(05.01)A picture is 5 inches wide and 8 inches tall: A rectangle is shown. The length of the rectangle is labeled 5 inches. The width of the rectangle is labeled 8 inches. A photographer wants to use a scale factor of 2.5 to enlarge a picture. What will the area of the picture be after it is enlarged? 40 in2 250 in2 100 in2 81.9 in2

Answer:

He would need to walk the dog 6 more times because 8 times 11 is 88 and if he has already walked the dog 5 times you would subtract that from 11 to get 6. So the answer would be 6

Step-by-step explanation:

8·11= 88

11-5= 6

Answer

the first one is the answer and none of the above

Step-by-step explanation:

Answer:

Average rate of change for the function [tex]f(x)= x^2-x-1[/tex] over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: [tex]f(x)= x^2-x-1[/tex]

The formula used to find average rate of change is:

[tex]Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}[/tex]

We have, a = -1 and b = 1

Finding f(b) when b=1

[tex]f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1[/tex]

Now, finding f(a), when a= -1

[tex]f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1[/tex]

Now, putting values and finding average rate of change

[tex]Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1[/tex]

So, average rate of change for the function [tex]f(x)= x^2-x-1[/tex] over the interval -1<x<1 is -1

Answer:  [tex]\frac{8x^3}{27y^6}[/tex]

This is the fraction 8x^3 all over 27y^6

On a keyboard, we can write it as (8x^3)/(27y^6)

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Explanation:

The exponent tells you how many copies of the base to multiply with itself.

We'll have three copies of [tex]\left(\frac{2x}{3y^2}\right)[/tex] multiplied with itself due to the cube exponent on the outside.

So,

[tex]\left(\frac{2x}{3y^2}\right)^3 = \left(\frac{2x}{3y^2}\right)*\left(\frac{2x}{3y^2}\right)*\left(\frac{2x}{3y^2}\right)\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{2x*2x*2x}{(3y^2)*(3y^2)*(3y^2)}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{(2*2*2)*(x*x*x)}{(3*3*3)*(y^2*y^2*y^2)}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{8x^3}{9y^6}\\\\[/tex]

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Or another approach you could take is to cube each component of the fraction. The rule I'm referring to is [tex]\left(\frac{a}{b}\right)^c = \frac{a^c}{b^c}[/tex]

Applying that rule will lead to:

[tex]\left(\frac{2x}{3y^2}\right)^3 = \frac{(2x)^3}{(3y^2)^3}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{2^3*x^3}{3^3*(y^2)^3}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{8x^3}{27y^{2*3}}\\\\\left(\frac{2x}{3y^2}\right)^3 = \frac{8x^3}{27y^6}\\\\[/tex]

Either way you should get 8x^3 all over 27y^6 as one fraction.

Answer:

D

Step-by-step explanation:

This is equivalent to t < 4.

clearly this is not part of the set.

Answer: It's (A) 12<X

Step-by-step explanation: I chose that one because the line highlighted on the number line, it's bigger than 12!

Discount amount = price x discount percentage as a decimal:

Discount amount = 62.00 x 0.15 = 9.30

Discount = $9.30

Answer:

$52.70

Step-by-step explanation:

Answer:

120°

Step-by-step explanation:

m<ABD+m<DBC=m<ABC

61°+59°=120°

hope this helped!

Answer:

We conclude that the value of m∠ABC = 120°

Step-by-step explanation:

Given

m∠ABD = 61°

m ∠DBC = 59°

To Determine

m∠ABC = ?

It is clear that the value of m∠ABC can be determined by adding m∠ABD and m∠DBC because m∠ABC the segment BD divides the angle m∠ABC into two adjacent angles m∠ABD and ∠DBC.

Therefore,

m∠ABC = m∠ABD + m∠DBC

             = 61° + 59°            ∵ m∠ABD = 61°, m ∠DBC = 59°

             = 120°

Therefore, we conclude that the value of m∠ABC = 120°

Answer:

[tex]G' = (1,4)[/tex]

[tex]H' = (-4,5)[/tex]

[tex]I = (-8,2)[/tex]

Step-by-step explanation:

Given

[tex]G = (4,1)[/tex]

[tex]H = (5,-4)[/tex]

[tex]I = (2,-8)[/tex]

Reflection: [tex]y = x[/tex]

Required

Determine the coordinates of G'H'I'

The following applies when a line A is reflected over [tex]y = x[/tex]

[tex]A = (x,y)[/tex]

[tex]A' = (y,x)[/tex]

i.e, we simply swap the positions of x and y

So, for:

[tex]G = (4,1)[/tex]

[tex]H = (5,-4)[/tex]

[tex]I = (2,-8)[/tex]

The reflections are:

[tex]G' = (1,4)[/tex]

[tex]H' = (-4,5)[/tex]

[tex]I = (-8,2)[/tex]

See attachment

Answer:

let the third proportion be x.

then 8,12 and x are in proportion

then 8:12=12:x

8x=12×12

x=144/8=18

Step-by-step explanation:

Answer:

12%

Step-by-step explanation:

We can get SI of 3 years = 12005 - 9800 = 2205

SI for 5 years = (2205/3)*5 = 3675 [so that we can get principal amount after deducting SI]

Principal = 12005 - 3675 = 6125

So Rate = (100*3675)/(6125*5) = 12%

Answer:

Length = 22 ; width = 10

Step-by-step explanation:

Perimeter of a rectangle = 2(length + width)

Perimeter = 64 feets

Length = 2 + (2*width)

Let :

Length = l ; width = w

Perimeter = 2((2 + (2w)) + w)

64 = 2(2 + 3w)

64 = 4 + 6w

64 - 4 = 6w

60 = 6w

w = 60/6

w = 10

Width = 10

Length = 2 + (2*width) = 2 + (2*10) = 2 + 20 = 22

Answer:

sam will take the 75 pollywog pralines and divide them into the three bags

75÷3 =25

Answer:

Step-by-step explanation:

1/2

Answer:

its the first one

Step-by-step explanation:

Answer:

Solution in photo

Step-by-step explanation:

Answer:

d 4x^2 + 24x - 8

Step-by-step explanation:

Perimeter of the rectangle = 2x² - 5 + 12x + 1 + 2x² - 5 + 12x + 1

                                            = (2x²+ 2x²) + (12x+ 12x) + (- 5 + 1 - 5 + 1)

                                            = 4x² + 24x - 8

Answer:

50

Step-by-step explanation:

Answer: the answer is 50

Step-by-step explanation:

Step-by-step explanation:

Given that,

For 4 weeks in June, Cameron biked 3 1/4 miles each week and swam 2 1/2 miles each week.

For 3 weeks in July, he biked 4 3/4 miles each week and swam 3 1/2 miles each week.

We need to find how much greater was the total distance Cameron bike and swim in July compared to the total distance he bike in swim in June.

In July, total distance is ,

[tex]4\dfrac{3}{4}\times 3+3\dfrac{1}{2}\times 3\\\\= \dfrac{19}{4}\times 3+\dfrac{7}{2}\times 3\\\\=24.75\ \text{miles}[/tex]

In June, total distance is :

[tex]=4\times 3\dfrac{1}{4}+4\times 2\dfrac{1}{2}\\\\=\dfrac{13}{4}\times 4+\dfrac{5}{2}\times 4\\\\=23\ \text{miles}[/tex]

Hence, in June total distance is 23 miles and in July total distance is 24.75 miles.

Inequality Answer: 1 + y ≥ 3

I hope this helps, and Happy Holidays! :)