1) 70% of what number is 28?

Answer:

The system is of equations is:

[tex]\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.[/tex]

Where g is the amount of general tickets and r is the amount of reserve tickets.

35 general tickets and 25 reserve tickets were sold.

Step-by-step explanation:

Let general tickets be represented by g and reserved tickets be represented by r.

Each general ticket sells for $10 each and reserved tickets $15 each. Dave collected a total of $725. Thus:

[tex]10g+15r=725[/tex]

And a total of 60 tickets were sold. Hence:

[tex]g+r=60[/tex]

Our system of equations is:

[tex]\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.[/tex]

We can solve by substitution. First, divide both sides of the first equation by 5:

[tex]2g+3r=145[/tex]

Next, we can subtract a variable (r in this case) from the second equation:

[tex]g=60-r[/tex]

Substitute:

[tex]2(60-r)+3r=145[/tex]

Distribute:

[tex]120-2r+3r=145[/tex]

Simplify:

[tex]120+r=145[/tex]

Subtract:

[tex]r=25[/tex]

Using the previous equation:

[tex]g=60-r[/tex]

Substitute and evaluate:

[tex]g=60-(25)=35[/tex]

So, 35 general tickets and 25 reserve tickets were sold.

Answer:

5:3

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

The interquartile range of the given data set is 2.

We need to find the interquartile range of the data set given.

To find the interquartile range (IQR), ​first, find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

The given set of data is

0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 5, 6, 6

To find Q1:

The lower half of the numbers are

That is 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 2,

So the median of the lower half (Q1)=1

To find Q3:

The upper half of the numbers are 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 5, 6, 6

So the median of the upper half (Q3)=3

Then, IQR=Q3-Q1=3-1=2

Therefore, the interquartile range of the given data set is 2.

To learn more about the interquartile range visit:

https://brainly.com/question/15686744.

#SPJ5

Answer:

Slope is -7 and the y-intercept is 8

Step-by-step explanation:

Answer:

x>36

Step-by-step explanation:

Hope this helps and good luck

Answer:

18

Step-by-step explanation:

[tex]\frac{6}{1}[/tex] ÷ [tex]\frac{1}{3}[/tex]

Keep Change Flip

[tex]\frac{6}{1}[/tex] × [tex]\frac{3}{1}[/tex] = [tex]\frac{18}{1}[/tex]

Step-by-step explanation:

To prove - Using the method of proof by contradiction, prove that if

                  a product of two positive real numbers is greater than

                  1,000,000, then at least one of the numbers is greater

                   than 1000.

Proof -

For a proof of contradiction , firstly we have to assume that the statement is not true.

Here given statement is -  A product of two positive real numbers is greater than 1,000,000.

Let if possible, there does not exist 2 +ve integer real number such that at least one of the numbers is greater than 1000.

⇒both the number are in between 0 to 1000

Let a and b are 2 +ve real numbers.

⇒ab < 1000×1000

⇒ab < 1000000

As given,

ab > 1000000

Contradiction.

Hence proved.

If a product of two positive real numbers is greater than 1,000,000, then at least one of the numbers is greater than 1000.

Answer:

8.3

Step-by-step explanation:

Answer:

x=0 y=2 z=5

Step-by-step explanation:

so for z

2z=10

divid both side by 2

z=5

equation one

x+2y+5=9

x+2y=4 ------eqn1

equation two

x-y+ 3(5)=13

x-y+15=13

x-y=-2-----eqn2

now you solve it by elimination

eqn1-eqn2

3y=6

y=2

put y=2 into eqn2

x-2=-2

x=0

Answer:

Step-by-step explanation:

Perimeter = 2l + 2w

With the given statement, the width of the rectangle is 4 meters less than the

length,

w = l - 4

sub that in the first equation,

Perimeter = 2l + 2(l - 4)

Perimeter = 2l + 2l - 8

Perimeter = 4l - 8

Since perimeter is 72m,

72 = 4l - 8

4l = 80

l = 20m

Answer:

Cabral is right

Step-by-step explanation:

Mark me brainleyest plz

Answer:

20

Step-by-step explanation:

add 3ft+3ft+11ft+3ft and that's your answer

Answer:

Step-by-step explanation:

Use pythagorean theorem

9^2 +40^2=x^2

81+1600=x^2

1681=x^2

now find the square root of each side

[tex]\sqrt{1681} =\sqrt{x}[/tex]

x=41

Answer:

20 + 75 = 95

Step-by-step explanation:

10 - 5 = 5 x 4 = 20

5 x 15 = 75

Add them together,

75 + 20 = 95

Step-by-step explanation:

Please refer to the attachment

Answer:

C) 1 3/8

I hope this helped :)

explanation:

I used the process of elimination. The other answers didn't make sense.

Answer:

c

Step-by-step explanation:

Answer:

y=3x^2 -15x-42

Step-by-step explanation:

Answer:

for 1 student it would equal 11.25

11.25 x 50 = 562.50

ur answer is 50 students hope this helps :)

Answer:

the teacher has 50 students

Step-by-step explanation:

1.75+9.50=11.25

562.50/11.25=50

Answer:

[tex]\frac{dA}{A} = -\frac{1}{70} dt[/tex]

A(t) = [tex]40 e^{-\frac{t}{70}}[/tex]

Step-by-step explanation:

Given - A tank contains 350 liters of fluid in which 40 grams of salt is dissolved. Pure water is then pumped into the tank at a rate of 5 L/min; the well-mixed solution is pumped out at the same rate. Let the A(t) be the number of grams of salt in the tank at time t.

To find - Find the rate at which the number of grams of salt in the tank is changing at time t.

Find the number A(t) of grams of salt in the tank at time t.

Proof -

Given that,

Total fluid in the tank = 350 litres

Total salt = 40 grams

Rate in flow = 5 L/min

Rate out flow = 5 L/min

Concentration in = 0

Concentration out = (Amount of salt at time t )/ (Solution in tank at time t)

Now,

Total solution in the tank at time t = Total fluid in the tank + (Rate in flow - Rate out flow )t

                                                        = 350 + (5 - 5)t

                                                        = 350

⇒Solution in the tank at time t = 350

⇒Concentration out = [tex]\frac{A(t)}{350}[/tex]

Now,

Rate of change in the tank at time t = [tex]\frac{dA}{dt}[/tex]

                                                           =  (Rate in flow )( Concentration In) - (Rate out flow )( Concentration out)

                                                           = 5(0) - 5([tex]\frac{A(t)}{350}[/tex])

                                                           = 0 - [tex]\frac{A(t)}{70}[/tex]

                                                           = [tex]-\frac{A(t)}{70}[/tex]

⇒[tex]\frac{dA}{dt}[/tex] = [tex]-\frac{A(t)}{70}[/tex]

⇒[tex]\frac{dA}{A} = -\frac{1}{70} dt[/tex]

Integrate both sides , we get

ln(A) = [tex]-\frac{1}{70}t + C[/tex]

⇒A(t) = [tex]e^{-\frac{t}{70}+ C}[/tex]

         = [tex]e^{-\frac{t}{70}}*e^{C}[/tex]

         = [tex]C_{1} e^{-\frac{t}{70}}[/tex]

⇒A(t) = [tex]C_{1} e^{-\frac{t}{70}}[/tex]

Now,

Given that,

Initially, the tank has 40 grams of salt

⇒A(0) = 40

⇒C₁ = 40

⇒A(t) = [tex]40 e^{-\frac{t}{70}}[/tex]

Answer:

B.

Step-by-step explanation:

(f-g)(x) = f(x) - g(x) =

= (3x³ + 8x² -7x - 4) - (2x - 6) = 3x³ + 8x² - 7x - 4 - 2x + 6 =

= 3x³ + 8x² - 9x + 2

Answer:

She can invite 66 people so 66 x 5 = $330 + 120 = $450

Step-by-step explanation:

Answer:

=4m+8

Step-by-step explanation:

=(4)(m+2)

=(4)(m)+(4)(2)

=4m+8

Answer:

4m +8

Step-by-step explanation:

Take out the parenthesis

Answer:

D.

Step-by-step explanation:

If you add them all up and subtract 30 you get 60

I MAYBE MESSED UP // haven't done this math in a while

Answer:

it is C.

Step-by-step explanation:

we know,

14+17= 31

so if we subtarct 17 from 31 we get 14

and if we subtract 14 from 31 we get 17