horizontal cable
A person weighing 875 N sitting on a 305 N seat will exert 1180 N of tension on the horizontal cable.
To find the tension in the horizontal cable, we can use the principle of equilibrium. The principle of equilibrium states that in order for an object to be in equilibrium, the sum of all the forces acting on it must be equal to zero. In this case, the seat and the person sitting in it are in equilibrium, so the sum of all the forces acting on it must be equal to zero. We know that the weight of the seat is 305 N, and the weight of the person sitting in it is 875 N. The weight of the seat and the person is the force acting downward on the seat and the person. We also know that the tension in the horizontal cable is the force acting upward on the seat and the person. Therefore, the sum of the forces acting on the seat and the person is:
Tension in horizontal cable - (weight of seat + weight of person) = 0
Tension in horizontal cable = (weight of seat + weight of person) = 305 N + 875 N = 1180 N
So the tension in the horizontal cable is 1180 N.
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