you're reading from the journal of a European explorer from the early 1600s. In one passage, the explorer describes itting on the Atlantic Ocean with little wind. He describes the area as being quite far north of the equator and having nigh pressure. n which type of global wind was this explorer sailing? doldrums horse latitudes jet stream O polar easterlies ​

Answer:

7.55 g

Explanation:

Using the relation :

Δt = temperature change = (6° - 0°) = 6°

Q = quantity of heat

C = specific heat capacity = 4190 j/kg/k

1000 J = 1kJ

333 KJ = 333000 j

The quantity of ice that will melt ;

= 0.419 * 6 * 100 / 333000

= 2514000 / 333000

= 7.549 g

The mass of ice that will melt :

2.514 / 0.333

= 7.549 g

Answer:

Explanation:

m₂ is hanging vertically and m₁ is placed on inclined plane . Both are in limiting equilibrium so on m₁ , limiting friction will act in upward direction as it will tend to slip in downward direct . Tension in cord connecting the masses be T .

For equilibrium of m₁

m₁ g sinα= T + f where f is force of friction

m₁ g sinα= T + μsx m₁ g cosα

m₁ g sinα -  μs x m₁ g cosα = T

For equilibrium of m₂

T = m₂g

Putting this value in equation above

m₁ g sinα -  μs x m₁ g cosα = m₂g

m₂ = m₁ sinα -  μs x m₁ cosα

Answer:

10.116 Pounds/45 newtons = 10.1164024 pounds/force

Explanation:

Divide the newtons by the rate of acceleration, which will give you the mass of the object. The mass will be in kilograms, because a single newton represents the amount of force needed to move one kilogram one meter. For our example, we will divide 10 N by 2 m/s/s, which give us a mass of 5 kg

Answer:

F2 = 834 N

Explanation:

We are given the following for the bicycle;

Diameter; d1 = 63 cm = 0.63 m

Mass; m = 1.75 kg

Resistive force; F1 = 121 N

For the sprocket, we are given;

Diameter; d2 = 8.96 cm = 0.0896 m

Radius; r2 = 0.0896/2 = 0.0448 m

Radial acceleration; α = 4.4 rad/s²

Now moment of inertia of the wheel which is assumed to be a hoop is given by; I = m(r1)²

Where r1 = (d1)/2 = 0.63/2

r1 = 0.315 m

Thus, I = 1.75 × 0.315²

I = 0.1736 Kg.m²

The torque is given by the relation;

I•α = F1•r1 - F2•r2

Where F2 is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².

Thus;

0.1736 × 4.4 = (121 × 0.315) - (0.0448F2)

>> 0.76384 = 38.115 - (0.0448F2)

>> 0.0448F2 = 38.115 - 0.76384

>> F2 = (38.115 - 0.76384)/0.0448

>> F2 = 833.73 N

Approximately; F2 = 834 N

The force applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2 is F2 = 834 N

Force is an external agent applied on any object to displace it from its position. Force is a vector quantity, so with magnitude it also requires direction. Direction is necessary to examine the effect of the force and to find the equilibrium of the force.

We are given the following for the bicycle;

Diameter; d1 = 63 cm = 0.63 m

Mass; m = 1.75 kg

Resistive force; F1 = 121 N

For the sprocket, we are given;

Diameter; d2 = 8.96 cm = 0.0896 m

Radius; r2 = 0.0896/2 = 0.0448 m

Radial acceleration; α = 4.4 rad/s²

Now the moment of inertia of the wheel which is assumed to be a hoop is given by;

[tex]I=mr_1^2[/tex]

Where

r1 = 0.315 m

I = 1.75 × 0.315²

I = 0.1736 Kg.m²

The torque is given by the relation;

[tex]I\alpha=F_1\times r_1-F_2\times r_2[/tex]

Where [tex]F_2[/tex]  is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².

0.1736 × 4.4 = (121 × 0.315) - (0.0448[tex]F_2[/tex])

0.76384 = 38.115 - (0.0448[tex]F_2[/tex])

[tex]F_2= \dfrac{38.115-0.7638}{0.0448}[/tex]

[tex]F_2=833.73\ N[/tex]  

Approximately; F2 = 834 N

Thus the force applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2 is F2 = 834 N

To know more about Force follow

https://brainly.com/question/25239010

Answer:

Dead

Explanation:

there are no blood vessels in the epidermis so the cells get their nutrients by diffusion from the connective tissue below

Answer: barometer.

A cyclone is a storm or system of winds that rotates around a center of low atmospheric pressure. An anticyclone is a system of winds that rotates around a center of high atmospheric pressure.

Answer:

Explanation:

radius of circle r = 0.9 m.

(a ) In a motion on circular path , work done is zero because force ( centripetal force ) acts perpendicular to displacement .

( b )

Tension in string T = m ω²r

Putting the values

60 = .072 x ω² x 0.9

ω² = 926

ω = 30.4 rad /s

angle made in 20 revolutions θ = 20 x 2π = 126.6 rad

time taken = θ / ω

= 126.6 / 30.4

= 4.16 s .

The angle of deviation is defined as the angle which is obtained from the difference between the angle of incidence and the angle of refraction created by the ray of light travelling from one medium to another that has a different refractive index.  I hope this helps you

Answer:

minimum length of runway is needed for take off 243.16 m

Explanation:

Given the data in the question;

mass of glider = 700 kg

Resisting force = 3700 N one one glider

Total resisting force on both glider  = 2 × 3700 N = 7400 N

maximum allowed tension = 12000 N

from the image below, as we consider both gliders as a system

Equation force in x-direction

2ma = T -f

a = T-f / 2m

we substitute

a = (12000 - 7400 ) / (2 × 700 )

a = 4600/1400

a = 3.29 m/s²

Now, let Vf be the final speed and Ui = 0 ( as starts from rest )

Vf² = Ui² + 2as

solve for s

Vf² = 0 + 2as

2as = Vf²

s = Vf² / 2a

given that take of speed for the gliders and the plane is 40 m/s

we substitute

s = (40)² / 2×3.29

s = 1600 / 6.58

s = 243.16 m

Therefore, minimum length of runway is needed for take off 243.16 m

Answer:

Answer:

a

Explanation:

Answer:

 v = 27.28 m /s, θ = 63.9º

Explanation:

For this exercise we can approximate the movement to a projectile launch, let's analyze the situation.

* We must find the horizontal speed, for this we will find the descent time and the horizontal distance

* We look for the vertical speed

At the highest point the speed is horizontal

Let's find the time it takes for the kite to reach the ground

             y = y₀ + v_{oy} t - ½ g t²

             0 =y₀ + 0 -1/2 gt²

             t = [tex]\sqrt{ \frac{2y_o}{g} }[/tex]

             t = √(2 40/32)

             t = 2.5 s

to find the horizontal velocity we must know the horizontal distance, let's use trigonometry

          sin θ = y / l

          θ = sin⁻¹1 y / l

          θ = sin⁻¹ 40/50

          θ = 53.1º

therefore the horizontal distance is

          x = l cos 53.1

          x = 50cos 53.1

          x = 30 m

let's use the equation

          x = v₀ₓ t

          v₀ₓ = x / t

          v₀ₓ = 30 / 2.5

          v₀ₓ = 12 m / s

we look for the vertical component of the velocity

          v_y = v_{oy} - g t

          v_y = 0 - g t

          v_y = - 9.8 2.5

          v_y = -24.5 m / s

the negative sign indicates that the speed is directed downwards, because it is the arrival point, as they indicate that there is no friction, the exit speed is the same, worse with the opposite sign

We already have the two components of the velocity, let's use the Pythagorean theorem to find the modulus

          v = [tex]\sqrt{v_x^2 + v_y^2}[/tex]

          v = [tex]\sqrt{12^2 + 24.5^2}[/tex]

          v = 27.28 m /s

we use trigonometry for the angle

          tan θ = v_y / vₓ

          θ = tan⁻¹ v_y / vₓ

          θ = tan⁻¹ 24.5 / 12

          θ = 63.9º

Answer:

Explanation:

Please post if there is a graph showing the data.

Without a graph, in general the trend can be described as:

"positive" when the dependent variable increases with an increase in independent variable

"negative" when the dependent variable decreases with an increase in independent variable

"neutral" when the dependent variable remains the same with an increase or decrease in independent variable

My Response:

If the mass of an object increases, then its kinetic energy will increase proportionally because mass and kinetic energy have a linear relationship when graphed.

Sample Response:

If the speed of an object increases, then its kinetic energy will increase proportionally because speed and kinetic energy have a linear relationship when graphed.

Answer:

The answer is "39.95 J".

Explanation:

Please find the complete question in the attached file.

[tex]\to W_{AC}=(\mu \ m \ g \ \cos \theta ) d[/tex]

            [tex]=(0.45 \times 1.60 \times 9.8 \times \cos 26^{\circ}) 6.30 \\\\=(7.056 \times \cos 26^{\circ}) 6.30 \\\\=6.34189079\times 6.30\\\\=39.95 \ J\\\\[/tex]

[tex]\therefore \\\\\bold{\Delta E =39.95 \ J}[/tex]

Answer:

a). 53.78 m/s

b) 52.38 m/s

c) -75.58 m

Explanation:

See attachment for calculation

In the c part, The negative distance is telling us that the project went below the lunch point.

Answer: 22.1 m/s

Explanation:

The velocity of Car traveling 30 m/s towards the north

In vector form it is

[tex]v_x=30\hat{j}[/tex]

The velocity of car Y w.r.t X is

[tex]\Rightarrow v_{yx}=15[-\cos 45^{\circ}\hat{i}-\sin 45^{\circ}\hat{j}][/tex]

Solving this

[tex]\Rightarrow v_{yx}=v_y-v_x\\\Rightarrow v_y=v_{yx}+v_x[/tex]

putting values

[tex]\Rightarrow v_y=15[-\cos 45^{\circ}\hat{i}-\sin 45^{\circ}\hat{j}]+30\hat{j}[/tex]

[tex]\Rightarrow v_y=-10.606\hat{i}+19.39\hat{j}[/tex]

absolute velocity relative to ground is

[tex]\left | v_y\right |=\sqrt{(-10.606)^2+(19.39)^2}\\\left | v_y\right |=22.101\ m/s[/tex]

Answer:

extreme heat, because no physical damage can demagnetize a magnet

Explanation:

Answer:

the 3rd one

Explanation:

Answer:

Explanation:

The voltage of a disconnected charged capacitor increases when the plate area is decreased.

When plate area decreases , capacitance C decreases , but charge Q remains constant .

Q = C V where C is capacitance and V is voltage .

when C decreases , V increases for keeping Q constant .

So the statement is true.

The electric field is dependent on the charge density on the plates.

This statement is true .

The voltage of a connected charged capacitor remains the same when the plate area is decreased .

For a connected capacitor , V or voltage is constant which is equal to voltage of charging battery .

So the statement is true .

Answer:

false I think

Explanation:

hope that help

so it's not divided in 3 regions

Answer:

This does not sound too abstract

Explanation:

An example of an Imaginative conservative force field defined in terms of a certain region of space is : A gravitational field and it can be expressed as

[tex]Fx = - \frac{dU_{x} }{dx}[/tex]  and this is because the potential energy in a gravitational field is determined only by the initial and final position of the objects found with the Gravitational field

To determine the change in potential energy  ΔU we will integrate the above equation

hence :  ΔU = [tex]\int\limits^2_1 {F} \, ds[/tex]  

Hence this does not sound too abstract

Answer:

d

Explanation:

Answer:

C

Explanation:

Horsepower refers to the power an engine produces. It's calculated through the power needed to move 550 pounds one foot in one second or by the power needs to move 33,000 pounds one foot in one minute. The power is gauged by the rate it takes to do the work.

Ps:Can I be brainliest.

Have a nice day

Answer:

B as distance increase force decrease, but it is not a linear relationship.

Answer:

Distance S = 11.77 m (Approx.)

Explanation:

Given:

Time t = 1.55 Second

Gravity acceleration = 9.8 m/s²

Find:

Distance S

Computation:

S = ut + (1/2)(g)(t)²

S = (0)(1.55) + (1/2)(9.8)(1.55)²

S = (0)(1.55) + (1/2)(9.8)(1.55)²

Distance S = 11.77 m (Approx.)

Answer:

v = 2591.83 m/s

Explanation:

Given that,

The electric field is 1.27 kV/m and the magnetic field is 0.49 T. We need to find the electron's speed if the fields are perpendicular to each other. The magnetic force is balanced by the electric force such that,

[tex]qE=qvB\\\\v=\dfrac{E}{B}\\\\v=\dfrac{1.27\times 10^3}{0.49}\\\\v=2591.83\ m/s[/tex]

So, the speed of the electron is 2591.83 m/s.

Answer:

 h = [tex](\frac{m}{m+M} )^2 \ \frac{v_o^2}{2g}[/tex]

Explanation:

To solve this problem, let's work in parts, let's start with the conservation of the moment, for this we define a system formed by the block and the bullet, in such a way that the forces during the collision have been internal and the moment is conserved.

initial instant. Before the crash

         p₀ = m v₀

final instant. Right after the crash, but before the pendulum started to climb

         m_f = (m + M) v

the moment is preserved

        p₀ = p_f

        m v₀ = (m + M) v

        v = [tex]\frac{m}{m+M} \ v_o[/tex]  

Now we work the pendulum system with embedded block, we use the concept of conservation of energy

starting point. Lower

        Em₀ = K = ½ (m + M) v²

final point. higher, when it stops

         Em_f = U = (m + M) g h

as there is no friction, energy is conserved

        Em₀ = Em_f

        ½ (m + M) v² = (m + M) g h

         h = [tex]\frac{v^2}{2g}[/tex]

we substitute the speed value of the block plus bullet set

        h = [tex]( \frac{m}{ m+M} \ v_o )^2 \ \frac{1}{2g}[/tex]

        h = [tex](\frac{m}{m+M} )^2 \ \frac{v_o^2}{2g}[/tex]

Answer:

V_{average} = [tex]\frac{1}{2} V_o[/tex]  ,     V_{average} = 2 V

Explanation:

he average or effective voltage of a wave is the value of the wave in a period

            V_average = ∫ V dt

in this case the given volage is a square wave that can be described by the function

           V (t) = [tex]\left \{ {{V=V_o \ \ \ t< \tau /2} \atop {V=0 \ \ \ \ t> \tau /2 } } \right.[/tex]

to substitute in the equation let us separate the into two pairs

             V_average = [tex]\int\limits^{1/2}_0 {V_o} \, dt + \int\limits^1_{1/2} {0} \, dt[/tex]

             V_average = [tex]V_o \ \int\limits^{1/2}_0 {} \, dt[/tex]

             V_{average} = [tex]\frac{1}{2} V_o[/tex]

we evaluate  V₀ = 4 V

             V_{average} = 4 / 2)

             V_{average} = 2 V

Answer:

The order of the light starting from the light closest to the normal line is

Blue light, followed by green ight and then lastly red light

Explanation:

White light travels from one medium to another such as from air to glass is refracted according to Snell's law as follows

n₁·sin(θ₁) = n₂·sin(θ₂)

The given parameters of the white light are;

The angle the incident (incoming) light makes with the surface = 90°

The angle of incidence of the light, θ₁ = 30°

The index of refraction of red light for the glass, n₂ = 1.710

The index of refraction of green light for the glass, n₃ = 1.723

The index of reaction of blue light for the glass, n₄ = 1.735

The refractive index of air, n₁ = 1

The angle of refraction of the red light, θ₂ is given as follows;

1 × sin(30°) = 1.710 × sin(θ₂)

sin(θ₂) = 1 × sin(30°)/1.710

θ₂ = sin⁻¹(1 × sin(30°)/1.710) ≈ 17°

The angle of refraction (to the surface's normal line) of the red light, θ₂ ≈ 17°

The angle of refraction of the green light, θ₃ is given as follows;

1 × sin(30°) = 1.723 × sin(θ₃)

sin(θ₃) = 1 × sin(30°)/1.723

θ₃ = sin⁻¹(1 × sin(30°)/1.723) ≈ 16.869°

The angle of refraction of the green light, θ₃ ≈ 16.869°

The angle of refraction of the green light, θ₄ is given as follows;

1 × sin(30°) = 1.723 × sin(θ₄)

sin(θ₄) = 1 × sin(30°)/1.735

θ₄ = sin⁻¹(1 × sin(30°)/1.735) ≈ 16.749°

The angle of refraction of the green light, θ₄ ≈ 16.749°

The order of colors we see as the in the refracted light inside the glass as the light leave the surface are;

The red light, with an angle of refraction of approximately 17° will be furthest from the normal

The green light which has an angle of refraction of 16.869° will follow and will be intermediate between the red and the blue light

The blue light which has an angle of refraction of 16.749° will follow next and it will be closest to the normal

The order of the light from the normal line will be blue, followed by green and then red light