You would like to study all of the numbers that are at a distance 10 or less from a number -20. Write this using absolute value notation and use the variable x

Answers

Answer 1

Answer:

Step-by-step explanation:

dad hates me sorry bye

Answer 2

Checking for approximate normality in the population is essential for constructing a valid confidence interval, particularly when dealing with small sample sizes. This ensures the accuracy and reliability of the interval in estimating the true population parameter.

It's important to check whether the population is approximately normal before constructing a confidence interval because the accuracy and validity of the interval depend on the underlying distribution of the population. Here's a step-by-step explanation:

1. A confidence interval is a range of values within which the true population parameter (e.g., mean or proportion) is likely to fall, with a certain level of confidence (e.g., 95% or 99%).

2. The process of constructing a confidence interval relies on the Central Limit Theorem, which states that, for large sample sizes, the sampling distribution of the sample mean will be approximately normal, regardless of the population distribution.

3. However, for small sample sizes, the distribution of the population needs to be approximately normal in order to obtain an accurate confidence interval. This is because the normality assumption is crucial for the proper interpretation of the interval.

4. If the population is not approximately normal, the confidence interval may not provide a reliable estimate of the true population parameter, leading to incorrect conclusions and potentially invalid results.

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Related Questions

A storage container got 200 gears from supplier A and 300 gears from supplier B.Inspector told me the gears are identical. What is the probability of randomly NOT selecting a gear made by supplier B? 30% 40% 60% 20%

Answers

The probability of randomly NOT selecting a gear made by supplier B is 40%.

There are a total of 500 gears in the storage container, with 300 of them made by supplier B. The probability of randomly selecting a gear made by supplier B is therefore 300/500, or 60%.

The probability of NOT selecting a gear made by supplier B is 1 minus the probability of selecting a gear made by supplier B. So, the probability of randomly NOT selecting a gear made by supplier B is 1 - 0.6, or 0.4.

Therefore, the answer is 40%.


To find the probability of NOT selecting a gear made by supplier B, follow these steps:

1. Determine the total number of gears: There are 200 gears from supplier A and 300 gears from supplier B, so there are a total of 200 + 300 = 500 gears in the storage container.

2. Calculate the proportion of gears made by supplier A: Since there are 200 gears from supplier A out of a total of 500 gears, the proportion is 200/500.

3. Convert the proportion to a percentage: (200/500) * 100 = 40%

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The first rule is add 12, then divide by 2 starting from 4. The second rule is multiply by 2, then subtract 2 starting from 3. What are the first four ordered pairs using the two sequences?(4, 4), (8, 6), (10, 10), (11, 18)(0, 4), (3, 6), (4, 10), 5, 18)(4, 3), (8, 4), (10, 6), (11, 10)(0, 3), (3, 4), (4, 6), (5, 10)

Answers

The first four ordered pairs using both sequences are (4, 14), (8, 9), (10, 20), and (11, 15).

To find the ordered pairs using both rules, we simply apply both rules to each starting value.

Starting with 4:
- Applying the first rule gives us 8, which we then apply the second rule to and get 14. So the first ordered pair is (4, 14).
- Applying the second rule first gives us 6, which we then apply the first rule to and get 9. So the second ordered pair is (8, 9).

Starting with 10:
- Applying the first rule gives us 11, which we then apply the second rule to and get 20. So the third ordered pair is (10, 20).
- Applying the second rule first gives us 18, which we then apply the first rule to and get 15. So the fourth ordered pair is (11, 15).

Therefore, the first four ordered pairs using both sequences are (4, 14), (8, 9), (10, 20), and (11, 15).

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I’ll give brainless if right

Answers

Answer:

3x - 15 + 5x + 9 = 180

8x - 6 = 180

8x = 186

x = 23.25

So angle ABC measures 3(23.25) - 15 = 54.75°, and angle LMN measures

5(23.25) + 9 = 125.25°.

B is correct.

A new golf instructional expert is on the scene. She claims that her students can hit their drivers an average of 300yds. The LPGA does not think that this is accurate and that the students actually hit the ball less than that. The LPGA took a random sample of 45 of her students.

Answers

In order to determine if the golf instructional expert's claim is accurate, the LPGA would need to analyze the data collected from the random sample of 45 students.

Based on the given information, the new golf instructional expert claims that her students can hit their drivers an average of 300 yards. However, the LPGA is skeptical about this claim and believes that the students actually hit the ball less than that. To test this hypothesis, the LPGA took a random sample of 45 of her students.

By taking a random sample, the LPGA can estimate the average driving distance of all of the expert's students. If the sample's average is significantly less than 300 yards, then the LPGA's hypothesis would be supported. On the other hand, if the sample's average is close to 300 yards, then the new golf instructional expert's claim would be supported.

It is important to note that the average driving distance of a random sample may not necessarily represent the average driving distance of all of the expert's students. However, taking a random sample is a reliable way to estimate the population's average with a certain level of confidence.


To address your question, let's break it down into steps:

1. A golf instructional expert claims that her students can hit their drivers an average of 300 yards.
2. The LPGA believes this claim is inaccurate and thinks the students' actual average distance is less than 300 yards.
3. To test the claim, the LPGA takes a random sample of 45 students from the golf instructional expert's students.

In order to determine if the golf instructional expert's claim is accurate, the LPGA would need to analyze the data collected from the random sample of 45 students. They would calculate the average distance these students can hit their drivers and compare it to the claimed 300-yard average. If the actual average distance is significantly less than 300 yards, the LPGA would have evidence to dispute the golf instructional expert's claim.

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Complete Question:

A new golf instructional expert is on the scene. She claims that her students can hit their drivers an average of 300 yards. The LPGA does not think that this is accurate and that the students actually hit the ball less than that. The LPGA took a random sample of 45 of her students. Assume an error level of 5%. What is the null hypothesis?

In seventh grade, Emile grew
3 7/10cm, and in eighth grade he grew 3 4/5cm. How much did his height increase during these two years?

The answer should be written as a proper mixed number and should be simplified, if possible

Answers

The change in Emile's height based on old and new height is 0.9 cm or 9/10 cm.

The change in Emile's height can be calculated using the subtraction. The formula to be used for it is -

Change in height = New height - Old height

Firstly changing the height to fraction.

Old height = [tex]3 \frac{7}{10} [/tex]

Old height = ((10×3)+7)/10

Old height = 37/10 cm

New height = [tex]4 \frac{3}{5} [/tex]

New height = ((5×4)+3)/5

New height = 23/5 cm

Keep the values in formula to find the value of change in height

Change in height = 23/5 - 37/10

Change = 23×2 - 37/10

Change = 46 - 37/10

Change = 0.9 cm

Hence, the change in height is 0.9 cm.

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The complete question is -

In seventh grade, Emile grew

3 7/10cm, and in eighth grade, he grew 4 3/5cm. How much did his height increase during these two years?

The answer should be written as a proper mixed number and should be simplified, if possible

During these two years, Emile's height increased by 0.9 cm or 9/10 cm.

We will calculate the change in Emile's height using Subtraction. The formula that we will use is:

Change in height = Eighth-grade height - Seventh-grade height

Firstly, we will convert the height to a fraction.

Seventh-grade height = ((10×3)+7)/10

Seventh-grade height = 37/10 cm

Now,

Eighth-grade height = ((5×4)+3)/5

Eighth-grade height = 23/5 cm

Now, find the change in height by substituting the values in the formula.

Change in height = Eighth-grade height - seventh-grade height

                             =   23/5 - 37/10

Change in height = 23×2 - 37/10

Change = 46 - 37/10

Change = 0.9 cm

Therefore, the increase in height during these two years is 0.9 cm or 9/10 cm.

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#4Change from standard form to vertex formy= x²+4x+3

Answers

So the vector form of the quadratic function y = x² + 4x + 3 is: y = (x + 2)² - 1.

To change from standard form to vertex form, we need to complete the square.

First, we group the x-terms together and factor out any common coefficient of x², giving:

y = x² + 4x + 3

y = 1(x² + 4x) + 3

Next, we need to add and subtract a constant inside the parentheses to complete the square. To determine this constant, we take half of the coefficient of x (4) and square it:

(4/2)² = 4

So we add and subtract 4 inside the parentheses:

y = 1(x² + 4x + 4 - 4) + 3

Now we can factor the quadratic expression inside the parentheses as a perfect square:

y = 1[(x + 2)² - 4] + 3

Simplifying and rearranging terms, we get:

y = (x + 2)² - 1

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Factor ????????????

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Hello! How are you? The answer for this is f(x)=(2x+3)(4x-7).
Sorry for the messy hand writing, I was trying to hurry up so u can get the answers. Enjoy your day! :)

A function of the form f(x) = ab* is modified so that the b value remains the same but the a value is increased by 2.
How do the domain and range of the new function compare to the domain and range of the original function?
Check all that apply.
O The range stays the same.
O The range becomes y > 2.
O The domain stays the same.
O The domain becomes x > 2.
O
The range becomes y ≥ 2.
O The domain becomes x ≥ 2.

Answers

The correct statement regarding the domain and the range of the exponential function is given as follows:

The range stays the same.The domain stays the same.

How to define an exponential function?

An exponential function has the definition presented as follows:

[tex]y = ab^x[/tex]

In which the parameters are given as follows:

a is the value of y when x = 0.b is the rate of change.

The function is in the standard format, meaning that the horizontal asymptote is y = 0, and thus the multiplication of a by zero does not change the horizontal asymptote, and the range stays the same.

The domain also remains the same, as an exponential function is defined for all real values.

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T/F : A determinant of an nÃn matrix can be defined as a sum of multiples of determinants of (nâ1)Ã(nâ1) submatrices.

Answers

True. The determinant of an n x n matrix can be defined as a sum of multiples of determinants of (n-1) x (n-1) submatrices, which are called the minors of the matrix.

The determinant of an n x n matrix can be defined as a sum of multiples of determinants of (n-1) x (n-1) submatrices, which are called the minors of the matrix.

More specifically, let A be an n x n matrix with entries a_ij. The determinant of A, denoted by det(A), can be defined recursively as follows:

- If n = 1, then det(A) = a_11.
- If n > 1, then det(A) = sum((-1)^(i+j) * a_ij * det(A_ij)), where the sum is taken over the first row or first column of A. Here, A_ij denotes the (n-1) x (n-1) submatrix obtained by deleting the i-th row and j-th column of A.

This recursive definition shows that the determinant of an n x n matrix can be expressed as a sum of (n-1) x (n-1) determinants of submatrices, with appropriate signs and coefficients. This is known as the cofactor expansion of the determinant along the first row or first column of the matrix.

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Last year Bob opened an investment account with $5200. At the end of the year the amount in the account has decreased by 23.5%. How much is this decrease in dollars and how much money was in his account at the end of last year

Answers

The required decrease in dollars was $1222 and the amount of money in Bob's account at the end of last year was $3978.

To find the decrease in dollars and the amount of money in Bob's account at the end of last year, we can use the following steps:

Calculate the amount of the decrease. We can do this by multiplying the original amount by the percentage decrease as a decimal:

Decrease = 0.235 x $5200 = $1222

So, the decrease in dollars is $1222.

Calculate the amount of money in Bob's account at the end of last year. We can do this by subtracting the decrease from the original amount:

Amount at end of last year = $5200 - $1222 = $3978

So, the amount of money in Bob's account at the end of last year was $3978.

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Using the information in the diagram ABDCCalculate i.the length of CBii.the angle CBDiii.the area of the diagram ABDC

Answers

The area of the diagram ABDC is 625cm2.

We are given that;

RQ is parallel to ST, which implies that ∆PRQ and ∆PST are similar by the AA criterion (angle-angle). We are also given that ST = 4 cm, RP = 10 cm, and PT = 5 cm;

Now,

we can use the fact that RP = 10 cm and PT = 5 cm to find PQ by using the Pythagorean theorem. PQ is the hypotenuse of the right triangle PRT, so we get:

PQ2 = RP2 + PT2 PQ2 = 102 + 52 PQ2 = 100 + 25 PQ2 = 125 PQ = √125 PQ ≈ 11.18 cm

Now we can use PQ and ST as corresponding sides to find the scale factor. We get:

Scale factor = PQ / ST Scale factor ≈ 11.18 / 4 Scale factor ≈ 2.795

ii. To find |RQ|, we can use the scale factor and multiply it by |ST|. We get:

|RQ| = Scale factor * |ST| |RQ| ≈ 2.795 * 4 |RQ| ≈ 11.18 cm

b. Find the area of ∆PST if the area of ∆PRQ is 80 cm2.

To find the area of ∆PST, we can use the fact that the ratio of the areas of similar triangles is equal to the square of the scale factor. We get:

Area of ∆PST / Area of ∆PRQ = (Scale factor)2 Area of ∆PST / 80 = (2.795)2 Area of ∆PST / 80 = 7.812 Area of ∆PST = 7.812 * 80 Area of ∆PST ≈ 625 cm2

Therefore, by the area the answer will be 625cm2.

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en el siguiente triángulo empleando las propiedades del mismo ​

Answers

From the triangle, the values of α  , β and Ф are 97⁰, 45⁰ and 38⁰

How to determine the values?

Recall that the sum of angles of a straight line is 180 degrees and the sum of angles of a triangle is 180 degrees also.

using the given properties of a triangle and angles,

We have that Y + β - 180  ( sum of angles on a straight line)

where β = 135 degrees

Y = 180-135

Y = 45⁰

Also, using the same properties,

α + <EAC = 180 (sum of <s of a straight line)

α + 83 = 180

α = 97⁰

Ф = 180 - (97 + 45)

Ф = 180 -  142

Ф = 38⁰

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Dilations about a point I need help asap please

Answers

The coordinates of the image of the dilation of the quadrilateral MNOP are;

M = (0, 4)       M' = (0, 3)

N = (1, 2)        N' = (2, -1)

O = (0, 0)       O' = (0, -5)

P = (-1, 2)        P' = (-2, -1)

The drawing of the figure with the vertices labeled, created with MS Excel is attached

What is a dilation transformation?

A dilation transformation is one in which a geometric figure is resized to become smaller or larger.

The coordinates of the dilation of a point about the point (0, 5) can be found by first translating the quadrilateral MNOP with regards to the point (0, 5), such that the center is located at the origin as follows;

The coordinates of MNOP are; M(0, 4), N(1, 2), O(0, 0), and P(-1, 2)

The  coordinates of the image following the translation are;

M' = M - (0, 5) = (0, -1)

N' = N - (0, 5) = (1, -3)

O' = O - (0, 5) = (0, -5)

P' = P - (0, 5) = (-1, -3)

The translated points are then dilated as follows;

The coordinates of the image following the dilation are;

M'' = 2 × M' = (0, -2)

N'' = 2 × N' = (2, -6)

O'' = 2 × O' = (0, -10

P'' = 2 × P' = (-2, -6)

The above image are translated to their initial position to get;

M''' = M'' + (0, 5) = (0, 3)

N''' = N'' + (0, 5) = (2, -1)

O''' = O'' + (0, 5) = (0, -5)

P''' = P'' + (0, 5) = (-2, -1)

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There are 10 brown, 10 black, 10 green, and 10 gold marbles in bag. A student pulled a marble, recorded the color, and placed the marble back in the bag. The table below lists the frequency of each color pulled during the experiment after 40 trials.


Outcome Frequency
Brown 13
Black 9
Green 7
Gold 11


Compare the theoretical probability and experimental probability of pulling a gold marble from the bag.
The theoretical probability, P(gold), is 25%, and the experimental probability is 27.5%.
The theoretical probability, P(gold), is 50%, and the experimental probability is 11.5%.
The theoretical probability, P(gold), is 25%, and the experimental probability is 25%.
The theoretical probability, P(gold), is 50%, and the experimental probability is 13.0%.

Answers

The correct option is the first one:

The theoretical probability, P(gold), is 25%, and the experimental probability is 27.5%.

How to find the probabilities?

The experimental probability is equal to the quotient between the number of times that a gold block was taken and the total number of trials, so it is:

E = 11/40 = 0.275

Multiply this by 100% to get the percentage:

0.275*100% = 27.5%

For the theoretical probability, take the quotient between the number of gold blocks and the total number:

T = 10/40 = 0.25

And multiply it by 100%

100%*0.25 = 25%

Then the correct option is The theoretical probability, P(gold), is 25%, and the experimental probability is 27.5%.

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solve the equation p+(1/2p+3)=21

Answers

Answer:

p = 12

Step-by-step explanation:

Make p an independent variable. First, combine like terms.

3/2p+3=21

Multiply everything by 2.

3p+6=42

Subtract 6 from both sides.

3p=42-6

3p=36

Divide both sides by 3.

p=36/3

p=12

What’s the answer? Help me plsease I need help

Answers

Answer:  A

Step-by-step explanation:

Draw a line going out in 3rd quadrant.

your opposite side from angle is5 using pythagorean

and it's positive because it's in the +5 y direction

so sin x = 5/13

A ) 5

13
Is the correct answer

In ΔNOP, o = 2.2 cm, n = 8.6 cm and ∠N=134°. Find all possible values of ∠O, to the nearest 10th of a degree.

Answers

The values of angle O in the triangle is 13.1 degrees

Finding the values of angle O

From the question, we have the following parameters that can be used in our computation:

o = 2.2 cm, n = 8.6 cm and ∠N=134

Using the law of sine, we have

o/sin(O) = n/sin(N)

substitute the known values in the above equation, so, we have the following representation

2.2/sin(O) = 8.6/sin(134)

So, we have

sin(O) = 2.2 * sin(134)/8.6

Evaluate and talke the arc sin

O = 13.1 degrees

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Answer:

10.6

Step-by-step explanation:

Trust; also im smart so like yeah.

a 90% confidence interval for the mean of a population is computed to be 135 to 160. which one of the following claims would the interval tend to refute?

Answers

The only claim that would tend to be refuted by the 90% confidence interval of 135 to 160 is B) The population mean is 125.

The 90% confidence interval for the mean of a population being computed to be 135 to 160 means that if we were to take multiple samples from the population and compute the mean of each sample, 90% of the intervals we construct would contain the true population mean. Therefore, any claim that falls outside of this interval would tend to be refuted.

Let's consider the options.

A) The population mean is 145.
This claim falls within the 90% confidence interval of 135 to 160, so it is not refuted by the interval.

B) The population mean is 125.
This claim falls outside of the 90% confidence interval of 135 to 160, so it is refuted by the interval.

C) The population mean is 170.
This claim also falls outside of the 90% confidence interval of 135 to 160, so it is refuted by the interval.

D) The population mean is between 130 and 150.
This claim falls within the 90% confidence interval of 135 to 160, so it is not refuted by the interval.

Therefore, the only claim that would tend to be refuted by the 90% confidence interval of 135 to 160 is B) The population mean is 125.
A 90% confidence interval for the mean of a population, computed to be 135 to 160, provides a range in which we can be 90% confident that the true population mean lies. This confidence interval helps us make inferences about the population based on sample data. The given interval would tend to refute any claim that falls outside of this range.

For example, if someone claims that the population mean is either below 135 or above 160, this confidence interval would challenge that assertion. Since we are 90% confident that the true population mean falls between 135 and 160, it would be statistically unlikely for the actual mean to be outside of this range. In conclusion, any claim suggesting a population mean outside the 135 to 160 interval would be refuted by this 90% confidence interval.

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Complete question: For the problem, select the best response.

A 90% confidence interval for the mean of a population is computed to be 135 to 160. Which one of the following claims would the interval tend to refute?

A. The population mean is more than 110.

B. The population mean is less than 150.

C. The population mean is between 140 and 150.

D. The population mean is more than 140.

E. The population mean is less than than 125.

. Sasha has 2 blocks of clay shaped like the
rectangular prism below. She joins them to form
a rectangular prism with a length of 12 inches.
What is the surface area of the larger prism?
6 in.
2 in.
2 in.

Answers

The surface area of the larger prism is 104 square inches

What is the surface area of the larger prism?

From the question, we have the following parameters that can be used in our computation:

Length = 2 inchesWidth = 2 inchesHeight = 6 inches (12 inches, when doubled)

The surface area is then calculated as

Area = 2(lw + wh + lh)

Where:

l = Length = 2 inchesw = Width = 2 inchesh = Height = 6 inches (12 inches, when doubled)

By substitution, we have the following equation

Area = 2 * (2 * 2 + 2 * 12 + 12 * 2)

Evaluate the sum and the products

Area = 104

Hence, the surface area is 104 square inches

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2. Circle A has a radius of 21 meters. Circle B has a radius of
28 meters.
a. Find the circumference of each circle. Use wr as part of the answer.

b. Generalize is the relationship between the radius and
circumference the same for all circles? Explain.

Answers

a. The circumference of circle A and B are 131. 88 meters and 175. 84 meters

b. Yes, the the relationship between the radius and circumference the same for all circles. As the radius increases, the circumference also increases

How to determine the circumference

The formula that is used to calculate the circumference of a circle is expressed as;

C = 2πr

It is so such that the parameters of the equation are;

C is the circumference of the circleπ takes the constant value of 22/7 or 3.14r is the radius of the circle

From the information given, we have that;

For circle A

Circumference = 2× 3.14 × 21

Multiply the values

Circumference = 131. 88 meters

For circle B

Circumference = 2× 3.14 × 28

Multiply the values

Circumference = 175. 84 meters

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May I please get some help on these

Answers

Answer:

The Correct answer is

57°

a student club is designing a trebuchet for launching a pumpkin into projectile motion. based on an analysis of their design, they predict that the trajectory of the launched pumpkin will be parabolic and described by the equation y(x)

Answers

A student club is designing a trebuchet to launch a pumpkin into projectile motion. The trajectory of the launched pumpkin is predicted to be parabolic, and can be described by the equation y(x). This means that as the pumpkin moves through the air, its path will follow a parabolic shape, which is common in projectile motion scenarios.



Based on the student club's design, they predict that the trajectory of the launched pumpkin will follow a parabolic path. This means that the height of the pumpkin (y) will depend on its horizontal distance from the launch point (x). The equation that describes this relationship is known as the "trajectory equation" or "equation of motion."

The general form of the trajectory equation for projectile motion is:

y(x) = ax^2 + bx + c

where a, b, and c are constants that depend on the initial velocity, angle of launch, and other factors.

To determine the specific values of a, b, and c for the student club's trebuchet, they will need to conduct experiments or simulations to measure the pumpkin's height at different horizontal distances. They can then use this data to fit the trajectory equation to the observed data points.

Once they have the trajectory equation, they can use it to make predictions about the pumpkin's flight path and adjust their design accordingly. For example, if the pumpkin is not landing where they want it to, they can tweak the launch angle, velocity, or other factors to get a better result.

Based on your question, a student club is designing a trebuchet to launch a pumpkin into projectile motion. The trajectory of the launched pumpkin is predicted to be parabolic, and can be described by the equation y(x). This means that as the pumpkin moves through the air, its path will follow a parabolic shape, which is common in projectile motion scenarios.

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The random variable X representing the number of cherries in a cherry puff has the following probability distribution:
x 4 5 6 7
P (X = x) .2 .4 .3 .1
(a) Find the population mean and variance of X.
(b) Find the mean and the variance of the mean for random samples of 36 cherry puffs.
(c) Find the probability that the average number of cherries in 36 cherry puffs will be less than 5.5.

Answers

The probability that the average number of cherries in 36 cherry puffs will be less than 5.5 is approximately 0.997.

(a) The population mean of X is:

E(X) = 4(.2) + 5(.4) + 6(.3) + 7(.1) = 4.9

The population variance of X is:

Var(X) = E(X^2) - [E(X)]^2

= 4^2(.2) + 5^2(.4) + 6^2(.3) + 7^2(.1) - (4.9)^2

= 1.49

(b) Since the distribution is discrete and the sample size is large (n = 36), we can use the Central Limit Theorem to approximate the distribution of the sample mean as normal. Therefore, the mean of the sample mean is equal to the population mean, which is 4.9, and the variance of the sample mean is given by:

Var(X) = Var(X)/n

= 1.49/36

≈ 0.0414

(c) To find the probability that the average number of cherries in 36 cherry puffs will be less than 5.5, we standardize the variable as follows:

Z = (X - μ) / (σ / √n)

where μ = 4.9, σ = √Var(X) = √0.0414 ≈ 0.2035, and X = 5.5

Z = (5.5 - 4.9) / (0.2035 / √36) = 2.95

Using a standard normal distribution table or calculator, the probability that Z is less than 2.95 is approximately 0.997. Therefore, the probability that the average number of cherries in 36 cherry puffs will be less than 5.5 is approximately 0.997.

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A box with an open top has a square base and four sides of
equal height. The volume of the box is 490 ft³. If the surface
area is 329 ft², find the dimensions of the box.

Answers

The he dimensions of the box are approximately 7 ft x 7 ft x 10 ft  are

How to solve for the dimensions

Volume: x² * h = 490 ft³

Surface area: x² + 4 * x * h = 329 ft²

volume equation

[tex]h = 490 / x^2[/tex]

substitute this expression for h into the surface area equation:

[tex]x^2 + 4 * x * (490 / x^2) = 329[/tex]

solve for x:

[tex]x^2 + 1960 / x = 329[/tex]

we can multiply both sides by x:

[tex]x^3 + 1960 = 329x[/tex]

This is a cubic equation:

[tex]x^3 - 329x + 1960 = 0[/tex]

The approximate solution for x using cubic equation  is:

x ≈ 7

h = 490 / (7^2)

h = 490 / 49

h = 10

So, the dimensions of the box are approximately 7 ft x 7 ft x 10 ft

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what percentage of survey respondents reported having colleagues who are rude or disrespectful? multiple choice 39% 53% 79% 90% 10%

Answers

According to the survey results, 53% of respondents reported having colleagues who are rude or disrespectful. This is a concerning finding, as workplace incivility can have negative effects on employee well-being, job satisfaction, and productivity.

It is important for organizations to address and prevent such behaviors through training, policies, and a culture of respect and accountability. It is also important for individuals to speak up and address rude or disrespectful behavior when it occurs, in a constructive and professional manner. By promoting civility and respect in the workplace, we can create a more positive and productive work environment for everyone.

According to the survey, 53% of respondents reported having colleagues who are rude or disrespectful. This percentage indicates that more than half of the surveyed individuals have experienced unprofessional behavior from their coworkers.

It is essential for everyone in a professional environment to treat their colleagues with respect and maintain a positive work environment.

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At a track meet, a relay race with a total distance of 1\2 mile is run by a team of 3 runners. Each runner completed the same distance in the race.

Which of these models could be used to find the distance, in miles, run by each of the 3 runners? Choose the THREE correct answers.

Answers

First models could be used to find the distance, in miles, run by each of the 3 runners.

We have,

A relay race with a total distance of 1/2 mile is run by a team of 3 runners.

So, Distance Covered by each runner is

= (1/3) (1/2)  

= 1/16

So, (1/2) x (1/3) = 1/6

(1/2) ÷ 3 = 1/6

So, the correct model  1/2 mile is divided in 3 equal parts are the correct options.

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What is the slope of the line that passes through the points (2, 8) and (-3, 14)? Write your answer in simplest form.

Answers

Answer:

-6/5

Step-by-step explanation:

The slope of a line passing through two points (x1, y1) and (x2, y2) can be found using the slope formula:

slope = (y2 - y1) / (x2 - x1)

Plugging in the given points, we get:slope = (14 - 8) / (-3 - 2) = 6 / (-5)

To write this in simplest form, we can divide the numerator and denominator by their greatest common factor, which is 1 in this case. So the slope in simplest form is:

slope = 6 / (-5) = -6/5

Using the rise/run notation, we can say that the slope of the line passing through the points (2, 8) and (-3, 14) is -6/5, or -6 over 5.

The rise is -6 (since we move down 6 units from y1 to y2), and the run is 5 (since we move 5 units to the left from x1 to x2).

In ΔRST, r = 94 inches, s = 78 inches and ∠T=49°. Find the area of ΔRST, to the nearest square inch.

Answers

The area of ΔRST is 2767 square inches.

We have,

r = 94 inches, s = 78 inches and ∠T=49

We will use the formula

Area= 1/2 a b sin C

So, area of ΔRST

= 1/2 r s sin <T

= 1/2 (94) (78) sin (49)

= 3666 sin(49)

= 2766.7653

= 2767 square inches

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In Minnesota the sales tax rate is 6.875%

B. If the price of a tablet computer sold in Minnesota is $513 including sales tax, what was the list price of the computer?

Answers

The calculated list price of the computer is $480

What was the list price of the computer?

From the question, we have the following parameters that can be used in our computation:

Total price = $513

Sales tax = 6.875%

using the above as a guide, we have the following:

Total price = List price * (1 + tax)

Substitute the known values in the above equation, so, we have the following representation

List price * (1 + 6.875%)  = 513

Evaluate

List price  = 480

Hence, the List price  = 480

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An article in the IEEE Transactions on Electron Devices (Nov. 1986, pp. 1754) describes a study on polysili- con doping. The experiment shown below is a variation of their study. The response variable is base current. Anneal Temperature C) 950 10.15 10.20 9.38 10.02 Polysilicorn Doping (ions) 900 4.60 4.40 3.20 3.50 1000 11.01 10.58 10.81 10.60 I x 1030 2 x 102 tarts there evidence (with α-0.05) indicating that either polysilicon doping level or anneal temperature affects base current? (by Prepare graphical displays to assist in interpreting this experiment. nalyze (d) Iş the model he residuals and comment on supported by this experiment (x.-doping level, x,- temperature)? Estimate the parameters in this model and plot the response surface.

Answers

Based on the given data, it seems that both the polysilicon doping level and anneal temperature can affect the base current.

To visually interpret the data, we can create a scatter plot with the polysilicon doping level on the x-axis and the base current on the y-axis, with different colors or symbols representing the different anneal temperatures. We can also create a similar plot with the anneal temperature on the x-axis and the base current on the y-axis, with different colors or symbols representing the different polysilicon doping levels.

To analyze the model, we can examine the residuals to see if they are randomly distributed around zero, indicating that the model is a good fit for the data. If the residuals show a pattern, it may suggest that the model is not a good fit.

Assuming a linear model, we can estimate the parameters using regression analysis. The model could be of the form:

Base current = β0 + β1(doping level) + β2(anneal temperature) + ε

where β0 is the intercept, β1 is the coefficient for doping level, β2 is the coefficient for anneal temperature, and ε is the error term.

Once we have estimated the parameters, we can plot the response surface to see how the base current changes as a function of both the doping level and annealing temperature. This will give us a better understanding of the relationship between these variables and the response variable.

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